A caliper is a device used to measure the distance between two opposing sides of an object.
The tips of the caliper are adjusted to fit across the points to be measured and the caliper is then removed and the distance between the tips is measured using a ruler.
The modern Vernier caliper was invented by Joseph R. Brown in 1851.
The Vernier Caliper consists of a main scale fitted with a jaw at one end (figure). Another jaw, containing the Vernier scale, moves over the main scale (slidable). When the two jaws are in contact, the zero of the main scale and the zero of the Vernier scale should coincide. If both the zeros do not coincide, there will be an error called zero error.
Vernier Caliper
The main scale consists of a steel metallic strip graduated in centimeters at one edge and in inches at the other edge . It carries the inner and outer measuring jaws.
A vernier scale slides on the strip. It can be fixed in any position by the retainer. On the Vernier scale, generally, 0.9 cm is divided into ten equal parts.
The outer measuring jaws help to take the outer dimension of an object while the inner measuring jaws help to take the inner dimension of an object.
The retainer helps to retain the object within the jaws of the Vernier calipers
The depth measuring prong helps to measure the depth of an object
First calculate the least count and only then place the object between the two jaws.
Record the position of zero of the Vernier scale on the main scale.
When a body is between the jaws of the Vernier Caliper; firstly, we need to ensure that the zero of the main scale and the zero of the Vernier scale should coincide. If both the zeros do not coincide, there will be an error called zero error.
Now,
Observe the position of the zero on the Vernier Scale. If the zero of the Vernier scale lies ahead of the Nth division of the main scale, then the main scale reading (MSR) is;
MSR = N
If nth division of Vernier scale coincides with any division of the main scale, then the Vernier scale reading (VSR) is;
VSR = n × L.C, ( L.C is least count of vernier calliper)
Now, the total reading of the length is,
Total Reading (TR)=Main Scale Reading + Vernier Scale Reading
i.e
TR = MSR + VSR = N + (n × L.C) .....(2)
Volume of the beaker / calorimeter = internal area of the cross section x depth
This can be expressed as;
V = π(D/2)2.d
where 'D' is the internal diameter of beaker / calorimeter and 'd' the depth of beaker / calorimeter.
Now, readings of D and d which represents the diameter of cross section and depth respectively can be taken using the Vernier Caliper. The diameter can be measured by clamping the cross section area into the jaws while the depth can be measured using Depth Measuring Prong.
V = (4/3)πr3
where 'r' is the radius of the sphere.
Measurement of r is done using the Vernier Caliper
V = l * b * h
where 'l' is length of the block, 'b' the breadth and 'h' the height of the block.
(1) We'll first determine the vernier constant (VC), which is the least count (L.C) of the vernier calliper and record it stepwise as in the equation,
L.C = 1 MSD - 1 VSD.
(2) Now, bring the movable jaw in close contact with the fixed jaw and find the zero error. Do this three times and record the values. If there is no zero error, then record 'zero error nil'.
(3) Open the jaws of the Vernier Calliper and place the sphere or cylinder between the two jaws and adjust the movable jaw, such that it gently grips the body without any undue pressure on it. After that, tighten the screw attached to the Vernier scale (figure).
(4) Note the position of the zero mark of the Vernier scale on the main scale. Record the main scale reading just before the zero mark of the Vernier scale. This reading (N) is called main scale reading (MSR).
(5) Note the number (n) of the Vernier scale division which coincides with the division of the main scale.
(6) You'll have to repeat steps 5 and 6 after rotating the body by 90o for measuring the diameter in a perpendicular direction.
(7) Repeat steps 4 to 7 for at least three different positions and record the observations.
(8) Now find total reading using the equation, TR = MSR+VSR = N+(n x L.C) and apply the zero correction.
(9) Take the mean of the different values of the diameter and show that in the result with the proper unit.
Note:
To measure the internal diameter of a calorimeter or beaker, place the beaker upside down over the internal jaws of the vernier calipers.Then repeat the steps 4 to 8.
To find the ‘Depth’ of the beaker, move the metallic strip till it touches the bottom of the beaker. Then repeat steps 4 to 8.
Q.1. What is the smallest possible reading (in cm) of a Vernier caliper?
Ans.The smallest possible reading of a Vernier caliper is 0.01 cm also called the Least Count of the scale (L.C.).
Q.2. A measurement on the Vernier Caliper is made. Report the length of the scale.
