Formaldehyde polymerizes to form glucose according to the reaction 6HCHO C6H12O6 The theoretically computed equilibrium constant for this reaction is found to be 6 andtimes; 1022. If 1 M solution of glucose dissociates according to the above equilibrium, the concentration of formaldehyde in the solution will bea)1.6 x 10-2Mb)1.6 x 10-4Mc)1.6 x 10-6Md)1.6 x 10-8MCorrect answer is option 'B'. Can you explain this answer?

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Formaldehyde polymerizes to form glucose according to the reaction 6HCHO

C₆H₁₂O₆ The theoretically computed equilibrium constant for this reaction is found to be 6 × 10²². If 1 M solution of glucose dissociates according to the above equilibrium, the concentration of formaldehyde in the solution will be

a)
1.6 x 10^-2M
b)
1.6 x 10^-4M
c)
1.6 x 10^-6M
d)
1.6 x 10^-8M

Correct answer is option 'B'. Can you explain this answer?

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Formaldehyde polymerizes to form glucose according to the reaction 6HC...

The dissociation of glucose to form formaldehyde at very high value of equilibrium constant is very small.
Therefore at equilibrium,

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Formaldehyde polymerizes to form glucose according to the reaction 6HCHO C6H12O6 The theoretically computed equilibrium constant for this reaction is found to be 6 × 1022. If 1 M solution of glucose dissociates according to the above equilibrium, the concentration of formaldehyde in the solution will bea)1.6 x 10-2Mb)1.6 x 10-4Mc)1.6 x 10-6Md)1.6 x 10-8MCorrect answer is option 'B'. Can you explain this answer?

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Formaldehyde polymerizes to form glucose according to the reaction 6HCHO C6H12O6 The theoretically computed equilibrium constant for this reaction is found to be 6 × 1022. If 1 M solution of glucose dissociates according to the above equilibrium, the concentration of formaldehyde in the solution will bea)1.6 x 10-2Mb)1.6 x 10-4Mc)1.6 x 10-6Md)1.6 x 10-8MCorrect answer is option 'B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Formaldehyde polymerizes to form glucose according to the reaction 6HCHO C6H12O6 The theoretically computed equilibrium constant for this reaction is found to be 6 × 1022. If 1 M solution of glucose dissociates according to the above equilibrium, the concentration of formaldehyde in the solution will bea)1.6 x 10-2Mb)1.6 x 10-4Mc)1.6 x 10-6Md)1.6 x 10-8MCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Formaldehyde polymerizes to form glucose according to the reaction 6HCHO C6H12O6 The theoretically computed equilibrium constant for this reaction is found to be 6 × 1022. If 1 M solution of glucose dissociates according to the above equilibrium, the concentration of formaldehyde in the solution will bea)1.6 x 10-2Mb)1.6 x 10-4Mc)1.6 x 10-6Md)1.6 x 10-8MCorrect answer is option 'B'. Can you explain this answer?.

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