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NEET Previous Year Questions (2016-2024): Biomolecules | Biology Class 11 PDF Download

2024

Q1: Lecithin, a small molecular weight organic compound found in living tissues, is an example of:     (NEET 2024)
(a) Amino acids
(b) Phospholipids
(c) Glycerides
(d) Carbohydrates
Ans:
(b)
The correct answer is option (2).
Some lipids have phosphorous and a phosphorylated organic compound in them. These are phospholipids. They are found in cell membrane. Lecithin is one example.
Option (3) is incorrect as glycerides are another group of lipids in which both glycerol and fatty acids are present.
Option (1) and (2) are incorrect as amino acids and carbohydrates are separate groups of biomolecules.

Q2: The cofactor of the enzyme carboxypeptidase is:      (NEET 2024)
(a) Zinc
(b) Niacin
(c) Flavin
(d) Haem
Ans:
(a)
The enzyme carboxypeptidase is well-known for its utilization of a zinc ion as a cofactor in its catalytic mechanism. The zinc ion plays a crucial role in the hydrolysis of peptide bonds, the reaction facilitated by carboxypeptidase. The presence of zinc allows for proper stabilization of water molecules which are necessary in the catalysis, making the hydrolysis of the peptide bond effective. This zinc dependency categorizes carboxypeptidase as a metalloenzyme.
Therefore, the correct answer is: Option A: Zinc
Other options mentioned, such as Niacin, Flavin, and Haem, serve as cofactors for different enzymes. For example, Niacin is involved in the formation of NAD+ (Nicotinamide adenine dinucleotide) which acts as an electron carrier in many enzymatic reactions. Flavins (like FMN and FAD) are involved in a myriad of oxidation-reduction (redox) reactions. Haem, found in hemoglobin and cytochromes, also plays crucial roles primarily in electron transfer processes and oxygen transport. These are not associated with the functioning of carboxypeptidase, which specifically requires zinc for its enzymatic activity.

Q3: Match List I with List II      (NEET 2024)
NEET Previous Year Questions (2016-2024): Biomolecules | Biology Class 11Choose the correct answer from the options given below.
(a) A-IV, B-I, C-II, D-III
(b) A-I, B-II, C-III, D-IV
(c) A-II, B-III, C-IV, D-I
(d) A-III, B-IV, C-I, D-II
Ans: 
(a)
To solve this matching question, we need to correctly identify what each item in List I represents and match it with its corresponding description in List II:

  • GLUT-4 is a glucose transporter protein that allows glucose to be absorbed into cells when insulin is present. Hence, it should be matched with "Enables glucose transport into cells."
  • Insulin is a hormone produced by the pancreas that helps regulate blood glucose levels by facilitating the uptake of glucose into tissues. It should be matched with "Hormone."
  • Trypsin is an enzyme that aids in the digestion of proteins in the digestive system. It should be matched with "Enzyme."
  • Collagen is a primary structural protein that forms connective tissues throughout the body, including the extracellular matrix. It should be matched with "Intercellular ground substance."

Here's how we match each term with the correct description from List II:

A-IV, B-I, C-II, D-III

This corresponds to:

  • A (GLUT-4) - IV (Enables glucose transport into cells)
  • B (Insulin) - I (Hormone)
  • C (Trypsin) - II (Enzyme)
  • D (Collagen) - III (Intercellular ground substance)

Therefore, the answer is Option A

Q4: Match List I with List II:      (NEET 2024)
NEET Previous Year Questions (2016-2024): Biomolecules | Biology Class 11Choose the correct answer from the options given below :
(a) A-IV, B-II, C-III, D-I
(b) A-III, B-II, C-I, D-IV
(c) A-II, B-IV, C-I, D-III
(d) A-IV, B-I, C-III, D-II
Ans: 
(c)
The task here is to correctly match the enzymes listed in List I with their corresponding type of bond they hydrolyze or act on, as listed in List II. To do this, we need to understand the function of each enzyme:

  • Lipase: This enzyme catalyzes the breakup of fats (lipids), primarily working on the ester bonds in triglycerides. Thus, Lipase corresponds to Ester bond (II).
  • Nuclease: Nucleases are enzymes that cleave the phosphodiester bonds within the nucleic acids, DNA and RNA. Therefore, Nuclease corresponds to Phosphodiester bond (IV).
  • Protease: These enzymes hydrolyze proteins by breaking peptide bonds between amino acids. Thus, Protease matches with Peptide bond (I).
  • Amylase: Amylase acts on starches, breaking down the glycosidic bonds in carbohydrate molecules to produce simple sugars. Hence, Amylase corresponds to Glycosidic bond (III).