Ans.
Observe that the Main scale reading (MSR) = 3.0 mm
Also, the 7th division mark on the Vernier scale exactly coincides with the main scale. Hence, Vernier scale reading is 7.
Now, the total reading,
TR = MSR + VSR = N + (n × L.C) ..... (2)
TR = 3.0 mm + (7 × 0.1)mm = 3.7 mm
Hence, the reading recorded would be 3.7 mm.
Q.3. A measurement on the Vernier Caliper is made. Report the length of the scale.
Ans.
Observe that the Main scale reading (MSR) = 15.0 mm
Also, the 8th division mark on the Vernier scale exactly coincides with the main scale. Hence, Vernier scale reading is 8.
Now, the total reading,
TR = MSR + VSR = N + (n × L.C) ..... (2)
TR = 15.0 mm + (8 × 0.1)mm = 15.8 mm
Hence, the reading recorded would be 15.8 mm.
Using Vernier Calipers allows for accurate length measurements up to 0.1mm. However, for even finer measurements, down to 0.01mm or 0.005mm, a screw gauge surpasses Vernier Calipers in precision. In this document, we will study in detail the screw gauge and its usage followed by calculation techniques.
Using Vernier Calipers allows for accurate length measurements up to 0.1mm. However, for even finer measurements, down to 0.01mm or 0.005mm, a screw gauge surpasses Vernier Calipers in precision. In this document, we will study in detail the screw gauge and its usage followed by calculation techniques.
The purpose of screw gauge is:
The screw gauge is an instrument used for measuring accurately the diameter of a thin wire or the thickness of a sheet of metal. It consists of a U-shaped frame fitted with a screwed spindle which is attached to a thimble.
Screw Gauge
When this is done, any of the following three situations can arise:
(a) The zero mark of the circular scale comes on the reference line. In this case, the zero error and the zero correction, both are nil.
(b) The zero mark of the circular scale remains above the reference line and does not cross it. In this case, the zero error is positive and the zero correction is negative depending on how many divisions it is above the reference line.
(c) The zero mark of the head scale is below the reference line. In this case, the zero error is negative and the zero correction is positive depending on how many divisions it is below the reference line.
To find the diameter of the lead shot with the lead shot between the screw and anvil, if the edge of the cap lies ahead of the Nth division of the linear scale.
Then, linear scale reading (P.S.R.) = N.
If the nth division of the circular scale lies over the reference line.
Then, circular scale reading (H.S.R.) = n × (L.C.) (L.C. is the least count of screw gauge)
Total reading (T.R.) = P.S.R. + corrected H.S.R. = N + (n x L.C.).
If D is the mean diameter of the lead shot,
Then, the volume of the lead shot,
V = (4/3)π (D/2)3
Place the wire between the anvil and the screw and note down the PSR and HSR as before.
The diameter of the wire is given by;
T.R = PSR + (corrected HSR × L.C) = N + (n × L.C) ....(3)
If r is the radius of the wire, and l is the mean length of the wire.
Then, the volume of the wire,
V = π r2 I ....(4)
The glass plate is gripped between the tip of the screw and the anvil. The PSR and HSR are noted as before.
The thickness of the glass plate is;
t = PSR + corrected HSR = N + (n × L.C) ....(5)
To find the Volume of glass plate (irregular lamina)
Find the thickness, t of irregular lamina as before. Then place the lamina over a graph paper and trace its outline on the graph paper. The area A of the lamina is taken from the graph paper.
The volume of the glass plate is calculated from the equation;
V = A ∗ t ........ (6)
Solution. Reading of main scale = 4.50 mm
Reading of vernier scale = 10
Reading of Vernier scale x accuracy of Vernier caliper = 10 × 0.01 = 0.10 mm
Add the result of step III and step I to get the reading of the micrometer screw gauge.
= 4.50 + 0.10 = 4.60 mm
Reading of Vernier caliper = 4.60 mm
Example 2. What are the readings of the reading of the micrometer meter screw gauges as shown in the figures below?
Solution. Reading of main scale = 22.0 mm
Reading of Vernier scale = 33
Reading of Vernier scale x accuracy of
Vernier caliper = 33 × 0.01 = 0.33 mm
Add the result of step III and step I to get the reading of the micrometer screw gauge.
= 22.0 + 0.33 = 22.33 mm
Reading of Vernier caliper = 22.33 mm
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