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Sudhir PatelEduRev Computer Science Engineering (CSE) |
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Sudhir Patel
EduRev Computer Science Engineering (CSE)
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Discussed Questions
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Dhruba Goyal upvoted • Feb 20, 2025 |
What will be output of the following c code? ( according to GCC compiler)#include<stdio.h>
int main()
{
signed x;
unsigned y;
x = 10 +- 10u + 10u +- 10;
y = x;
if(x==y) printf("%d %d",x,y);
else if(x!=y) printf("%u %u",x,y);
return 0;
}- a)0 0
- b)65536 -10
- c)0 65536
- d)Compilation error
Correct answer is option 'A'. Can you explain this answer?
What will be output of the following c code? ( according to GCC compiler)
#include<stdio.h>
int main()
{
signed x;
unsigned y;
x = 10 +- 10u + 10u +- 10;
y = x;
if(x==y) printf("%d %d",x,y);
else if(x!=y) printf("%u %u",x,y);
return 0;
}
int main()
{
signed x;
unsigned y;
x = 10 +- 10u + 10u +- 10;
y = x;
if(x==y) printf("%d %d",x,y);
else if(x!=y) printf("%u %u",x,y);
return 0;
}
a)
0 0
b)
65536 -10
c)
0 65536
d)
Compilation error
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Arka Shah answered |
Explanation: Consider on the expression:
x = 10 +- 10u + 10u +- 10;
10: It is signed integer constant.
10u: It is unsigned integer constant.
X: It is signed integer variable.
As we know operators enjoy higher precedence than binary operators. So
x = 10 + (-10u) + 10u + (-10);
= 10 + -10 + 10 + (-10);
= 0
So, Corresponding signed value of unsigned 10u is +10.
x = 10 +- 10u + 10u +- 10;
10: It is signed integer constant.
10u: It is unsigned integer constant.
X: It is signed integer variable.
As we know operators enjoy higher precedence than binary operators. So
x = 10 + (-10u) + 10u + (-10);
= 10 + -10 + 10 + (-10);
= 0
So, Corresponding signed value of unsigned 10u is +10.
The commands, from client to server, and replies, from server to client, are sent across the control connection in ________ bit ASCII format- a)8
- b)7
- c)3
- d)5
Correct answer is option 'B'. Can you explain this answer?
The commands, from client to server, and replies, from server to client, are sent across the control connection in ________ bit ASCII format
a)
8
b)
7
c)
3
d)
5
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Dhruba Goyal answered • Jan 28, 2025 |
Understanding ASCII Format
ASCII (American Standard Code for Information Interchange) is a character encoding scheme used for text representation in computers and communication devices. It assigns a unique numeric value to each character.
Why 7-bit ASCII?
- ASCII originally uses a 7-bit binary number to represent characters, allowing for 128 unique symbols, which inclu... more
ASCII (American Standard Code for Information Interchange) is a character encoding scheme used for text representation in computers and communication devices. It assigns a unique numeric value to each character.
Why 7-bit ASCII?
- ASCII originally uses a 7-bit binary number to represent characters, allowing for 128 unique symbols, which inclu... more
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Dhruba Goyal upvoted • Jan 18, 2025 |
Consider the following code which is used to detect the loop in the linked list. Find the missing statement A?p = head;q = head->next;while(A){ if(p == q) exit(0) //loop detected p = p->next; q = (q->next)?(q->next->next) : q->next;}- a)(p!=NULL) || (q!=NULL)
- b)p!=NULL
- c)q!=NULL
- d)(p!=NULL) && (q!=NULL)
Correct answer is option 'C'. Can you explain this answer?
Consider the following code which is used to detect the loop in the linked list. Find the missing statement A?
p = head;
q = head->next;
while(A)
{
if(p == q) exit(0) //loop detected
p = p->next;
q = (q->next)?(q->next->next) : q->next;
}
a)
(p!=NULL) || (q!=NULL)
b)
p!=NULL
c)
q!=NULL
d)
(p!=NULL) && (q!=NULL)
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Ankita Bose answered |
q will go end of list first and will accept
q==NULL and will terminate.
Otherwise p and q both get a valid pointer value and keep moving.