Matching these to the given options:

  • A - Lipase corresponds to Ester bond (II).
  • B - Nuclease corresponds to Phosphodiester bond (IV).
  • C - Protease corresponds to Peptide bond (I).
  • D - Amylase corresponds to Glycosidic bond (III).

This matches with Option C, hence the correct response is: Option C

Q5: Regarding catalytic cycle of an enzyme action, select the correct sequential steps :     (NEET 2024)
A. Substrate enzyme complex formation.
B. Free enzyme ready to bind with another substrate.
C. Release of products.
D. Chemical bonds of the substrate broken.
E. Substrate binding to active site.
Choose the correct answer from the options given below :
(a) E, A, D, C, B
(b) A, E, B, D, C
(c) B, A, C, D, E
(d) E, D, C, B, A
Ans: 
(a)
The correct order of the steps in the catalytic cycle of enzyme action involves the following key events:

  1. Substrate binding to the active site: Before any reaction can take place, the substrate must bind to the enzyme's active site. This is where the substrate is correctly positioned for the reaction.
  2. Formation of the substrate-enzyme complex: Once the substrate binds to the active site, a substrate-enzyme complex is formed. This complex stabilizes the transition state of the reaction and lowers the activation energy required for the reaction.
  3. Chemical bonds of the substrate broken : Within the substrate-enzyme complex, the specific chemical reaction occurs, leading to the breaking of bonds within the substrate. This step often involves changes to the chemical structure of the substrate, turning it into the product(s) of the reaction.
  4. Release of products: After the reaction occurs, the product(s) of the reaction are released from the enzyme, leaving the enzyme unchanged.
  5. Free enzyme ready to bind with another substrate: Once the product is released, the enzyme is free again to bind with another substrate, repeating the cycle.

Given the correct sequence and your provided options, the correct answer is: Option A
This sequence correctly describes the steps involved in the catalytic cycle of enzyme action, from substrate binding to the release of products and the readiness of the enzyme to start a new cycle.

Q6: Inhibition of Succinic dehydrogenase enzyme by malonate is a classical example of:     (NEET 2024)
(a) Cofactor inhibition
(b) Feedback inhibition
(c) Competitive inhibition
(d) Enzyme activation
Ans:
(c)
Sol:  The inhibition of the enzyme succinic dehydrogenase by malonate is a classic example of competitive inhibition. To understand why this is the case, let's explore the mechanism and dynamics of this specific type of inhibition in the context of the given enzyme and inhibitor.
Competitive Inhibition: This type of enzyme inhibition occurs when an inhibitor compound resembles the substrate's structure and competes with the substrate for binding to the active site of the enzyme. If the inhibitor binds to the active site, it prevents the substrate from binding, temporarily blocking the enzyme’s activity. Importantly, competitive inhibition can typically be overcome by increasing the concentration of the substrate, as this can displace the inhibitor from the active site.
Succinic Dehydrogenase and Malonate: Succinic dehydrogenase is an enzyme that plays a critical role in the citric acid cycle, an essential metabolic pathway for energy production. It catalyzes the oxidation of succinate into fumarate. The structure of malonate is closely similar to that of succinate, the natural substrate of succinic dehydrogenase. Because of its structural similarity, malonate competes with succinate for the active site on succinic dehydrogenase. When malonate binds to the active site, it effectively inhibits the enzyme from catalyzing the reaction to convert succinate into fumarate.
Conclusion: Considering these points, Option C, Competitive inhibition, is correct for describing the inhibition of succinic dehydrogenase by malonate, as it directly competes with the substrate for the active site of the enzyme.
Other options such as cofactor inhibition, feedback inhibition, and enzyme activation do not accurately describe the situation with malonate and succinic dehydrogenase. Cofactor inhibition involves inhibition by substances that affect the enzyme's cofactors, feedback inhibition generally pertains to the regulation of biochemical pathways by their product, and enzyme activation is a process that increases the enzyme's activity, none of which apply in this context.

