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Nilesh SainiStudent |
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Nilesh Saini
EduRev JEE
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Content, tests & courses saved by you for accessing later. (visible to you only)
Currently preparing for
Top Scoring Tests by Nilesh
Test: Temperature Dependence of a Reaction | 30/40 |
Test: Types of Organic Reactions | 30/40 |
Test: Conformational Analysis - 1 | 30/40 |
Test: Chemical Equilibrium: Le Chatelier's Principle | 56/76 |
Test: Binomial Theorem- 2 | 70/100 |
Test: Linear Programming (CBSE Level) - 1 | 70/100 |
Test: Surface Chemistry - 1 (Old NCERT) | 70/100 |
JEE Advanced Test- 8 | 186/270 |
Test: Critical Phenomenon (Old NCERT) | 44/64 |
Test: MET (Old NCERT) | 55/80 |
Rated 5 
by Nilesh
by Nilesh | Example Derivative Inverse Trigono (Part - 22) - Continuity & Differentiability , Maths, Class 12 Video | 14:19 min |  |
 | L12 : Examples - Straight line, Mathematics, Class 11 Video | 09:20 min | |
 | Shortest distance between lines (Part - 13) - Three Dimensional Geometry, Maths, Class 12 Video | 11:38 min | |
 | NCERT Solutions: Magnetism & Matter Doc | 23 pages | |
 | NCERT Solutions: Electromagnetic Waves Doc | 11 pages | |
 | Homegeneous differential Equation-4 (Part - 16) - Differential Equation, Maths, Class 12 Video | 09:02 min | |
 | L7 : Examples Point Slope Form - Straight line, Mathematics, Class 11 Video | 12:07 min | |
 | L16 : Integration by substitution-4 - Integrals, Maths, Class 12 Video | 11:38 min | |
 | NCERT Textbook: Electrostatic Potential & Capacitance Doc | 36 pages | |
 | L35 : Numerical - 5 - Haloalkanes & Haloarenes, Chemistry, Class 12 Video | 19:52 min | |
 | CURRENT ELECTRICITY, Chapter Notes, Class 12, Physics, (IIT-JEE & AIPMT) Doc | 61 pages | |
 | L14 : Examples middle term - Binomial theorem, Mathematics, Class 11 Video | 09:58 min | |
 | NCERT Textbook: Electromagnetic Waves Doc | 14 pages | |
 | 180 degree plus minus X functions (Part - 11)- Trigonometry Functions, Mathematics, Class 11 Video | 02:31 min | |
 | Example Continuous function (Part - 9) - Continuity & Differentiability, Maths, Class 12 Video | 12:58 min | |
 | Ketones Common, IUPAC names nomenclature (Part 4) - Aldehydes, Ketones & Carboxylic Acids, Chemistry Video | 11:23 min | |
 | L14 : Example-2 - Straight line, Mathematics, Class 11 Video | 14:45 min | |
 | FAQs Regarding All India IIT JEE Main 2017 Online Test Series Doc | 3 pages | |
 | L1 : Introduction to sequence - Sequences and Series, Mathematics, Class 11 Video | 14:40 min | |
 | NCERT Textbook: Alternating Current Doc | 24 pages | |
| Schedule of All India IIT-JEE Main 2017 Online Test Series Doc | 1 page | |
 | NCERT Solutions: Electric Charges & Fields Doc | 26 pages | |
 | L4 : Adsorption Chart - Surface Chemistry, Chemistry, Class 12 Video | 08:32 min | |
 | L11 : Nernst Equation - Electrochemistry, Chemistry, Class 12 Video | 11:52 min | |
 | L19 : Problems-1 - Trigonometry Functions, Mathematics, Class 11 Video | 09:11 min | |
 | Alternating Current, Class 12, Chapter Notes, Physics (IIT - JEE & AIPMT) Doc | 37 pages | |
 | NCERT Solutions: Application of Derivatives Doc | 32 pages | |
 | Parabola Doc | 21 pages | |
 | Electrostatics, Chapter Notes, Class 12, Physics, (IIT-JEE & AIPMT) Doc | 32 pages | |
 | NCERT Textbook: Atoms Doc | 16 pages | |
 | Solved Examples for JEE: Solutions Doc | 23 pages | |
 | NCERT Solutions - Limits and Derivatives, Class 11, Maths Doc | 24 pages | |
 | Detailed Chapter Notes - Electrochemistry, Class 12, Chemistry (IIT-JEE and AIPMT) Doc | 24 pages | |
Discussed Questions
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Nilesh Saini upvoted • Mar 28, 2025 |
Can you explain the answer of this question below:Two blocks of the masses 10 kg and 4 kg are connected by a spring of negligible mass and placed on a frictionless horizontal surface. An impulse gives a velocity of 14 m/s to the heavier block. The velocity of centre of mass is
- A:
10 m/s
- B:
5 m/s
- C:
15 m/s
- D:
20 m/s
The answer is a.
