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**Q****.1. A hollow metal sphere of radius R is uniformly charged. The electric field due to the sphere at a distance r from the centre. (2019)A: Increases as r increases for both r < R and r > RB: Zero as r increases for r < R, decreases as r increases for r > RC: Zero as r increases for r < R, increases as r increases for r > RD: **

Answer:

(i) For r < R (inside)

By Gauss law,

⇒ E

(ii) For r > R (outside)

A: Zero

B:

C:

D:

Answer:

Electric field due to line charge (1)

Electric field due to line charge (2)

**Q.3. Two point charges A and B, having charges +Q and –Q respectively, are placed at certain distance apart and force acting between them is F. If 25% charge of A is transferred to B, then force between the charges becomes : (2019)A: FB: 9F/16C: 16F/9D: 4F/3Answer:** B

If 25% of charge of A transferred to B then**Q.4. An electron falls from rest through a vertical distance h in a uniform and vertically upward directed electric field E. The direction of electrical field is now reversed, keeping its magnitude the same. A proton is allowed to fall from rest in through the same vertical distance h. The time fall of the electron, in comparison to the time fall of the proton is :- (2018)A: smallerB: 5 times greaterC: 10 times greaterD: equalAnswer: **A

**Q.5. A toy car with charge q moves on a frictionless horizontal plane surface under the influence of a uniform electric fieldDue to the forceits velocity increases from 0 to 6 m/s in one second duration. At that instant the direction of the field is reversed. The car continues to move for two more seconds under the influence of this field. The average velocity and the average speed of the toy car between 0 to 3 seconds are respectively :- (2018)A: 2 m/s, 4 m/sB: 1 m/s, 3 m/sC: 1 m/s, 3.5 m/sD: 1.5 m/s, 3 m/sAnswer: **B

0 < t < 1s : velocity increases from 0 to 6 m/s

1 < t < 2s : velocity decreases from 6 to 0 m/s

but car continues to move forward

2 < t < 3s : since field strength is same ⇒ same acceleration

∴ car's velocity increases

from 0 to –6 m/s

B: v ∝ x

C: v ∝ x

D: v ∝ x

Answer:

**Q.7. ****A square loop ABCD carrying a current i, is placed near and coplanar with a long straight conductor XY carrying a current I, the net force on the loop will be :**

A:

B:

C:

D: **Answer: **B** Solution:**

A:

B:

C:

D:

Answer:

Solution:

**Q.9. ****A wire carrying current I has the shape as shown in the adjoining figure. Linear parts of the wire are very long and parallel to X -axis while semicircular portion of radius R is lying in a Y-Z plane. The magnetic field at point O is. (2015)A:**

C:

D:

Answer:

Solution:

A:

B:

C: zero

D:

Answer: A

**Q.11. ****Following figures show the arrangement of bar magnets in different configurations. Each magnet has magnetic dipole momentWhich configuration has highest net magnetic dipole moment? (2014)****A:**

B:

C:

D:

**Answer: **C

Solution:

Net magnetic moment will be maximum if cos θ is maximum.

cos θ will be maximum when θ will be minimum. So, at θ = 30º m

The direction of magnetic moment is from S to N

Net magnetic moment will be maximum if cos θ is maximum.

cos θ will be maximum when θ will be minimum. So, at θ = 30º m

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