Question 2 - Principles of Inheritance and Evolution Video Lecture - NEET

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question of entry using a balance where
what about the distribution of
phenotypic features in the first P and
generation after a cross between a
homozygous opinion and a heterozygous
male for a single locus so here it says
that if we have to cross a homozygous
female let us suppose that is denoted by
a P and the heterozygous male is denoted
by a capital T small a so we have to do
a cross between these two so graphically
is one a and small is wanting so what
are the possible gametes that will be
produced capitalize on a and in this is
it will be small a small n so these are
the possible gametes here right now once
we know the Gammons how do we prepare a
punnett square we put the gamete on the
topmost row and on the leftmost column
so let us put the gavin's here so to
suppose these are the Gammage which have
been placed on the topmost row and the
leftmost column now let us try to find
out the combinations so these are the
various combinations possible so from
this we can try to find out the
phenotypic and genotypic ratio so
basically this table will give you the
f1 generation so looking at this table
what do you see what would be the
phenotypic ratio so if you talk about
the phenotypic ratio this this will have
the same few more times right so the
phenotypic ratio is going to be 1 is to
1 they have the same phenotype similarly
these two have same to your life if you
talk about the genotypic ratio what is
going to be the genotypic ratio so the
ratio between a a and a tail so that is
also going to be y means 2 months and
this is the phenotypic ratio and the
genotypic ratio is going to be the same
for the f1 generation question number 4
when a cross is made between 12 lunch
with
the new seeds heterozygous and torn down
with green seed that is tall there's
heterozygous but being is all things
what proportions of phenotype in the
offspring could we expect it will be
gone and green door friendly so let us
try to perform this cross so in this
case we have amethyst this one in
capital X 1 Y this is crossed with this
is crossed with capital T small T for my
small bike first we have to find out the
oil possible gametes so all possible
damage here will be capital T capital y
capital T small why spoil the capital
variance wanting to online it was B
unless and until it is mentioned in the
question that the genes are linked we do
not consider any linkage revelation that
they will catch on independently so here
also we will try to find out all in them
expecting the capital T small when able
to do small values for T smaller my and
snorting smaller okay so these are the
possible gametes in this case so now
once you have all the gamut so basically
if you see here is just repetition of
the same gang so you see there think we
need types of gametes that I will reduce
family we come to life
and small to small by so let us write
down the gathers on the top first row
and on the left post forums let us
suppose we write these 4 gametes of the
top mutual
so this is how you write is for hammocks
and we like these two gametes of the
leftmost column now please 11 to do not
write unnecessarily then the beach
accounts but anyways that is one good
anything okay everybody stay cannot get
in the same so this is and this is
another so this is the punnett square
okay so let us try to make the
combinations so this will be capital T
capital my spawn times for like this
would be capital T is 4 by 4 T like this
will be small T's 14,000 by
right and this one this one this one
right like this one in here it will be T
capital by capital T small like this
will be capital T's or like a little too
small like this with a capital T smaller
is walking out to my and this is T V Y T
so these are the various combinations
that we get now we have to find out how
many of them what proportion of them
will be tall and leave now here you can
see so tall is denoted by capital T then
and yellow is denoted by capital X
capital key they don't strong and
capital y denotes yellow and these are
the dominant traits okay so if we want
something will be tall so it should have
capital T so and if we want me to be
green so green is the recessive trait so
you should have two small ones
what being tall it has to have at least
one capital T and for being green it
should have two small bites so how many
will satisfy the criteria
so again if you see this one has one
capital T but it has one capital by also
so this will not satisfy the criteria if
you look at this one this has one
capital T and this has two small Y so
this this particular criteria it will
look like this this doesn't fit will be
the granular because you move that will
be taking in a capital T here but you do
not have to small right but here you
have one capital T from small like so
this also fits into the criteria here or
here you do not have one like here again
you have one capital T and from small Y
so this is 3 out of 4 and green is 3 out
of 8 right 2 3 out of 8 are going movie
so 3 8 I am going to beat 1 and V so the
next question asks dwarf friendly so in
order to be brought the cash to me there
has been two small key together and
hoping it has to be one by together so
how many do you have where we
SWAT teams and use for online just one
