Example 1: What is the potential for the following cell?
Zn|Zn2+ (1.0M)||Cu2+ (1.0M)| Cu
Ans: From a table of standard reduction potentials we have the following values
Cu2+ + 2e− → CuE∘ = 0.337 (1)
Zn → Zn2+ + 2e−E∗ = 0.763 (2)
Add (1) and (2) to yield
Zn+ Cu2+ → Zn2+ + CuDE∘ = E∘ + E∗ = 1.100 V
Note that E* is the oxidation standard potential, and E° is the reduction standard potential, E* = - E°. The standard cell potential is represented by dE°.
Discussion
The positive potential confirms your observation that zinc metal reacts with cupric ions in solution to produce copper metal.
Example 2: What is the potential for the following cell?
Ag|Ag+ (1.0M)||Li + (1.0M)|Li
Ans: From the table of standard reduction potentials, you find
Li+ + e− → Li E∘ = −3.045 (3)
Ag → Ag+ + e− E∗ = − 0.799 (4)
According to the convention of the cell, the reduction reaction is on the right. The cell on your left-hand side is an oxidation process. Thus, you add (4) and (3) to obtain
Li+ + Ag→Ag+ + Li dE∘ = -3.844 V
Discussion
Summary
1. What is electromotive force (EMF)? |
2. How is the standard cell potential (E°) evaluated for galvanic cells? |
3. What is the significance of evaluating the standard cell potential (E°) of galvanic cells? |
4. How can the electromotive force (EMF) of a cell be calculated using the standard cell potential (E°)? |
5. Why is it important to consider the standard cell potential (E°) in galvanic cells? |
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