Table of contents |
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What is Riemann Integral? |
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Riemann Sums |
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Riemann Integral Formula |
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Properties of Riemann Integral |
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Applications of Riemann Integral |
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Riemann integral is a method in calculus to find the total area under a curve between two points. It involves dividing the area into small rectangles and adding up their areas to approximate the total area under the curve. As the width of these rectangles approaches zero, the sum of their areas gives the exact value of the integral.
Multiply each height by the width of the corresponding subinterval (which is 0.50.5 in this case) to find the area of each rectangle.
Now add up the areas of all the rectangles to get an approximation of the total area under the curve.
In this example, the sum of the areas of the rectangles is approximately 0×0.5 + 0.25×0.5 + 1×0.5 + 2.25×0.5 = 1.125
So, the Riemann sum approximation of the area under the curve y=x2 between x=0 and x=2 is approximately 1.125 square units.
Riemann integral possesses several important properties that make it useful in calculus and analysis. Here are some key properties:
The Riemann integral is linear, meaning that it satisfies the properties of additivity and scalar multiplication. That is, for functions f(x) and g(x) and constants c and d, we have:
The integral of a sum of functions is the sum of their integrals. That is, for functions f(x) and g(x), we have:
Monotonicity property of the Riemann integral sates that if one function is always greater than or equal to another function over an interval, then the integral of the first function should be greater than or equal to the integral of the second function over that interval. Let f and g be two Riemann integrable functions on the closed interval [a, b]. If f(x) ≤ g(x) for all x ∈ [a, b], then:
The integral of a constant multiple of a function is the constant multiplied by the integral of the function. That is, for a constant c, we have:
The integral over a sum of intervals is the sum of the integrals over each individual interval. That is, for intervals [a,c] and [c,b], we have:
If f(x) is non-negative on an interval [a,b] and f(x) ≥ g(x) for all x in [a,b], then:
The Riemann integral finds application across various fields:
The difference between Lebesgue integral and Riemann integral can be understood from the table below:
Example 1: Compute Riemann integral of function f(x) = x3 over the interval [−2, 2].
Sol:
Riemann integral of f(x) over [a,b] is given by:
where Δx = nb−a is the width of each subinterval, and xi∗ is any point in the ith subinterval.
In this case, a = −2, b = 2, and f(x) = x3.
First, we need to partition the interval [−2,2] into n equal subintervals. Let's choose n=4 for simplicity.
Δx=[2−(−2)]/4=4/4=1
So, the subintervals are [−2,−1], [−1,0], [0,1], and [1,2].
Next, we'll choose a point in each subinterval to evaluate f(x). Let's choose the midpoint of each subinterval:
- For [−2,−1]: x1∗= −1.5
- For [−1,0]: x2∗= −0.5
- For [0,1]: x3∗= 0.5
- For [1,2]: x4∗= 1.5
Now, we'll evaluate f(x)=x3 at each point:
- f(−1.5) = (−1.5)3 = −3.375
- f(−0.5) = (−0.5)3 = −0.125
- f(0.5) = (0.5)3 = 0.125
- f(1.5) = (1.5)3 = 3.375
Finally, we'll sum up the products of
and Δx for each subinterval and take the limit as n approaches infinity.
[(−3.375)(1)+(−0.125)(1)+(0.125)(1)+(3.375)(1)]
=limn→∞(−3.375−0.125+0.125+3.375)
=limn→∞0 = 0
Therefore, the Riemann integral of f(x) = x3 over the interval [−2,2] is 0.
Example 2: Find Riemann integral of function f(x) = ex over the interval [0, 2].
Sol:
Riemann integral of f(x) over [a,b] is given by:
where Δx=nb−a is the width of each subinterval, and xi∗ is any point in the ith subinterval.
In this case, a=0, b=2, and f(x)=ex.
First, we need to partition the interval [0,2] into n equal subintervals. Let's choose n=4 for simplicity.
So, the subintervals are [0,0.5], [0.5,1], [1,1.5], and [1.5,2].
Next, we'll choose a point in each subinterval to evaluate f(x). Let's choose the right endpoint of each subinterval:
- For [0,0.5]: x1∗ = 0.5
- For [0.5,1]: x2∗ = 1
- For [1,1.5]: x3∗ = 1.5
- For [1.5,2]: x4∗ = 2
Now, we'll evaluate f(x)=ex at each point:
- f(0.5) = e0.5
- f(1) = e1
- f(1.5) = e1.5
- f(2) = e2
Finally, we'll sum up the products of f(xi∗) and Δx for each subinterval and take the limit as n approaches infinity.
Thus, Riemann integral of f(x)=ex over the interval [0,2] is approximately e0.5+e1+e1.5+e2.
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1. What is the Riemann Integral and how is it defined? | ![]() |
2. What are Riemann Sums and how do they relate to the Riemann Integral? | ![]() |
3. What are some key properties of the Riemann Integral? | ![]() |
4. How does the Riemann Integral differ from the Lebesgue Integral? | ![]() |
5. Can you provide an example of calculating a Riemann Integral? | ![]() |