so this is the only one reading and
responding sentence one bite
so basically just one out of eight so
this is the one-eighth of the proportion
would be water and green and 3/8 of the
proportion would be tall and green
so this is how we actually find out that
how the objects will be like all the
vertical across question number five two
heterozygous parents are crossed if the
two loci are eight what would be the
distribution of phenotypic features in
f1 generation for a dying hybrid cross
so now you have the concept of linkage
because the question specifically sees
that they are linked so now two
heterozygous parents are cross so this
is how a heterozygous parent will look
like because we are considering and I
migrated across so two trails need to be
considered so the to treat sorry Emily
okay so when these heterozygous parents
are crossed so first of all we have to
find out all possible gametes now since
it is say that a and B are linked
together so a and B we get inherited
together therefore one aims for me being
present on the whole of those rows of
maybe also get inherited together
so therefore the possible gametes are
capital baby and spawn maybe similarly
here in this case also the possible
damage will be capital e b and small
gaming so what are the possible
combinations that are possible with this
so these are the possible combinations
with this so what can we form capital B
capital A B or you can form capital e
small evening or you can have capital e
if you small Navy or that's for ladies
for name so if you do not their
phenotypes so all these three have the
parental phenotypes so they have the
padding the phenotype right because we
wrote I body is capital a is dominant
over small in civility capital B is
dominant over small B so in this case
also a mean we will express they are
also a legal expense of these we
the panic and fear events whereas if you
talk about this one
and this is all exactly how the patterns
to play right so even the little
patterns also they the dominant ones are
getting expressed but if you look at
this one this is the only one we're
going to the recessive traits are
getting expressed so what you see
since the look things they are linked
but it is not mentioned that they are
completely because I have they been
completely linked in that is you have
received all the offspring as parental
phenotypes and most of them are parental
phenotypes but some of them have belief
formulations so you can observe Fury
populations however you see mostly
parental phenotypes so mostly parental
phenotypes so the ratio is around 3 is
to 1 so parental phenotypes to
recombinants ratio as k is to one
question of the snakes a child has led
to oh if the father has led to a and
mother it learn to be what about the
genotypes of the balance and the
possible genotypes of other offsprings
now in the question it says that the
father has black truth a now what are
the way is possible zero times if the
phenotype has to be blood with a the
fatherland's genotype can be iaia or the
father's genotype can also be IP act
because ie is dominant over right so in
that case also with the blood route will
be a so these are the two possibilities
for fire selector so if you consider the
mother's blood look weather is like this
B so what are the various possibilities
for mother's bedroom
mothers learning can be
maybe or it can be ibi so these are the
two possibilities again for the mother
now it has been given that the child has
blood group O so if the child has plenty
o that means the genotype of the child
has to be high so now if the genotype of
the child it has to be I I in that case
it is very obvious that the parents have
to be heterozygous only then this I will
come into picture right because if the
parents are homozygous so there is no
small line anywhere so how will this iid
form
so therefore the parents have to be
heterozygous so let us look at this an
atom and move the parents I heterozygous
so in that case the cross will be like
this
ie I cross I be I all right so what all
this can contribute I a on I this can
contribute I a or I so now this can
combine with this this can also combine
with this this can combine methods or
this can combine with this so the
various possible options would be I a IV
or I a i or i bi or I I so there is a
possibility there is 25% chance that
these are the possibility of the blood
group of the offspring so there is 25%
chance that the offspring can be of
blood route oh there is a very fine
person possibility that the blood route
can be P there is a 25-person
possibility that the Brotherhood can be
a and there is a 25-person possibility
that the blood fruit can be able so I I
would mean blood route oh I be I believe
that will be I I will rule like you in
and I a I be would mean let cook able
right
so from this to answer this question
says genotype of the parents so the
genotype of the patterns will be I a I
and I and these are the genotypes of the
parents and what are the possible
genotypes of other options so these are
the possible genotypes for the other
four strings now if you want for your
own our understanding if you want you
can
cross between these homozygous patterns
and then you will be able to see that in
that case none of those things will have
blood group oh thank you please visit
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