Important Points
Q1: What percent is student 1’s average marks to that of student 2’s average marks in the 4th year
(a) 88.2
(b) 85.6
(c) 90
(d) 87.6
Ans: a
Sol:
In 2003, Student 1 = 75
Student 2 = 85
Required % = 75/85 * 100 = 88.2
Q2: What is the ratio of the average marks of Student 1 over the years to that of Student 2?
(a) 79.2 : 773
(b) 792 : 773
(c) 79 : 77
(d) None of these
Ans: a
Sol:
Average marks of student 1 = (85 + 80 + 60 + 75 + 85 + 90 + 80)/7 = 79.2
Average marks of student 2 = (70 + 66.5 + 90 + 85 + 75+ 77 + 78)/7 = 77.3
Ratio = 79.2 : 77.3
Q3: In which of the following years is the total marks maximum?
(a) 2006
(b) 2001
(c) 2003
(d) 2000
Ans: d
Sol:
Quicker Method: Since the number of subjects are the same, the total marks would be higher in the year whose average marks is the highest. Hence, 2000
Q4: What would be the ratio of Student 1’s total average marks of the first and the last year to Student 2’s difference of marks in the first and last year
(a) 9 : 10
(b) 165 : 8
(c) 8 : 165
(d) 1
Ans: b
Sol:
Student 1’s total marks in 1st and last year = 85 + 80 = 165
Student 2’s difference in marks in 2st and last year = 78 – 70 = 8
Ratio = 165 : 8
(a) 2004
(b) 2005
(c) 2003
(d) 2002
Ans: a
Sol: Quicker Method: Since the number of subjects are the same, the total marks would be minimum in the year whose average marks is the lowest. Hence, 2004
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