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Dhruba Goyal upvoted • Jan 04, 2025 |
A processor uses 2-level page tables for virtual to physical address translation. Page tables for both levels are stored in the main memory. Virtual and physical addresses are both 32 bits wide. The memory is byte addressable. For virtual to physical address translation, the 10 most significant bits of the virtual address are used as index into the first level page table while the next 10 bits are used as index into the second level page table. The 12 least significant bits of the virtual address are used as offset within the page. Assume that the page table entries in both levels of page tables are 4 bytes wide. Further, the processor has a translation look-aside buffer (TLB), with a hit rate of 96%. The TLB caches recently used virtual page numbers and the corresponding physical page numbers. The processor also has a physically addressed cache with a hit rate of 90%. Main memory access time is 10 ns, cache access time is 1 ns, and TLB access time is also 1 ns. Assuming that no page faults occur, the average time taken to access a virtual address is approximately (to the nearest 0.5 ns)... more
A processor uses 2-level page tables for virtual to physical address translation. Page tables for both levels are stored in the main memory. Virtual and physical addresses are both 32 bits wide. The memory is byte addressable. For virtual to physical address translation, the 10 most significant bits of the virtual address are used as index into the first level page table while the next 10 bits are used as index into the second level page table. The 12 least significant bits of the virtual address are used as offset within the page. Assume that the page table entries in both levels of page tables are 4 bytes wide. Further, the processor has a translation look-aside buffer (TLB), with a hit rate of 96%. The TLB caches recently used virtual page numbers and the corresponding physical page numbers. The processor also has a physically addressed cache with a hit rate of 90%. Main memory access time is 10 ns, cache access time is 1 ns, and TLB access time is also 1 ns. Assuming that no page faults occur, the average time taken to access a virtual address is approximately (to the nearest 0.5 ns)
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Cstoppers Instructors answered |
The possibilities are
TLB Hit*Cache Hit +
TLB Hit*Cache Miss +
TLB Miss*Cache Hit +
TLB Miss*Cache Miss
= 0.96*0.9*2 + 0.96*0.1*12 + 0.04*0.9*22 + 0,04*0.1*32
= 3.8
≈ 4
Why 22 and 32? 22 is because when TLB miss occurs it takes 1ns and the for the physical address it has to go through two level page tables which are in main memory and takes 2 memory access and the that page is found in cache taking 1 ns which gives a total of 22
TLB Hit*Cache Hit +
TLB Hit*Cache Miss +
TLB Miss*Cache Hit +
TLB Miss*Cache Miss
= 0.96*0.9*2 + 0.96*0.1*12 + 0.04*0.9*22 + 0,04*0.1*32
= 3.8
≈ 4
Why 22 and 32? 22 is because when TLB miss occurs it takes 1ns and the for the physical address it has to go through two level page tables which are in main memory and takes 2 memory access and the that page is found in cache taking 1 ns which gives a total of 22
If the property of locality of reference is well pronounced a program:
1. The number of page faults will be more.
2. The number of page faults will be less.
3. The number of page faults will remain the same.
4. Execution will be faster.- a)1 and 2
- b)2 and 4
- c)3 and 4
- d)None of the above
Correct answer is option 'B'. Can you explain this answer?
If the property of locality of reference is well pronounced a program:
1. The number of page faults will be more.
2. The number of page faults will be less.
3. The number of page faults will remain the same.
4. Execution will be faster.
1. The number of page faults will be more.
2. The number of page faults will be less.
3. The number of page faults will remain the same.
4. Execution will be faster.
a)
1 and 2
b)
2 and 4
c)
3 and 4
d)
None of the above
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Dhruba Goyal answered • Nov 25, 2024 |
Understanding Locality of Reference
Locality of reference is a principle that describes the tendency of a program to access a relatively small portion of its address space at any given time. This behavior can significantly influence the performance of programs, particularly in the context of virtual memory systems.
Effects on Page Faults
- Locality of reference leads t... more
Locality of reference is a principle that describes the tendency of a program to access a relatively small portion of its address space at any given time. This behavior can significantly influence the performance of programs, particularly in the context of virtual memory systems.
Effects on Page Faults
- Locality of reference leads t... more
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Dhruba Goyal upvoted • Oct 26, 2024 |
DIRECTIONS for question:
Four sentences related to a topic are given below. Three of them can be put together to form a meaningful and coherent short paragraph. Identify the odd one out. Choose its number as your answer .
