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A piece of steel has a weight W in air, W1 when completely immersed in water and W2 when completely immersed in an unknown liquid. The relative density (specific gravity) of liquid is :
  • a)
     
  • b)
  • c)
  • d)
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
A piece of steel has a weight W in air, W1when completely immersed in ...
If the loss of weight of a body in water is 'a' while in liquid is 'b' then
Sigma in liquid / sigma in water = upthrust on body in liquid / upthrust on body in water
Then a / b = (W air - W liquid) / (W air - W water).
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Most Upvoted Answer
A piece of steel has a weight W in air, W1when completely immersed in ...
If the loss of weight of a body in water is 'a' while in liquid is 'b'... then, sigma in liquid / sigma in water = upthrust on body in liquid / upthrust on body in water.. then a / b = W air - W liquid / W air - W water.....
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Community Answer
A piece of steel has a weight W in air, W1when completely immersed in ...
If the loss of weight of a body in water is 'a' while in liquid is 'b' then
Sigma in liquid / sigma in water = upthrust on body in liquid / upthrust on body in water
Then a / b = (W air - W liquid) / (W air - W water).
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A piece of steel has a weight W in air, W1when completely immersed in water and W2when completely immersed in an unknown liquid. The relative density (specific gravity) of liquid is :a)b)c)d)Correct answer is option 'B'. Can you explain this answer?
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