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Rotational Motion & Moment of Inertia - Physics for JEE Main & Advanced

Rotational Motion

1. Rigid Body

Rigid body is a system of particles in which the distance between each pair of particles remains constant in time. In a rigid body the shape and size do not change during motion. Examples: fan, pen, table, stone.

Objects that deform (for example, two blocks joined by a spring, or a body that stretches) are not rigid bodies. For every pair of particles in a rigid body there is no relative approach or separation between them.

Consider two points A and B on a rigid body. In the figure shown the velocities of A and B with respect to the ground are

1. Rigid Body
1. Rigid Body
1. Rigid Body
1. Rigid Body

If the body is rigid, the components of velocities along the line joining the two points satisfy the geometric constraint

VA cos θ1 = VB cos θ2

Note : With respect to any given particle of a rigid body, the motion of any other particle of that rigid body is circular about that particle (instantaneously), since the distance between them is fixed.

VBA denotes the relative velocity of B with respect to A.

1. Rigid Body

1.1 Pure Translational Motion

A body is said to be in pure translational motion when every particle in the body undergoes the same displacement in a given time interval. In pure translation all particles have the same velocity and the same acceleration at any instant.

1.1 Pure Translational Motion

Example. A box pushed on a horizontal surface translates (if it does not rotate).

1.1 Pure Translational Motion
1.1 Pure Translational Motion
1.1 Pure Translational Motion
1.1 Pure Translational Motion

For a rigid body composed of many particles (m1, m2, m3, ...), each particle has the same acceleration in pure translation. If the accelerations are a1, a2, a3, ... then

1.1 Pure Translational Motion
1.1 Pure Translational Motion

But accelerations of all particles are equal, so

1.1 Pure Translational Motion

Therefore,

1.1 Pure Translational Motion

Where M is the total mass of the body and a is the acceleration of any particle or of the centre of mass of the body.

1.1 Pure Translational Motion

Similarly for velocities: if velocities of particles are v1, v2, v3, ... and all are equal in pure translation,

1.1 Pure Translational Motion

Therefore the velocity of the centre of mass equals the common velocity of all particles.

1.1 Pure Translational Motion

The total kinetic energy of the body in pure translation is

1.1 Pure Translational Motion

1.2 Pure Rotational Motion

A body is said to be in pure rotational motion when every particle moves on a circular path about a fixed line (axis) and the perpendicular distance of each particle from the axis remains constant. Particles do not translate parallel to the axis. In pure rotation all particles have the same angular velocity and the same angular acceleration at an instant. Examples: rotating ceiling fan, hands of a clock.

1.2 Pure Rotational Motion

In rigid-body pure rotation about a fixed axis, each particle describes a circle whose centre lies on the axis of rotation. If the angular displacement of the body is θ (in radians), the arc length s travelled by a particle at a perpendicular distance r from the axis is

s = r θ

The relation between linear and angular quantities is therefore

v = ω r

atan = α r

arad = ω² r

2. Kinematics of Rotational Motion

Angular displacement: θ (radian)

Angular velocity: ω = dθ/dt

Angular acceleration: α = dω/dt = d²θ/dt²

For constant angular acceleration, the kinematic equations (analogous to linear motion) are

  • ω = ω₀ + α t
  • θ = θ₀ + ω₀ t + ½ α t²
  • ω² = ω₀² + 2 α (θ - θ₀)

Velocity of a particle at position vector r (measured from axis) in rigid body rotation is given by the vector relation

v = ω × r

Here ω is the angular velocity vector directed along the axis of rotation (right-hand rule). The magnitude of v is ω r sin φ where φ is the angle between ω and r; for planar rotation with r perpendicular to ω, |v| = ω r.

3. Dynamics of Rotational Motion

Torque (moment of a force): For a force F acting at position r (measured from chosen origin), the torque about that origin is

τ = r × F

The magnitude of torque about an axis is τ = r F sin θ, where θ is angle between r and F. Torque tends to produce rotational acceleration.