2023

Q1: Cellulose does not form blue colour with Iodine because      (NEET 2023)
(a) It is a disaccharide
(b) It is a helical molecule
(c) It does not contain complex helices and hence cannot hold iodine molecules
(d) It breaks down when iodine reacts with it

Ans: (c)

NEET Previous Year Questions (2016-2024): Biomolecules | Biology Class 11

Option (c) is the correct answer because cellulose does not contain complex helices and hence cannot hold iodine molecules. Option (a), (b) and (d) are not correct 


Q2: Given below are two statements:     (NEET 2023)
Statement I: A protein is imagined as a line, the left end represented by first amino acid (C-terminal) and the right end represented by last amino acid (N-terminal).
Statement II: Adult human haemoglobin, consists of 4 subunits (two subunits of α type and two subunits of β type.)
In the light of the above statements, choose the correct answer from the options given below:
(a) Both Statement I and Statement II are false.
(b) Statement I is true but Statement II is false.
(c) Statement I is false but Statement II is true.
(d) Both Statement I and Statement II are true.
Ans:
(c)

Statement I is false - A protein is not imagined as a line with the N-terminal (amino terminus) on the left end and the C-terminal (carboxyl terminus) on the right end. In reality, the N-terminal is on the left side, and the C-terminal is on the right side when representing the amino acid sequence of a protein.

Statement II is true -  Adult human hemoglobin consists of 4 subunits: two subunits of α-type and two subunits of β-type. These subunits come together to form a complex protein structure responsible for carrying oxygen in the blood.

The correct option is (C): Statement I is false but Statement II is true

Q3: Given below are two statements:      (NEET 2023)
Statement I: low temperature preserves the enzyme in a temporarily inactive state whereas high temperature destroys enzymatic activity because proteins are denatured by heat.
Statement II: when the inhibitor closely resembles the substrate in its molecular structure and inhibits the activity of enzyme, it is known as competitive inhibitor.
(a) Both Statement I and Statement II are true.
(b) Both Statement I and Statement II are false.
(c) Statement I is true but Statement II is false.
(d) Statement I is false but Statement II is true.

Ans: (a)

  • Statement I is true - Low temperatures can slow down enzymatic reactions by placing the enzyme in an inactive state, and high temperatures can denature proteins, including enzymes, which can lead to a loss of enzymatic activity.
  • Statement II is also true - A competitive inhibitor is a molecule that closely resembles the substrate of an enzyme and competes for the active site, thus reducing the enzyme's activity. This type of inhibition is called competitive inhibition.

So, the correct answer is : Option A : Both Statement I and Statement II are true.

2022

Q1: When a carrier protein facilitates the movement of two molecules across the membrane in same direction, it is called
(a) Symport
(b) Uniport
(c) Transport
(d) Antiport   (NEET 2022 Phase 2)
Ans: 
(a)

  • A symport is the transport of two types of molecules across the membrane in same direction.
  • Antiport is the transport of two different molecules in opposite directions.
  • Uniport is transport of a molecule across the membrane independent of other molecule.


Q2: Match List-I with List-II

NEET Previous Year Questions (2016-2024): Biomolecules | Biology Class 11

Choose the correct answer from the options given below
(a) (a) - (i), (b) - (iv), (c) - (iii), (d) - (ii)
(b) (a) - (iv), (b) - (i), (c) - (ii), (d) - (iii)
(c) (a) - (iv), (b) - (iii), (c) - (ii), (d) - (i)
(d) (a) - (iii), (b) - (i), (c) - (iv), (d) - (ii)   (NEET 2022 Phase 2)
Ans:
(b)
Option (b) is the correct answer as adenine is a purine, anthocyanin is a pigment, chitin is a polysaccharide and codeine is an alkaloid.

Q3: Primary proteins are also called as polypeptides because :
(a) They can assume many conformations
(b) They are linear chains
(c) They are polymers of peptide monomers
(d) Successive amino acids are joined by peptide bonds   (NEET 2022 Phase 2)
Ans: 
(d)

  • Option (4) is the correct answer because primary proteins are heteropolymers containing strings of amino acids linked by peptide bonds.
  • Option (1) and (2) are incorrect as primary proteins are called polypeptides due to the presence of many monomers linked via peptide bonds, not due to the presence of many conformations.
  • Option (3) is incorrect because proteins are polymers of amino acid monomers.


