CBSE Physics Past year paper (Solutions) - 2014, Class 12 Class 12 Notes | EduRev

Physics Class 12

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Class 12 : CBSE Physics Past year paper (Solutions) - 2014, Class 12 Class 12 Notes | EduRev

 Page 1


  
 
CBSE  |  Physics 
Board Paper – 2014 
 
     
CBSE Board 
Class XII Physics (Theory) 
Board Question Paper 2014 – Set 3 
 
 
1. Anticlockwise 
 
2. Metal A , because ?? ?? '
> ?? 0
   
 
3. The ampere is the value of that steady current which, when maintained in each of the 
two very long, straight, parallel conductors of negligible cross-section, and placed one 
metre apart in vacuum, would produce on each of these conductors a force equal to 2 × 
10
-7
 newtons per metre of length. 
 
4. The lens will behave as a diverging lens.  
The lens is of refractive index lesser than the medium in which it is placed. Hence, its 
nature does not change. 
 
5. Electric field line is a curve drawn in such a way that the tangent to it at each point is in 
the direction of the net field at that point. Two fields can never cross each other. If they 
did ,it means the field at the point of intersection will not have a unique direction, which 
is meaningless) 
 
6. The frequency belongs to microwave region of the electromagnetic spectrum. 
 
7. Neutrinos interact very weakly with other particles. Since they can penetrate large 
quantity of matter without interacting  they remain  undetected throughout the  
experiments. 
 
8. a.c. voltage is preferred over d.c. because 
(i) a.c. voltages can be easily stepped up or down with the help of transformers. 
(ii) Electrical energy can be transmitted efficiently and economically over long 
distances with higher voltage and lower current. 
 
 
 
 
 
 
 
 
 
 
Page 2


  
 
CBSE  |  Physics 
Board Paper – 2014 
 
     
CBSE Board 
Class XII Physics (Theory) 
Board Question Paper 2014 – Set 3 
 
 
1. Anticlockwise 
 
2. Metal A , because ?? ?? '
> ?? 0
   
 
3. The ampere is the value of that steady current which, when maintained in each of the 
two very long, straight, parallel conductors of negligible cross-section, and placed one 
metre apart in vacuum, would produce on each of these conductors a force equal to 2 × 
10
-7
 newtons per metre of length. 
 
4. The lens will behave as a diverging lens.  
The lens is of refractive index lesser than the medium in which it is placed. Hence, its 
nature does not change. 
 
5. Electric field line is a curve drawn in such a way that the tangent to it at each point is in 
the direction of the net field at that point. Two fields can never cross each other. If they 
did ,it means the field at the point of intersection will not have a unique direction, which 
is meaningless) 
 
6. The frequency belongs to microwave region of the electromagnetic spectrum. 
 
7. Neutrinos interact very weakly with other particles. Since they can penetrate large 
quantity of matter without interacting  they remain  undetected throughout the  
experiments. 
 
8. a.c. voltage is preferred over d.c. because 
(i) a.c. voltages can be easily stepped up or down with the help of transformers. 
(ii) Electrical energy can be transmitted efficiently and economically over long 
distances with higher voltage and lower current. 
 
 
 
 
 
 
 
 
 
 
  
 
CBSE  |  Physics 
Board Paper – 2014 
 
     
 
9. Consider the charging of a capacitor. 
The electric field between the plates of the capacitor is shown below 
 
 
 
If the plates of the capacitor have an area A and a total charge Q, the magnitude of the 
electric field between the plates is 
 
0
Q
E
A
?
?
 
The field is perpendicular to the surface S as shown in the figure. 
Thus, using Gauss’s law the electric flux through the surface is 
 
E
00
QA Q
EA
A
? ? ? ?
??
 
Now, if the charge Q on the capacitor is changing with time, there is a current 
dQ
i
dt
?
associated with it, so we have 
 
E
00
E
0
d d Q 1 dQ
dt dt dt
d
i
dt
?
??
??
? ??
? ? ?
??
??
 
This term is the current due to changing electric field and is called displacement 
current. Thus, the Ampere’s Circuital law is modified to give 
 
E
0 c 0 0
d
B dl i
dt
?
? ? ? ? ? ?
?
 
