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Riemann Integration (Definite Integrals and their Properties) | Mathematics Optional Notes for UPSC PDF Download

What is Riemann Integral?

Riemann integral is a method in calculus to find the total area under a curve between two points. It involves dividing the area into small rectangles and adding up their areas to approximate the total area under the curve. As the width of these rectangles approaches zero, the sum of their areas gives the exact value of the integral.

Riemann Integration (Definite Integrals and their Properties) | Mathematics Optional Notes for UPSC

Riemann Integral Definition

  • The function (f) is Riemann integrable on [a, b] if the limit of the Riemann sums exists as the norm of the partition approaches zero, independently of the choice of sample points ci
  • This limit is called the Riemann integral of f over [a, b] and is denoted by:
    Riemann Integration (Definite Integrals and their Properties) | Mathematics Optional Notes for UPSC

Riemann Sums

  • Riemann sums are a way to estimate the total area under a curve by breaking it into smaller pieces. Imagine dividing the area under the curve into rectangles. By adding up the areas of these rectangles, we get an approximation of the total area under the curve. 
  • The more rectangles we use, the closer our estimate gets to the actual area. Riemann sums help us understand and calculate the total accumulation or value represented by a curve within a specific interval.
  • For Example: To find the area under the curve y = x2 between x = 0 and x = 2.
    Riemann Integration (Definite Integrals and their Properties) | Mathematics Optional Notes for UPSC
  • We can use Riemann sums to approximate this area by dividing the interval [0, 2] into smaller subintervals and approximating the area of each subinterval with a rectangle.
  • Let's say we divide the interval into four equal subintervals: [0, 0.5], [0.5, 1], [1, 1.5] and [1.5, 2].
  • For each subinterval, we find the height of the rectangle by evaluating the function y=x2 at a specific point within the subinterval. For simplicity, let's choose the left endpoint of each subinterval.
    For the first subinterval [0, 0.5], the height of the rectangle is y = (0)= 0.
    For the second subinterval [0.5, 1], the height of the rectangle is y = (0.5)= 0.25.
    For the third subinterval [1, 1.5], the height of the rectangle is y = (1)= 1.
    For the fourth subinterval [1.5, 2], the height of the rectangle is y = (1.5)2= 2.25.

Multiply each height by the width of the corresponding subinterval (which is 0.50.5 in this case) to find the area of each rectangle.

Now add up the areas of all the rectangles to get an approximation of the total area under the curve.

In this example, the sum of the areas of the rectangles is approximately 0×0.5 + 0.25×0.5 + 1×0.5 + 2.25×0.5 = 1.125

So, the Riemann sum approximation of the area under the curve y=x2 between x=0 and x=2 is approximately 1.125 square units.

Riemann Integral Formula

  • Riemann integral formula represents the calculation of the integral of a function over a specified interval. In its basic form, for a function f(x) defined on the interval [a,b], the Riemann integral is given by:
    Riemann Integration (Definite Integrals and their Properties) | Mathematics Optional Notes for UPSC
  • This notation represents the sum of infinitely many infinitely small rectangles under the curve of the function f(x) between x = a and x=b. 
  • The integral symbol ∫∫ represents integration, f(x) is the function being integrated, dx denotes the variable of integration, and a and b are the lower and upper limits of integration, respectively.

Properties of Riemann Integral

Riemann integral possesses several important properties that make it useful in calculus and analysis. Here are some key properties:

1. Linearity

The Riemann integral is linear, meaning that it satisfies the properties of additivity and scalar multiplication. That is, for functions f(x) and g(x) and constants c and d, we have:
Riemann Integration (Definite Integrals and their Properties) | Mathematics Optional Notes for UPSC

2. Additivity

The integral of a sum of functions is the sum of their integrals. That is, for functions f(x) and g(x), we have:
Riemann Integration (Definite Integrals and their Properties) | Mathematics Optional Notes for UPSC