Two blocks of the masses 10 kg and 4 kg are connected by a spring of negligible mass and placed on a frictionless horizontal surface. An impulse gives a velocity of 14 m/s to the heavier block. The velocity of centre of mass is
10 m/s
5 m/s
15 m/s
20 m/s
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EduRev JEE answered |
Velocity of heavier block (v2) = 14m/s
Velocity of lighter block (v1) = 0m/s
Velocity of centre of mass,
Velocity of lighter block (v1) = 0m/s
Velocity of centre of mass,
The area(square units) bounded by the curves y=√x, and line 2y-x 3=0, x-axis and lying in first quadrant is: a.) 18 b.) 27/4 c.) 9 d.) 36 Correct answer is c.) 9. Explain.?
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Nilesh Saini answered • Mar 26, 2025 |
Understanding the Curves and Lines
To find the area bounded by the curves y = √x and the line 2y - x - 3 = 0, we first rewrite the line equation for clarity:
- Rearranging gives: y = (x + 3)/2.
Identifying Points of Intersection
Next, we find the points where these two curves intersect in the first quadrant:
1. Set √x = (x + 3)/2.
2. Squaring both sides ... more
To find the area bounded by the curves y = √x and the line 2y - x - 3 = 0, we first rewrite the line equation for clarity:
- Rearranging gives: y = (x + 3)/2.
Identifying Points of Intersection
Next, we find the points where these two curves intersect in the first quadrant:
1. Set √x = (x + 3)/2.
2. Squaring both sides ... more
What is the equivalent weight of H3PO4 ?
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Nilesh Saini answered • Mar 26, 2025 |
Understanding Equivalent Weight
The equivalent weight of a substance is defined as the mass of that substance which will combine with or displace 1 mole of hydrogen atoms or 1 mole of electrons in a reaction. For acids, the equivalent weight is determined based on the number of replaceable hydrogen ions (H+) they can donate.
Calculating Equivalent Weight of H3PO4
To fi... more
The equivalent weight of a substance is defined as the mass of that substance which will combine with or displace 1 mole of hydrogen atoms or 1 mole of electrons in a reaction. For acids, the equivalent weight is determined based on the number of replaceable hydrogen ions (H+) they can donate.
Calculating Equivalent Weight of H3PO4
To fi... more
What is the full form of NSEJS
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Nilesh Saini answered • Mar 26, 2025 |
NSEJS Full Form
The full form of NSEJS is National Standard Examination in Junior Science. It is an examination conducted by the Indian Association of Physics Teachers (IAPT) to encourage students in the field of science.
Objective of NSEJS
- The primary aim of NSEJS is to identify and nurture young talents in science among students.
- It serves as a platfo... more
The full form of NSEJS is National Standard Examination in Junior Science. It is an examination conducted by the Indian Association of Physics Teachers (IAPT) to encourage students in the field of science.
Objective of NSEJS
- The primary aim of NSEJS is to identify and nurture young talents in science among students.
- It serves as a platfo... more
what is meant by drawing against capital and drawing against profit???
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Nilesh Saini answered • Mar 26, 2025 |
Understanding Drawings Against Capital and Profit
When it comes to business finances, owners often withdraw funds from their business in two primary ways: against capital and against profit. These terms refer to different methods of taking money out of the business.
Drawings Against Capital
- Definition: Drawings against capital refer to withdrawals made by the ... more
When it comes to business finances, owners often withdraw funds from their business in two primary ways: against capital and against profit. These terms refer to different methods of taking money out of the business.
Drawings Against Capital
- Definition: Drawings against capital refer to withdrawals made by the ... more
What is relative permittivity?
