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Time and Distance | Quantitative Techniques for CLAT

Speed is a very basic concept in motion which is all about how fast or slow any object moves. We define speed as distance divided by time.

Distance is directly proportional to Velocity when time is constant.

Few Formulae

  • Distance travelled = speed x time
  • Speed = distance / tim
  • Time = distance / speed1
    km/hr = (5/18) meter / sec
    1 metre / sec = 18 / 5 km / hr.    

If the time taken, to travel two distances with different speeds, is equal then

Average speed = (speed1 + speed2) / 2

Also     

  • average speed = total distance travelled  / total time taken  
  • if two distances travelled are equal and two speeds are x km /hr and y km / hr then average speed = Time and Distance | Quantitative Techniques for CLAT
  • if 3 equal distances are travelled at speeds x km /hr, ykm/ hr and z km/hr respectively then average speed =Time and Distance | Quantitative Techniques for CLAT

 Formulae for Questions on Train

  • To pass a pole or signal post or a standing man, a train has to travel a distance equal to its length. So, the time taken to pass a pole = length of the train/ speed off the train 
  • To pass a platform of length A, the train has to travel a distance equal to its length + the length of the platform (A). So, time taken by the train (length T) to pass a platform (length A) = T+A / Speed
  • Let the speeds of two trains be x km / hr and y km /hr then
    The relative speed if the direction of the trains is the same = (x – y) km/ hr
    The relative speed if the direction of trains is opposite to each other
    = (x+y) km /hr

Example 1: A bike crosses a bridge at a speed of 180 km/hr. what will be length of the bridge if the bike takes 3 minutes to cross the bridge. 

Solution: 
Length of the bridge = distance travelled by the bike in 3 minutes = speed x time

Speed = 180 km/hr = (180 x 5) / 18 = 50 meters / sec.

Time = 3 x 60 = 180 seconds.

So, length of the bridge

= 50 X 180 meters

= (50 x 180) / 1000 km

= 9 km

Example 2: Two persons are moving in the direction opposite to each other. The speeds of the two persons are 8 km/hr and 5 km per hour. Find their relative speed wrt each other.

Solution: We know that when two objects move in the direction opposite to each other, the relative speed is the sum of two speeds.

So, required relative speed = 8 + 5 = 13 km/hr

Example 3: Two trains A and B are moving at the speeds in the ratio of 2 : 5. Find the ratio of the time taken to travel the same distance. 

Solution: The ratio of time taken is inverse of the speeds of the two cars.

i.e. since speeds are 2 : 5

so, time must be 5 : 2

Example 4: Prem can cover a certain distance in 42 minutes by covering 2/3 of the distance at 4 km/hr and the rest at 5 km/hr. find the total distance. 

Solution: Let total distance be x

So, as per the given condition.

Distance / speed + distance / speed = total time

Or (2x/3) x ¼ + (x/3) x (1/5) = 42/60

Or x/2 + x/5 = 42/20

7x/10 x= 42/20

X = 3 km

Example 5: A man completes 60 km of a journey at 12 km / hr and the remaining 80 km of the journey in 5 hours. Find the average speed for the whole journey. 

Solution: Total distance travelled = 60 km + 80 km = 140 km

Total time taken = 5 hours + 5 hours = 10 hours

So, average speed for the whole journey = 140/10

= 14 km/hr

Speed during the first part = 12 km/hr

Time taken during the first part to cover 60 km = 60 / 12= 5 hours

Time taken to cover the second part = 5 hrs

And the speed during 2nd part = 80/5 = 16 km/hr

So, the time taken during the two journeys is equal

So, average speed = (12 km/hr + 16 km/hr) / 2 = 28/2

= 14 km/hr

Question for Time and Distance
Try yourself: A bullock cart has to cover a distance of 40 km in 5 hours. If it covers half of the journey in 3/5 th of the time, what should be its speed to cover the remaining distance in the left over time. 
View Solution

Example 6: A car travels from A to B at a speed of 58 km/hr and travels back from B to A at the speed of 42 km/hr. what is average speed of the car in covering the distance both ways. 

