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Reductive Elimination

Reductive elimination is the microscopic reverse of oxidative addition. It is literally oxidative addition run in reverse. Chemically, reductive elimination and oxidative addition share the same reaction coordinate. The only difference between their reaction coordinate diagrams relates to what we call “reactants” and “products.” Thus, their mechanisms depend on one another, and trends in the speed and extent of oxidative additions correspond to opposite trends in reductive eliminations. In this section, we’ll address reductive elimination in a general sense, as we did for oxidative addition.
Reductive Elimination | Chemistry Optional Notes for UPSCFigure  11.4.1: A general reductive elimination scheme. The oxidation state of the metal decreases by two units, and open coordination sites become available.

During reductive elimination, the electrons in the M–X bond head toward ligand Y, and the electrons in M–Y head to the metal. The eliminating ligands are always anionic. On the whole, the oxidation state of the metal decreases by two units, two new open coordination sites become available, and an X–Y bond forms. What does the change in oxidation state suggest about changes in electron density at the metal? As suggested by the name “reductive,” the metal gains electrons. The ligands lose electrons as the new X–Y bond cannot possibly be polarized to both X and Y, as the original M–X and M–Y bonds were.

It’s been observed in a number of cases that a ligand dissociates from octahedral complexes before concerted reductive elimination occurs. Presumably, dissociation to form a distorted trigonal bipyramidal geometry brings the eliminating groups closer to one another to facilitate elimination. Square planar complexes may either take on an additional fifth ligand or lose a ligand to form an odd-coordinate complex before reductive elimination. Direct reductive elimination without dissociation or association is possible, too.
Reductive Elimination | Chemistry Optional Notes for UPSC

Question for Reductive Elimination
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During reductive elimination, what happens to the oxidation state of the metal?
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Reactivity trends in reductive elimination are opposite those of oxidative addition. More electron-rich ligands bearing electron-donating groups react more rapidly, since the ligands lose electron density as the reaction proceeds. More electron-poor metal centers—bearing π-acidic ligands and/or ligands with electron-withdrawing groups—react more rapidly, since the metal center gains electrons. Sterically bulky ancillary ligands promote reductive elimination since the release of X and Y can “ease” steric strain in the starting complex. Steric hindrance helps explain, for example, why coordination of a fifth ligand to a square planar complex promotes reductive elimination even though coordination increases electron density at the metal center. A second example: trends in rates of reductive eliminations of alkanes parallel the steric demands of the eliminating ligands: C–C > C–H > H–H.Reductive Elimination | Chemistry Optional Notes for UPSC

Mechanistic trends for reductive elimination actually parallel trends in mechanisms of oxidative addition, since these two reactions are the microscopic reverse of one another. Non-polar and moderately polar ligands react by concerted or radical mechanisms; highly polarized ligands and/or very electrophilic metal complexes react by ionic (SN2) mechanisms. The thermodynamics of reductive elimination must be favorable in order for it to occur! Most carbon–halogen reductive eliminations, for example, are thermodynamically unfavorable (this has turned out to be a good thing, especially for cross-coupling reactions).

Reductive elimination is an important step in many catalytic cycles—it usually comes near the “end” of catalytic mechanisms, just before product formation. For some catalytic cycles it’s the turnover-limiting step, making it very important to consider. Hydrocyanation is a classic example; in the mechanism of this reaction, reductive elimination of C–CN is the slow step. Electron-poor alkyl ligands, derived from electron-poor olefins like unsaturated ketones, are bad enough at reductive elimination to prevent turnover altogether.

Question for Reductive Elimination
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Which of the following is true about reductive elimination?
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FAQs on Reductive Elimination - Chemistry Optional Notes for UPSC

1. What is reductive elimination?
Ans. Reductive elimination is a type of chemical reaction in which two atoms or groups are eliminated from a metal complex, resulting in the formation of a new bond between the remaining atoms or groups.
2. How does reductive elimination occur?
Ans. Reductive elimination typically occurs in transition metal complexes when a metal atom or ion undergoes a change in oxidation state. This process involves the breaking of a metal-ligand bond and the formation of a new bond between two ligands, resulting in the elimination of a small molecule such as hydrogen or a halogen.
3. What are the applications of reductive elimination in chemistry?
Ans. Reductive elimination reactions play a crucial role in various chemical transformations. They are utilized in organic synthesis to create new carbon-carbon or carbon-heteroatom bonds, as well as in catalytic processes for the production of pharmaceuticals, polymers, and fine chemicals. Additionally, reductive elimination is important in the field of organometallic chemistry for designing new catalysts and studying metal-ligand bonding.
4. Can you provide an example of a reductive elimination reaction?
Ans. Yes, an example of a reductive elimination reaction is the conversion of a palladium(II) complex to a palladium(0) species. In this reaction, the palladium(II) complex undergoes reductive elimination of two ligands, resulting in the formation of a palladium(0) species with a lower oxidation state.
5. What factors influence the rate of reductive elimination reactions?
Ans. The rate of reductive elimination reactions can be influenced by several factors, including the nature of the metal center, the identity of the ligands, the steric hindrance around the metal center, and the reaction conditions such as temperature and solvent. Additionally, the electronic properties of the ligands and the presence of other coordinating groups can also affect the rate of reductive elimination.
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