Rotational analogue of Newton's second law: For a rigid body rotating about a fixed axis, the net external torque about the axis equals the rotational inertia times angular acceleration:

∑τ = I α

Here I is the moment of inertia about the axis of rotation (see next section).

Work done by torque: If a torque τ acts and body rotates through angle dθ, the infinitesimal work is

dW = τ dθ

Rotational kinetic energy: For a rigid body rotating about a fixed axis with angular speed ω, the total kinetic energy is

K = ½ I ω²

Power supplied by torque is

P = τ ω

4. Moment of Inertia (Rotational Inertia)

Definition: The moment of inertia of a rigid body about a given axis is

I = ∫ r² dm

where r is the perpendicular distance of the mass element dm from the axis. The SI unit of moment of inertia is kg·m².

Properties:

  • Moment of inertia depends on the mass distribution and the axis chosen.
  • Moments of inertia add for composite bodies: the total I is the sum of I of constituent pieces about the same axis.

Parallel axis theorem (Steiner's theorem): If ICM is the moment of inertia of a body about an axis through its centre of mass (parallel to the required axis), then the moment of inertia about an axis parallel to it and at distance d from it is

I = ICM + M d²

Perpendicular axis theorem (for planar lamina): For a planar object lying in the xy-plane, moments about x and y axes and about z (perpendicular) axis through the same point satisfy

Iz = Ix + Iy

This holds only for thin flat bodies (lamina) whose thickness is negligible.

5. Common Moments of Inertia

Useful results for standard rigid bodies (mass = m):

  • Thin circular ring (radius R) about central axis: I = m R²
  • Thin circular disc or solid cylinder (about central axis): I = ½ m R²
  • Solid sphere (about diameter): I = 2/5 m R²
  • Thin spherical shell (hollow sphere): I = 2/3 m R²
  • Thin rod (length L) about central axis perpendicular to rod and through centre: I = 1/12 m L²
  • Thin rod about an axis perpendicular to rod through one end: I = 1/3 m L²
  • Rectangular lamina about axis through centre and perpendicular to plane (sides a and b): I = 1/12 m (a² + b²)

These formulae can be derived by integration or obtained by applying the parallel axis theorem to known results.

6. Derivation examples (stepwise presentation)

Example: Moment of inertia of a thin uniform rod (length L, mass m) about an axis through the centre and perpendicular to the rod.

Consider the rod along the x-axis from -L/2 to +L/2. Take an element of length dx at position x with mass dm = (m/L) dx.

Distance of the element from the axis is |x| so its contribution to I is dI = x² dm.

I = ∫ dI = ∫_{-L/2}^{L/2} x² (m/L) dx.

Integrate: I = (m/L) [ (x³/3) ]_{-L/2}^{L/2} = (m/L) [ (L³/24) + (L³/24) ] = (m/L) (L³/12) = 1/12 m L².

Example: Using Parallel Axis Theorem - rod about one end.

Moment of inertia about centre is ICM = 1/12 m L².

Distance from centre to end is d = L/2.

Using parallel axis theorem: I = ICM + m d² = 1/12 m L² + m (L/2)² = 1/12 m L² + 1/4 m L² = 1/3 m L².

7. Angular Momentum and Conservation

Angular momentum (of a rigid body about a fixed axis): L = I ω.

For a particle, angular momentum about an origin is l = r × p, and for a system of particles the total is sum over particles. If net external torque about the axis is zero, angular momentum is conserved:

∑τext = dL/dt

Conservation of angular momentum explains phenomena such as the increase in spin rate when a skater pulls in her arms (I decreases, ω increases so that I ω is constant in absence of external torque).

8. Rolling without slipping

A body of radius R rolling without slipping on a surface satisfies the kinematic relation between the velocity of its centre of mass v and its angular speed ω:

v = ω R

The total kinetic energy of a rolling rigid body is the sum of translational kinetic energy of the centre of mass and rotational kinetic energy about the centre of mass:

K = ½ M v² + ½ ICM ω²

Using v = ω R, for a solid cylinder (ICM = ½ M R²) the fraction of energy in translation is greater than in rotation; the acceleration of a rolling object down an incline can be obtained by applying energy or torque methods.

