The length of a road roller is 2 m and its base diameter is 50 cm .It ...
Given information:
- Length of the road roller = 2 m.
- Base diameter of the road roller = 50 cm.
- Number of revolutions to level the ground = 700.
Calculating the circumference of the roller:
- The base diameter of the roller is given as 50 cm, which implies the radius is half of the diameter, i.e., 25 cm or 0.25 m.
- The circumference of a circle is given by the formula C = 2πr, where r is the radius.
- Substituting the value of the radius, we get C = 2π(0.25) = 1.57 m.
Calculating the distance covered by the roller in 700 revolutions:
- The distance covered by the roller in one revolution is equal to its circumference, which is 1.57 m.
- Therefore, the total distance covered in 700 revolutions is 1.57 m/rev * 700 rev = 1099 m.
Calculating the area of the ground:
- The area covered by the roller in one revolution is a rectangle with length equal to the length of the roller (2 m) and width equal to the distance covered in one revolution (1.57 m).
- Therefore, the area covered in one revolution is 2 m * 1.57 m = 3.14 m².
- The total area covered by the roller in 700 revolutions is 3.14 m²/rev * 700 rev = 2198 m².
Final answer:
The area of the ground leveled by the road roller is 2198 m².
The length of a road roller is 2 m and its base diameter is 50 cm .It ...
Given that
height = 2m
radius = 0.50/2=0.25m
so,
CSA of roller = 2*π*r*h
= 2×22/7 ×0.25× 2
= 22/7m2
Now, area of the ground = CSA *number of revolutions
SO, 22/7×700
= 2,200m2....
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