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Nilesh Saini answered • Mar 26, 2025 |
What is Relative Permittivity?
Relative permittivity, often denoted as εr, is a fundamental property of materials that describes how an electric field interacts with a dielectric medium. It is a dimensionless quantity that compares the permittivity of a substance to the permittivity of free space (vacuum).
Key Concepts
- Definition: Relative permittivity is defi... more
Relative permittivity, often denoted as εr, is a fundamental property of materials that describes how an electric field interacts with a dielectric medium. It is a dimensionless quantity that compares the permittivity of a substance to the permittivity of free space (vacuum).
Key Concepts
- Definition: Relative permittivity is defi... more
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Nilesh Saini upvoted • Feb 15, 2025 |
In the following velocity-time graph of a body, the distance and displacement travelled by the body in 5 second in meters will be - 
- a)75,115
- b) 105, 75
- c)45, 75
- d) 95, 55
Correct answer is option 'B'. Can you explain this answer?
In the following velocity-time graph of a body, the distance and displacement travelled by the body in 5 second in meters will be -
a)
75,115
b)
105, 75
c)
45, 75
d)
95, 55
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EduRev JEE answered |
From the given velocity graph we get that displacement is w=equal to the area under the curve taken with sign while distance is area under the curve after the modulus is taken at first.
Thus displacement is
( ½ x 20 x 2 + 20 x 3 + ½ x 20 x 1) - (½ x 30 x 1) = 90 - 15 = 75m
And the distance will be
( ½ x 20 x 2 + 20 x 3 + ½ x 20 x 1) + (½ x 30 x 1) = 90 + 15 = 105m
Thus displacement is
( ½ x 20 x 2 + 20 x 3 + ½ x 20 x 1) - (½ x 30 x 1) = 90 - 15 = 75m
And the distance will be
( ½ x 20 x 2 + 20 x 3 + ½ x 20 x 1) + (½ x 30 x 1) = 90 + 15 = 105m
Which of the following statement is false for theproperties of electromagnetic waves? [2010]- a)Both electric and magnetic field vectorsattain the maxima and minima at the sameplace and same time.
- b)The energy in electromagnetic wave isdivided equally between electric andmagnetic vectors
- c)Both electric and magnetic field vectors areparallel to each other and perpendicular tothe direction of propagation of wave
- d)These waves do not require any materialmedium for propagation.
Correct answer is option 'C'. Can you explain this answer?
Which of the following statement is false for theproperties of electromagnetic waves? [2010]
a)
Both electric and magnetic field vectorsattain the maxima and minima at the sameplace and same time.
b)
The energy in electromagnetic wave isdivided equally between electric andmagnetic vectors
c)
Both electric and magnetic field vectors areparallel to each other and perpendicular tothe direction of propagation of wave
d)
These waves do not require any materialmedium for propagation.
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Nilesh Saini answered • Feb 04, 2025 |
Understanding Electromagnetic Waves
Electromagnetic waves have unique properties that distinguish them from other types of waves. Let’s explore why option 'C' is the false statement regarding these waves.
Key Properties of Electromagnetic Waves:
- Maxima and Minima Alignment:
Both electric and magnetic field vectors reach their maxima and minima at the sa... more
Electromagnetic waves have unique properties that distinguish them from other types of waves. Let’s explore why option 'C' is the false statement regarding these waves.
Key Properties of Electromagnetic Waves:
- Maxima and Minima Alignment:
Both electric and magnetic field vectors reach their maxima and minima at the sa... more
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Nilesh Saini upvoted • Jan 24, 2025 |
A thick plano convex lens made of crown glass (refractive index 1.5) has a thickness of 3cm at its centre. The radius of curvature of its curved face is 5cm. An ink mark made at the centre of its plane face, when viewed normally through the curved face, appears to be at a distance ‘x’ from the curved face. Then, x is equal to:
- a)2.5cm
- b)2.3cm
- c)2cm
- d)2.1cm
Correct answer is option 'A'. Can you explain this answer?
