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A function accepts an input, performs a rule, and produces an output. An inverse function reverses this process: it accepts the output and returns the original input.
Ordinary trigonometric functions (sin, cos, tan, cot, sec, cosec) are not one-to-one on their entire natural domains; they are many-to-one. Hence an inverse in the usual sense does not exist unless we restrict the domain so that the function becomes one-to-one (injective). On such a restricted domain we can define a unique inverse called the principal inverse.
Principal-value notation and multivaluedness
For a trigonometric equation z = sin ω there are infinitely many ω giving the same z. The notation sin-1z usually denotes the principal value, the unique value chosen from a specified range (for arcsin it is [-π/2, π/2]). Some texts write arcsin z to emphasise the principal value.
The principal branches (domain of the inverse function and range of the original) are normally taken as follows.
| Function | Domain | Range (principal value) |
|---|---|---|
| sin-1x | [-1, 1] | [-π/2, π/2] |
| cos-1x | [-1, 1] | [0, π] |
| tan-1x | R (all real numbers) | (-π/2, π/2) |
| cot-1x | R (all real numbers) | (0, π) |
| sec-1x | (-∞, -1] ∪ [1, ∞) | [0, π] \ {π/2} |
| cosec-1x | (-∞, -1] ∪ [1, ∞) | [-π/2, π/2] \ {0} |
Fig: Inverse Trigonometric FunctionsQues 1: Find the exact value of each expression without a calculator, in [0, 2π).
Ans:
sin θ = -√3/2. The reference angle with sine √3/2 is π/3.
The value of θ in the principal range [-π/2, π/2] where sine is -√3/2 is θ = -π/3.
Therefore sin-1(-√3/2) = -π/3.
cos θ = -√2/2. The reference angle with cosine √2/2 is π/4.
The principal value of arccos lies in [0, π] where cosine is negative in (π/2, π). The angle is θ = 3π/4.
Therefore cos-1(-√2/2) = 3π/4.
tan θ = √3. The reference angle is π/3.
The principal value of arctan lies in (-π/2, π/2), so θ = π/3.
Therefore tan-1(√3) = π/3.
Note. If the problem asked for all solutions in [0, 2π), each trig equation has multiple solutions (for example sin θ = -√3/2 gives θ = 4π/3 and 5π/3 in [0,2π)). But inverse functions by convention return the principal value.
Ques 2: Find the value of tan-1(1.1106).
Ans:
A = tan-1(1.1106)
tan A = 1.1106
Using a calculator in degree mode gives A ≈ 48°.
Therefore tan-1(1.1106) ≈ 48° (or in radians ≈ 0.8378 rad).
We list commonly used properties and give proofs or short justifications. In each identity the domains indicated ensure expressions are defined.
Property 1 - Reciprocal relations
Proof (first relation) - sin-1(1/x) = cosec-1x for |x| ≥ 1:
Let y = sin-1(1/x).
Then sin y = 1/x and so cosec y = x, provided x ≠ 0.
Thus y = cosec-1x (with the usual principal-value choices), so sin-1(1/x) = cosec-1x.

Property 2 - Oddness of certain inverses
Proof - sin-1(-x) = -sin-1(x):
Let y = sin-1(-x).
Then sin y = -x.
So sin(-y) = -sin y = x.
Therefore sin-1(x) = -y, which gives y = -sin-1(x).
Hence sin-1(-x) = -sin-1(x) for x ∈ [-1, 1].
Property 3 - Relations with π
Proof - cos-1(-x) = π - cos-1(x):
Let y = cos-1(-x).
Then cos y = -x, so -x = cos y = cos(π - y).
Thus cos(π - y) = x, so cos-1(x) = π - y.
Therefore y = π - cos-1(x), i.e. cos-1(-x) = π - cos-1(x).
Ques 1: Prove that sin-1(-x) = -sin-1(x), x ∈ [-1,1]
Ans:
Assume y = sin-1(-x).
Then sin y = -x.
So sin(-y) = -sin y = x.
Therefore sin-1(x) = -y.
Hence y = -sin-1(x), which demonstrates sin-1(-x) = -sin-1(x).
Ques 2: sin-1(cos π/3) = ?
Ans:
cos(π/3) = 1/2.
sin-1(1/2) = π/6 (principal value in [-π/2, π/2]).
Therefore sin-1(cos π/3) = π/6.

Ques 3: Find the value of sin(π/4 + cos-1(√2/2)).
Ans:
Let A = cos-1(√2/2).
Then cos A = √2/2 = 1/√2.
The principal value A in [0, π] satisfying cos A = 1/√2 is A = π/4.
Therefore sin(π/4 + cos-1(√2/2)) = sin(π/4 + π/4) = sin(π/2) = 1.


This completes the discussion on the basic concepts of inverse trigonometric functions, their principal values, domains and ranges, standard properties, and worked examples useful for school-level and competitive examinations.
173 videos|510 docs|154 tests |
| 1. What is the definition of an inverse function? | ![]() |
| 2. How do inverse trigonometric functions relate to trigonometric functions? | ![]() |
| 3. What are some examples of inverse trigonometric functions? | ![]() |
| 4. How can inverse trigonometric functions be useful in real-life applications? | ![]() |
| 5. Are there any restrictions on the domains of inverse trigonometric functions? | ![]() |
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