Class 10 Exam  >  Class 10 Notes  >  Mathematics (Maths) Class 10  >  Very Short Answer Questions: Areas Related to Circles

Class 10 Maths Chapter 11 Question Answers - Area Related to Circles

VERY SHORT ANSWER TYPEQUESTIONS

Q1. PQRS is a diameter of a circle of radius 6 cm. The equal lengths PQ, QR and RS are drawn on PQ and QS as diameters, as shown in figure. Find the perimeter of the shaded region.

Class 10 Maths Chapter 11 Question Answers - Area Related to Circles

Sol. Diameter PS = 12 cm      [∵ Radius OS = 6 cm]

Since PQ, QR and RS are three equal parts of diameter,

Class 10 Maths Chapter 11 Question Answers - Area Related to Circles

Now, the total required perimeter

Class 10 Maths Chapter 11 Question Answers - Area Related to Circles

Q2. A sheet of paper is in the form of a rectangle ABCD in which AB = 40 cm, and BC = 28 cm. A semi-circlular portion with BC as diameter is cut off. Find the area of the remaining paper.

Class 10 Maths Chapter 11 Question Answers - Area Related to Circles

Sol. Length of the paper = 40 cm, width of the paper = 28 cm.
∴ Area of the rectangle =length × breadth = 40 × 28 cm2 = 1120 cm2
Again, diameter of semi-circle = 28 cm.
⇒ Radius of the semi-circle = 28/2 = 14 cm.

∴ Area of the semi-circle 

Class 10 Maths Chapter 11 Question Answers - Area Related to Circles

∴ Area of the remaining paper = 1120 cm2 − 308 cm2 = 812 cm2.

Q3. Find the area of the shaded region in the figure, if ABCD is a square of side 14 cm and APD and BPC are semi-circles.

Class 10 Maths Chapter 11 Question Answers - Area Related to Circles

Sol. Side of the square = 14 cm
∴ Area of the square = 14 × 14 cm2 = 196 cm2

Also, diameter of each semi-circle = side of the square = 14 cm.
⇒ Radius =  14/2 = = 7 cm.
Area of 1 semi-circle = 1/2 πr2

Class 10 Maths Chapter 11 Question Answers - Area Related to Circles

⇒ Area of both semi-circles = 2 × 77 cm2
= 154 cm2.
Now, the area of the shaded region = [Area of the square ABCD] − [Area of both the semi-circles]
= (196 − 154) cm2 = 42 cm2.

Q4. Find the perimeter of the shaded region, if ABCD is a square of side 21 cm and APB and CPD are semi-circles. (use π = 22/7)

Sol. Here diameter = 21 cm ⇒  r = 21/2

Class 10 Maths Chapter 11 Question Answers - Area Related to Circles

Class 10 Maths Chapter 11 Question Answers - Area Related to Circles

Thus the required perimeter of shaded region is 108 cm.

Q5. A park is in the form of a rectangle 120 m long and 100 m wide. At the centre, there is a circular lawn of radius  Class 10 Maths Chapter 11 Question Answers - Area Related to Circles Find the area of the park excluding the lawn.

[Take π = 22/7]

Sol. Length of the park l = 120 m
Breadth of the park b = 100 m

Class 10 Maths Chapter 11 Question Answers - Area Related to Circles
Class 10 Maths Chapter 11 Question Answers - Area Related to Circles

∴ Area of the park excluding the central park

= 12000 − 3300 m2
= 8700 m2.

Q6. In the given figure, OAPB is a sector of a circle of radius 3.5 cm with the centre at O and ∠AOB = 120°. Find the length of OAPBO.

Class 10 Maths Chapter 11 Question Answers - Area Related to Circles

Sol. Here, the major sector angle is given by θ = 360° − 120° = 240°

Class 10 Maths Chapter 11 Question Answers - Area Related to Circles

∴ Circumference of the sector APB
Class 10 Maths Chapter 11 Question Answers - Area Related to Circles
∴ Perimeter of OAPBO = [Circumference of sector AOB] + OA + OB]

Class 10 Maths Chapter 11 Question Answers - Area Related to Circles
Class 10 Maths Chapter 11 Question Answers - Area Related to Circles

Q7. Find the area of the shaded region of the following figure, if the diameter of the circle with centre O is 28 cm and AQ = 1/4 AB.