Solution: Since the car travels equal distance with different speed, the average speed is the harmonic mean of the two speeds.

Average speed = Time and Distance | Quantitative Techniques for CLAT

Time and Distance | Quantitative Techniques for CLAT

Example 7: The speed of A and B are in the ratio 3 : 4. A takes 20 minutes more than the time taken by B to reach a destination. In what time doesA reach the destination

Solution: Let time taken by A be x hours.

Then time taken by B = (x – 20/60) hours

Or (x – 1/3) hours

Ratio of speeds = inverse ratio of time

Time and Distance | Quantitative Techniques for CLAT 

or x = 4/3 hours

Example 8: A train crosses a platform in 20 seconds but a man standing on the platform in 8 seconds. Length of the platform is 180 meters. Find the length of the train and its speed.

Solution: Time taken to cross the platform = 20 sec.

Time taken to cross the man = 8 sec.

20 – 8 = 12 sec is the time taken by the train to travel the distance equal to platform.

The train travels 180 meter in 12 seconds

So, its speed is 180/12 = 15 m/sec.

Time and Distance | Quantitative Techniques for CLAT

And the length of the train = distance travelled in

8 sec. = 15 x 8 = 120 meter

Example 9: A train running at 54 km/hr. takes 25 seconds to pass a platform and 15 seconds to pass a man walking at 6 km/h in the same direction in which train is going. Find the length of the train and the length of the platform. 

Solution: Let x and y be the length of the train and of the platform respectively.

Speed of the train w.r.t the man = 54 – 6 = 48 km/ph

= 48 x 5/18 = 40/3 meter / seconds

In passing the man the train covers its own length with the relative speed.

So the length of the train = Relative speed x time

= (40/3 x 15) m = 200 m.

Speed of the train = 54 x 5/18 = 15 m/second.

Distance travelled to pass the platform = x + y

So, x + y = 200 + y

So, (200 + y) / 15 = 25

Or y + 200 = 375

Or y = 175 meters.

Question for Time and Distance
Try yourself: A train 165 meter in length is running with a speed of 59 km/hr. in what time will it pass a man who is running at a speed of 7 km/hr in the direction opposite to that in which the train is going? 
View Solution

The document Time and Distance | Quantitative Techniques for CLAT is a part of the CLAT Course Quantitative Techniques for CLAT.
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FAQs on Time and Distance - Quantitative Techniques for CLAT

1. What is time and distance?
Ans. Time and distance is a concept in mathematics and physics that calculates the duration it takes for an object to travel a certain distance. It involves measuring the time elapsed during a journey and the physical distance covered.
2. How is time and distance related to speed?
Ans. Time and distance are directly related to speed. Speed is the rate at which an object covers a certain distance in a given amount of time. It is calculated by dividing the distance traveled by the time taken.
3. How can I calculate the time taken to travel a certain distance at a given speed?
Ans. To calculate the time taken, divide the distance by the speed. For example, if the distance is 100 kilometers and the speed is 50 kilometers per hour, the time taken would be 2 hours (100 km ÷ 50 km/h = 2 hours).
4. How can I calculate the speed of an object if I know the distance and time?
Ans. To calculate the speed, divide the distance by the time taken. For example, if the distance is 200 kilometers and the time taken is 4 hours, the speed would be 50 kilometers per hour (200 km ÷ 4 hours = 50 km/h).
5. What are some practical applications of time and distance calculations?
Ans. Time and distance calculations are used in various real-life scenarios, such as determining the estimated time of arrival for a journey, calculating the average speed of vehicles, planning travel routes, and estimating fuel consumption. These calculations are also important in physics for analyzing motion and studying concepts like velocity and acceleration.
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