NEET > Chemistry Class 11 > Isothermal Expansion of Ideal Gas
Isothermal Expansion of Ideal Gas Video Lecture - Chemistry Class 11 - NEET
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FAQs on Isothermal Expansion of Ideal Gas Video Lecture - Chemistry Class 11 - NEET
| 1. What is an isothermal expansion of an ideal gas? |  |
Ans. An isothermal expansion of an ideal gas refers to a process in which the gas expands while maintaining a constant temperature. This means that the energy of the gas remains constant throughout the expansion, resulting in a decrease in pressure and an increase in volume.
| 2. How does an isothermal expansion of an ideal gas occur? | |
Ans. During an isothermal expansion, the gas is allowed to expand slowly in a controlled manner, while being in contact with a heat reservoir that maintains a constant temperature. As the gas expands, it does work on its surroundings, and the heat from the reservoir is continuously transferred to the gas to keep its temperature constant.
| 3. What is the significance of an isothermal expansion? | |
Ans. Isothermal expansions are significant because they allow us to study and understand the behavior of ideal gases under realistic conditions. By maintaining a constant temperature, isothermal expansions provide a controlled environment to observe the relationship between pressure, volume, and temperature, as described by the ideal gas law.
| 4. What is the ideal gas law, and how does it relate to isothermal expansion? | |
Ans. The ideal gas law states that the pressure, volume, and temperature of an ideal gas are related by the equation PV = nRT, where P is the pressure, V is the volume, n is the number of moles of gas, R is the gas constant, and T is the temperature. During an isothermal expansion, the ideal gas law remains valid, and the equation allows us to analyze the changes in pressure and volume of the gas.
| 5. What are some real-life applications of isothermal expansion? | |
Ans. Isothermal expansions have practical applications in various fields. For example, they are utilized in the design and operation of heat engines, such as steam engines and gas turbines. Isothermal expansions are also important in refrigeration and air conditioning systems, where gases undergo controlled expansions to cool down the surroundings. Additionally, isothermal processes are crucial in the liquefaction of gases, such as the production of liquid nitrogen or oxygen.
Text Transcript from Video
hello friends this video on
thermodynamics part 12 is brought to you
by exam viacom no more fear from exam
before watching the video please make
sure that you have watched part 1 to
part 11 again free expansion of gas in
vacuum
can you guess what will be the world
them in free expansion of gas in verbal
work done in free expansion of gas in
vacuum is 0 why because the external
pressure 0 see the formula we had was
work is equal to minus px Delta V for
non reversible so this guy is zero
pressure external is 0 because that is
called free expansion there is no
external pressure so there is no work
done during free expansion it is
reversible either as well on care this
is 0 subordinates for isothermal
expansion of ideal gas Delta U is 0 why
because see the U is function of T this
is something we have discuss earlier
also that Delta u change in internal
energy or isothermal expansion or
isothermal bosses 0 why because internal
energy is nothing but function of T this
formula we won't study we don't study
how it this derive but this is the
formula I got from Wikipedia it says
that internal energy the is CV in R T so
this is the only thing is variable as
T's it varies on T C if T is constant
Delta u will be 0 why because T is
constant right will be no change in
internal energy so please note the
change in internal energy for isothermal
process where temperature response it is
ze go correctly so what are you done
learnt along work done is equal to zero
for free expansion
please owner has one more wall down
there and change in the internal energy
is 0 for D is the deposit so if T is
constant if temperature is constant
internal energy change is 0 and if free
expansion work the original not talking
I'm not saying that the internal energy
change is zero work done is zero maybe
the heat which is the exchange and the
internal energy may change but the world
that will be zero for free expansion at
the internal energy will be change in V
zero for isothermal so look confusing
but this understand in fact put a do
different thing I have just edited it
together but there are do different
thing when I talk about work done that
will be zero for free expansion like you
call the peaks I talk about internal
energy change in isothermal process that
will be zero because internal energy is
a function of T if T is not changing
there is no change in so with Delta u
zero for isothermal process we have one
model additionally and see I told Dave
value is nothing but Q plus them if this
is zero for isothermal Q is equal to
minus seven
okay so you can be equal to minus T and
I told change internal energies do but
not the work that work may be there
I do not will be same on la gel formula
will be VF minus VI minus W so I am NOT
to punish it and for a reversible again
Q is equal to minus W for isothermal but
here the bottom will be 2.303 are NRT
log v fi here correct so the main thing
is for isothermal process change in
internal energy is zero but they've all
done can be there
right for three expansion of gas in
vacuum work done is zero but change in
internal energy can beat there let me
write once again here so I have
discussed to see I use it one is the
free expansion in vacuum and this is
isothermal and I talked about two thing
here Delta U and Delta the only W so in
free expansion Delta in isothermal Delta
U is zero but in free expansion Delta u
can have some values some one in free
expansion work the reserve right see in
free expansion work done in zero nicely
third one Delta u 0 but if you see in
free expansion work done can have some
value it can be positive or negative or
0 you don't know same thing in
isothermal case work done can be
positive negative or 0 correct so in
this case isothermal process evolved and
came out to be W came out to be minus
