Table of contents |
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What is Perimeter and Area? |
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Area of Parallelograms |
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Area of Triangle |
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Circles |
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Circumference of Circle |
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Area and perimeter are two fundamental concepts in geometry that describe the size and shape of a 2D object.
Perimeter
Area
A parallelogram is a two-dimensional geometrical shape whose sides are parallel to each other. It is a type of polygon having four sides (also called quadrilateral), where the pair of parallel sides are equal in length.
To find the area of a parallelogram, you can follow these steps:
Let us understand this with an example:
Example 1: Find the area of the following parallelograms:
Ans:
Base = 8 cm
Height = 3.5 cm
Area of parallelogram = Base × Height
Area of parallelogram = 8 cm x 3.5 cm = 28 cm2
Ans:
Base = 8 cm
Height = 2.5 cm
Area of parallelogram = Base × Height
Area of parallelogram = 8 cm x 2.5 cm = 20 cm2
Example 2: PQRS is a parallelogram. QM is the height from Q to SR and QN is the height from Q to PS. If SR = 12 cm and QM = 7.6 cm. Find:
(a) the area of the parallelogram PQRS
(b) QN, if PS = 8 cm
Ans:
Given: SR=12 cm, QM = 7.6 cm, PS = 8cm
(a) Area of parallelogram = base x height = 12 x 7.6 = 91.2 cm2
(b) Area of parallelogram = base x height
=> 91.2 = 8 x QN
=> QN = 91.2/8
= 11.4 cm.
A triangle is a polygon with three vertices, and three sides or edges that are line segments. A triangle with vertices A, B, and C is denoted as ABC.
Triangle ABC
To find the area of a triangle within a parallelogram, you can follow these steps
1. Identify the Triangle
2. Understand the Relationship
3. Calculate the Area of the Parallelogram
4. Apply the Relationship for the Triangle
Parallelogram ABCD
Area of each triangle = (Area of parallelogram)
= (base × height) (Since area of a parallelogram = base × height)
=(or , in short)
All the congruent triangles are equal in area but the triangles equal in area need not be congruent.
Example 1: Find BC, if the area of the triangle ABC is 36 cm2 and the height AD is 3 cm.
Ans:
Height = 3 cm, Area = 36 cm2
Area of the triangle ABC = 1/2 x b x h
=> 36 = 1/2 x b x 3 => b = 24 cm
Base BC = 24 cm
Ans:
In triangle ABC, AD = 6cm and BC = 9cm
Area of triangle = 1/2 x base x height = 1/2 x AB x CE
=> 27 = 1/2 x 7.5 x CE
=> CE = (27 x 2) /7.5 => CE = 7.2 cm
Height from C to AB ie.., CE is 7.2 cm
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Test: Perimeter and Area
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A circle is defined as a collection of points on a plane that are at an equal distance.
Circle
The distance around a circular region is known as its circumference.
where,
Diameter(d) of a circle is equal to twice the radius(r) =2r
Therefore, Circumference = Diameter x π
C = π d
Note: Circles with the same centre but different radii are called concentric circles.
Example: If the radius of the circle is 25 units, find the circumference of the circle. (Take π = 3.14)
Ans:
Given, radius = 25 units
Let us write the circumference formula and then we will substitute the value of r (radius) in it.
Circumference of circle formula = 2πr
C = 2 × π × 25
C = 2 × 3.14 × 25 = 157 units
Therefore, the circumference of a circle is 157 units.
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Chapter Notes - Perimeter and Area
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The area of a circle is the region enclosed in the circle.
where
Example 1: The radius of a circular pipe is 10 cm. What length of a tape is required to wrap once around the pipe (π = 3.14)?
Ans:
Radius of the pipe (r) = 10 cm
Length of tape required is equal to the circumference of the pipe. Circumference of the pipe = 2πr = 2 × 3.14 × 10 cm = 62.8 cm
Therefore, length of the tape needed to wrap once around the pipe is 62.8 cm.
Example 2: Find the perimeter of the given shape (Take π = 22/7 ).
Ans: In this shape, we need to find the circumference of semicircles on each side of the square.Circumference of the circle = πd
Circumference of the semicircle = 1/2 πd = 1/2 x 22/7 × 14 cm = 22 cm Circumference of each of the semicircles is 22 cm .Therefore, the perimeter of the given figure = 4 × 22 cm = 88 cm.
Example 3: Diameter of a circular garden is 9.8 m. Find its area.
Ans:
Diameter, d = 9.8 m
Therefore, radius r = 9.8 ÷ 2 = 4.9 m
Area of the circle = πr2 = 22/7 x (4.9)2 m2 = 22/7 × 4.9 x 4.9 m2= 75.46 m2
Example 4:The adjoining figure shows two circles with the same centre. The radius of the larger circle is 10 cm and the radius of the smaller circle is 4 cm. Find:
(a) the area of the larger circle
(b) the area of the smaller circle
(c) the shaded area between the two circles. (π = 3.14)
Ans:
(a) Radius of the larger circle = 10 cm So, area of the larger circle = πr2 = 3.14 × 10 × 10 = 314 cm2
(b) Radius of the smaller circle = 4 cm Area of the smaller circle = πr2 = 3.14 × 4 × 4 = 50.24 cm2
(c) Area of the shaded region = (314 – 50.24) cm2 = 263.76 cm2
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