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De Broglie's Postulate & Heisenberg Uncertainty Principle | Chemistry Optional Notes for UPSC PDF Download

Introduction

  • The next real advance in understanding the atom came from an unlikely quarter - a student prince in Paris. Prince Louis de Broglie was a member of an illustrious family, prominent in politics and the military since the 1600's. Louis began his university studies with history, but his elder brother Maurice studied x-rays in his own laboratory, and Louis became interested in physics. After World War I, de Broglie focused his attention on Einstein's two major achievements, the theory of special relativity and the quantization of light waves. 
  • He wondered if there could be some connection between them. Perhaps the quantum of radiation really should be thought of as a particle. De Broglie suggested that if waves (photons) could behave as particles, as demonstrated by the photoelectric effect, then the converse, namely that particles could behave as waves, should be true. He associated a wavelength λ to a particle with momentum p using Planck's constant as the constant of proportionality:
    λ = h/p
  • which is called the de Broglie wavelength. The fact that particles can behave as waves but also as particles, depending on which experiment you perform on them, is known as the wave-particle duality.

Deriving the de Broglie Wavelength

  • From the discussion of the photoelectric effect, we have the first part of the particle-wave duality, namely, that electromagnetic waves can behave like particles. These particles are known as photons, and they move at the speed of light. Any particle that moves at or near the speed of light has kinetic energy given by Einstein's special theory of relatively. In general, a particle of mass  m  and momentum  p has an energy

De Broglie`s Postulate & Heisenberg Uncertainty Principle | Chemistry Optional Notes for UPSC

  • Note that if  p = 0 , this reduces to the famous rest-energy expression  E = mc2 . However, photons are massless particles (technically rest-massless) that always have a finite momentum  p . In this case, Equation  4.5.2  becomes
    E = pc.
  • From Planck's hypothesis, one quantum of electromagnetic radiation has energy  E = hν. Thus, equating these two expressions for the kinetic energy of a photon, we have
    hν = hc/λ = pc
    Solving for the wavelength  λ  gives Equation  4.5.1
    λ = h/p = hmv
    where v  is the velocity of the particle. Hence, de Broglie argued that if particles can behave as waves, then a relationship like this, which pertains particularly to waves, should also apply to particles.
  • Equation  4.5.1 allows us to associate a wavelength  λ  to a particle with momentum  p . As the momentum increases, the wavelength decreases. In both cases, this means the energy becomes larger. i.e., short wavelengths and high momenta correspond to high energies. It is a common feature of quantum mechanics that particles and waves with short wavelengths correspond to high energies and vice versa.
  • Having decided that the photon might well be a particle with a rest mass, even if very small, it dawned on de Broglie that in other respects it might not be too different from other particles, especially the very light electron. In particular, maybe the electron also had an associated wave. The obvious objection was that if the electron was wavelike, why had no diffraction or interference effects been observed? But there was an answer. If de Broglie's relation between momentum and wavelength also held for electrons, the wavelength was sufficiently short that these effects would be easy to miss. 
  • As de Broglie himself pointed out, the wave nature of light is not very evident in everyday life. As the next section will demonstrate, the validity of de Broglie’s proposal was confirmed by electron diffraction experiments of G.P. Thomson in 1926 and of C. Davisson and L. H. Germer in 1927. In these experiments it was found that electrons were scattered from atoms in a crystal and that these scattered electrons produced an interference pattern. These diffraction patterns are characteristic of wave-like behavior and are exhibited by both electrons (i.e., matter) and electromagnetic radiation (i.e., light).