Q4: Which of the following pair represents free living nitrogen fixing aerobic bacteria?
(a) Pseudomonas and Thiobacillus
(b) Rhizobium and Frankia
(c) Azotobacter and Beijernickia
(d) Anabaena and Rhodospirillum   (NEET 2022 Phase 2)
Ans:
(c)

  • The free living nitrogen fixing aerobic microbes are Azotobacter and Beijernickia
  • Rhizobium and Frankia are symbiotic nitrogen fixers.
  • Rhodospirillum is anaerobic nitrogen fixer.
  • Pseudomonas and Thiobacillus are denitrifying bacteria.


Q5: Choose the incorrect enzymatic rection:
(a) NEET Previous Year Questions (2016-2024): Biomolecules | Biology Class 11
(b) NEET Previous Year Questions (2016-2024): Biomolecules | Biology Class 11
(c) NEET Previous Year Questions (2016-2024): Biomolecules | Biology Class 11
(d) NEET Previous Year Questions (2016-2024): Biomolecules | Biology Class 11   (NEET 2022 Phase 2)
Ans: 
(b)
Option (b) is the correct answer because maltose is a disaccharide which on hydrolysis gives two molecules of glucose.
NEET Previous Year Questions (2016-2024): Biomolecules | Biology Class 11
Options (a), (c) and (d) represent correct enzymatic reactions so they are not the answer. 


Q6: If DNA contained sulfur instead of phosphorus and proteins contained phosphorus instead of sulfur, what would have been the outcome of Hershey and Chase experiment?
(a) Radioactive phosphorus in bacterial cells
(b) No radioactive sulfur in bacterial cells
(c) Both radioactive sulfur and phosphorus in bacterial cells
(d) Radioactive sulfur in bacterial cells   (NEET 2022 Phase 2)
Ans: 
(d)
In Hershey-chase experiment when radioactive sulphur was in protein capsule and radioactive phosphorus was in DNA then, no sulphur radioactivity detected in the cells as protein coat remains outside the bacterial cell after infection
In the given question, sulphur is shown in the DNA and phosphorus in the protein coat. Hence radioactive sulphur will be seen in bacterial cells.

Q7: Given below are two statements:
Statement I : Amino acids have a property of ionizable nature of NH2 and COOH groups, hence have different structures at different pH. 
Statement-II : Amino acids can exist as Zwitterionic form at acidic and basic pH.
In the light of the above statements, choose the most appropriate answer from the options given below:
(a) Statement I is incorrect but Statement II is correct
(b) Both Statement I and Statement II are correct
(c) Both Statement I and Statement II are incorrect
(d) Statement I is correct but Statement II is incorrect   (NEET 2022 Phase 2)
Ans:
(d)
Option (d) is the correct answer as statement I is correct but statement II is incorrect
A particular property of amino acids is the ionizable nature of −NH2 and −COOH groups. Hence, in solutions of different pH, the structure of amino acid changes. Amino acid exists as a dipolar ion called a zwitterion at a particular pH called isoelectric point.


Q8: In the enzyme which catalyses the breakdown of:    (NEET 2022 Phase 2)
H2O2 → H2O + O2 
the prosthetic group is :
(a) Niacin
(b Nicotinamide adenine dinucleotide
(c) Haem
(d) Zinc
Ans:
(c)

  • Option (c) is the correct answer because peroxidase is the enzyme that catalyzes the breakdown of hydrogen peroxide to water and oxygen; haem is the prosthetic group of this enzyme.
  • Option (a) and (b) are incorrect because co-enzyme nicotinamide adenine dinucleotide (NAD) and NADP contain the vitamin niacin.
  • Option (d) is incorrect because zinc is a co-factor for the proteolytic enzyme carboxypeptidase.

Q9: Read the following statements on lipids and find out correct set of statements:     (NEET 2022 Phase 1)
(A) Lecithin found in the plasma membrane is a glycolipid
(B) Saturated fatty acids possess one or more c = c bonds
(C) Gingely oil has lower melting point, hence remains as oil in winter
(D) Lipids are generally insoluble in water but soluble in some organic solvents
(E) When fatty acid is esterified with gIycerol, monoglycerides are formed
Choose the correct answer from the options given below:
(a) (A), (D) and (E) only
(b) (A), (B) and (D) only
(c) (C), (D) and (E) only
(d) (A), (B) and (C) only
Ans: 
(c)

  • Option (c) is the correct answer because statements (c), (d) and (e) correct as oils have lower melting point and hence remain oil in winters. Lipids are generally insoluble in water but soluble in some organic solvents.
  • Option (a), (b) and (d) are incorrect because statements (a) and (b) are incorrect. Lecithin is a type of phospholipid found in plasma membrane. Saturated fatty acids are without double bond.


