Passage Based Questions: Quantitative Aptitude - 12 | Passage Based Questions for CLAT Preparation PDF Download

Number of students who passed half-yearly exams in the school = (Number of students passed in half-yearly but failed in annual exams) + (Number of students passed in both exams)
= (6 + 17 + 9 + 15) + (64 + 55 + 46 + 76)
= 288.
Also, Number of students who passed annual exams in the school
= (Number of students failed in half-yearly but passed in annual exams) + (Number of students passed in both exams)
= (14 + 12 + 8 + 13) + (64 + 55 + 46 + 76)
= 288.
Since, the number of students passed in half-yearly = the number of students passed in annual exams. Therefore, it can be inferred that both the examinations had almost the same difficulty level.
Thus Statements (a), (b) and (d) are false and Statement (c) is true.

Pass percentages in at least one of the two examinations for different sections are:

Clearly, the pass percentage is maximum for Section D.

Total number of failures in half-yearly exams in a section = [(Number of students failed in both exams) + (Number of students failed in half-yearly but passed in Annual exams)] in that section
∴ Failure rate in half-yearly exams in Section A

Similarly, failure rate in half-yearly exams in:

Clearly, the failure rate is minimum for Section D.

Since the classification of the students on the basis of their results and sections form independent groups, so the total number of students in the class:
= (28 + 23 + 17 + 27 + 14 + 12 + 8 + 13 + 6 + 17 + 9 + 15 + 64 + 55 + 46 + 76)
= 430.

Total number of students passed in annual exams in a section = [ (No. of students failed in half-yearly but passed in annual exams) + (No. of students passed in both exams)] in that section
∴ Success rate in annual exams in Section A

Similarly, success rate in annual exams in:

Clearly, the success rate in annual examination is maximum for Section A.