1. A friend who stumbled upon my Twitter account told me that my tweets made me sound like an unrecognisable jerk. “You’re much nicer than this in real life,” she said.
2. The internet and social media change personalities of people.
3. But as face-to-face conversation becomes rarer it’s time to stop thinking that it is authentic and social media are artificial.
4. This is a common refrain about social media: that they make people behave worse than they do in “real life”.- a)1
- b)2
- c)3
- d)4
Correct answer is option 'B'. Can you explain this answer?
DIRECTIONS for question:
Four sentences related to a topic are given below. Three of them can be put together to form a meaningful and coherent short paragraph. Identify the odd one out. Choose its number as your answer .
1. A friend who stumbled upon my Twitter account told me that my tweets made me sound like an unrecognisable jerk. “You’re much nicer than this in real life,” she said.
2. The internet and social media change personalities of people.
3. But as face-to-face conversation becomes rarer it’s time to stop thinking that it is authentic and social media are artificial.
4. This is a common refrain about social media: that they make people behave worse than they do in “real life”.
Four sentences related to a topic are given below. Three of them can be put together to form a meaningful and coherent short paragraph. Identify the odd one out. Choose its number as your answer .
1. A friend who stumbled upon my Twitter account told me that my tweets made me sound like an unrecognisable jerk. “You’re much nicer than this in real life,” she said.
2. The internet and social media change personalities of people.
3. But as face-to-face conversation becomes rarer it’s time to stop thinking that it is authentic and social media are artificial.
4. This is a common refrain about social media: that they make people behave worse than they do in “real life”.
a)
1
b)
2
c)
3
d)
4
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Gate Gurus answered |
Statements 1 & 4 are mandatory pair, as they express the author's own encounter with his friend (“This’ in statement 4, refers to the comment made in Statement 1). Statement 3, brings-in author’s opinion to counter the common refrain that people think that behaviour portrayed on social media is not “real”.
Statement 2, is altogether different as personalities do not change instead social sites help people to express themselves.
Statement 2, is altogether different as personalities do not change instead social sites help people to express themselves.
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Dhruba Goyal upvoted • Oct 03, 2024 |
Given a directed graph where weight of every edge is same, we can efficiently find shortest path from a given source to destination using?- a)Breadth First Traversal
- b)Dijkstra's Shortest Path Algorithm
- c)Neither Breadth First Traversal nor Dijkstra's algorithm can be used
- d)Depth First Search
Correct answer is option 'A'. Can you explain this answer?
Given a directed graph where weight of every edge is same, we can efficiently find shortest path from a given source to destination using?
a)
Breadth First Traversal
b)
Dijkstra's Shortest Path Algorithm
c)
Neither Breadth First Traversal nor Dijkstra's algorithm can be used
d)
Depth First Search
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Sanya Agarwal answered |
With BFS, we first find explore vertices at one edge distance, then all vertices at 2 edge distance, and so on.
Header size of the ICMP message is _________- a)8-bytes
- b)8-bits
- c)16-bytes
- d)16-bits
Correct answer is option 'A'. Can you explain this answer?
Header size of the ICMP message is _________
a)
8-bytes
b)
8-bits
c)
16-bytes
d)
16-bits
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Dhruba Goyal answered • Dec 22, 2023 |
Header size of the ICMP message is 8-bytes
ICMP (Internet Control Message Protocol) is a network protocol used for error reporting, diagnostic, and informational purposes in IP networks. It is primarily used by network devices to communicate error messages, such as unreachable hosts or network congestion, back to the source IP address.
The ICMP message consists of two ... more
ICMP (Internet Control Message Protocol) is a network protocol used for error reporting, diagnostic, and informational purposes in IP networks. It is primarily used by network devices to communicate error messages, such as unreachable hosts or network congestion, back to the source IP address.
The ICMP message consists of two ... more
Which of the following is a transport layer protocol?- a)stream control transmission protocol
- b)internet control message protocol
- c)neighbor discovery protocol
- d)dynamic host configuration protocol
Correct answer is option 'A'. Can you explain this answer?
Which of the following is a transport layer protocol?
a)
stream control transmission protocol
b)
internet control message protocol
c)
neighbor discovery protocol
d)
dynamic host configuration protocol
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Dhruba Goyal answered • Dec 22, 2023 |
Transport Layer Protocol:
A transport layer protocol is responsible for the end-to-end communication between two hosts in a network. It ensures reliable and efficient delivery of data packets from the source to the destination. One of the widely used transport layer protocols is the Stream Control Transmission Protocol (SCTP).
