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For a portion of highway descending gradient 1 in 25 meets an ascending gradient 1 in 20. A valley curve needs to be designed at a velocity of 90 kmph based on
(i) Head light sight distance equal to stopping sight distance of a level terrain. Consider length of curve > SSD
(ii) Comfort condition if rate of change of acceleration is 0.5 m / s3
Reaction time = 2.5 sec, coefficient of longitudinal friction μ = 0.35. Height of head light = 0.75 m, and beam angle= 1°
(i) Head light sight distance equal to stopping sight distance of a level terrain. Consider length of curve > SSD
(ii) Comfort condition if rate of change of acceleration is 0.5 m / s3
Reaction time = 2.5 sec, coefficient of longitudinal friction μ = 0.35. Height of head light = 0.75 m, and beam angle= 1°
What is the length of valley curve (in m)based on the comfort condition? __________
Correct answer is between '106,107'. Can you explain this answer?
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To design the valley curve, we need to calculate the required length based on the headlight sight distance and stopping sight distance.
First, let's calculate the stopping sight distance on a level terrain at a velocity of 90 km/h. The stopping sight distance can be calculated using the formula:
SSD = 0.278 * V^2 / (2 * a)
Where:
SSD = Stopping Sight Distance (in meters)
V = Velocity (in km/h)
a = Deceleration or braking rate (in m/s^2)
Assuming a deceleration rate of 3 m/s^2, we can calculate the stopping sight distance:
V = 90 km/h = 25 m/s
a = 3 m/s^2
SSD = 0.278 * (25)^2 / (2 * 3)
SSD = 9.72 meters
Now, let's calculate the headlight sight distance on the descending gradient. The headlight sight distance on a descending gradient can be calculated using the formula:
HSD = SSD + (L * (G1 - G2))
Where:
HSD = Headlight Sight Distance (in meters)
SSD = Stopping Sight Distance (in meters)
L = Length of the curve (in meters)
G1 = Gradient of the descending slope (1 in 25)
G2 = Gradient of the ascending slope (1 in 20)
We need to make HSD equal to SSD, so we can set up the equation:
SSD = SSD + (L * (G1 - G2))
Substituting the values:
9.72 = 9.72 + (L * (1/25 - 1/20))
Simplifying the equation:
0 = L * (1/25 - 1/20)
0 = L * (4/100 - 5/100)
0 = L * (-1/100)
Since the length cannot be negative, we can conclude that the length of the curve should be 0 meters. This means that no additional curve is required on the highway section with the given gradients and velocity.
First, let's calculate the stopping sight distance on a level terrain at a velocity of 90 km/h. The stopping sight distance can be calculated using the formula:
SSD = 0.278 * V^2 / (2 * a)
Where:
SSD = Stopping Sight Distance (in meters)
V = Velocity (in km/h)
a = Deceleration or braking rate (in m/s^2)
Assuming a deceleration rate of 3 m/s^2, we can calculate the stopping sight distance:
V = 90 km/h = 25 m/s
a = 3 m/s^2
SSD = 0.278 * (25)^2 / (2 * 3)
SSD = 9.72 meters
Now, let's calculate the headlight sight distance on the descending gradient. The headlight sight distance on a descending gradient can be calculated using the formula:
HSD = SSD + (L * (G1 - G2))
Where:
HSD = Headlight Sight Distance (in meters)
SSD = Stopping Sight Distance (in meters)
L = Length of the curve (in meters)
G1 = Gradient of the descending slope (1 in 25)
G2 = Gradient of the ascending slope (1 in 20)
We need to make HSD equal to SSD, so we can set up the equation:
SSD = SSD + (L * (G1 - G2))
Substituting the values:
9.72 = 9.72 + (L * (1/25 - 1/20))
Simplifying the equation:
0 = L * (1/25 - 1/20)
0 = L * (4/100 - 5/100)
0 = L * (-1/100)
Since the length cannot be negative, we can conclude that the length of the curve should be 0 meters. This means that no additional curve is required on the highway section with the given gradients and velocity.
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For a portion of highway descending gradient 1 in 25 meets an ascending gradient 1 in 20. A valley curve needs to be designed at a velocity of 90 kmph based on(i) Head light sight distance equal to stopping sight distance of a level terrain. Consider length of curve > SSD(ii) Comfort condition if rate of change of acceleration is 0.5 m / s3Reaction time = 2.5 sec, coefficient of longitudinal friction μ = 0.35. Height of head light = 0.75 m, and beam angle= 1°What is the length of valley curve (in m)based on the comfort condition? __________Correct answer is between '106,107'. Can you explain this answer?
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For a portion of highway descending gradient 1 in 25 meets an ascending gradient 1 in 20. A valley curve needs to be designed at a velocity of 90 kmph based on(i) Head light sight distance equal to stopping sight distance of a level terrain. Consider length of curve > SSD(ii) Comfort condition if rate of change of acceleration is 0.5 m / s3Reaction time = 2.5 sec, coefficient of longitudinal friction μ = 0.35. Height of head light = 0.75 m, and beam angle= 1°What is the length of valley curve (in m)based on the comfort condition? __________Correct answer is between '106,107'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about For a portion of highway descending gradient 1 in 25 meets an ascending gradient 1 in 20. A valley curve needs to be designed at a velocity of 90 kmph based on(i) Head light sight distance equal to stopping sight distance of a level terrain. Consider length of curve > SSD(ii) Comfort condition if rate of change of acceleration is 0.5 m / s3Reaction time = 2.5 sec, coefficient of longitudinal friction μ = 0.35. Height of head light = 0.75 m, and beam angle= 1°What is the length of valley curve (in m)based on the comfort condition? __________Correct answer is between '106,107'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for For a portion of highway descending gradient 1 in 25 meets an ascending gradient 1 in 20. A valley curve needs to be designed at a velocity of 90 kmph based on(i) Head light sight distance equal to stopping sight distance of a level terrain. Consider length of curve > SSD(ii) Comfort condition if rate of change of acceleration is 0.5 m / s3Reaction time = 2.5 sec, coefficient of longitudinal friction μ = 0.35. Height of head light = 0.75 m, and beam angle= 1°What is the length of valley curve (in m)based on the comfort condition? __________Correct answer is between '106,107'. Can you explain this answer?.
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