3. Monotonicity

Monotonicity property of the Riemann integral sates that if one function is always greater than or equal to another function over an interval, then the integral of the first function should be greater than or equal to the integral of the second function over that interval. Let f and g be two Riemann integrable functions on the closed interval [a, b]. If f(x) ≤ g(x) for all x ∈ [a, b], then:
Riemann Integration (Definite Integrals and their Properties) | Mathematics Optional Notes for UPSC

4. Constant Multiple Rule

The integral of a constant multiple of a function is the constant multiplied by the integral of the function. That is, for a constant c, we have:
Riemann Integration (Definite Integrals and their Properties) | Mathematics Optional Notes for UPSC

5. Interval Splitting

The integral over a sum of intervals is the sum of the integrals over each individual interval. That is, for intervals [a,c] and [c,b], we have:
Riemann Integration (Definite Integrals and their Properties) | Mathematics Optional Notes for UPSC

6. Order Preservation

If f(x) is non-negative on an interval [a,b] and f(x) ≥ g(x) for all x in [a,b], then:
Riemann Integration (Definite Integrals and their Properties) | Mathematics Optional Notes for UPSC

Applications of Riemann Integral

The Riemann integral finds application across various fields:

  • Integration and Differential Calculus: It's fundamental in calculus for finding areas under curves and solving problems related to rates of change, such as velocity and acceleration.
  • Physics Problems: Used extensively in physics for calculating quantities like work, energy, and fluid flow rates. It helps in analyzing continuous phenomena and predicting outcomes.
  • Partial Differential Equations: Applied in solving partial differential equations, which describe how functions change in response to changes in multiple variables. This is crucial in fields like engineering and physics.
  • Trigonometric Series: Utilized in representing functions as trigonometric series, which can simplify complex functions into a sum of simpler trigonometric functions.
  • Measurement of Distance Traveled: In scenarios where an object's velocity changes over time, the Riemann integral can determine the total distance traveled by analyzing the area under the velocity-time graph. This concept helps in understanding motion and predicting trajectories accurately.

Difference Between Lebesgue Integral and Riemann Integral

The difference between Lebesgue integral and Riemann integral can be understood from the table below:

Riemann Integration (Definite Integrals and their Properties) | Mathematics Optional Notes for UPSC

Examples of Riemann Integral

Example 1: Compute Riemann integral of function f(x) = x3 over the interval [−2, 2].

Sol:
Riemann integral of f(x) over [a,b] is given by:
Riemann Integration (Definite Integrals and their Properties) | Mathematics Optional Notes for UPSC
where Δx = nb−a is the width of each subinterval, and xi is any point in the ith subinterval.
In this case, a = −2, b = 2, and f(x) = x3.
First, we need to partition the interval [−2,2] into n equal subintervals. Let's choose n=4 for simplicity.
Δx=[2−(−2)]/4=4/4=1
So, the subintervals are [−2,−1], [−1,0], [0,1], and [1,2].
Next, we'll choose a point in each subinterval to evaluate f(x). Let's choose the midpoint of each subinterval:

  • For [−2,−1]: x1= −1.5
  • For [−1,0]: x2= −0.5
  • For [0,1]: x3= 0.5
  • For [1,2]: x4= 1.5

Now, we'll evaluate f(x)=x3 at each point:

  • f(−1.5) = (−1.5)3 = −3.375
  • f(−0.5) = (−0.5)3 = −0.125
  • f(0.5) = (0.5)3 = 0.125
  • f(1.5) = (1.5)3 = 3.375

Finally, we'll sum up the products of Riemann Integration (Definite Integrals and their Properties) | Mathematics Optional Notes for UPSC and Δx for each subinterval and take the limit as n approaches infinity.

Riemann Integration (Definite Integrals and their Properties) | Mathematics Optional Notes for UPSC[(−3.375)(1)+(−0.125)(1)+(0.125)(1)+(3.375)(1)]
=limn→∞(−3.375−0.125+0.125+3.375)
=limn→∞0 = 0
Therefore, the Riemann integral of f(x) = x3 over the interval [−2,2] is 0.