Q10:  A dehydration reaction links two glucose molecules to produce maltose. If the formula for glucose is C6H12O6 then what is the formula for maltose?      (NEET 2022 Phase 1)
(a)C12H24O12
(b)C12H22O11
(c)C12H24O11
(d)C12H20O10
Ans: 
(b)
Option (b) is correct because maltose is a disaccharide formed by dehydration process i.e., synthesis by elimination of one water molecule to form a glycosidic bond in between two glucose molecules. So, its molecular formula is

NEET Previous Year Questions (2016-2024): Biomolecules | Biology Class 11


Q11: Match List-I with List-II       (NEET 2022 Phase 1)
NEET Previous Year Questions (2016-2024): Biomolecules | Biology Class 11
Choose the correct answer from the options given below:
(A) (a) - (iv), (b) - (ii), (c) - (i), (d) - (iii)
(B) (a) - (ii), (b) - (iv), (c) - (iii), (ii) - (i)
(C) (a) - (iv), (b) - (iii), (c) - (i), (d) - (ii)
(D) (a) - (iii), (b) - (ii), (c) - (iv), (d) - (i)
Ans: 
(c)
Option (d) is the correct answer as glycogen is a polysaccharide and is a storage product in animals.

  • Globulins form antibodies which are also known as immunoglobulins.
  • Steroids form hormones like testosterone.
  • Thrombin is a biocatalyst which converts soluble fibrinogen to insoluble fibrin.

2021

Q1: Which of the following are not secondary metabolites in plants? (NEET 2021)
(a) Vinblastin, curcumin
(b) Rubber, gums
(c) Morphine, codeine
(d) Amino acids, glucose
Ans:
(d)

  • Amino acids and glucose are included under the category of primary metabolites as they have identifiable functions and play known roles in normal physiological processes.
  • Rubber, gums, morphine, codeine, vinblastin and curcumin are included under the category of secondary metabolites as their role or functions in host organisms is not known yet. However, many of them are useful to human welfare.


Q2: Match List -I with List - II.        (NEET 2021)
NEET Previous Year Questions (2016-2024): Biomolecules | Biology Class 11
Choose the correct answer from the options given below.

     (a)  (b)  (c) (d)
(a) (ii)  (i)  (iv) (iii)
(b) (iv) (iii) (i)  (ii)
(c) (iv) (i)  (ii)  (iii)
(d) (i) (iv) (iii)  (ii)
Ans: (c)

  • In a polypeptide or a protein, amino acids are linked by a peptide bond which is formed when the carboxyl (−COOH) group of one amino acid reacts with amino (−NH2) group of the next amino acid with the elimination of a water moiety.
  • Unsaturated fatty acids are with one or more C = C double bonds.
  • In nucleic acids, a phosphate moiety links the 3'-carbon of one sugar of one nucleotide to the 5'-carbon of the sugar of the succeeding nucleotide. The bond between the phosphate and hydroxyl group is an ester bond. As there is one such ester bond on either side, it is called phosphodiester bond.
  • In a polysaccharide, the individual monosaccharides are linked by a glycosidic bond.

Q3: Following are the statements with reference to 'lipids'.  (NEET 2021)
(a) Lipids having only single bonds are called unsaturated fatty acids.
(b) Lecithin is a phospholipid.
(c) Trihydroxy propane is glycerol.
(d) Palmitic acid has 20 carbon atoms including carboxyl carbon.
(e) Arachidonic acid has 16 carbon atoms.
Choose the correct answer from the options given below.
(a) (b) and (c) only
(b) (b) and (e) only
(c) (a) and (b) only
(d) (c) and (d) only
Ans: (a)

  • The correct option is (a) because lipids having only single bonds are called saturated fatty acids and lipids having one or more C = C double bonds are called unsaturated fatty acids. 
  • Palmitic acid has 16 carbon atoms including carboxyl carbon. 
  • Arachidonic acid has 20 carbon atoms including the carboxyl carbon. 
  • Lecithin is a phospholipid found in cell membrane. 
  • Glycerol has 3 carbons, each bearing a hydroxyl ( − OH) group.

