UPSC Exam  >  UPSC Notes  >  Chemistry Optional Notes for UPSC  >  Cell EMF

Cell EMF | Chemistry Optional Notes for UPSC PDF Download

Electromotive Force (EMF)

  • The electromotive force (EMF) is the maximum potential difference between two electrodes of a galvanic or voltaic cell. This quantity is related to the tendency for an element, a compound or an ion to acquire (i.e. gain) or release (lose) electrons. For example, the maximum potential between  Zn and Cu of a well known cell
    Zn(s)|Zn2+(1M)||Cu2+(1M)|Cu(s)
  • has been measured to be 1.100 V. A concentration of 1 M in an ideal solution is defined as the standard condition, and 1.100 V is thus the standard electromotive force, ΔEo, or standard cell potential for the  Zn−Cu galvanic cell.

Cell EMF | Chemistry Optional Notes for UPSC

  • The standard cell potential, ΔEo, of a galvanic cell can be evaluated from the standard reduction potentials of the two half cells Eo. The reduction potentials are measured against the standard hydrogen electrode (SHE):
    Pt(s)|H2(g,1.0atm)|H+ (1.0M)
  • Its reduction potential or oxidation potential is defined to be exactly zero.Cell EMF | Chemistry Optional Notes for UPSC
  • The reduction potentials of all other half-cells measured in volts against the SHE are the difference in electrical potential energy per coulomb of charge.
  • Note that the unit for energy J = Coulomb volt, and the Gibbs free energy G is the product of charge q and potential difference E:
    G in J = q E in C V
    for electric energy calculations.

Question for Cell EMF
Try yourself:
What is the maximum potential difference between two electrodes of a galvanic or voltaic cell called?
View Solution

Evaluating Standard Cell Potential DE° of Galvanic Cells

  • A galvanic cell consists of two half-cells. The convention in writing such a cell is to put the (reduction) cathode on the right-hand side, and the (oxidation) anode on the left-hand side. For example, the cell
    Pt|H2|H + ||Zn2+ |Zn
    consists of the oxidation and reduction reactions:
    • H→ 2e + 2Hanode (oxidation) reaction
    • Zn2+ + 2e → Zn cathode (reduction) reaction
  • If the concentrations of  H+ and  Zn2+  ions are 1.0 M and the pressure of  H2 is 1.0 atm, the voltage difference between the two electrodes would be -0.763 V(the  Zn  electrode being the negative electrode). The conditions specified above are called the standard conditions and the EMF so obtained is the standard reduction potential.
  • Note that the above cell is in reverse order compared to that given in many textbooks, but this arrangement gives the standard reduction potentialsdirectly, because the  Zn half cell is a reduction half-cell. The negative voltage indicates that the reverse chemical reaction is spontaneous. This corresponds to the fact that  Zn metal reacts with an acid to produce  H2 gas.
    As another example, the cell
    • Pt|H2|H+||Cu+|Cu
  • consists of an oxidation and a reduction reaction:
    • H→ 2e + 2Hanode reaction
    • Cu2+ + 2e− → Cucathode reaction
  • and the standard cell potential is 0.337 V. The positive potential indicates a spontaneous reaction,
    Cu2+ + H→ Cu + 2H+
    but the potential is so small that the reaction is too slow to be observed.

Solved Example

Example 1: What is the potential for the following cell?
Zn|Zn2+ (1.0M)||Cu2+ (1.0M)| Cu
Ans:
From a table of standard reduction potentials we have the following values
Cu2+ + 2e → CuE = 0.337 (1)
Zn → Zn2+ + 2eE = 0.763 (2)
Add (1) and (2) to yield
ZnCu2+ → Zn2+ + CuDE∘ = E∘ + E = 1.100 V
Note that E* is the oxidation standard potential, and E° is the reduction standard potential, E* = - E°. The standard cell potential is represented by dE°.

Discussion
The positive potential confirms your observation that zinc metal reacts with cupric ions in solution to produce copper metal.

Example 2: What is the potential for the following cell?
Ag|Ag+ (1.0M)||Li + (1.0M)|Li
Ans: 
From the table of standard reduction potentials, you find
Li+ e− → Li E∘ = −3.045 (3)
Ag → Ag+ + e− E = − 0.799 (4)
According to the convention of the cell, the reduction reaction is on the right. The cell on your left-hand side is an oxidation process. Thus, you add (4) and (3) to obtain
Li+ + AgAg+ Li dE∘ = -3.844 V

Discussion

  • The negative potential indicates that the reverse reaction should be spontaneous.
  • Some calculators use a lithium battery. The atomic weight of  Li  is 6.94, much lighter than Zn (65.4).

Summary

  • The electromotive force (EMF) is the maximum potential difference between two electrodes of a galvanic or voltaic cell.
  • The standard reduction potential of  Mn+,1M | M couple is the standard cell potential of the galvanic cell:
    Pt|H2,1atm|H+,1M||Mn+, 1M|M
  • The standard oxidation potential of  M|Mn+,  1M couple is the standard cell potential of the galvanic cell:
    M|Mn+,1M||H+,1M|H2,1atm|Pt
  • If the cell potential is negative, the reaction is reversed. In this case, the electrode of the galvanic cell should be written in a reversed order.
The document Cell EMF | Chemistry Optional Notes for UPSC is a part of the UPSC Course Chemistry Optional Notes for UPSC.
All you need of UPSC at this link: UPSC
308 docs

Top Courses for UPSC

FAQs on Cell EMF - Chemistry Optional Notes for UPSC

1. What is electromotive force (EMF)?
Ans. Electromotive force (EMF) is the maximum potential difference that can be achieved by a galvanic or voltaic cell. It represents the driving force for the flow of electric current in a circuit.
2. How is the standard cell potential (E°) evaluated for galvanic cells?
Ans. The standard cell potential (E°) of a galvanic cell is evaluated by measuring the potential difference between the two electrodes of the cell when no current is flowing. This measured potential difference is compared to a standard reference electrode to determine the standard cell potential.
3. What is the significance of evaluating the standard cell potential (E°) of galvanic cells?
Ans. Evaluating the standard cell potential (E°) of galvanic cells allows us to determine the direction and magnitude of the flow of electrons in a redox reaction. It helps in predicting whether a reaction is spontaneous or non-spontaneous and in calculating the cell potential under different conditions.
4. How can the electromotive force (EMF) of a cell be calculated using the standard cell potential (E°)?
Ans. The electromotive force (EMF) of a cell can be calculated by subtracting the potential of the cathode from the potential of the anode. This can be obtained using the formula: EMF = E°(cathode) - E°(anode).
5. Why is it important to consider the standard cell potential (E°) in galvanic cells?
Ans. Considering the standard cell potential (E°) in galvanic cells is important because it allows us to compare the tendencies of different redox reactions to occur. The E° value helps in determining the feasibility and spontaneity of a reaction, which is crucial in various applications such as battery design and electrochemical processes.
308 docs
Download as PDF
Explore Courses for UPSC exam

Top Courses for UPSC

Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
10M+ students study on EduRev
Related Searches

Sample Paper

,

Previous Year Questions with Solutions

,

Exam

,

shortcuts and tricks

,

mock tests for examination

,

Objective type Questions

,

Viva Questions

,

practice quizzes

,

Cell EMF | Chemistry Optional Notes for UPSC

,

Cell EMF | Chemistry Optional Notes for UPSC

,

Extra Questions

,

MCQs

,

pdf

,

ppt

,

Semester Notes

,

Summary

,

past year papers

,

study material

,

Important questions

,

Cell EMF | Chemistry Optional Notes for UPSC

,

Free

,

video lectures

;