Explanation:
In the given options, t... more
A transport layer protocol is responsible for the end-to-end communication between two hosts in a network. It ensures reliable and efficient delivery of data packets from the source to the destination. One of the widely used transport layer protocols is the Stream Control Transmission Protocol (SCTP).
Explanation:
In the given options, t... more
Consider the schedule s1:r1(x),r2(x),R2(y),w2(y),r1(y),W1(x) determine serilazibility?
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Dhruba Goyal answered • Dec 22, 2023 |
Schedule: s1:r1(x),r2(x),R2(y),w2(y),r1(y),W1(x)
Step 1: Construct a precedence graph:
- The nodes in the graph represent the transactions.
- Draw an edge from transaction Ti to Tj if there exists a conflict between Ti and Tj, where a conflict occurs when both Ti and Tj access the same data item, and at least one of them is a write operation.
r1(x)
/ \
/ \
/ \
r2(x) R2(y)
| |
| |
| |
| w2(y)
\ /
\ /
\ /
\ /
r1(y)
|
W1(x)
... more
Step 1: Construct a precedence graph:
- The nodes in the graph represent the transactions.
- Draw an edge from transaction Ti to Tj if there exists a conflict between Ti and Tj, where a conflict occurs when both Ti and Tj access the same data item, and at least one of them is a write operation.
r1(x)
/ \
/ \
/ \
r2(x) R2(y)
| |
| |
| |
| w2(y)
\ /
\ /
\ /
\ /
r1(y)
|
W1(x)
The minimum number of cards to be dealt from an arbitrarily shuffled deck of 52 cards to guarantee that three cards are from same suit is- a)3
- b)8
- c)9
- d)12
Correct answer is option 'C'. Can you explain this answer?
The minimum number of cards to be dealt from an arbitrarily shuffled deck of 52 cards to guarantee that three cards are from same suit is
a)
3
b)
8
c)
9
d)
12
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Dhruba Goyal answered • Dec 22, 2023 |
The minimum number of cards to be dealt from an arbitrarily shuffled deck of 52 cards to guarantee that three cards are from the same suit is 9.
To explain why the correct answer is option 'C', let's consider the worst-case scenario where we want to minimize the number of cards dealt while guaranteeing that three cards are from the same suit.
To achieve this, we need to dea... more
To explain why the correct answer is option 'C', let's consider the worst-case scenario where we want to minimize the number of cards dealt while guaranteeing that three cards are from the same suit.
To achieve this, we need to dea... more
In Go-Back-N window, when the timer of the packet times out, several packets have to be resent even some may have arrived safe. Whereas in Selective Repeat window, the sender resends ___________- a)Packet which are not lost
- b)Only those packets which are lost or corrupted
- c)Packet from starting
- d)All the packets
Correct answer is option 'B'. Can you explain this answer?
In Go-Back-N window, when the timer of the packet times out, several packets have to be resent even some may have arrived safe. Whereas in Selective Repeat window, the sender resends ___________
a)
Packet which are not lost
b)
Only those packets which are lost or corrupted
c)
Packet from starting
d)
All the packets
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Dhruba Goyal answered • Dec 22, 2023 |
Explanation:
In the Go-Back-N (GBN) protocol, when the timer of a packet times out, all the packets from that point onwards in the sender's window need to be retransmitted. This is because the sender does not know which packets have been successfully received by the receiver and which packets have been lost or corrupted. Therefore, it assumes that all the packets in the current w... more
In the Go-Back-N (GBN) protocol, when the timer of a packet times out, all the packets from that point onwards in the sender's window need to be retransmitted. This is because the sender does not know which packets have been successfully received by the receiver and which packets have been lost or corrupted. Therefore, it assumes that all the packets in the current w... more
Recall that Belady’s anomaly is that the page-fault rate may increase as the number of allocated frames increases. Now, consider the following statements:S1: Random page replacement algorithm (where a page chosen at random is replaced)
Suffers from Belady’s anomaly
S2: LRU page replacement algorithm suffers from Belady’s anomalyWhich of the following is CORRECT?- a)S1 is true, S2 is true
- b)S1 is true, S2 is false
- c)S1 is false, S2 is true
- d)S1 is false, S2 is false
Correct answer is option 'B'. Can you explain this answer?