Solved Examples

Example 1: Calculate the de Broglie wavelength for an electron with a kinetic energy of 1000 eV.
Ans: To calculate the de Broglie wavelength (Equation  4.5.1 ), the momentum of the particle must be established and requires knowledge of both the mass and velocity of the particle. The mass of an electron is  9.109383 × 10−28g  and the velocity is obtained from the given kinetic energy of 1000 eV:

De Broglie`s Postulate & Heisenberg Uncertainty Principle | Chemistry Optional Notes for UPSC
Solve for momentum

De Broglie`s Postulate & Heisenberg Uncertainty Principle | Chemistry Optional Notes for UPSC
convert to SI units

De Broglie`s Postulate & Heisenberg Uncertainty Principle | Chemistry Optional Notes for UPSC
expanding definition of joule into base SI units and cancel

De Broglie`s Postulate & Heisenberg Uncertainty Principle | Chemistry Optional Notes for UPSC

Now substitute the momentum into the equation for de Broglie's wavelength (Equation  4.5.1) with Planck's constant (h = 6.626069 × 10−34J⋅s ). After expanding units in Plank's constant

De Broglie`s Postulate & Heisenberg Uncertainty Principle | Chemistry Optional Notes for UPSC

Example 2:  Calculate the de Broglie wavelength for a fast ball thrown at 100 miles per hour and weighing 4 ounces. Comment on whether the wave properties of baseballs could be experimentally observed.
Ans: Following the unit conversions below, a 4 oz baseball has a mass of 0.11 kg. The velocity of a fast ball thrown at 100 miles per hour in m/s is 44.7 m/s.

De Broglie`s Postulate & Heisenberg Uncertainty Principle | Chemistry Optional Notes for UPSC
The de Broglie wavelength of this fast ball is:
De Broglie`s Postulate & Heisenberg Uncertainty Principle | Chemistry Optional Notes for UPSC

Example 3: If an electron and a proton have the same velocity, which would have the longer de Broglie wavelength?
(a) The electron
(b) The proton
(c) They would have the same wavelength
Ans:
Equation  4.5.1 shows that the de Broglie wavelength of a particle's matter wave is inversely proportional to its momentum (mass times velocity). Therefore the smaller mass particle will have a smaller momentum and longer wavelength. The electron is the lightest and will have the longest wavelength.

This was the prince's Ph.D. thesis, presented in 1924. His thesis advisor was somewhat taken aback, and was not sure if this was sound work. He asked de Broglie for an extra copy of the thesis, which he sent to Einstein. Einstein wrote shortly afterwards: "I believe it is a first feeble ray of light on this worst of our physics enigmas" and the prince got his Ph.D.

The Heisenberg Uncertainty Principle

  • In classical physics, studying the behavior of a physical system is often a simple task due to the fact that several physical qualities can be measured simultaneously. However, this possibility is absent in the quantum world. In 1927 the German physicist Werner Heisenberg described such limitations as the Heisenberg Uncertainty Principle, or simply the Uncertainty Principle, stating that it is not possible to measure both the momentum and position of a particle simultaneously.
  • The Heisenberg Uncertainty Principle is a fundamental theory in quantum mechanics that defines why a scientist cannot measure multiple quantum variables simultaneously. Until the dawn of quantum mechanics, it was held as a fact that all variables of an object could be known to exact precision simultaneously for a given moment. 
  • Newtonian physics placed no limits on how better procedures and techniques could reduce measurement uncertainty so that it was conceivable that with proper care and accuracy all information could be defined. Heisenberg made the bold proposition that there is a lower limit to this precision making our knowledge of a particle inherently uncertain.

Question for De Broglie's Postulate & Heisenberg Uncertainty Principle
Try yourself:
According to the de Broglie wavelength equation, what happens to the wavelength of a particle as its momentum increases?
View Solution

Probability

  • Matter and photons are waves, implying they are spread out over some distance. What is the position of a particle, such as an electron? Is it at the center of the wave? The answer lies in how you measure the position of an electron. Experiments show that you will find the electron at some definite location, unlike a wave. But if you set up exactly the same situation and measure it again, you will find the electron in a different location, often far outside any experimental uncertainty in your measurement. Repeated measurements will display a statistical distribution of locations that appears wavelike  (Figure 1.9.1 ).

