Table of contents | |
What is Refraction? | |
What is Total Internal Reflection? | |
Formula of Total Internal Reflection | |
Applications of Total Internal Reflection | |
Important Questions for Exam |
Why do stars twinkle?
Did you know that the twinkling effect of stars is due to atmospheric refraction? The starlight undergoes several refractions while reaching the Earth. This atmospheric refraction occurs in a medium of gradually changing refractive index.
Laws of refraction state that:
Refraction has many applications in optics and technology. A few of the prominent applications are listed below:
Q.1. Light travelling in air enters into an optical fibre of refractive index 1.44.
a) In which direction does the light bend?
b) If the angle of incidence on one end of the fibre is 22o, then what is the angle of refraction?
Solution:
a) The light travels from rarer medium(air) to denser medium(optical fibre), hence the refracted ray will bend towards the normal.
b) The angle of refraction can be calculated as follows:
Let air be medium 1 and optical fibre be medium 2. Therefore, n1 = 1.00, n2 = 1.44, and θ1= 22o.
Now, substituting the values in the equation as follows:
(1.00) sin 22o = 1.44 sin θ2.
sin θ2 = (1.00/1.44) sin 22o = 0.260
θ2 = sin-1 (0.260) = 15o
Q.2. The light travelling through the optical fibre reaches the end of the optical fibre and exits into the air. If the angle of incidence at the end of the tube is 30o. Then what would the angle of refraction outside the fibre be?
Solution: Let the fibre be medium 1 and air medium 2. Therefore, n1 = 1.44, n2 = 1.00, and θ,1 = 30o. Substituting the values in the equation, we get
(1.44) sin 30o = 1.00 sin θ2
sin θ2 = (1.44/1.00) sin 30o = 1.44 (0.500) = 0.720
θ2 = sin-1 (0.720) = 46o
This time we notice that the angle of refraction is larger than the angle of incidence. This indicates that the light is bending away from the normal as it enters a rarer material.
Q.1. Define Refraction.
The change in the direction of a wave when it passes from one medium to another is known as refraction.
Q.2. When does refraction of waves occur?
The refraction of light occurs when a light wave, incident at an angle away from the normal, passes a boundary from one medium into another in which there is a change in velocity of the light.
Q.3. When is the refraction of light not possible?
When the incident light is perpendicular to the boundary, refraction of light is not possible.
Q.4. What is the difference between reflection and refraction in the light?
Reflection of light is when the light bounces off a medium. If the medium has a smooth surface, then the angle of incidence is equal to the angle of reflection. Refraction of light is the change in the direction of light as it passes from one medium to another.
Q.5. State an example of refraction of light.
An example of refraction is the rainbow. The light rays bend as they enter water drops in the atmosphere forming a rainbow.
When a light ray travelling from a denser medium towards a rarer medium is incident at the interface at an angle of incidence greater than the critical angle, then light rays get reflected back into the denser medium. This phenomenon is called Total Internal Reflection.
Total Internal Reflection
[Question: 907154]
The following are the two conditions of total internal reflection:
Note: The critical angle increases with temperature.
[Question: 907156]
Total Internal Reflection:
Critical Angle, θ: sinθ = n2/n1 (n1 > n2)
Applications of Total Internal Reflection
➢ Optical Fibre
➢ Diamond
➢ Mirage
Q1: An optical fibre made up of glass with a refractive index of n1 = 1.5 which is surrounded by another glass with refractive index n2. Find the refractive index n2 of the cladding such that the critical angle between the two cladding is 80°.
Solution.
Critical angle, θ = 80°
Refractive index, n1 = 1.5
Refractive index n2 =?
Using the below formula, we can calculate n2:
sinθ = n2/n1
sin80∘ = (n2 / 1.5)
n2 = 1.5 * sin80∘
n2 = 1.48
Q2: Find the refractive index of the medium whose critical angle is 40°.
Solution.
Critical angle, θ = 40°
The refractive index of the medium, μ =?
μ = 1/sinθ
μ = 1/sin40∘
μ =1/0.65
µ = 1.6
Q3: Which of the following is an example of total internal reflection?
1. Mirror
2. Twinkling of stars
3. Mirage
4. Thin film of soap bubble
Answer: Option 3: Mirage
Explanation: Mirage is an example of total internal reflection.On hot summer days, the air near the ground becomes hotter than the air at higher levels. Due to this, there is a difference in the refractive index of the air in different layers.
Q4: A scuba diver is wearing a head lamp and looking up at the surface of the water. If the minimum angle to the vertical resulting in total internal reflection is 25∘, what is the index of refraction of the water?
θair=1
a) 2.37
b) 0.85
c) 0.49
d) 1.12
Answer: 2.37
Solution:
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1. What is refraction and how does it occur? |
2. What conditions are necessary for total internal reflection to occur? |
3. What is the formula for calculating the critical angle in total internal reflection? |
4. What are some practical applications of total internal reflection? |
5. How does the refractive index affect the refraction and total internal reflection of light? |
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