Recall that Belady’s anomaly is that the page-fault rate may increase as the number of allocated frames increases. Now, consider the following statements:
S1: Random page replacement algorithm (where a page chosen at random is replaced)
Suffers from Belady’s anomaly
S2: LRU page replacement algorithm suffers from Belady’s anomaly
Suffers from Belady’s anomaly
S2: LRU page replacement algorithm suffers from Belady’s anomaly
Which of the following is CORRECT?
a)
S1 is true, S2 is true
b)
S1 is true, S2 is false
c)
S1 is false, S2 is true
d)
S1 is false, S2 is false
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Dhruba Goyal answered • Dec 22, 2023 |
Was a computer scientist who proposed the Belady's anomaly in page replacement algorithms. This anomaly states that in certain cases, increasing the number of page frames in a memory can actually increase the number of page faults.
Belady's anomaly challenges the common intuition that increasing the number of page frames should always lead to a decrease in page faults. It occurs in page... more
Belady's anomaly challenges the common intuition that increasing the number of page frames should always lead to a decrease in page faults. It occurs in page... more
Size of TCP segment header ranges between- a)16 and 32 bytes
- b)16 and 32 bits
- c)20 and 60 bytes
- d)20 and 60 bits
Correct answer is option 'C'. Can you explain this answer?
Size of TCP segment header ranges between
a)
16 and 32 bytes
b)
16 and 32 bits
c)
20 and 60 bytes
d)
20 and 60 bits
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Dhruba Goyal answered • Dec 22, 2023 |
The size of a TCP segment header ranges between 20 and 60 bytes.
Explanation:
TCP Protocol:
TCP (Transmission Control Protocol) is a reliable and connection-oriented protocol used for data transmission in computer networks. It provides a reliable stream of data transfer by establishing a connection between the sender and the receiver.
TCP Segm... more
In TCP, data is transmitted in segments. Each TCP segment consists of a header and the data being transmitted. The header contains control information necessary for the proper delivery and sequencing of the data.
Size of TCP Segment Header:
The size of the TCP segment header is variable and can range from 20 to 60 bytes. The actual size depends on various factors such as the presence of optional fields, such as TCP options, and the size of the data being transmitted.
Factors affecting the size of TCP segment header:
1. Minimum Size: The minimum size of the TCP segment header is 20 bytes, which includes the mandatory fields such as source and destination port numbers, sequence number, acknowledgment number, control flags, and checksum.
2. Optional Fields: TCP allows for the inclusion of optional fields, known as TCP options, in the segment header. These options can include additional control information or parameters required for specific purposes. The presence of TCP options increases the size of the segment header.
3. Data Size: The size of the data being transmitted in the TCP segment can also affect the size of the segment header. If the data size is small, the segment header will be larger in proportion to the data. Conversely, if the data size is large, the segment header will be relatively smaller.
Conclusion:
In conclusion, the size of the TCP segment header can range from 20 to 60 bytes, depending on the presence of optional fields (TCP options) and the size of the data being transmitted. The minimum size of the segment header is 20 bytes, while the maximum size is 60 bytes.
Explanation:
TCP Protocol:
TCP (Transmission Control Protocol) is a reliable and connection-oriented protocol used for data transmission in computer networks. It provides a reliable stream of data transfer by establishing a connection between the sender and the receiver.
TCP Segm... more
In TCP, data is transmitted in segments. Each TCP segment consists of a header and the data being transmitted. The header contains control information necessary for the proper delivery and sequencing of the data.
Size of TCP Segment Header:
The size of the TCP segment header is variable and can range from 20 to 60 bytes. The actual size depends on various factors such as the presence of optional fields, such as TCP options, and the size of the data being transmitted.
Factors affecting the size of TCP segment header:
1. Minimum Size: The minimum size of the TCP segment header is 20 bytes, which includes the mandatory fields such as source and destination port numbers, sequence number, acknowledgment number, control flags, and checksum.
2. Optional Fields: TCP allows for the inclusion of optional fields, known as TCP options, in the segment header. These options can include additional control information or parameters required for specific purposes. The presence of TCP options increases the size of the segment header.
3. Data Size: The size of the data being transmitted in the TCP segment can also affect the size of the segment header. If the data size is small, the segment header will be larger in proportion to the data. Conversely, if the data size is large, the segment header will be relatively smaller.