Class 10 Maths Chapter 11 Question Answers - Area Related to Circles

Sol. We have AB = 28 cm

∴ Class 10 Maths Chapter 11 Question Answers - Area Related to Circles

Class 10 Maths Chapter 11 Question Answers - Area Related to Circles
⇒ BQ = 28 − 7 = 21 cm
∴ Area of the semi-circle having diameter as 21 cm
Class 10 Maths Chapter 11 Question Answers - Area Related to Circles

∴ Also area of the semi-circle having diameter as 7 cm

Class 10 Maths Chapter 11 Question Answers - Area Related to Circles

Thus the area of the shaded region

Class 10 Maths Chapter 11 Question Answers - Area Related to Circles

= 192.5 cm2.

Q8. PQRS is a square land of side 28 m. Two semi-circular grass covered postions are to be made on two of its opposite sides as shown in the figure. How much area will be left uncovered? [Take π = 22/7]

Class 10 Maths Chapter 11 Question Answers - Area Related to Circles

Sol. Side of the square = 28 m
∴ Area of the square PQRS = 28 × 28 m2
Diameter of a semi-circle = 28 m

⇒ Radius of a semi-circle = 28/2 = 14m

∴ Area of 1 semi-circle = 1/2πr2  =  Class 10 Maths Chapter 11 Question Answers - Area Related to Circles

⇒ Area of both the semi-circles = 2 × 308 m2 = 616 m2

∴ Area of the square left uncovered = (28 × 28) − 616 m2 = 784 − 616 m2 = 168 m2.

Q9. Find the area of a square inscribed in a circle of radius 10 cm.

Sol. Let ABCD be the square such that

Class 10 Maths Chapter 11 Question Answers - Area Related to Circles

AB = BC = 10 cm
∴ AC2 = AB2 + BC2
AB2 + BC2 = (10 × 2)
⇒ x2 + x2 = (20)2
[Let AB = BC = x]
⇒ 2x2 = 400

⇒  Class 10 Maths Chapter 11 Question Answers - Area Related to Circles

∴ Area of the square = 200 cm2.

Q10. In the given figure, O is the centre of a circular arc and AOB is a straight line. Find the perimeter of the shaded region.

Class 10 Maths Chapter 11 Question Answers - Area Related to Circles

Sol. O is the centre of the circle.
∴ AB is its diameter.
In right Δ ABC,
AC2 + BC2 = AB2
⇒ 122 + 162 = AB2
⇒ 144 + 256 = AB2 ⇒ AB2 = 400

⇒ Class 10 Maths Chapter 11 Question Answers - Area Related to Circles
∴ Circumference of semi-circle ACB
Class 10 Maths Chapter 11 Question Answers - Area Related to Circles

∴ Perimeter of the shaded region = 22/7 cm + 12 cm + 16 cm
= 31.43 cm + 12cm + 16cm
= 59.43 cm

The document Class 10 Maths Chapter 11 Question Answers - Area Related to Circles is a part of the Class 10 Course Mathematics (Maths) Class 10.
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FAQs on Class 10 Maths Chapter 11 Question Answers - Area Related to Circles

1. What is the formula to find the area of a circle?
Ans. The formula to find the area of a circle is A = πr², where A is the area and r is the radius of the circle.
2. How do you calculate the circumference of a circle?
Ans. The circumference of a circle can be calculated using the formula C = 2πr, where C is the circumference and r is the radius of the circle.
3. What is the relationship between the radius and diameter of a circle?
Ans. The diameter of a circle is two times the radius. In other words, the diameter is equal to 2r, where r is the radius.
4. How can I find the radius of a circle if I know the circumference?
Ans. If you know the circumference of a circle, you can find the radius using the formula r = C/2π, where r is the radius and C is the circumference.
5. How do I find the area of a sector of a circle?
Ans. To find the area of a sector of a circle, you can use the formula A = (θ/360) * πr², where A is the area, θ is the central angle of the sector, and r is the radius of the circle.
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