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Introduction

  • One of the major reasons for studying chemical kinetics is to use measurements of the macroscopic properties of a system, such as the rate of change in the concentration of reactants or products with time, to discover the sequence of events that occur at the molecular level during a reaction. This molecular description is the mechanism of the reaction; it describes how individual atoms, ions, or molecules interact to form particular products. The stepwise changes are collectively called the reaction mechanism.
    In an internal combustion engine, for example, isooctane reacts with oxygen to give carbon dioxide and water:
    Reaction Mechanisms | Chemistry Optional Notes for UPSC
  • For this reaction to occur in a single step, 25 dioxygen molecules and 2 isooctane molecules would have to collide simultaneously and be converted to 34 molecules of product, which is very unlikely. It is more likely that a complex series of reactions takes place in a stepwise fashion. Each individual reaction, which is called an elementary reaction, involves one, two, or (rarely) three atoms, molecules, or ions. The overall sequence of elementary reactions is the mechanism of the reaction. The sum of the individual steps, or elementary reactions, in the mechanism must give the balanced chemical equation for the overall reaction. 

The overall sequence of elementary reactions is the mechanism of the reaction.

Molecularity and the Rate-Determining Step

  • To demonstrate how the analysis of elementary reactions helps us determine the overall reaction mechanism, we will examine the much simpler reaction of carbon monoxide with nitrogen dioxide.
    Reaction Mechanisms | Chemistry Optional Notes for UPSC
  • From the balanced chemical equation, one might expect the reaction to occur via a collision of one molecule of NO2 with a molecule of CO that results in the transfer of an oxygen atom from nitrogen to carbon. The experimentally determined rate law for the reaction, however, is as follows:
    Reaction Mechanisms | Chemistry Optional Notes for UPSC
  • The fact that the reaction is second order in  [NO2] and independent of  [CO] tells us that it does not occur by the simple collision model outlined previously. If it did, its predicted rate law would be
    Reaction Mechanisms | Chemistry Optional Notes for UPSC
  • The following two-step mechanism is consistent with the rate law if step 1 is much slower than step 2:
    Reaction Mechanisms | Chemistry Optional Notes for UPSC
  • According to this mechanism, the overall reaction occurs in two steps, or elementary reactions. Summing steps 1 and 2 and canceling on both sides of the equation gives the overall balanced chemical equation for the reaction. The NO3 molecule is an intermediate in the reaction, a species that does not appear in the balanced chemical equation for the overall reaction. It is formed as a product of the first step but is consumed in the second step.

The sum of the elementary reactions in a reaction mechanism must give the overall balanced chemical equation of the reaction.

Question for Reaction Mechanisms
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What is the purpose of studying chemical kinetics?
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Using Molecularity to Describe a Rate Law

  • The molecularity of an elementary reaction is the number of molecules that collide during that step in the mechanism. If there is only a single reactant molecule in an elementary reaction, that step is designated as unimolecular; if there are two reactant molecules, it is bimolecular; and if there are three reactant molecules (a relatively rare situation), it is termolecular. Elementary reactions that involve the simultaneous collision of more than three molecules are highly improbable and have never been observed experimentally. (To understand why, try to make three or more marbles or pool balls collide with one another simultaneously!)
    Reaction Mechanisms | Chemistry Optional Notes for UPSCFigure  14.6.1: The Basis for Writing Rate Laws of Elementary Reactions. This diagram illustrates how the number of possible collisions per unit time between two reactant species, A and B, depends on the number of A and B particles present. The number of collisions between A and B particles increases as the product of the number of particles, not as the sum. This is why the rate law for an elementary reaction depends on the product of the concentrations of the species that collide in that step.
  • Writing the rate law for an elementary reaction is straightforward because we know how many molecules must collide simultaneously for the elementary reaction to occur; hence the order of the elementary reaction is the same as its molecularity (Table  14.6.1 ). In contrast, the rate law for the reaction cannot be determined from the balanced chemical equation for the overall reaction. The general rate law for a unimolecular elementary reaction (A → products) is
    rate = k[A].
  • For bimolecular reactions, the reaction rate depends on the number of collisions per unit time, which is proportional to the product of the concentrations of the reactants, as shown in Figure  14.6.1 . For a bimolecular elementary reaction of the form A + B → products, the general rate law is
    rate = k[A][B].
    Table  14.6.1: Common Types of Elementary Reactions and Their Rate Laws
    Reaction Mechanisms | Chemistry Optional Notes for UPSC