A thick plano convex lens made of crown glass (refractive index 1.5) has a thickness of 3cm at its centre. The radius of curvature of its curved face is 5cm. An ink mark made at the centre of its plane face, when viewed normally through the curved face, appears to be at a distance ‘x’ from the curved face. Then, x is equal to:
a)
2.5cm
b)
2.3cm
c)
2cm
d)
2.1cm
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EduRev Humanities answered |
A thick Plano convex lens made of crown glass (refractive index 1.5) has a thickness of 3cm at its centre. The radius of curvature of its curved face is 5cm. An ink mark made at the centre of its plane face, when viewed normally through the curved face, appears to be at a distance ‘x’ from the curved face, and we have to determine the value of ' x'
According to the picture, the ray of light gets refracted at the interface between the air and the lens from the object 'p' and 'I' is the refracted image of 'p'
object distance 'u'= BO
Image distance 'v'/'x' = BI
we know
n2/v - n1/u = (n2- n1) / R
or 1/v - 1.5/(-3 )= (1-1.5)/ (-5) [where n2= 1, n1= 1.5 ,u= -3 ,R= -5]
so, 1/v = -6/15
or, v = -2.5
so, x is equal to 2.5 cm
According to the picture, the ray of light gets refracted at the interface between the air and the lens from the object 'p' and 'I' is the refracted image of 'p'
object distance 'u'= BO
Image distance 'v'/'x' = BI
we know
n2/v - n1/u = (n2- n1) / R
or 1/v - 1.5/(-3 )= (1-1.5)/ (-5) [where n2= 1, n1= 1.5 ,u= -3 ,R= -5]
so, 1/v = -6/15
or, v = -2.5
so, x is equal to 2.5 cm
The wounded soldier belonged to- a)The Russian army
- b)U.S. Navy
- c)The British army
- d)The Japanese army
Correct answer is option 'B'. Can you explain this answer?
The wounded soldier belonged to
a)
The Russian army
b)
U.S. Navy
c)
The British army
d)
The Japanese army
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Nilesh Saini answered • Nov 26, 2024 |
The Context of the Wounded Soldier
The question regarding the wounded soldier's affiliation is specific to military history or a particular narrative context. In this case, the correct answer is option 'B', indicating that the soldier belonged to the U.S. Navy.
Understanding the U.S. Navy's Role
- The U.S. Navy plays a critical role in maritime operations and conflicts... more
The question regarding the wounded soldier's affiliation is specific to military history or a particular narrative context. In this case, the correct answer is option 'B', indicating that the soldier belonged to the U.S. Navy.
Understanding the U.S. Navy's Role
- The U.S. Navy plays a critical role in maritime operations and conflicts... more
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Nilesh Saini answered • Nov 26, 2024 |
Introduction
In C++, file handling is essential for reading from and writing to files. This is accomplished using two primary classes: ifstream and ofstream.
ifstream (Input File Stream)
- Purpose: Used to read data from files.
- Functionality:
- Allows you to open a file in read mode.
- Data can be extracted using the extr... more
In C++, file handling is essential for reading from and writing to files. This is accomplished using two primary classes: ifstream and ofstream.
ifstream (Input File Stream)
- Purpose: Used to read data from files.
- Functionality:
- Allows you to open a file in read mode.
- Data can be extracted using the extr... more
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Nilesh Saini upvoted • Oct 31, 2024 |
Electric field at the surface of a charged conductor is proportional to- a)Surface charge density
- b)Volume of the sphere
- c)Volume charge density
- d)Area of the sphere
Correct answer is option 'A'. Can you explain this answer?
Electric field at the surface of a charged conductor is proportional to
a)
Surface charge density
b)
Volume of the sphere
c)
Volume charge density
d)
Area of the sphere
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Ciel Knowledge answered |
Electric field at the surfaces of charged conductors is σ/ε0.n, where n is a unit vector normal to the surface.
We clearly see that the electric field is perpendicular to surface charge density (σ).
We clearly see that the electric field is perpendicular to surface charge density (σ).
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Nilesh Saini upvoted • Oct 08, 2024 |
Extent of crystal field splitting in octahedral complexes of the given metal with particular weak field ligand are such that- a)Fe(iii) < Cr(iii) < Rh(iii) < Ir(iii)
- b)Cr(iii) < Fe(iii) < Rh(iii) < Ir(iii)
- c)Ir(iii) < Rh(iii) < Fe(iii) < Cr(iii)
- d)Fe(iii) = Cr(iii) < Rh(iii) < Ir(iii)
Correct answer is option 'A'. Can you explain this answer?