Conclusion:
In conclusion, the size of the TCP segment header can range from 20 to 60 bytes, depending on the presence of optional fields (TCP options) and the size of the data being transmitted. The minimum size of the segment header is 20 bytes, while the maximum size is 60 bytes.
Let R (ABCDEFGH) be a relation schema and F be the set of dependencies F = {A → B, ABCD → E, EF → G, EF → H and ACDF →EG}. The minimal cover of a set of functional dependencies is- a)A → B, ACD → E, EF → G, EF → H and ACDF → G
- b)A → B, ACD → E, EF → G, EF → H and ACDF → E
- c)A → B, ABCD → E, EF → H and EF → G
- d)A → B, ACD → E, EF → G, and EF → H
Correct answer is option 'D'. Can you explain this answer?
Let R (ABCDEFGH) be a relation schema and F be the set of dependencies F = {A → B, ABCD → E, EF → G, EF → H and ACDF →EG}. The minimal cover of a set of functional dependencies is
a)
A → B, ACD → E, EF → G, EF → H and ACDF → G
b)
A → B, ACD → E, EF → G, EF → H and ACDF → E
c)
A → B, ABCD → E, EF → H and EF → G
d)
A → B, ACD → E, EF → G, and EF → H
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Dhruba Goyal answered • Nov 03, 2023 |
-> B, B -> C, C -> D, D -> E, E -> F, F -> G, G -> H}.
The closure of a set of attributes X under the set of functional dependencies F, denoted as X+, is the set of all attributes that are functionally determined by X based on the given functional dependencies.
To find the closure of a set of attributes under a set of functional dependencies, we can use Armstrong's axioms, wh... more
The closure of a set of attributes X under the set of functional dependencies F, denoted as X+, is the set of all attributes that are functionally determined by X based on the given functional dependencies.
To find the closure of a set of attributes under a set of functional dependencies, we can use Armstrong's axioms, wh... more
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Dhruba Goyal asked • Sep 27, 2022 |
Choose the correct verb to fill in the blank below:
Let us ________.- a)Introvert
- b)alternate
- c)atheist
- d)altruist
Correct answer is option 'B'. Can you explain this answer?
Choose the correct verb to fill in the blank below:
Let us ________.
Let us ________.
a)
Introvert
b)
alternate
c)
atheist
d)
altruist
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Akash Rane answered |
Answer:
Explanation:
The correct verb to fill in the blank is "alternate" (option B).
Meaning of the options:
1. Introvert: This is a noun that refers to a person who is predominantly concerned with their own thoughts and feelings, rather than with external things.
2. Alternate: This is a verb that means to take turns or to occur in turns ... more
Explanation:
The correct verb to fill in the blank is "alternate" (option B).
Meaning of the options:
1. Introvert: This is a noun that refers to a person who is predominantly concerned with their own thoughts and feelings, rather than with external things.
2. Alternate: This is a verb that means to take turns or to occur in turns ... more
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Dhruba Goyal asked • Jun 30, 2021 |
A CPU scheduling algorithm determines an order for the execution of its scheduled processes. Given 'n' processes to be scheduled on one processor, how many possible different schedules are there?- a)n
- b)n2
- c)n!
- d)2n
Correct answer is option 'C'. Can you explain this answer?
A CPU scheduling algorithm determines an order for the execution of its scheduled processes. Given 'n' processes to be scheduled on one processor, how many possible different schedules are there?
a)
n
b)
n2
c)
n!
d)
2n
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Yash Patel answered |
For 'n' processes to be scheduled on one processor, there can be n! different schedules possible. Example: Suppose an OS has 4 processes to schedule P1, P2, P3 and P4. For scheduling the first process, it has 4 choices, then from the remaining three processes it can take 3 choices, and so on. So, total schedules possible are 4*3*2*1 = 4!
Option (C) is correct.
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Dhruba Goyal asked • Jun 16, 2021 |
Which of the following statements is true for Branch - and - Bound search?- a)Underestimates of remaining distance may cause deviation from optimal path.
- b)Overestimates can't cause right path to be overlooked.
- c)Dynamic programming principle can be used to discard redundant partial paths.
- d)All of the above
Correct answer is option 'C'. Can you explain this answer?
