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What Is Reimer Tiemann Reaction?

Reimer Tiemann reaction is a type of substitution reaction named after chemists Karl Reimer and Ferdinand Tiemann. The reaction is used for the ortho-formylation of C6H5OH (phenols).

A common example of the Reimer Tiemann reaction is the conversion of phenol to salicylaldehyde (2-hydroxy benzaldehyde), as shown below.
Reimer-Tiemann | Chemistry Optional Notes for UPSC

Reimer Tiemann Reaction Details

  • Since hydroxides are not readily soluble in chloroform, a biphasic solvent system is employed to carry out the reaction. This biphasic solvent system can consist of an aqueous hydroxide solution with an organic phase that contains chloroform.
  • These two reagents that are separated are brought together for the reaction to occur. Techniques to bring these two reagents together include – rapid mixing, phase-transfer catalysts or the use of an emulsifying agent.
  • The reaction is quite effective when other hydroxy-aromatic compounds are used, for example, naphthols. Heterocyclic organic compounds that are quite rich in electrons, such as pyrroles and indoles, also can undergo the Reimer Tiemann reaction.
  • The reaction needs heat to initiate the process. However, once the reaction has begun, it can prove to be highly exothermic and further increase the reaction rate. This is the reason why the Reimer Tiemann reaction is prone to thermal runaways.

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Reimer Tiemann Reaction Mechanism

  • The mechanism of the Reimer Tiemann reaction begins with the deprotonation of chloroform by a strong base to form a chloroform carbanion. This chloroform carbanion quickly undergoes alpha elimination and gives rise to dichlorocarbene – the principal reactive species for this reaction.
  • The Reimer Tiemann reaction is an organic chemical reaction where phenol is converted into an ortho hydroxy benzaldehyde using chloroform, a base, and an acid workup. This reaction can also be described as the chemical reaction used for the ortho-formylation of phenols.
  • The mechanism of the Reimer Tiemann reaction can be explained in the below-given steps:
    • The chloroform is deprotonated by the strongly basic aqueous hydroxide solution, giving the chloroform carbanion.
    • This chloroform carbanion readily undergoes alpha elimination, giving dichlorocarbene as the product. As mentioned earlier, dichlorocarbene is the main reactive species.
    • The aqueous hydroxide also deprotonates the phenol reactant, yielding a negatively charged phenoxide.
    • This negative charge is now delocalized into the benzene ring, causing it to be far more nucleophilic.
    • This results in a nucleophilic attack on the dichlorocarbene, forming an intermediate dichloromethyl-substituted phenol.
    • This intermediate is subjected to basic hydrolysis to finally achieve the formation of the desired ortho-hydroxybenzaldehyde.

The illustration of the Reimer Tiemann reaction mechanism is given below:
Reimer-Tiemann | Chemistry Optional Notes for UPSC

Thus, the given phenol is converted into an ortho-hydroxy benzaldehyde using chloroform, a base and an acid workup. It can be noted that the carbene is highly electron-deficient due to the electron-withdrawing nature of its two chlorine groups. This is why it is strongly attracted to phenoxide, which is rich in electrons. The interaction favours ortho-formylation of a selective nature.

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Which compound is formed as a product in the Reimer Tiemann reaction?
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The document Reimer-Tiemann | Chemistry Optional Notes for UPSC is a part of the UPSC Course Chemistry Optional Notes for UPSC.
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FAQs on Reimer-Tiemann - Chemistry Optional Notes for UPSC

1. What is the Reimer-Tiemann reaction?
Ans. The Reimer-Tiemann reaction is a chemical reaction used to convert phenols to salicylaldehydes. It involves the reaction of a phenol with chloroform (CHCl3) and a strong base, such as sodium hydroxide (NaOH), to form the corresponding salicylaldehyde.
2. What is the mechanism of the Reimer-Tiemann reaction?
Ans. The Reimer-Tiemann reaction proceeds through a nucleophilic aromatic substitution mechanism. The base deprotonates the phenol to form a phenoxide ion, which then attacks the chloroform. This leads to the formation of an intermediate called dichloromethyl carbene. The dichloromethyl carbene then undergoes rearrangement to form the desired salicylaldehyde.
3. What are the conditions required for the Reimer-Tiemann reaction?
Ans. The Reimer-Tiemann reaction requires the presence of a phenol, chloroform (CHCl3), and a strong base, such as sodium hydroxide (NaOH). The reaction is usually carried out in an aqueous solution at elevated temperatures.
4. What is the purpose of the Reimer-Tiemann reaction?
Ans. The main purpose of the Reimer-Tiemann reaction is to convert phenols into salicylaldehydes. Salicylaldehydes have various applications, including their use as intermediates in the synthesis of pharmaceuticals and dyes.
5. Are there any limitations or drawbacks to the Reimer-Tiemann reaction?
Ans. Yes, there are some limitations to the Reimer-Tiemann reaction. It may not be suitable for phenols containing electron-withdrawing groups, as they can hinder the nucleophilic substitution step. Additionally, the reaction can be sensitive to side reactions, such as over-oxidation or polymerization. Careful optimization of reaction conditions is required to achieve high yields and selectivity.
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