2020

Q1: Identify the substances having glycosidic bond and peptide bond, respectively in their structure.     (NEET 2020)
(a) Cellulose, lecithin
(b) Inulin, Insulin
(c) Chitin, cholesterol
(d) Glycerol, trypsin
Ans: (b)
Inulin is a mixture of linear fructose polymers with different chain length and a glucose molecule at each C2 end. Adjacent fructose units are linked through glycosidic bond. The inulin that is used for medicine is most commonly obtained by soaking chicory roots in hot water. 
Insulin is a protein composed of 51 amino acids and acts as a hormone which is secreted by beta-cells of pancreas. Adjacent amino acids are attached through peptide bond.

Q2: Which one of the following is the most abundant protein in the animals?     (NEET 2020)
(a) Lectin
(b) Insulin
(c) Haemoglobin
(d) Collagen
Ans: 
(d)
Collagen is the most abundant protein in animal world. Collagen is the major insoluble fibrous protein found in the extracellular matrix and in connective tissue. RuBisCO is the most abundant protein in the whole of the Biosphere.


Q3: Identify the basic amino acid from the following     (NEET 2020)
(a) Lysine
(b) Valine
(c) Tyrosine
(d) Glutamic acid
 
Ans: (a)
Glutamic Acid - is an acidic amino acid.
Lysine - is a basic amino acid.
Valine - is an aliphatic amino acid.
Tyrosine - is an aromatic amino acid.


Q4: Identify the wrong statement with reference to the gene ‘I’ that controls ABO blood groups.    (NEET 2020)
(a) Allele ‘i’ does not produce any sugar.
(b) The gene (I) has three alleles.
(c) When IA and IB are present together, they express same type of sugar.
(d) A person will have only two of the three alleles.
Ans: 
(c)
When IA and IB are present together, they express same type of sugar is wrong statement with reference to the gene ‘I’ that controls ABO blood group because IA and IB are completely dominant over IO , but when IA and IB are present together, they both express their own types of sugar and thus behaving as codominant alleles. 


Q5: Match the following:     (NEET 2020)

NEET Previous Year Questions (2016-2024): Biomolecules | Biology Class 11

Choose the correct option from the following
(a) (A)  (ii), (B)  (iii), (C)  (i), (D)  (iv) 
(b) (A)  (iii), (B)  (i), (C)  (iv), (D)  (ii)
(c) (A)  (ii), (B)  (iv), (C)  (iii), (D)  (i)  
(d) (A)  (iii), (B)  (iv), (C)  (i), (D)  (ii) 
Ans: 
(c)
Malonate is the competitive inhibitor of catalytic activity of succinic dehydrogenase, Collagen is proteinaceous in nature and possesses peptide bonds, Chitin is a homopolymer present in the cell wall of fungi and exoskeleton of arthropods, Abrin and Ricin are toxins, secondary metabolites.

2019

Q1: Concanavalin A is    (NEET 2019)
(a) A pigment
(b) An alkaloid
(c) An essential oil
(d) A lectin
Ans: 
(d)
Concanavalin A is an example of lection.

Q2:  Consider the following statements.
(A) Coenzyme or metal ion that is tightly bound to enzyme protein is called prosthetic group.
(B) A complete catalytic active enzyme with its bound prosthetic group is called apoenzyme.
Select the correct option.    (NEET 2019)
(a) (A) is false but (B) is true.
(b) Both (A) and (B) are true.
(c) (A) is true but (B) is false.
(d) Both (A) and (B) are false.
Ans: 
(d)
Coenzyme or metal ion that is tightly bound to enzyme protein is called prosthetic group while a complete catalytic active enzyme with its bound prosthetic group is called holoenzyme.

2018

Q1: The two functional groups characteristic of sugars are    (NEET 2018)
(a) Hydroxyl and methyl
(b) Carbonyl and methyl
(c) Carbonyl and phosphate
(d) Carbonyl and hydroxyl
Ans:
(d)
Sugar is a carbohydrate. These are polyhydroxy aldehyde, ketone or their derivatives, which means they have carbonyl and hydroxyl groups in its structure.

2017

Q1: Which of the following statements is correct with reference to enzymes?    (NEET 2017)
(a) Holoenzyme = Apoenzyme + Coenzyme
(b) Coenzyme - Apoenzyme + Holoenzyme
(c) Holoenzyme = Coenzyme + Co-factor
(d) Apoenzyme = Holoenzyme + Coenzyme
Ans: 
(a)
Holoenzyme is the complete conjugate enzyme consisting of an apoenzyme and a cofactor. Cofactor may be organic or inorganic in nature. Organic cofactors are of two types-coenzyme and prosthetic group.