sorry P external VA minus VA when have
that and - 2.303 to NRT log of VM
and in this case three expansion Delta U
is equal to Q plus W right so this is 0
Delta U will become Q actually here
supply so whatever heat to supply that
will become change in term and this is a
lot of students get confused in
isothermal a narrative and the very
process should have been discusses well
again I should throw mclaws's
temperature in calm is kept constant
external heat may be required sometimes
example in this case is actually
expanding you next draw heat you need
extra heat for this and if this is
expanding people provide extra heat just
to maintain the temperature right so in
isothermal temperature is kept constant
the idea may take we have this adiabatic
walls there is no transfer of heat from
external world temperature may not be
constant because we have chemical
reaction going on here the chemical
reaction we agree the temperature
decreases based on there is exothermic
or endothermic reaction right so idea
maddening crosses there is no transfer
of heat from external world isothermal
process there may be transfer of heat
you don't know but the temperature has
to be kept so let's talk about energy
change for adiabatic and isochoric masks
see your adiabatic process I am saying
there is no transfer of heat from module
that is Q is equal to 0 it Q is equal to
0 if I have formula change in
intelligence or the what Q plus W this
is 0 then Delta U will be minus area
okay I know why this negative sign is
there is not required and ISO coding
process an ISO close and the volume is
constant right if volume is constant if
you know the work that we work P
external irritable and this is constant
the botnet is gone
zero if W is zero Delta U is what Q plus
them this is 0 Delta usually what you
that is my change internally so let's do
quick summary of all the different aging
process and the internal energy change
but isothermal process is the most
critical change in internal energy is
zero difficult to visualize if you don't
know the formula the the reason why we
call the you enter my energy was nothing
but CV NRT where it depends only on
temperature if temperature is changing
it depend on temperature earth is a
constant for a given system if the
temperature change is not there Delta
values will be 0 if Delta U is 0 I have
the formula Delta U is equal to plus
double this become 0 so QQ becomes minus
double right and W is minus of 2 is
nothing but P X syndrome into VF minus
VA it is minus W so this is my case for
isothermal but a free expansion of gas
in vacuum please note it is vacuum and
free expansion in that case the work
that was 0 why because of T external was
0 so work done is nothing but P external
and driving px is 0 so work then the
water is 0 my Delta U is nothing but Q
plus W and W is 0 Delta U comes out to
meet you for adiabatic process there is
no heat transfer so Q is 0 if Q is 0 my
Delta U will be W because Delta U is W
plus q q is 0 Delta u becomes term for
isochoric process
there is no change volume there is no
shilling pollen by volver is what P
Delta V this is 0 Delta V 0 so what the
resume evolved the resume did change
internally bv q + W this is 0 will
become human the last case remaining is
I think isobaric process for isobaric
process there is nothing special it will
be normal because the pressure is
constant Delta we can have some values
so volume will be there
pressure is constant I am NOT talking
about temperature or the heat transfer
you can have some value so my Delta U
will be normally Q plus W only agent
Fornell is nothing special in this case
for these case things where specials we
discuss but normally discuss isobaric
pressure where process is nothing
special
let's discuss that talks about this is
nothing special in that case is normal
form by using correct so this is the
internal energy change for various
scenarios for isothermal 0 internal
change for free expansion it is nothing
but the heat supplied for adiabatic
process it is the work done for
isochoric process it is nothing but the
heat supplied and for isobaric you have
to take both thing into factor the heat
supplied in the world thank you visit
exam viacom to watch free education
videos try free on my debts get the best
quality study materials study from the
best tutors and mentors and much more
thanks and screen
thermodynamics part 12 is brought to you
by exam viacom no more fear from exam
before watching the video please make
sure that you have watched part 1 to
part 11 again free expansion of gas in
vacuum
can you guess what will be the world
them in free expansion of gas in verbal
work done in free expansion of gas in
vacuum is 0 why because the external
pressure 0 see the formula we had was
work is equal to minus px Delta V for
non reversible so this guy is zero
pressure external is 0 because that is
called free expansion there is no
external pressure so there is no work
done during free expansion it is
reversible either as well on care this
is 0 subordinates for isothermal
expansion of ideal gas Delta U is 0 why
because see the U is function of T this
is something we have discuss earlier
also that Delta u change in internal
energy or isothermal expansion or
isothermal bosses 0 why because internal
energy is nothing but function of T this
formula we won't study we don't study
how it this derive but this is the
formula I got from Wikipedia it says
that internal energy the is CV in R T so
this is the only thing is variable as
T's it varies on T C if T is constant
Delta u will be 0 why because T is
constant right will be no change in
internal energy so please note the
change in internal energy for isothermal
process where temperature response it is
ze go correctly so what are you done
learnt along work done is equal to zero
for free expansion
please owner has one more wall down
there and change in the internal energy
is 0 for D is the deposit so if T is
constant if temperature is constant
internal energy change is 0 and if free
expansion work the original not talking
I'm not saying that the internal energy
change is zero work done is zero maybe
the heat which is the exchange and the
internal energy may change but the world
that will be zero for free expansion at
the internal energy will be change in V
zero for isothermal so look confusing
