NEET  >  Previous Year Questions (2014-22): Physical World, Units & Measurement

# Previous Year Questions (2014-22): Physical World, Units & Measurement - Notes | Study Physics Class 11 - NEET

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Q.1. The dimensions [MLT–2A–2 ] belong to the              [2022]
(1) Self-inductance
(2) Magnetic permeability
(3) Electric permittivity
(4) Magnetic flux

The dimensional formula of magnetic permeability is [MLT–2A–2 ]

Q.2. The area of a rectangular field (in m2 ) of length 55.3 m and breadth 25 m after rounding off the value for correct significant digits is                           [2022]
(1) 1382

(2) 1382.5
(3) 14 * 10
(4) 138 * 10
1
Area = Length × Breadth

= 55.3 × 25 m2
= 1382.5 m2
= 14 × 102 m2
(Rounding off of two significant figures)

Q.3. Match List-I with List-II

Choose the correct answer from the options given below                 [2022]
(1) (a) - (ii), (b) - (iv), (c) - (i), (d) - (iii)

(2) (a) - (ii), (b) - (iv), (c) - (iii), (d) - (i)

(3) (a) - (iv), (b) - (ii), (c) - (i), (d) - (iii)

(4) (a) - (ii), (b) - (i), (c) - (iv), (d) - (iii)

Q.4. Plane angle and solid angle have
(1) Dimensions but no units
(2) No units and no dimensions
(3) Both units and dimensions
(4) Units but no dimensions                                 [2022]

Q.5. A Screw Guage gives the following readings when used to measure the diameter of a wire.
Main scale reading = 0.0 mm
Circular scale reading = 52 divisions
Given that: 1 mm on the main scale corresponds to 100 divisions of the circular scale.
The diameter of the wire from the above data is:
[2021]
A: 0.026 cm
B: 0.005 cm
C: 0.52 cm
D: 0.052 cm
Ans:
D
Solution: Diameter of wire,

Q.6. If force [F], acceleration [A] and time [T] are chosen as the fundamental physical quantities. Find the dimensions of energy.    [2021]
A: [F][A][T-1]
B: [F][A-1][T]
C: [F][A][T]
D: [F][A][T2]
Ans:
D
Solution:

Q.7. If E and G respectively denote energy and gravitational constant, then E/G has the dimensions of :    [2021]
A: [M] [L0] [T0]
B: [M2] [L–2] [T–1]
C: [M2] [L–1] [T0]
D: [M] [L–1] [T–1]
Ans:
C
Solution:

E = energy = [ML2T–2]
G = Gravitational constant = [M–1L3T–2]
So,
E/G = [E]/[G]
= ML2T–2/M–1L3T–2
= [M2L-1T0]

Q.8. Taking into account of the significant figures, what is the value of 9.99 m-0.0099 m?    [2020]
A: 9.980 m
B: 9.9 m
C: 9.9801 m
D: 9.98 m

Ans: D

As per rule
least no. of place in decimal portion of any number 9.98

Q.9. In an experiment, the percentage of error occurred in the measurement of physical quantities A, B, C and D are 1%, 2%, 3% and 4% respectively. Then the maximum percentage of error in the measurement X, where  will be     [2019]
A:
B: 16 %
C: -10 %
D: 10 %
Ans:
B
Given

= 2% + 1%+ 1%+ 12%= 16%

Q.10. A student measured the diameter of a small steel ball using a screw gauge of least count 0.001 cm. The main scale reading is 5 mm and zero of circular scale division coincides with 25 divisions above the reference level. If screw gauge has a zero error of – 0.004 cm, the correct diameter of the ball is :-    [2018]
A: 0.521 cm
B: 0.525 cm
C: 0.053 cm
D: 0.529 cm

Ans: D
Solution:
Reading of screw gauge
= MSR + VSR × LC + zero error
= 0.5 cm + 25 × 0.001 cm + 0.004 cm
= 0.529 cm

Q.11. A physical quantity of the dimensions of length that can be formed out of  is velocity of light, G is universal constant of gravitation and e is charge] :-    [2017]

A:
B:
C:
D:
Ans: D
Solution:

Q.12. If energy (E), velocity (V) and time (T) are chosen as the fundamental quantities, the dimensional formula of surface tension will be:    [2015]
A: [E-2 V-1 T-3]
B: [E V-2 T-1]
C: [E V-1 T-2]
D: [E V-2 T-2]
Ans:
D
Solution:

Q.13. If force (F), velocity (V) and time(T) are taken as fundamental units, then the dimensions of mass are:    [2014]
A: [F V−1 T−1]
B: [F V−1 T]
C: [F V T−1]
D: [F V T−2]
Ans:
B
Solution:

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