Q2: Which of the following are not polymeric?    (NEET 2017)
(a) Proteins
(b) Polysaccharides
(c) Lipids
(d) Nucleic acids
Ans:
(c)
– Nucleic acids are polymers of nucleotides
– Proteins are polymers of amino acids
– Polysaccharides are polymers of monosaccharides
– Lipids are the tri-esters of fatty acids with glycerol. 

2016

Q1: A non-proteinaceous enzyme is    (NEET 2016 Phase 2)
(a) Lysozyme
(b) Ribozyme
(c) Ligase
(d) Deoxyribonuclease
Ans: 
(b)
A ribozyme is a ribonucleic acid (RNA) enzyme that catalyses a chemical reaction in a similar way to that of a protein enzyme. These are found in ribosomes and are also called catalytic RNAs.

Q2: Which of the following is the least likely to be involved in stabilising the three-dimensional folding of most proteins?
(a) Hydrogen bonds
(b) Electrostatic interaction
(c) Hydrophobic interaction
(d) Ester bonds   (NEET 2016 Phase 2)
Ans:
(d)
Tertiary structure or three dimensional structure of protein is stabilised by several types of bonds-hydrogen bonds, ionic bonds, van der Waal's interactions, covalent bonds and hydrophobic bonds.

Q3: Which of the following describes the given graph correctly?   (NEET 2016 Phase 2)
NEET Previous Year Questions (2016-2024): Biomolecules | Biology Class 11
(a) Endothermic reaction with energy A in presence of enzyme and B in absence of enzyme.
(b) Exothermic reaction with energy A in presence of enzyme and B in absence of enzyme.
(c) Endothermic reaction with energy A in absence of enzyme and B in presence of enzyme.
(d) Exothermic reaction with energy A in absence of enzyme and B in presence of enzyme.

Ans: (b)
The graph shows the activation energies of catalyzed and uncatalyzed reations. A transition state is observed when the reactants are at the crest of the hump. At this state, they are ready to be converted to products. If the products are at a lower level than the reactants, the reaction is exothermic.

Q4: A typical fat molecule is made up of   (NEET 2016 Phase 1)
(a) One glycerol and one fatty acid molecule
(b) Three glycerol and three fatty acid molecules
(c) Three glycerol molecules and one fatty acid molecule
(d) One glycerol and three fatty acid molecules.
Ans:
(d)
Neutral or true fats are triglycerides which are formed by esterification of three molecules of fatty acids with one molecule of trihydric alcohol, glycerol (glycerine or trihydroxy propane).

Q5: Which one of the following statements is wrong?   (NEET 2016 Phase 1)
(a) Uracil is a pyrimidine.
(b) Glycine is a sulphur containing amino acid.
(c) Sucrose is a disaccharide.
(d) Cellulose is a polysaccharide.
Ans:
(b)
Glycine (abbreviated as Gly or G) is the smallest of the 20 amino acids commonly found in proteins, and indeed is the smallest possible (having a hydrogen substituent as its side-chain). The formula is NH2CH2COOH. Its codons are GGU, GGC, GGA, GGG of the genetic code. 

The document NEET Previous Year Questions (2016-2024): Biomolecules | Biology Class 11 is a part of the NEET Course Biology Class 11.
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FAQs on NEET Previous Year Questions (2016-2024): Biomolecules - Biology Class 11

1. What are the four major classes of biomolecules?
Ans. The four major classes of biomolecules are carbohydrates, lipids, proteins, and nucleic acids. These biomolecules are essential for various biological processes in living organisms.
2. What is the primary function of carbohydrates in living organisms?
Ans. Carbohydrates serve as the primary source of energy for living organisms. They are also involved in cell structure, cell recognition, and cell signaling processes.
3. How are lipids different from other biomolecules?
Ans. Lipids are hydrophobic molecules that are insoluble in water, unlike carbohydrates, proteins, and nucleic acids. They serve as energy storage molecules and are important components of cell membranes.
4. What is the role of proteins in living organisms?
Ans. Proteins have diverse functions in living organisms, serving as enzymes, structural components, hormones, antibodies, and transport molecules. They are essential for the growth, repair, and regulation of cells and tissues.
5. How do nucleic acids contribute to genetic information in cells?
Ans. Nucleic acids, specifically DNA and RNA, store and transmit genetic information in cells. DNA carries the genetic instructions for the development, functioning, growth, and reproduction of organisms, while RNA is involved in protein synthesis and gene expression.
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