 
 
 
 
 
 
 
Page 3


  
 
CBSE  |  Physics 
Board Paper – 2014 
 
     
CBSE Board 
Class XII Physics (Theory) 
Board Question Paper 2014 – Set 3 
 
 
1. Anticlockwise 
 
2. Metal A , because ?? ?? '
> ?? 0
   
 
3. The ampere is the value of that steady current which, when maintained in each of the 
two very long, straight, parallel conductors of negligible cross-section, and placed one 
metre apart in vacuum, would produce on each of these conductors a force equal to 2 × 
10
-7
 newtons per metre of length. 
 
4. The lens will behave as a diverging lens.  
The lens is of refractive index lesser than the medium in which it is placed. Hence, its 
nature does not change. 
 
5. Electric field line is a curve drawn in such a way that the tangent to it at each point is in 
the direction of the net field at that point. Two fields can never cross each other. If they 
did ,it means the field at the point of intersection will not have a unique direction, which 
is meaningless) 
 
6. The frequency belongs to microwave region of the electromagnetic spectrum. 
 
7. Neutrinos interact very weakly with other particles. Since they can penetrate large 
quantity of matter without interacting  they remain  undetected throughout the  
experiments. 
 
8. a.c. voltage is preferred over d.c. because 
(i) a.c. voltages can be easily stepped up or down with the help of transformers. 
(ii) Electrical energy can be transmitted efficiently and economically over long 
distances with higher voltage and lower current. 
 
 
 
 
 
 
 
 
 
 
  
 
CBSE  |  Physics 
Board Paper – 2014 
 
     
 
9. Consider the charging of a capacitor. 
The electric field between the plates of the capacitor is shown below 
 
 
 
If the plates of the capacitor have an area A and a total charge Q, the magnitude of the 
electric field between the plates is 
 
0
Q
E
A
?
?
 
The field is perpendicular to the surface S as shown in the figure. 
Thus, using Gauss’s law the electric flux through the surface is 
 
E
00
QA Q
EA
A
? ? ? ?
??
 
Now, if the charge Q on the capacitor is changing with time, there is a current 
dQ
i
dt
?
associated with it, so we have 
 
E
00
E
0
d d Q 1 dQ
dt dt dt
d
i
dt
?
??
??
? ??
? ? ?
??
??
 
This term is the current due to changing electric field and is called displacement 
current. Thus, the Ampere’s Circuital law is modified to give 
 
E
0 c 0 0
d
B dl i
dt
?
? ? ? ? ? ?
?
 
 
 
 
 
 
 
 
  
 
CBSE  |  Physics 
Board Paper – 2014 
 
     
 
10. Given: 
 
28 -3
19
72
I 2.7 A
n 9 10 m
e 1.6 10 C
A 2.5 10 m
?
?
?
??
??
??
 
 
The drift speed is given as 
 
? ? ? ? ? ?
4
d
28 19 7
I 2.7
v 7.5 10 m/s
neA 9 10 1.6 10 2.5 10
?
??
? ? ? ?
? ? ?
 
 
11. The terminal voltage across a cell is given as 
 V E Ir ?? 
Here, E is the e.m.f. of the cell and r is its internal resistance. 
The above equation is of the form y = mx + c where y = V, m = -r, x = I and c = E 
 
Hence, the graph of V vs I will be as shown below. 
 
From the graph, it is clear that the y-intercept, that is, the intercept on V-axis gives the 
value of e.m.f. (E) of the cell. 
Also, the negative of slope of the graph gives the internal resistance (r) of the cell. 
 
12. The capacitance of two capacitors is same, i.e. C. 
The voltage across charged capacitor is V 1 = V and that across uncharged capacitor is V 2 
= 0. 
 
