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Let [∈0] denote the dimensional formula of the permittivity of vacuum. If M = mass, L = length, T = time and A = electric current, then:a)∈0 = [M–1 L–3T2 A]b)∈0 = [M1 L3T5 A2]c)∈0 = [M1 L2T1 A2]d)∈0 = [M1 L2T1 A]Correct answer is option 'B'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Let [∈0] denote the dimensional formula of the permittivity of vacuum. If M = mass, L = length, T = time and A = electric current, then:a)∈0 = [M–1 L–3T2 A]b)∈0 = [M1 L3T5 A2]c)∈0 = [M1 L2T1 A2]d)∈0 = [M1 L2T1 A]Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Let [∈0] denote the dimensional formula of the permittivity of vacuum. If M = mass, L = length, T = time and A = electric current, then:a)∈0 = [M–1 L–3T2 A]b)∈0 = [M1 L3T5 A2]c)∈0 = [M1 L2T1 A2]d)∈0 = [M1 L2T1 A]Correct answer is option 'B'. Can you explain this answer?.

Solutions for Let [∈0] denote the dimensional formula of the permittivity of vacuum. If M = mass, L = length, T = time and A = electric current, then:a)∈0 = [M–1 L–3T2 A]b)∈0 = [M1 L3T5 A2]c)∈0 = [M1 L2T1 A2]d)∈0 = [M1 L2T1 A]Correct answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.

Here you can find the meaning of Let [∈0] denote the dimensional formula of the permittivity of vacuum. If M = mass, L = length, T = time and A = electric current, then:a)∈0 = [M–1 L–3T2 A]b)∈0 = [M1 L3T5 A2]c)∈0 = [M1 L2T1 A2]d)∈0 = [M1 L2T1 A]Correct answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of Let [∈0] denote the dimensional formula of the permittivity of vacuum. If M = mass, L = length, T = time and A = electric current, then:a)∈0 = [M–1 L–3T2 A]b)∈0 = [M1 L3T5 A2]c)∈0 = [M1 L2T1 A2]d)∈0 = [M1 L2T1 A]Correct answer is option 'B'. Can you explain this answer?, a detailed solution for Let [∈0] denote the dimensional formula of the permittivity of vacuum. If M = mass, L = length, T = time and A = electric current, then:a)∈0 = [M–1 L–3T2 A]b)∈0 = [M1 L3T5 A2]c)∈0 = [M1 L2T1 A2]d)∈0 = [M1 L2T1 A]Correct answer is option 'B'. Can you explain this answer? has been provided alongside types of Let [∈0] denote the dimensional formula of the permittivity of vacuum. If M = mass, L = length, T = time and A = electric current, then:a)∈0 = [M–1 L–3T2 A]b)∈0 = [M1 L3T5 A2]c)∈0 = [M1 L2T1 A2]d)∈0 = [M1 L2T1 A]Correct answer is option 'B'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice Let [∈0] denote the dimensional formula of the permittivity of vacuum. If M = mass, L = length, T = time and A = electric current, then:a)∈0 = [M–1 L–3T2 A]b)∈0 = [M1 L3T5 A2]c)∈0 = [M1 L2T1 A2]d)∈0 = [M1 L2T1 A]Correct answer is option 'B'. Can you explain this answer? tests, examples and also practice JEE tests.