De Broglie`s Postulate & Heisenberg Uncertainty Principle | Chemistry Optional Notes for UPSC

  • After de Broglie proposed the wave nature of matter, many physicists, including Schrödinger and Heisenberg, explored the consequences. The idea quickly emerged that, because of its wave character, a particle’s trajectory and destination cannot be precisely predicted for each particle individually. However, each particle goes to a definite place (Figure 1.9.1 ). After compiling enough data, you get a distribution related to the particle’s wavelength and diffraction pattern. There is a certain probability of finding the particle at a given location, and the overall pattern is called a probability distribution. Those who developed quantum mechanics devised equations that predicted the probability distribution in various circumstances.
  • It is somewhat disquieting to think that you cannot predict exactly where an individual particle will go, or even follow it to its destination. Let us explore what happens if we try to follow a particle. Consider the double-slit patterns obtained for electrons and photons in Figure 1.9.2 . The interferrence patterns build up statistically as individual particles fall on the detector. This can be observed for photons or electrons—for now, let us concentrate on electrons. You might imagine that the electrons are interfering with one another as any waves do. To test this, you can lower the intensity until there is never more than one electron between the slits and the screen. The same interference pattern builds up!
  • This implies that a particle’s probability distribution spans both slits, and the particles actually interfere with themselves. Does this also mean that the electron goes through both slits? An electron is a basic unit of matter that is not divisible. But it is a fair question, and so we should look to see if the electron traverses one slit or the other, or both. One possibility is to have coils around the slits that detect charges moving through them. What is observed is that an electron always goes through one slit or the other; it does not split to go through both.
  • But there is a catch. If you determine that the electron went through one of the slits, you no longer get a double slit pattern—instead, you get single slit interference. There is no escape by using another method of determining which slit the electron went through. Knowing the particle went through one slit forces a single-slit pattern. If you do not observe which slit the electron goes through, you obtain a double-slit pattern. How does knowing which slit the electron passed through change the pattern? The answer is fundamentally important—measurement affects the system being observed. 
  • Information can be lost, and in some cases it is impossible to measure two physical quantities simultaneously to exact precision. For example, you can measure the position of a moving electron by scattering light or other electrons from it. Those probes have momentum themselves, and by scattering from the electron, they change its momentum in a manner that loses information. There is a limit to absolute knowledge, even in principle.

Question for De Broglie's Postulate & Heisenberg Uncertainty Principle
Try yourself:
What is the behavior of the position of a particle, such as an electron, according to the wave nature of matter?
View Solution

Heisenberg’s Uncertainty Principle

It is mathematically possible to express the uncertainty that, Heisenberg concluded, always exists if one attempts to measure the momentum and position of particles. First, we must define the variable “x” as the position of the particle, and define “p” as the momentum of the particle. The momentum of a photon of light is known to simply be its frequency, expressed by the ratio  h/λ , where h represents Planck’s constant and λ  represents the wavelength of the photon. The position of a photon of light is simply its wavelength (λ). To represent finite change in quantities, the Greek uppercase letter delta, or Δ, is placed in front of the quantity. Therefore,
Δp = hλ (4.6.1)
Δx = λ (4.6.2)
By substituting  Δx  for  λ  into Equation  4.6.1, we derive
Δp = h/Δ x (4.6.3)
or,
ΔpΔx = h early form of the uncertainty principle (4.6.4)

A Common Trend in Quantum Systems
Equation  4.6.4  can be derived by assuming the particle of interest is behaving as a particle, and not as a wave. Simply let  Δp = mv , and  Δx = h/(mv) (from De Broglie’s expression for the wavelength of a particle). Substituting in  Δp  for  mv  in the second equation leads to Equation  4.6.4.
Equation  4.6.4 was further refined by Heisenberg and his colleague Niels Bohr, and was eventually rewritten as
De Broglie`s Postulate & Heisenberg Uncertainty Principle | Chemistry Optional Notes for UPSC(4.6.5)
with ℏ = h/2π = 1.0545718 × 10−34m2⋅kg/s
Equation 4.6.5 reveals that the more accurately a particle’s position is known (the smaller Δx is), the less accurately the momentum of the particle in the x direction (Δpx) is known. Mathematically, this occurs because the smaller Δx becomes, the larger Δpmust become in order to satisfy the inequality. However, the more accurately momentum is known the less accurately position is known (Figure 1.9.2 ).