Thus, the initial energy stored in the capacitor is 
 
22
1 1 1
11
U C V CV
22
?? 
When the charged capacitor is connected across the uncharged capacitor, the two 
capacitors form a parallel combination. 
Thus, the resultant capacitance is C’ = C + C = 2C 
Page 4


  
 
CBSE  |  Physics 
Board Paper – 2014 
 
     
CBSE Board 
Class XII Physics (Theory) 
Board Question Paper 2014 – Set 3 
 
 
1. Anticlockwise 
 
2. Metal A , because ?? ?? '
> ?? 0
   
 
3. The ampere is the value of that steady current which, when maintained in each of the 
two very long, straight, parallel conductors of negligible cross-section, and placed one 
metre apart in vacuum, would produce on each of these conductors a force equal to 2 × 
10
-7
 newtons per metre of length. 
 
4. The lens will behave as a diverging lens.  
The lens is of refractive index lesser than the medium in which it is placed. Hence, its 
nature does not change. 
 
5. Electric field line is a curve drawn in such a way that the tangent to it at each point is in 
the direction of the net field at that point. Two fields can never cross each other. If they 
did ,it means the field at the point of intersection will not have a unique direction, which 
is meaningless) 
 
6. The frequency belongs to microwave region of the electromagnetic spectrum. 
 
7. Neutrinos interact very weakly with other particles. Since they can penetrate large 
quantity of matter without interacting  they remain  undetected throughout the  
experiments. 
 
8. a.c. voltage is preferred over d.c. because 
(i) a.c. voltages can be easily stepped up or down with the help of transformers. 
(ii) Electrical energy can be transmitted efficiently and economically over long 
distances with higher voltage and lower current. 
 
 
 
 
 
 
 
 
 
 
  
 
CBSE  |  Physics 
Board Paper – 2014 
 
     
 
9. Consider the charging of a capacitor. 
The electric field between the plates of the capacitor is shown below 
 
 
 
If the plates of the capacitor have an area A and a total charge Q, the magnitude of the 
electric field between the plates is 
 
0
Q
E
A
?
?
 
The field is perpendicular to the surface S as shown in the figure. 
Thus, using Gauss’s law the electric flux through the surface is 
 
E
00
QA Q
EA
A
? ? ? ?
??
 
Now, if the charge Q on the capacitor is changing with time, there is a current 
dQ
i
dt
?
associated with it, so we have 
 
E
00
E
0
d d Q 1 dQ
dt dt dt
d
i
dt
?
??
??
? ??
? ? ?
??
??
 
This term is the current due to changing electric field and is called displacement 
current. Thus, the Ampere’s Circuital law is modified to give 
 
E
0 c 0 0
d
B dl i
dt
?
? ? ? ? ? ?
?
 
 
 
 
 
 
 
 
  
 
CBSE  |  Physics 
Board Paper – 2014 
 
     
 
10. Given: 
 
28 -3
19
72
I 2.7 A
n 9 10 m
e 1.6 10 C
A 2.5 10 m
?
?
?
??
??
??
 
 
The drift speed is given as 
 
? ? ? ? ? ?
4
d
28 19 7
I 2.7
v 7.5 10 m/s
neA 9 10 1.6 10 2.5 10
?
??
? ? ? ?
? ? ?
 
 
11. The terminal voltage across a cell is given as 
 V E Ir ?? 
Here, E is the e.m.f. of the cell and r is its internal resistance. 
The above equation is of the form y = mx + c where y = V, m = -r, x = I and c = E 
 
Hence, the graph of V vs I will be as shown below. 
 
From the graph, it is clear that the y-intercept, that is, the intercept on V-axis gives the 
value of e.m.f. (E) of the cell. 
Also, the negative of slope of the graph gives the internal resistance (r) of the cell. 
 
12. The capacitance of two capacitors is same, i.e. C. 
The voltage across charged capacitor is V 1 = V and that across uncharged capacitor is V 2 
= 0. 
 
Thus, the initial energy stored in the capacitor is 
 
22
1 1 1
11
U C V CV
22
?? 
When the charged capacitor is connected across the uncharged capacitor, the two 
capacitors form a parallel combination. 
Thus, the resultant capacitance is C’ = C + C = 2C 
  
 
CBSE  |  Physics 
Board Paper – 2014 
 
     
The initial charge on the capacitor is q = CV 
The final potential across the combination will be 
 
12
qq q CV V
V'
C' 2C 2C 2
?
? ? ? ? 
Hence, the final energy in the combination of capacitors is 
 ? ?
2
22
2
2
1 1 V 2CV 1 CV
U C'V' 2C
2 2 2 8 2 2
??
? ? ? ?
??
??
 