9. Equation of Motion for a Rotating Rigid Body (about fixed axis)

For rotation about a fixed axis, sum of torques equals rotational inertia times angular acceleration:

∑τ = I α

Apply this to problems involving pulleys, discs, or cylinders subject to tensions, frictional torques, or applied moments to find angular acceleration and subsequent motion.

10. Physical (Compound) Pendulum

A physical pendulum is any rigid body oscillating about a horizontal axis under gravity. If the centre of mass is at distance d from the pivot and the moment of inertia about the pivot is I, for small angular displacement θ the restoring torque is -M g d sin θ ≈ -M g d θ, giving

I α = -M g d θ

Hence the angular frequency of small oscillations is

ω = √(M g d / I)

And the period is

T = 2 π √(I / M g d)

11. Solving Typical Problems - Strategy

When faced with rotational motion problems, follow these steps:

  • Identify the axis of rotation and whether it is fixed or moving.
  • Write down geometry: distances r of mass elements or points of application of forces.
  • Compute or use known value of moment of inertia about the axis; use parallel axis theorem if needed.
  • Apply Newton's second law for rotation: ∑τ = I α, and/or energy methods: work-energy relations.
  • Check limiting cases (e.g., no slipping v = ω R) and units for consistency.

12. Applications and Examples

  • Design of flywheels: large moment of inertia stores rotational energy stabilising machines.
  • Rotating shafts and rotors: calculate critical speeds using moment of inertia and torque.
  • Analysis of rolling vehicles: combines translation and rotation to determine acceleration and braking distances.
  • Seismic and civil engineering: rotating components and dynamic balancing use moment of inertia concepts to reduce vibrations.

13. Summary

Rotational motion of rigid bodies is described by angular kinematics (θ, ω, α), rotational dynamics (torque τ and ∑τ = I α), and energy (K = ½ I ω²). The moment of inertia I is the rotational analogue of mass and depends on mass distribution relative to the axis. Useful theorems are the parallel-axis theorem and perpendicular-axis theorem. Combining translation and rotation is required for rolling motion and for many engineering applications.

The document Rotational Motion & Moment of Inertia - Physics for JEE Main & Advanced is a part of the JEE Course Physics for JEE Main & Advanced.
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FAQs on Rotational Motion & Moment of Inertia - Physics for JEE Main & Advanced

1. What is rotational motion and how does it differ from linear motion?
Ans. Rotational motion refers to the movement of an object around an axis, while linear motion is the movement of an object along a straight line. In rotational motion, the object moves in a circular or curved path, while in linear motion, it moves in a straight path.
2. What is moment of inertia and how is it calculated?
Ans. Moment of inertia is a measure of an object's resistance to changes in its rotational motion. It depends on the mass distribution of the object and the axis of rotation. The moment of inertia of an object can be calculated by summing the products of each particle's mass and its squared distance from the axis of rotation.
3. How does the distribution of mass affect the moment of inertia?
Ans. The distribution of mass affects the moment of inertia by determining how the mass is spread out around the axis of rotation. Objects with more mass concentrated farther from the axis of rotation have a larger moment of inertia, while objects with more mass concentrated closer to the axis have a smaller moment of inertia.
4. What is the relationship between moment of inertia and rotational motion?
Ans. The moment of inertia plays a crucial role in determining an object's rotational motion. According to Newton's second law of rotational motion, the torque acting on an object is equal to the moment of inertia multiplied by the angular acceleration. Therefore, the moment of inertia affects how quickly or slowly an object rotates when a torque is applied.
5. How does the moment of inertia affect an object's stability?
Ans. The moment of inertia affects an object's stability by determining its resistance to changes in its rotational motion. Objects with larger moments of inertia are generally more stable since they require a larger external torque to change their rotational state. On the other hand, objects with smaller moments of inertia are less stable and can be easily rotated with less applied torque.
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