but this understand in fact put a do
different thing I have just edited it
together but there are do different
thing when I talk about work done that
will be zero for free expansion like you
call the peaks I talk about internal
energy change in isothermal process that
will be zero because internal energy is
a function of T if T is not changing
there is no change in so with Delta u
zero for isothermal process we have one
model additionally and see I told Dave
value is nothing but Q plus them if this
is zero for isothermal Q is equal to
minus seven
okay so you can be equal to minus T and
I told change internal energies do but
not the work that work may be there
I do not will be same on la gel formula
will be VF minus VI minus W so I am NOT
to punish it and for a reversible again
Q is equal to minus W for isothermal but
here the bottom will be 2.303 are NRT
log v fi here correct so the main thing
is for isothermal process change in
internal energy is zero but they've all
done can be there
right for three expansion of gas in
vacuum work done is zero but change in
internal energy can beat there let me
write once again here so I have
discussed to see I use it one is the
free expansion in vacuum and this is
isothermal and I talked about two thing
here Delta U and Delta the only W so in
free expansion Delta in isothermal Delta
U is zero but in free expansion Delta u
can have some values some one in free
expansion work the reserve right see in
free expansion work done in zero nicely
third one Delta u 0 but if you see in
free expansion work done can have some
value it can be positive or negative or
0 you don't know same thing in
isothermal case work done can be
positive negative or 0 correct so in
this case isothermal process evolved and
came out to be W came out to be minus
sorry P external VA minus VA when have
that and - 2.303 to NRT log of VM
and in this case three expansion Delta U
is equal to Q plus W right so this is 0
Delta U will become Q actually here
supply so whatever heat to supply that
will become change in term and this is a
lot of students get confused in
isothermal a narrative and the very
process should have been discusses well
again I should throw mclaws's
temperature in calm is kept constant
external heat may be required sometimes
example in this case is actually
expanding you next draw heat you need
extra heat for this and if this is
expanding people provide extra heat just
to maintain the temperature right so in
isothermal temperature is kept constant
the idea may take we have this adiabatic
walls there is no transfer of heat from
external world temperature may not be
constant because we have chemical
reaction going on here the chemical
reaction we agree the temperature
decreases based on there is exothermic
or endothermic reaction right so idea
maddening crosses there is no transfer
of heat from external world isothermal
process there may be transfer of heat
you don't know but the temperature has
to be kept so let's talk about energy
change for adiabatic and isochoric masks
see your adiabatic process I am saying
there is no transfer of heat from module
that is Q is equal to 0 it Q is equal to
0 if I have formula change in
intelligence or the what Q plus W this
is 0 then Delta U will be minus area
okay I know why this negative sign is
there is not required and ISO coding
process an ISO close and the volume is
constant right if volume is constant if
you know the work that we work P
external irritable and this is constant
the botnet is gone
zero if W is zero Delta U is what Q plus
them this is 0 Delta usually what you
that is my change internally so let's do
quick summary of all the different aging
process and the internal energy change
but isothermal process is the most
critical change in internal energy is
zero difficult to visualize if you don't
know the formula the the reason why we
call the you enter my energy was nothing
but CV NRT where it depends only on
temperature if temperature is changing
it depend on temperature earth is a
constant for a given system if the
temperature change is not there Delta
values will be 0 if Delta U is 0 I have
the formula Delta U is equal to plus
double this become 0 so QQ becomes minus
double right and W is minus of 2 is
nothing but P X syndrome into VF minus
VA it is minus W so this is my case for
isothermal but a free expansion of gas
in vacuum please note it is vacuum and
free expansion in that case the work
that was 0 why because of T external was
0 so work done is nothing but P external
and driving px is 0 so work then the
water is 0 my Delta U is nothing but Q
plus W and W is 0 Delta U comes out to
meet you for adiabatic process there is
no heat transfer so Q is 0 if Q is 0 my
Delta U will be W because Delta U is W
plus q q is 0 Delta u becomes term for
isochoric process
there is no change volume there is no
shilling pollen by volver is what P
Delta V this is 0 Delta V 0 so what the
resume evolved the resume did change
internally bv q + W this is 0 will
become human the last case remaining is
I think isobaric process for isobaric
process there is nothing special it will
be normal because the pressure is
constant Delta we can have some values
so volume will be there
pressure is constant I am NOT talking
about temperature or the heat transfer
you can have some value so my Delta U
will be normally Q plus W only agent
Fornell is nothing special in this case
for these case things where specials we
discuss but normally discuss isobaric
pressure where process is nothing
special
let's discuss that talks about this is
nothing special in that case is normal
form by using correct so this is the
internal energy change for various
scenarios for isothermal 0 internal
change for free expansion it is nothing
but the heat supplied for adiabatic
process it is the work done for
isochoric process it is nothing but the
heat supplied and for isobaric you have
to take both thing into factor the heat
supplied in the world thank you visit
exam viacom to watch free education
videos try free on my debts get the best
quality study materials study from the
best tutors and mentors and much more
thanks and screen
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Mohit Rajpoot |
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