 
Thus, the ratio of energy stored in the combined system to that in the initial single  
capacitor is given as 
 
2
2
2
1
1 CV
U 1
22
1
U2
CV
2
?? 
 
13. The Rutherford model of atom considers the atom as an electrically neutral sphere 
consisting of a very small, massive and positively charged nucleus at the centre 
surrounded by the revolving electrons in their respective dynamically stable orbits. 
 
The electrostatic force of attraction F e between the revolving electrons and the nucleus 
provides the centripetal force F c to keep them in stable orbits. 
 
?
?
??
??
??
ec
22
2
0
2
2
0
FF
mv 1 e
r 4 r
e
r
4 mv
 
The kinetic energy and electrostatic potential energy of the electron in hydrogen atom 
are 
 
2
2
0
2
0
1e
K mv
2 8 r
e
U
4r
??
??
??
??
 
Thus, the total energy E of the electron in a hydrogen atom is 
 
22
00
2
0
ee
E K U
8 r 4 r
e
                
8r
? ? ? ?
? ? ? ?
??
??
 
The total energy is negative. 
 
Page 5


  
 
CBSE  |  Physics 
Board Paper – 2014 
 
     
CBSE Board 
Class XII Physics (Theory) 
Board Question Paper 2014 – Set 3 
 
 
1. Anticlockwise 
 
2. Metal A , because ?? ?? '
> ?? 0
   
 
3. The ampere is the value of that steady current which, when maintained in each of the 
two very long, straight, parallel conductors of negligible cross-section, and placed one 
metre apart in vacuum, would produce on each of these conductors a force equal to 2 × 
10
-7
 newtons per metre of length. 
 
4. The lens will behave as a diverging lens.  
The lens is of refractive index lesser than the medium in which it is placed. Hence, its 
nature does not change. 
 
5. Electric field line is a curve drawn in such a way that the tangent to it at each point is in 
the direction of the net field at that point. Two fields can never cross each other. If they 
did ,it means the field at the point of intersection will not have a unique direction, which 
is meaningless) 
 
6. The frequency belongs to microwave region of the electromagnetic spectrum. 
 
7. Neutrinos interact very weakly with other particles. Since they can penetrate large 
quantity of matter without interacting  they remain  undetected throughout the  
experiments. 
 
8. a.c. voltage is preferred over d.c. because 
(i) a.c. voltages can be easily stepped up or down with the help of transformers. 
(ii) Electrical energy can be transmitted efficiently and economically over long 
distances with higher voltage and lower current. 
 
 
 
 
 
 
 
 
 
 
  
 
CBSE  |  Physics 
Board Paper – 2014 
 
     
 
9. Consider the charging of a capacitor. 
The electric field between the plates of the capacitor is shown below 
 
 
 
If the plates of the capacitor have an area A and a total charge Q, the magnitude of the 
electric field between the plates is 
 
0
Q
E
A
?
?
 
The field is perpendicular to the surface S as shown in the figure. 
Thus, using Gauss’s law the electric flux through the surface is 
 
E
00
QA Q
EA
A
? ? ? ?
??
 
Now, if the charge Q on the capacitor is changing with time, there is a current 
dQ
i
dt
?
associated with it, so we have 
 
E
00
E
0
d d Q 1 dQ
dt dt dt
d
i
dt
?
??
??
? ??
? ? ?
??
??
 
This term is the current due to changing electric field and is called displacement 
current. Thus, the Ampere’s Circuital law is modified to give 
 
E
0 c 0 0
d
B dl i
dt
?
? ? ? ? ? ?
?
 
 
 
 
 
 
 
 
  
 
CBSE  |  Physics 
Board Paper – 2014 
 
     
 
10. Given: 
 
28 -3
19
72
I 2.7 A
n 9 10 m
e 1.6 10 C
A 2.5 10 m
?
?
?
??
??
??
 
 
The drift speed is given as 
 
? ? ? ? ? ?
4
d
28 19 7
I 2.7
v 7.5 10 m/s
neA 9 10 1.6 10 2.5 10
?
??
? ? ? ?
? ? ?
 
