Table of contents 
Calendar 
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A calendar is a system of organizing units of time for the purpose of reckoning time over extended periods. By convention, the day is the smallest calendrical unit of time; the measurement of fractions of a day is classified as timekeeping.
Step I: Find out the number of odd days between the given date and the date for which the day is to be found one.
Step II: From the given day count the odd days in the forward direction to arrive at the day on the given date.
Example 1: If 10th January 1992 was Saturday, what day of the week was on 6^{th} March 1993.
Solution: Calculate number of odd days between 10^{th} Jan 1992 and 6^{th} Mar 1993 Jan 10, 1992, is Saturday
So, from Jan 11 to Dec 31 of 1992 – days are 366 – 10 = 356 days
Jan 1993 = 31days
Feb 1993 = 28 days
6^{th} March 1993 = 6 days
Total days = 421
= 60 weeks + 1 day
So No. of odd days = 1
Let us count one day after Saturday. The required day will be Sunday.
Example 2: On April 4, 1988, it was Monday. What day of the week was on 5^{th} Nov. 1987.
Solutions: No. of days between 5^{th} Nov. 1987 to 4^{th} April 1988 6^{th} Nov 1987 to 30 Nov = 25 days
Dec 1987 = 31 days
Jan 1988 = 31 days
Feb 1988 = 29 days
March 1988 = 31 days
4^{th} April 1988 = 4 days
Total = 151 days
No. of odd days = 151 / 7 = 21 weeks – 4 days
So, since 5^{th} Nov. 1987 is prior to 4^{th} April 1988
We are to count 4 days backwards from Monday, the required day is Thursday.
Example 3: Find the day of the week on 26^{th} Jan. 1960.
Solution: No. of odd days upto 26^{th} Jan. 1960
= Odd days for 1600 years + odd days for 300 years + odd days for 59 years + odd days of 26 days of Jan 1960
= 0 + 1 + 59 + 14 + 5 = 79 days
= 79 / 7 = 11 weeks + 2 days = 2 odd days
The required day is Tuesday Zero odd day means Sunday. We are to consider one odd day as Monday 2 odd days as Tuesday and so on.
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