For elementary reactions, the order of the elementary reaction is the same as its molecularity. In contrast, the rate law cannot be determined from the balanced chemical equation for the overall reaction (unless it is a single step mechanism and is therefore also an elementary step).

Question for Reaction Mechanisms
Try yourself:
What is the rate-determining step in a reaction mechanism?
View Solution
 

Identifying the Rate-Determining Step

  • Note the important difference between writing rate laws for elementary reactions and the balanced chemical equation of the overall reaction. Because the balanced chemical equation does not necessarily reveal the individual elementary reactions by which the reaction occurs, we cannot obtain the rate law for a reaction from the overall balanced chemical equation alone. In fact, it is the rate law for the slowest overall reaction, which is the same as the rate law for the slowest step in the reaction mechanism, the rate-determining step, that must give the experimentally determined rate law for the overall reaction.
  • This statement is true if one step is substantially slower than all the others, typically by a factor of 10 or more. If two or more slow steps have comparable rates, the experimentally determined rate laws can become complex. Our discussion is limited to reactions in which one step can be identified as being substantially slower than any other. The reason for this is that any process that occurs through a sequence of steps can take place no faster than the slowest step in the sequence. 
  • In an automotive assembly line, for example, a component cannot be used faster than it is produced. Similarly, blood pressure is regulated by the flow of blood through the smallest passages, the capillaries. Because movement through capillaries constitutes the rate-determining step in blood flow, blood pressure can be regulated by medications that cause the capillaries to contract or dilate. A chemical reaction that occurs via a series of elementary reactions can take place no faster than the slowest step in the series of reactions.
    Reaction Mechanisms | Chemistry Optional Notes for UPSCRate-determining step. The phenomenon of a rate-determining step can be compared to a succession of funnels. The smallest-diameter funnel controls the rate at which the bottle is filled, whether it is the first or the last in the series. Pouring liquid into the first funnel faster than it can drain through the smallest results in an overflow.
    Look at the rate laws for each elementary reaction in our example as well as for the overall reaction.
    rate laws for each elementary reaction in our example as well as for the overall reaction.
    Reaction Mechanisms | Chemistry Optional Notes for UPSC
  • The experimentally determined rate law for the reaction of  NO2 with  CO is the same as the predicted rate law for step 1. This tells us that the first elementary reaction is the rate-determining step, so k for the overall reaction must equal  k1. That is, NO3 is formed slowly in step 1, but once it is formed, it reacts very rapidly with CO in step 2. 
  • Sometimes chemists are able to propose two or more mechanisms that are consistent with the available data. If a proposed mechanism predicts the wrong experimental rate law, however, the mechanism must be incorrect.

Solved Examples

Example 1: A Reaction with an Intermediate

In an alternative mechanism for the reaction of  NO2 with  CO with  N2O4 appearing as an intermediate.
alternative mechanism for the reaction of  NO2 with  CO with  N2O4 appearing as an intermediate.
Reaction Mechanisms | Chemistry Optional Notes for UPSCWrite the rate law for each elementary reaction. Is this mechanism consistent with the experimentally determined rate law (rate = k[NO2]2)?
Ans: Given: 
elementary reactions
Asked for: rate law for each elementary reaction and overall rate law
Strategy: A. Determine the rate law for each elementary reaction in the reaction.
B. Determine which rate law corresponds to the experimentally determined rate law for the reaction. This rate law is the one for the rate-determining step.
Solution: A. The rate law for step 1 is rate = k1[NO2]2; for step 2, it is rate = k2[N2O4][CO].
B. If step 1 is slow (and therefore the rate-determining step), then the overall rate law for the reaction will be the same: rate = k1[NO2]2. This is the same as the experimentally determined rate law. Hence this mechanism, with N2O4 as an intermediate, and the one described previously, with NO3 as an intermediate, are kinetically indistinguishable. In this case, further experiments are needed to distinguish between them. For example, the researcher could try to detect the proposed intermediates, NOand N2O4, directly.