 
11. The terminal voltage across a cell is given as 
 V E Ir ?? 
Here, E is the e.m.f. of the cell and r is its internal resistance. 
The above equation is of the form y = mx + c where y = V, m = -r, x = I and c = E 
 
Hence, the graph of V vs I will be as shown below. 
 
From the graph, it is clear that the y-intercept, that is, the intercept on V-axis gives the 
value of e.m.f. (E) of the cell. 
Also, the negative of slope of the graph gives the internal resistance (r) of the cell. 
 
12. The capacitance of two capacitors is same, i.e. C. 
The voltage across charged capacitor is V 1 = V and that across uncharged capacitor is V 2 
= 0. 
 
Thus, the initial energy stored in the capacitor is 
 
22
1 1 1
11
U C V CV
22
?? 
When the charged capacitor is connected across the uncharged capacitor, the two 
capacitors form a parallel combination. 
Thus, the resultant capacitance is C’ = C + C = 2C 
  
 
CBSE  |  Physics 
Board Paper – 2014 
 
     
The initial charge on the capacitor is q = CV 
The final potential across the combination will be 
 
12
qq q CV V
V'
C' 2C 2C 2
?
? ? ? ? 
Hence, the final energy in the combination of capacitors is 
 ? ?
2
22
2
2
1 1 V 2CV 1 CV
U C'V' 2C
2 2 2 8 2 2
??
? ? ? ?
??
??
 
 
Thus, the ratio of energy stored in the combined system to that in the initial single  
capacitor is given as 
 
2
2
2
1
1 CV
U 1
22
1
U2
CV
2
?? 
 
13. The Rutherford model of atom considers the atom as an electrically neutral sphere 
consisting of a very small, massive and positively charged nucleus at the centre 
surrounded by the revolving electrons in their respective dynamically stable orbits. 
 
The electrostatic force of attraction F e between the revolving electrons and the nucleus 
provides the centripetal force F c to keep them in stable orbits. 
 
?
?
??
??
??
ec
22
2
0
2
2
0
FF
mv 1 e
r 4 r
e
r
4 mv
 
The kinetic energy and electrostatic potential energy of the electron in hydrogen atom 
are 
 
2
2
0
2
0
1e
K mv
2 8 r
e
U
4r
??
??
??
??
 
Thus, the total energy E of the electron in a hydrogen atom is 
 
22
00
2
0
ee
E K U
8 r 4 r
e
                
8r
? ? ? ?
? ? ? ?
??
??
 
The total energy is negative. 
 
  
 
CBSE  |  Physics 
Board Paper – 2014 
 
     
The significance of this negative energy is that the electron is bound to the nucleus. If it 
is positive, then the electron will not follow a closed orbit around the nucleus. 
OR 
To find the expression of radius, Bohr’s second postulate is used. 
The expression of angular momentum is 
 L mvr ? 
Bohr’s second postulate of quantisation says electron revolves only in those orbits for 
which the angular momentum is integral multiple of h/2 ?. 
 
nh
L
2
?
?
 
Thus, for electron in n
th
 orbit 
 
nn
nh
L mv r
2
??
?
     …… (1) 
The relation between velocity and radius for electron in n
th
 orbit is  
 
n
0n
e
v
4 mr
?
??
     …… (2) 
From equations (1) and (2), we get 
 
? ?
n
0
n
2
2 n
n
0
e
v
nh
4m
2 mv
ev
v
h
4n
2
?
??
?
??
??
?
 
 
? ?
2
n
0
e1
v
h 4n
2
??
??
?
     …… (3) 
Substituting (3) in (1), we get 
 
2
2
0
n 2
4 nh
r
m 2 e
?? ?? ??
?
????
?
??
??
    …… (4) 
This gives the radius of electron in the n
th
 orbit 
From equation (4), the radius of innermost orbit n = 1 is found as 
 
2
0
1 2
h
r
me
?
?
?
 
This is called the Bohr radius and is denoted as a 0. 
 
14.  
(i) Field lines around a paramagnetic substance 
 
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