De Broglie`s Postulate & Heisenberg Uncertainty Principle | Chemistry Optional Notes for UPSCFigure 1.9.2 : The animation shows the relevant spreads in the uncertainty for position and momentum of light/photons (light wave's corresponding photon particle). From the result of de Broglie, we know that for a particle with known momentum,  p  will have a precise value for its de Broglie wavelength can be determined (and hence a specific color of the light).

What is the Proper Definition of Uncertainty?

Equation  4.6.5 relates the uncertainty of momentum and position. An immediate questions that arise is if  Δx  represents the full range of possible x  values or if it is half (e.g.,  ⟨x⟩ ± Δx).  Δx  is the standard deviation and is a statistic measure of the spread of  x  values. The use of half the possible range is more accurate estimate of  Δx . As we will demonstrate later, once we construct a wavefunction to describe the system, then both  x  and  Δx  can be explicitly derived. However for now, Equation  4.6.5  will work.

  • For example: If a problem argues a particle is trapped in a box of length,  L , then the uncertainly of it position is  ±L/2 . So the value of  Δx  used in Equation  4.6.5  should be  L/2 , not  L .

Solved Examples

Example 1: An electron is confined to the size of a magnesium atom with a 150 pm radius. What is the minimum uncertainty in its velocity?
Ans: The uncertainty principle (Equation  4.6.5):
De Broglie`s Postulate & Heisenberg Uncertainty Principle | Chemistry Optional Notes for UPSC
can be written
De Broglie`s Postulate & Heisenberg Uncertainty Principle | Chemistry Optional Notes for UPSC
and substituting  Δp=mΔv  since the mass is not uncertain.
De Broglie`s Postulate & Heisenberg Uncertainty Principle | Chemistry Optional Notes for UPSC
the relevant parameters are

  • mass of electron  m=  me = 9.109383 × 10−31kg
  • uncertainty in position:  Δx = 150 × 10−12m

De Broglie`s Postulate & Heisenberg Uncertainty Principle | Chemistry Optional Notes for UPSC

Example 2: What is the maximum uncertainty of velocity the electron described in Example 1.9.1 ?
Ans: Infinity. There is no limit in the maximum uncertainty, just the minimum uncertainty.

Understanding the Uncertainty Principle through Wave Packets and the Slit Experiment

  • It is hard for most people to accept the uncertainty principle, because in classical physics the velocity and position of an object can be calculated with certainty and accuracy. However, in quantum mechanics, the wave-particle duality of electrons does not allow us to accurately calculate both the momentum and position because the wave is not in one exact location but is spread out over space. A "wave packet" can be used to demonstrate how either the momentum or position of a particle can be precisely calculated, but not both of them simultaneously. 
  • An accumulation of waves of varying wavelengths can be combined to create an average wavelength through an interference pattern: this average wavelength is called the "wave packet". The more waves that are combined in the "wave packet", the more precise the position of the particle becomes and the more uncertain the momentum becomes because more wavelengths of varying momenta are added. Conversely, if we want a more precise momentum, we would add less wavelengths to the "wave packet" and then the position would become more uncertain. Therefore, there is no way to find both the position and momentum of a particle simultaneously.
  • Several scientists have debated the Uncertainty Principle, including Einstein. Einstein created a slit experiment to try and disprove the Uncertainty Principle. He had light passing through a slit, which causes an uncertainty of momentum because the light behaves like a particle and a wave as it passes through the slit. Therefore, the momentum is unknown, but the initial position of the particle is known. Here is a video that demonstrates particles of light passing through a slit and as the slit becomes smaller, the final possible array of directions of the particles becomes wider. As the position of the particle becomes more precise when the slit is narrowed, the direction, or therefore the momentum, of the particle becomes less known as seen by a wider horizontal distribution of the light.

