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# Wave Motion - Physics, Solution by DC Pandey NEET Notes | EduRev

## DC Pandey (Questions & Solutions) of Physics: NEET

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## NEET : Wave Motion - Physics, Solution by DC Pandey NEET Notes | EduRev

The document Wave Motion - Physics, Solution by DC Pandey NEET Notes | EduRev is a part of the NEET Course DC Pandey (Questions & Solutions) of Physics: NEET.
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Introductory Exercise 14.1

Ques 1: Prove that the equation y = a sin wt does not satisfy the wave equation and hence it does not represent a wave.
Sol: Hence, the given equation does not represent a wave equation.

Ques 2: A wave pulse is described by , where a, b and c are positive constants. What is the speed of this wave?
Sol: Speed of wave = c/b

Ques 3: The displacement of a wave disturbance propagating in the positive x-direction is given by and where, x and y are in metre. The shape of the wave disturbance does not change during the propagation. What is the velocity of the wave?
Sol:
At t = 0, y is maximum at x = 0.
At t = 2 s, y is maximum at x = 1 m.
Hence, in 2 s, wave has travelled 2m in positive x-direction. = +0.5 m/s

Ques 4: A travelling wave pulse is given by, Here, x and y are in metre and t in second. In which direction and with what velocity is the pulse propagating? What is the amplitude of pulse?
Sol:
Since coefficient of t and x are opposite signs, wave is travelling along negative x-direction. Further,
Speed of wave = Amplitude = maximum value of y
= 10/5 = 2m

Ques 5: If at f = 0, a travelling wave pulse on a string is described by the function, Here x and y are in metre and t in second. What will be the wave function representing the pulse at time t, if the pulse is propagating along positive x-axis with speed 2 m/s?
Sol:
Since, wave is travelling along positive x-direction. Hence, coefficient of t and coefficient of x should have opposite signs. Further ∴  Coefficient of t = 2 (coefficient of x) = 2 x 1 = 2 SI units. Introductory Exercise 14.2

Ques 1: The equation of a travelling wave is,
y(x, t ) 0.02 sin Find: (a) The wave velocity and
(b) the particle velocity at x = 0.2 m and t = 0.3 s.
Given cos θ = -0.85 where θ = 34 rad
Sol:
(a) Wave velocity =  Since, coefficient of t and coefficient of x are of same signs. Hence, wave is travelling in negative x-direction.
or
v = -5 m/s
(b) Particle velocity  Substituting x = 0.2 and t = 0.3, we have Vp = 2cos(34)
= (2) (-0.85) =-1.7 m/s

Ques 2: Is there any relationship between wave speed and the maximum particle speed for a wave travelling on a string? If so, what is it?
Sol:
As we know, Wave speed, and maximum particle speed, (vp)max = wA
From these two expressions, we can see that,
(vp)max = (kA)V

Ques 3: Consider a sinusoidal travelling wave shown in figure. The wave velocity is + 40 cm/s. Find : (a) the frequency
(b) the phase difference between points 2.5 cm apart
(c) how long it takes for the phase at a given posit ion to change by 60°
(d) the velocity of a particle at point P at the instant shown.
Sol: ⇒ λ = 4cm   (d) At P, particle is at mean position. So, v = maximum velocity = 125.7 cm/s= 1.26 m/s
Further, ...(i)
Sign of v1, the wave velocity is given positive.
Sign of dy/dx, slope of y - x graph is also positive.
Hence, from Eq. (i) particle velocity is negative. vp = -1.26 m/s

Ques 4: Transverse waves on a string have wave speed 12.0 m/s, amplitude 0.05 m and wavelength 0.4 m. The waves travel in the + x direction and at t = 0 the x = 0 end of the string has zero displacement and is moving upwards.
(a) Write a wave function describing the wave.
(b) Find the transverse displacement of a point at x = 0.25 m at time t = 0.15 s.
(c) How much time must elapse from the instant in part (b) until the point at x = 0.25 m has zero displacement?
Sol:  Since wave is travelling along + ve x-direction, at and kx should have opposite signs. Further at t = 0, x = 0 the string has zero displacement and moving upward (in positive direction).
Hence at x = 0, we should have Asinwt not - Asinwt. Therefore, the correct expression is (b) Putting x = 0.2 m  and  t = 0.15 s  in the above equation we have,
y= 0.0354 m = 3.54 cm
(c) In part (b), y = A/√2
From to y = 0, time taken is = 4.2 × 10-3s = 4.2 ms

Introductory Exercise 14.3

Ques 1. Calculate the velocity of a transverse wave along a string of length 2 m and mass 0.06 kg under a tension of 500 N.
Sol:  Ques 2. Calculate the speed of a transverse wave in a wire of 1.0 mm2 cross-section under a tension of 0.98 N. Density of the material of wire is 9.8 × 103 kg/m3.
Sol:  Introductory Exercise 14.4

Ques 1. Spherical waves are emitted from a 1.0 W source in an isotropic non-absorbing medium. What is the wave intensity 1.0 m from the source?
Sol: Ques 2. A line source emits a cylindrical expanding wave. Assuming the medium absorbs no energy, find how the amplitude and intensity of the wave depend on the distance from the source?
Sol:
For line source,  Offer running on EduRev: Apply code STAYHOME200 to get INR 200 off on our premium plan EduRev Infinity!

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