Definition: Voltage regulation of a transformer is the rise in secondary terminal voltage expressed as a fraction of the full-load rated secondary voltage when the full load (at a specified power factor) is removed while the primary (input) voltage is kept constant.
Fractional form: Vreg = (Vno-load - Vfull-load)/Vfull-load
Percentage form: % Voltage regulation = Vreg × 100
When referred to the primary or when using per-unit notation the relationships between referred voltages may be written. For an ideal transformation relation between referred secondary and primary voltages one often writes:
V′2 = a V2
Approximate expressions for voltage regulation of a transformer are obtained by representing the transformer's series impedance by its equivalent resistance req and reactance xeq and using phasor algebra. These approximate formulae are useful for quick calculations and give insight into the influence of load power factor on regulation.
To find voltage regulation for a leading power factor, replace ø by -ø in the formulae derived for lagging power factor.
Maximum regulation occurs when the derivative of the regulation expression with respect to load power-factor angle is zero. This leads to a condition involving tan ø, the equivalent impedance angle θeq and the resistive/reactive parts.
Maximum voltage regulation occurs at a lagging power factor when tan ø is positive.
Note: Here tan ø is positive; therefore maximum voltage regulation occurs at a lagging load power factor.
Power factor corresponding to the equivalent impedance is given by:
p.f. = req/Zeq
There exists a particular load power factor (leading) for which the phasor drop due to series reactance cancels the drop due to series resistance and the secondary no-load and full-load voltages become equal (zero regulation). The algebraic form of this condition can be written in several equivalent ways depending on which variables are used.
Equivalently, zero regulation occurs when the load power factor angle satisfies:
ø = (90° - θeq) leading
Negative values of tan ø indicate a leading power factor; therefore zero voltage regulation occurs when the load is sufficiently leading that the reactive voltage drop balances the resistive drop.
Remember:
Losses in a transformer are of two main kinds: core (iron) losses and copper (ohmic) losses. These determine the efficiency and heating of the machine.
Core loss Pc is independent of load current and is usually taken as constant for a given supply voltage and frequency. Core loss comprises two parts:
The usual empirical expressions are:
Ph = Kh · f · Bmx
Pe = Ke · f2 · Bm2
Where:
Therefore total core loss is:
Pc = Ph + Pe
Core losses can also be expressed in terms of applied voltage and frequency; the appropriate expression for a given design is often found experimentally or from manufacturer data.
Ohmic loss (copper loss) occurs in both primary and secondary windings and varies with load current. The combined copper loss referred to a common side is given by:
Pcu = I2 req
where req is the equivalent resistance (primary and secondary referred to a common side) and I is the load current referred to the same side.
Note: Iron (core) loss Pi is also called constant loss because it does not depend on load current. Copper loss Pcu (I2 req) is called variable loss because it depends on the square of the load current.
Definition: Efficiency η of a transformer is the ratio of output power to input power.
η = Output power / Input power
Expressed with losses:
η = Pout / (Pout + Pc + Pcu)
Maximum efficiency occurs when the variable losses equal the constant losses.
Pi = Pcu
i.e. Iron (core) loss = Copper (ohmic) loss.
At a given load current the copper loss is proportional to I2, so the current at which maximum efficiency occurs can be obtained from:
The kVA at maximum efficiency can be calculated from known values at a reference load. If S(known load) is the kVA at a known load and Pcu(known load) the copper loss at that known load, then kVA at maximum efficiency may be obtained from the relation:
Where S(known load) = kVA at known load and Pcu(known load) = copper loss at known load.
Definition: An autotransformer is a transformer in which part of the winding is common to both the primary (high-voltage side) and the secondary (low-voltage side). It is a one-winding transformer and is not electrically isolated between primary and secondary.
Let the number of turns on the primary section AC be N1 and the number of turns on the secondary BC be N2. If an applied voltage V1 is placed across AC, the voltage across BC is given by the turn ratio relation:
For an ideal autotransformer, neglecting losses, input power equals output power (real power):
V1 I1 cos θ1 = V2 I2 cos θ2
If the load power factors on primary and secondary are the same (cos θ1 = cos θ2), then:
V1 I1 = V2 I2
Where a denotes the transformation (turn) ratio.
Copper saving in autotransformer:
Cu(auto) = Cu(2wdg) -
Percentage copper saving:
% Cu saving = (1 - 1/a) × 100
Note:
Parallel operation of single-phase transformers is used to increase capacity, improve reliability, and allow maintenance of individual units without interrupting supply (partially).
For satisfactory parallel operation of two or more single-phase transformers the following conditions must be satisfied.
This ensures that the transformers share active power and reactive volt-amperes proportional to their ratings and operate at the same power factor.
Where EA and EB are the no-load secondary voltages of transformers A and B respectively. The equivalent phasor and circuit relations can be used to find circulating currents and load sharing.
or
Similarly,
For proportional load sharing it is required that
or ZA(pu) = ZB(pu)
where the per-unit values are on their respective own base.
If the leakage impedance angles differ (θA ≠ θB) and both transformers supply the same apparent power S but with different impedance angles, the algebraic summation leads to resultant load SL. For the case θA > θB and equal apparent power S, the resultant load is given by the vector sum relations:
Then
If the transformers have unequal voltage ratios, an unbalanced voltage will cause circulating currents and imbalance in load sharing. The following method is used to calculate load kVA with unequal ratios.
Steps:
where
and
When three identical single-phase transformers are connected together, the arrangement is called a bank of three transformers or a three-phase transformer bank. Three-phase currents in the primaries produce three fluxes displaced by 120° in time. These fluxes pass through the yokes and central limbs; the net flux in the three central limbs taken together must be zero in a balanced system.
Three-phase core-type transformer from three single-phase units: When three single-phase core stacks are placed together the reluctance paths differ for the central limb and outer limbs. The central limb sees a different flux path reluctance so the exciting current of the winding on the central limb is generally less than those on the outer limbs.
A three-phase shell-type transformer is obtained by placing three single-phase shell cores side-by-side with windings on the limbs.
Three-phase shell type transformer with three windings wound in the same direction: In the magnetic circuits marked 2 and 3 the resultant flux is the phasor difference of component fluxes.
For the same flux density the cross-sectional areas at locations 2 and 3 are approximately 86% of the central core area for the shown construction.
Successful parallel operation of three-phase transformers requires fulfilling several conditions analogous to the single-phase case plus additional requirements related to phase displacement.
In addition:
Relative phase displacement: The relative phase displacement between the secondary line voltages of the transformers must be zero. In practice this means the transformers to be connected in parallel must belong to the same vector group (same group number).
Note:
| 1. What is the basic principle behind the operation of transformers? | ![]() |
| 2. How does the turns ratio affect the transformer's voltage and current? | ![]() |
| 3. What are the advantages of using transformers in electrical power transmission? | ![]() |
| 4. Can transformers be used to convert DC (direct current) to AC (alternating current)? | ![]() |
| 5. How can the efficiency of a transformer be improved? | ![]() |
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