Which of the following statements is true for Branch - and - Bound search?
a)
Underestimates of remaining distance may cause deviation from optimal path.
b)
Overestimates can't cause right path to be overlooked.
c)
Dynamic programming principle can be used to discard redundant partial paths.
d)
All of the above
|
Ravi Singh answered |
Branch and bound is a type of problem solving technique which is used to solve a combinatorial optimization problems. It is helps in solving them faster compare to other technique.it divides a problem into two subproblem. For branch and bound search Dynamic programming principle can be used to discard redundant partial paths. Option (C) is correct.
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Dhruba Goyal asked • Jan 01, 2021 |
A team of miner planned to mine 1800 tonnes in a certain number of days.Due to some difficulties in one third of the planned days, the team was able to achieve an output of 20 tons of ore less than the planned output.To make up for this, the team overachieved for the rest of the days by 20 tons.The end result for this that they completed the one day ahead of time.How many tone of ore did the team initially plan to ore per day?- a)50
- b)100
- c)150
- d)200
- e)250
Correct answer is option 'B'. Can you explain this answer?
A team of miner planned to mine 1800 tonnes in a certain number of days.Due to some difficulties in one third of the planned days, the team was able to achieve an output of 20 tons of ore less than the planned output.To make up for this, the team overachieved for the rest of the days by 20 tons.The end result for this that they completed the one day ahead of time.How many tone of ore did the team initially plan to ore per day?
a)
50
b)
100
c)
150
d)
200
e)
250
|
Naina Shah answered |
Let us assume the no. of days as ‘3d’ and the output per day as ‘x’
Then, 3d*x = 1800 … (1)
For the first ‘d’ days, the output was (x - 20).
For the next ‘2d - 1’ days, the output was (x + 20).
=> d(x-20) + (2d - 1) (x + 20) = 1800
=> dx – 20d + 2dx + 40d – x – 20 = 3dx {Replacing 1800 with 3dx from equation (1)}
=> 20d = x + 20
=> d = (x + 20)/20 … (2)
=> 3 [(x + 20)/20] x = 1800
=> x2 + 20x = (1800/3) *20
=> x2 + 20x – 12000 = 0
=> (x + 120) (x - 100) = 0
=> x = -120 or 100
Since x is the output it cannot be negative.
So, the initial planned output is 100 tonnes. Thus, Option B
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Dhruba Goyal asked • Jan 04, 2020 |
If p is pointer to an integer and t is a pointer to a character then size of (p) will be- a)Same as that of size of (t)
- b)Greater than that of size of (t)
- c)Less than that of size of (t)
- d)None of the above
Correct answer is option 'A'. Can you explain this answer?
If p is pointer to an integer and t is a pointer to a character then size of (p) will be
a)
Same as that of size of (t)
b)
Greater than that of size of (t)
c)
Less than that of size of (t)
d)
None of the above
|
Shraddha Iyer answered |
Pointer to an integer and pointer to a character are equivalent when the context of size of operator is used.
|
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Dhruba Goyal asked • Dec 28, 2019 |
Consider the following entity relationship diagram (ERD), where two entities E1 and E2 have a relation R of cardinality 1 : m.
The attributes of E1 are A11, A12 and A13where , A11 is key attribute. The attributes of E2 are A21, A22, and A23 where A21 is the key attribute and A23 is a multi-valued attribute. Relation R does not have any attribute. A relational database containing minimum number of tables with each table satisfying the requirements of the third normal form (3NF) is designed from the above ERD. The number of tables in the database is- a)2
- b)3
- c)5
- d)4
Correct answer is option 'B'. Can you explain this answer?
Consider the following entity relationship diagram (ERD), where two entities E1 and E2 have a relation R of cardinality 1 : m.
The attributes of E1 are A11, A12 and A13where , A11 is key attribute. The attributes of E2 are A21, A22, and A23 where A21 is the key attribute and A23 is a multi-valued attribute. Relation R does not have any attribute. A relational database containing minimum number of tables with each table satisfying the requirements of the third normal form (3NF) is designed from the above ERD. The number of tables in the database is
The attributes of E1 are A11, A12 and A13where , A11 is key attribute. The attributes of E2 are A21, A22, and A23 where A21 is the key attribute and A23 is a multi-valued attribute. Relation R does not have any attribute. A relational database containing minimum number of tables with each table satisfying the requirements of the third normal form (3NF) is designed from the above ERD. The number of tables in the database is
a)
2
b)
3
c)
5
d)
4
|
Vaishnavi Kaur answered |
Since each table is to in 3rd normal form for each multi-valued attribute individual table is to be created. Hence, total number of tables in the- database is 3.