Example 2: Find Riemann integral of function f(x) = ex over the interval [0, 2].

Sol:
Riemann integral of f(x) over [a,b] is given by:

Riemann Integration (Definite Integrals and their Properties) | Mathematics Optional Notes for UPSCwhere Δx=nb−a is the width of each subinterval, and xi is any point in the ith subinterval.
In this case, a=0, b=2, and f(x)=ex.
First, we need to partition the interval [0,2] into n equal subintervals. Let's choose n=4 for simplicity.

Riemann Integration (Definite Integrals and their Properties) | Mathematics Optional Notes for UPSCSo, the subintervals are [0,0.5], [0.5,1], [1,1.5], and [1.5,2].
Next, we'll choose a point in each subinterval to evaluate f(x). Let's choose the right endpoint of each subinterval:

  • For [0,0.5]: x1 = 0.5
  • For [0.5,1]: x2 = 1
  • For [1,1.5]: x3 = 1.5
  • For [1.5,2]: x4 = 2

Now, we'll evaluate f(x)=ex at each point:

  • f(0.5) = e0.5
  • f(1) = e1
  • f(1.5) = e1.5
  • f(2) = e2

Finally, we'll sum up the products of f(xi) and Δx for each subinterval and take the limit as n approaches infinity.

Riemann Integration (Definite Integrals and their Properties) | Mathematics Optional Notes for UPSC

Thus, Riemann integral of f(x)=ex over the interval [0,2] is approximately e0.5+e1+e1.5+e2.

The document Riemann Integration (Definite Integrals and their Properties) | Mathematics Optional Notes for UPSC is a part of the UPSC Course Mathematics Optional Notes for UPSC.
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FAQs on Riemann Integration (Definite Integrals and their Properties) - Mathematics Optional Notes for UPSC

1. What is the Riemann Integral and how is it defined?
Ans. The Riemann Integral is a method of integration that involves partitioning the domain of a function into smaller intervals, calculating the sum of function values at selected points within these intervals, and then taking the limit as the number of intervals increases. Formally, for a function f(x) defined on an interval [a, b], the Riemann Integral is defined as the limit of Riemann sums as the partition gets finer.
2. What are Riemann Sums and how do they relate to the Riemann Integral?
Ans. Riemann Sums are approximations of the area under a curve represented by a function over a specified interval. They are calculated by summing the products of the function values at certain points within each subinterval and the widths of those subintervals. As the number of subintervals increases (and their width decreases), the Riemann Sum approaches the value of the Riemann Integral.
3. What are some key properties of the Riemann Integral?
Ans. Key properties of the Riemann Integral include linearity (the integral of a sum is the sum of the integrals), the ability to integrate constant functions, and the additive property over intervals (the integral over a combined interval equals the sum of the integrals over its subintervals). Additionally, if a function is continuous over a closed interval, it is Riemann integrable on that interval.
4. How does the Riemann Integral differ from the Lebesgue Integral?
Ans. The primary difference between the Riemann Integral and the Lebesgue Integral lies in how they measure the area under a curve. The Riemann Integral partitions the x-axis and sums the areas of rectangles, while the Lebesgue Integral partitions the y-axis and measures the size of the set of points that map to each function value. This allows the Lebesgue Integral to handle more complex functions and convergence issues better than the Riemann Integral.
5. Can you provide an example of calculating a Riemann Integral?
Ans. Consider the function f(x) = x^2 over the interval [0, 1]. To calculate the Riemann Integral, we can partition the interval into n subintervals of equal width Δx = 1/n. The Riemann sum will be Σ (i=1 to n) f(x_i) * Δx, where x_i is a sample point in each subinterval. Taking the limit as n approaches infinity leads to the Riemann Integral of f(x) from 0 to 1, resulting in 1/3, which represents the area under the curve y = x^2 from 0 to 1.
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