Solved Examples

Example 1: The speed of a 1.0 g projectile is known to within  10−6m/s
(a) Calculate the minimum uncertainty in its position.
(b) What is the maximum uncertainty of its position?

Ans: (a) From Equation  4.6.5 , the  Δpx = mΔvx with  m = 1.0g . Solving for  Δx to get

De Broglie`s Postulate & Heisenberg Uncertainty Principle | Chemistry Optional Notes for UPSC

This negligible for all intents and purpose as expected for any macroscopic object.
(b) Unlimited (or the size of the universe). The Heisenberg uncertainty principles does not quantify the maximum uncertainty.

Example 2: Estimate the minimum uncertainty in the speed of an electron confined to a hydrogen atom within a diameter of  1×10−10m.
Ans: We need to quantify the uncertainty of the electron in position. We can estimate that as  ± 5 × 10−10m . Hence, substituting the relavant numbers into Equation  4.6.5 and solving for  Δv we get
Δv = 1.15 × 106km/s
Notice that the uncertainty is significantly greater for the electron in a hydrogen atom than in the magnesium atom (Example 1.9.1 ) as expected since the magnesium atom is appreciably bigger.

Heisenberg’s Uncertainty Principle not only helped shape the new school of thought known today as quantum mechanics, but it also helped discredit older theories. Most importantly, the Heisenberg Uncertainty Principle made it obvious that there was a fundamental error in the Bohr model of the atom. Since the position and momentum of a particle cannot be known simultaneously, Bohr’s theory that the electron traveled in a circular path of a fixed radius orbiting the nucleus was obsolete. Furthermore, Heisenberg’s uncertainty principle, when combined with other revolutionary theories in quantum mechanics, helped shape wave mechanics and the current scientific understanding of the atom.

The document De Broglie's Postulate & Heisenberg Uncertainty Principle | Chemistry Optional Notes for UPSC is a part of the UPSC Course Chemistry Optional Notes for UPSC.
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FAQs on De Broglie's Postulate & Heisenberg Uncertainty Principle - Chemistry Optional Notes for UPSC

1. What is the de Broglie wavelength?
Ans. The de Broglie wavelength is a concept in quantum mechanics that relates the momentum of a particle to its wavelength. It is given by the equation λ = h/p, where λ is the de Broglie wavelength, h is the Planck's constant, and p is the momentum of the particle.
2. How is the de Broglie wavelength derived?
Ans. The de Broglie wavelength is derived from the wave-particle duality concept in quantum mechanics. It is based on Louis de Broglie's postulate that every particle has an associated wave. By applying the principles of wave-particle duality to the momentum of a particle, the de Broglie wavelength can be derived using the equation λ = h/p.
3. What is the Heisenberg Uncertainty Principle?
Ans. The Heisenberg Uncertainty Principle is a fundamental principle in quantum mechanics that states that there is a limit to the precision with which certain pairs of physical properties, such as position and momentum, can be simultaneously known. It implies that the more precisely one property is measured, the less precisely the other property can be known.
4. How does the Heisenberg Uncertainty Principle relate to probability?
Ans. The Heisenberg Uncertainty Principle is related to probability because it introduces the concept of intrinsic uncertainty into the measurement of physical properties. It states that the precise values of certain properties cannot be known simultaneously, and instead, only probabilities of obtaining certain values can be determined. This probabilistic nature of quantum mechanics is a fundamental aspect of the theory.
5. What is the proper definition of uncertainty?
Ans. The proper definition of uncertainty, in the context of the Heisenberg Uncertainty Principle, refers to the inherent limit in the precision of measuring certain pairs of physical properties. It acknowledges that there is a fundamental uncertainty in the values of these properties and that our knowledge is limited to probabilities rather than precise measurements. Uncertainty, in this sense, is not a lack of knowledge or precision, but rather a fundamental aspect of the quantum world.
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