P-Block Elements Trends - Ionization Enthalpy Video Lecture - NEET

hello friends this video on be block
elements part 3 is brought you by exam
fear calm no more fear from exam now let
us talk about the ionization in Kalki so
what is I imagine that we energy
required to clock one electron so I have
to pluck one electron from here and the
energy required is nothing but
ionization will help your ionization so
this trend we have seen if you go from
here to where right this side the size
of atom decrees are charging he is
though these electrons are more highly
tied to the atoms the nucleus here right
so it's very difficult very we will do
platform length on heads it needs more
more energy is required but if you talk
about let's suppose this guy it is less
than list all right why because the size
more and this electron is less in
control with the barium nucleus so it's
all about the control rights if nitrogen
if you see in this case it has this
suppose some control over this electron
and if you talk about fluorine fluorine
has more control over it's in that form
because fluorine is more charged and the
size of the fluorine is less so all the
electrons are simple so if we compare
boron and oxygen also both oxygen has
more control over its electron as
compared to good and if you compare
let's suppose boron and let's take this
one it's sink more on gallium here right
so here also you see boron has less
control more control because gallium
size is very big right this electron is
not in that much control of gallium but
this electron is pretty much in control
with world so it's all comparative right
so our comparative so if you see the
moment you go from here to here the size
decrease and does the ionization
enthalpy and I initially thought being
energy increase is increasing why
because the more energy is required to
pluck electron if you go down also the
size of atom increase the control of
nucleus over the
electrons degrees and thus it is easy to
pick electron while we go down now by in
this case it is easy to pick electron
from this so the energy required is less
so nation will be digging one thing to
look here is that my group thirteen
ionization energy is less than Y let's
take some number for example going by
this logic if this was my X this will be
what X minus some number one sorry X
plus some bynum right so this epic verse
5 5 units of energy is required to take
out electrons so in this case the less
energy should be required correct so in
this case let's suppose for energy
should be required for 6 6 right what
was I told the moment you go from here
to here the it required more energy per
example it has 1 it has to it has 5 it
has 6 7 like that right you increase so
going by that logic if you see if if my
sodium requires X sodium atom requires X
energy to pluck one electron my Boron's
would required X plus 1 because the size
of boron decreases the charge increased
correct see the size decreased size
decrease in the charge increased so here
if you go
the size is diffusing in the charges
English so with that the control is mode
it should be like this but actually it
is not like this this is wrong
actually this is 5 this is 4 why because
if you see here my S orbitals are
involved here my P orbitals are angle
since I have seen let suppose these are
in to are in s third one is in P so
since P orbitals are involved it is easy
to clock electron from periodicals right
here easy to ah
P as compared to as compared to us so
the ease will be like this s will be
most difficult then we have P then we
have D is in the air the easiest will be
F right so since the orbitals involved a
different here right so there is a
slight deviation here so by the general
logic it should have increased right the
energy required to pluck electrons from
burns should increase as compared to
sodium but actually the energy required
to pluck one electron from boron is less
than what is required for sodium why
because no one you talked about Burin
the p orbitals are involved in it's easy
to pluck electron from P orbitals
because actually you see this is not the
action shape of that right just to
simplify things we have given the shape
of actually the ship to atom like this
we have this nucleus and we has orbitals
right the electron keep jumping here and
there so you have s orbital something
like this P something like this right so
in this case if the electron is in P
orbitals it is far away from nucleus and
it's easy to plug this but if it is an S
orbital it is somewhere here it's
difficult to pluck electrons so if it is
in P orbitals it easy to pluck electrons
so the ionization energy is less if you
are picking from P orbitals so just this
shift happens only Y in this case Y
because here we introduce geometers so
once you have P orbitals if you come pay
more and carbon there is not much
different the bow has pre operative site
the extra p orbital advantage is gone if
you compare boron carbon or carbon
nitrogen but reading compares already
even more on the extra p orbital
advantage is there and that's why we
have this division similar thing what -
similar to what we have seen earlier and
gallium we have because here we have D
orbital coming into place this here D
orbital is not day so you get extra D
orbital it has some mixture I think it
was poor shielding it does that no make
size decrease here also if you see the
extra P orbitals it has an extra
advantage that the ease of hanging out
electron from p orbital was easy so the
ionization are we actually thank you
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