Example 2: Nitrogen Oxide Reacting with Molecular Hydrogen

Assume the reaction between  NO and  Hoccurs via a three-step process:
the reaction between  NO and  H2 occurs via a three-step process
Reaction Mechanisms | Chemistry Optional Notes for UPSCWrite the rate law for each elementary reaction, write the balanced chemical equation for the overall reaction, and identify the rate-determining step. Is the rate law for the rate-determining step consistent with the experimentally derived rate law for the overall reaction:
Reaction Mechanisms | Chemistry Optional Notes for UPSC
Ans:
Reaction Mechanisms | Chemistry Optional Notes for UPSC
The overall reaction is then
Reaction Mechanisms | Chemistry Optional Notes for UPSC

  • Rate Determining Step: #2 
  • Yes, because the rate of formation of  [N2O2] = k1[NO]2. Substituting  k1[NO]for  [N2O2] in the rate law for step 2 gives the experimentally derived rate law for the overall chemical reaction, where  k = k1k2.

Summary

  • A balanced chemical reaction does not necessarily reveal either the individual elementary reactions by which a reaction occurs or its rate law. A reaction mechanism is the microscopic path by which reactants are transformed into products. Each step is an elementary reaction. 
  • Species that are formed in one step and consumed in another are intermediates. Each elementary reaction can be described in terms of its molecularity, the number of molecules that collide in that step. The slowest step in a reaction mechanism is the rate-determining step.
The document Reaction Mechanisms | Chemistry Optional Notes for UPSC is a part of the UPSC Course Chemistry Optional Notes for UPSC.
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FAQs on Reaction Mechanisms - Chemistry Optional Notes for UPSC

1. What is molecularity and how does it relate to the rate-determining step?
Ans. Molecularity refers to the number of molecules or particles involved in a particular step of a chemical reaction. In the context of reaction kinetics, molecularity is used to describe the rate of a reaction. The rate-determining step is the slowest step in a reaction mechanism and it determines the overall rate of the reaction. The molecularity of the rate-determining step corresponds to the rate law of the overall reaction.
2. How is molecularity used to describe a rate law?
Ans. Molecularity is used to determine the order of a reaction and write its rate law. The rate law expresses the relationship between the rate of a reaction and the concentrations of the reactants. The molecularity of the rate-determining step is equal to the sum of the exponents in the rate law equation for that reaction. For example, if the rate-determining step involves the collision of two reactant molecules, the rate law would be second order with respect to each of those reactants.
3. How can we identify the rate-determining step in a reaction mechanism?
Ans. The rate-determining step in a reaction mechanism can be identified by examining the individual steps and their respective rate constants. The rate-determining step is typically the slowest step in the mechanism, meaning it has the highest activation energy and the lowest rate constant. It is important to note that the overall rate of the reaction is determined by the slowest step.
4. Can you provide an example of how molecularity and the rate-determining step are related?
Ans. Let's consider the reaction A + B -> C, which occurs through the following mechanism: 1. A + B -> D (fast) 2. D + B -> C (slow) In this mechanism, the second step is the rate-determining step because it is slower than the first step. The molecularity of the rate-determining step is second order with respect to D and first order with respect to B. Therefore, the rate law for the overall reaction would be rate = k[D][B].
5. How can understanding reaction mechanisms and molecularity help in solving problems related to reaction rates?
Ans. Understanding reaction mechanisms and molecularity is crucial in solving problems related to reaction rates. By knowing the rate-determining step and the molecularity of that step, one can determine the rate law for the overall reaction. This allows for the prediction of how changes in reactant concentrations or temperature will affect the reaction rate. Additionally, understanding reaction mechanisms can provide insights into the efficiency of catalysts and help in designing more effective chemical reactions.
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