1 for entity set E1, 2 for entity set E2 and 3 for attributes A23.
|
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Dhruba Goyal asked • Dec 19, 2019 |
Assume a fully associative write-back cache with many cache entries that starts empty. We define a sequence of memory operations. The address or locations is in square brackets.
Q. What are the number of misses when using no write allocate versus write allocate?- a)2,1
- b)2, 4
- c)3, 3
- d)4, 2
Correct answer is option 'D'. Can you explain this answer?
Assume a fully associative write-back cache with many cache entries that starts empty. We define a sequence of memory operations. The address or locations is in square brackets.
Q. What are the number of misses when using no write allocate versus write allocate?
a)
2,1
b)
2, 4
c)
3, 3
d)
4, 2
|
|
Soumya Pillai answered |
Number of misses for no write allocate are S1, S2, S3 and S5. For write allocate misses are S1 and S3. So pair contains 4, 2.
|
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Dhruba Goyal asked • Dec 14, 2019 |
The following transition diagram is for:
(i) >
(ii) >=- a)Only (i)
- b)Only (ii)
- c)Neither (i) nor (ii)
- d)Both (i) and (ii)
Correct answer is option 'D'. Can you explain this answer?
The following transition diagram is for:
(i) >
(ii) >=
(i) >
(ii) >=
a)
Only (i)
b)
Only (ii)
c)
Neither (i) nor (ii)
d)
Both (i) and (ii)
|
Atharva Mehra answered |
The given transition diagram is for the pattern > = and >, Its start state is sate 0. In state 0 we read the next input character. The edge labeled > from state 0 is to be followed to state 6 if this input character is >. Otherwise, we have failed to recognize either > or <=.
On reaching state 6, we read the next input character. The edge labeled = from state 6 is to be followed to state 7 if the input character is an = otherwise, the edge labeled other indicates that go to state 8. The double circle on state 7 indicates that it is accepting state, a state in which the token >= has been found.
On reaching state 6, we read the next input character. The edge labeled = from state 6 is to be followed to state 7 if the input character is an = otherwise, the edge labeled other indicates that go to state 8. The double circle on state 7 indicates that it is accepting state, a state in which the token >= has been found.
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Dhruba Goyal asked • Dec 07, 2019 |
The 2’s complement representation of the decimal value - 15 is- a)1111
- b)11111
- c)111111
- d)10001
Correct answer is option 'D'. Can you explain this answer?
The 2’s complement representation of the decimal value - 15 is
a)
1111
b)
11111
c)
111111
d)
10001
|
Pranab Banerjee answered |
The 2’s complement of negative numbers are represented as the binary number that when added to a positive number of the same magnitude equals zero
+15 = 0 1 1 1 1
The 2’s complement representation of the decimal value -15 is
-15 in 2’s complement = 10001
+15 = 0 1 1 1 1
The 2’s complement representation of the decimal value -15 is
-15 in 2’s complement = 10001
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Dhruba Goyal asked • Nov 25, 2019 |
Consider the grammar given below:
The grammar is :(i) LL(1)(ii)LR(0)(iii)LR(1)- a)(i) & (iii) are correct
- b)(i) & (ii) are correct
- c)All are correct
- d)All are incorrect
Correct answer is option 'D'. Can you explain this answer?
Consider the grammar given below:
The grammar is :
(i) LL(1)
(ii)LR(0)
(iii)LR(1)
a)
(i) & (iii) are correct
b)
(i) & (ii) are correct
c)
All are correct
d)
All are incorrect
|
|
Vaishnavi Kaur answered |
The Grammar is ambiguous. For a string “abab” two derivations are possible and no ambiguous grammar can be LR.
Derivation 1 : S → AS → SAS → ASAS → aSAS → abAS → abaS → abab
Derivation 2 : S → AS → aS → aAS → aSAS → abAS → abaS → abab
Derivation 1 : S → AS → SAS → ASAS → aSAS → abAS → abaS → abab
Derivation 2 : S → AS → aS → aAS → aSAS → abAS → abaS → abab
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