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Important Questions for Class 8 Maths - Mensuration

Match the column


Q1:Important Questions for Class 8 Maths - MensurationAns:
(p) → (iv)
(q) → (i)
(r) → (ii)
(s) → (iii)

Sol :Important Questions for Class 8 Maths - Mensuration

Q2:

Important Questions for Class 8 Maths - MensurationAns:

(p) → (ii)

(q) → (iii)

(r) → (i)

Sol:
Important Questions for Class 8 Maths - Mensuration

Fill in the blanks


(i) Curved surface area of a cylinder of radius 2b and height 2a is _______.
(ii) Volume of a cylinder with radius p and height q is __________.
(iii) 6.55m2= ______cm2
(iv)The volume of a cylinder becomes __________ the original volume if its radius becomes doubles of the original radius and height becomes half of its original values
Ans: 

(i) 8πab

Sol: 2πr
2π × 2b × 2
8πab

(ii) πp2q

Sol: V=π r2
Substituting value of radius = p and Height = q 
We get ,
V=π p2q

(iii) 65,500cm2
Sol1 m= 10,000 cm2
6.55m= 6.55×10,000cm= 65,500cm2

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(iv)double
Sol:V1πr2H
V2=π(2r)2(1/2)H
=2πr2H
So it becomes double

True & False


(i) Amount of region occupied by a solid is called its surface area
(ii)The areas of any two faces of a cube are equal.
(iii)The areas of two oppossite faces of a cuboid are equal.
(iv) 2.5 litres is equal to 0.025 cubic meters
(v) Total surface area of cuboid is  2h (l + b).
Ans:

(i)False
Sol: The amount of region occupied by a solid is called its volume, not surface area.
(ii)True
Sol: All six faces of a cube are squares and have equal areas.
(iii) True
Sol: Opposite faces of a cuboid are identical in dimensions, hence their areas are equal.
(iv) False 
Sol: 1litre = 0.001m3, so 2.5 \, \text{litres} = 2.5 \times 0.001 = 0.0025 \, \text{m}^32.5litres = 2.5 × 0.001 = 0.0025m3. (This makes it True, correcting the prior explanation.)
(v) False
Sol: Total surface area of cuboid 2(lb + bh + hl),  not 2h (l + b).

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Answer the following questions 

Q1: The parallel sides of a trapezium are 20 cm and 10 cm. Its nonparallel sides are both equal, each being 13 cm. Find the area of the trapezium.
Sol:Let ABCD is the trapezium with AB and CD are the parallel sides.
Now
AB=10 cm, CD=20 cm, BC=13 cm
Now draw line BE || AD and draw a perpendicular from B on EC

Important Questions for Class 8 Maths - MensurationNow ABED is a parallelogram, then BE=13 cm
In triangle BEC, BE =BC, So Isoceles triangle,So perpendicular will bisect the EC
Hence EF = FC
Now EC=  DC -DE = 20 -10 =10 cm
Therefore EF = FC = EC/2 = 5 cm
Now in Triangle BEF, it is right angle at F,So by pythagorous theorem
BE2 BF2 EF2
169 BF2 25
BF12cm
This is also the perpendicular distance between the parallel sides. So now coming back to Area of trapezium
1/2[b× h
Here a = 10 cm , b = 20 cm, h = 12 cm., A =?
Therefore
1/2[10 20]×12
180cm2


Q2: The area of a rhombus is 300 cm², and one of the diagonals is 20 cm. Find the other diagonal.

Sol:
Important Questions for Class 8 Maths - MensurationQ3: A circular garden has a radius of 14 m. Find the cost of fencing the garden along its circumference at the rate of ₹12 per meter.
Sol:

Important Questions for Class 8 Maths - MensurationQ4: Find the area of a trapezium whose parallel sides are 38.7 cm and 22.3 cm, and the distance between them is 18 cm.
Sol: Area of trapezium = Half the product of the sum of the lengths of parallel sides and the perpendicular distance between them gives the
1/2[b× h
Here a = 38.7 cm , b = 22.3 cm h = 18 cm
Therefore
1/2[38.7 22.3× 18
549cm2

Q5: Find the area of a trapezium whose parallel sides are 12 cm and 20 cm and the distance between them is 15 cm.
Sol:
Area of trapezium = Half the product of the sum of the lengths of parallel sides and the perpendicular distance between them gives the
12[b× h
Here a = 12 cm , b = 20 cm h =15 cm
Therefore
12[12 20× 15 
240cm2

Q6: A box in the form of a cuboid has external dimensions of 60 cm × 40 cm × 30 cm. The top face, two side faces, and the front face are to be painted with a glossy finish. Calculate the area that needs to be painted.
Sol:
Important Questions for Class 8 Maths - MensurationQ7: The area of a trapezium is 384cm2. Its parallel sides are in the ratio 2: 6 and the perpendicular distance between them is 12 cm. Find the length of each of the parallel sides.
Sol:

Area of trapezium=Half the product of the sum of the lengths of parallel sides and the perpendicular distance between them gives the
12[b× h
Here a = 2x cm , b = 6x, h = 12 cm., A = 384 cm2
Therefore
384 12[26x× 12
8cm
So parallel sides are 16 cm and 48 cm

Q8: A cylindrical road roller makes 750 complete revolutions to level a road. The diameter of the roller is 84 cm, and its length is 1 m. Calculate the total area leveled by the road roller.
Sol:

Important Questions for Class 8 Maths - Mensuration
Q9: A rectangular piece of cardboard measuring 18 cm × 7 cm is folded without overlapping to make a cylinder of height 7 cm. Find the volume of the cylinder.

Sol:Important Questions for Class 8 Maths - Mensuration

Q10: A storage room is in the shape of a cuboid with dimensions 50 m × 30 m × 20 m. How many smaller cuboidal containers of volume 1.2 m³ can be stored in it?

 Sol: 
Important Questions for Class 8 Maths - Mensuration

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FAQs on Important Questions for Class 8 Maths - Mensuration

1. What is mensuration in mathematics?
2. How do you calculate the area of a rectangle?
Ans.To calculate the area of a rectangle, you multiply its length by its width. The formula is: Area = Length × Width. For example, if the length is 5 units and the width is 3 units, the area would be 5 × 3 = 15 square units.
3. What is the formula for finding the volume of a cylinder?
Ans.The volume of a cylinder can be calculated using the formula: Volume = π × r² × h, where "r" is the radius of the base and "h" is the height of the cylinder. For instance, if the radius is 2 units and the height is 5 units, the volume would be π × (2)² × 5 = 20π cubic units.
4. What is the difference between perimeter and area?
Ans.Perimeter refers to the total distance around a two-dimensional shape, while area measures the extent of the space contained within that shape. For example, a rectangle has a perimeter calculated by adding up all its sides, while the area is found by multiplying its length and width.
5. How can I find the surface area of a cube?
Ans.The surface area of a cube can be found using the formula: Surface Area = 6 × a², where "a" is the length of one side of the cube. For example, if each side measures 4 units, the surface area would be 6 × (4)² = 96 square units.
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