Extent of crystal field splitting in octahedral complexes of the given metal with particular weak field ligand are such that
a)
Fe(iii) < Cr(iii) < Rh(iii) < Ir(iii)
b)
Cr(iii) < Fe(iii) < Rh(iii) < Ir(iii)
c)
Ir(iii) < Rh(iii) < Fe(iii) < Cr(iii)
d)
Fe(iii) = Cr(iii) < Rh(iii) < Ir(iii)
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Anoushka Chopra answered |
Fe(iii) < Cr(iii) < Rh(iii) < Ir(iii)
Factors affecting the price elasticity of demand?
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Nilesh Saini answered • Aug 24, 2024 |
Factors affecting the price elasticity of demand
Factors that influence the price elasticity of demand include:
Availability of substitutes:
- If there are many substitutes available for a product, the demand tends to be more elastic as consumers can easily switch to alternatives when the price of the product changes.
- For example, if the price of one brand... more
Factors that influence the price elasticity of demand include:
Availability of substitutes:
- If there are many substitutes available for a product, the demand tends to be more elastic as consumers can easily switch to alternatives when the price of the product changes.
- For example, if the price of one brand... more
Find the value of determinant . log x log y log z log 2x log 2y log 2z log 3x log 3y log 3z?
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Nilesh Saini answered • Aug 24, 2024 |
Calculating the Determinant
To find the value of the determinant given, we can use the properties of determinants for a 3x3 matrix. The given matrix represents the logarithms of various values, so we will simplify it step by step to find the determinant.
Step 1: Expand the Determinant
We can expand the determinant along the first row. The determinant of a 3x3 mat... more
To find the value of the determinant given, we can use the properties of determinants for a 3x3 matrix. The given matrix represents the logarithms of various values, so we will simplify it step by step to find the determinant.
Step 1: Expand the Determinant
We can expand the determinant along the first row. The determinant of a 3x3 mat... more
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Nilesh Saini asked • Feb 05, 2020 |
A particle, of mass 10−3 kg and charge 1.0 C is initially at rest. At time t = 0 , the particle comes under the influence of an electric field 
where E0 = 1.0 NC−1 and ω = 103 rad s−1. Consider the effect of only the electrical force on the particle. Then the maximum speed, in ms−1, attained by the particle at subsequent times is ____________.
Correct answer is '2'. Can you explain this answer?
A particle, of mass 10−3 kg and charge 1.0 C is initially at rest. At time t = 0 , the particle comes under the influence of an electric field where E0 = 1.0 NC−1 and ω = 103 rad s−1. Consider the effect of only the electrical force on the particle. Then the maximum speed, in ms−1, attained by the particle at subsequent times is ____________.
where E0 = 1.0 NC−1 and ω = 103 rad s−1. Consider the effect of only the electrical force on the particle. Then the maximum speed, in ms−1, attained by the particle at subsequent times is ____________.
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Milan Shah answered |
The velocity of the charged particle is maximum when the electrostatic force becomes zero. Thus,
Due to electric field, charge particles start to be in motion, therefore,
Simplify the above equation,
Due to electric field, charge particles start to be in motion, therefore,
Simplify the above equation,
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Nilesh Saini asked • Feb 02, 2020 |
Let S be the set of all complex numbers z satisfying |z - 2 + i| ≥ √5. If the complex number z0 is such that 
is the maximum of the set 
then the principal argument of 
- a)π/4
- b)- π/2
- c)3π/4
- d)π/2
Correct answer is option 'B'. Can you explain this answer?
Let S be the set of all complex numbers z satisfying |z - 2 + i| ≥ √5. If the complex number z0 is such that is the maximum of the set then the principal argument of
is the maximum of the set then the principal argument of a)
π/4
b)
- π/2
c)
3π/4
d)
π/2
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Krithika Nair answered |
= arg(–ki) ; k > 0 (as Rez0 < 2 & Imz0 > 0)
= - π/2
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Nilesh Saini asked • Jan 26, 2020 |
Locus of the image of the point (2, 3) in the line (2x – 3y + 4) + k(x – 2y + 3) = 0, k ∈ R, is a- a)Straight line parallel to x-axis
- b)Straight line parallel to y-axis
- c)Circle of radius √2
- d)Circle of radius √3
Correct answer is option 'C'. Can you explain this answer?
Locus of the image of the point (2, 3) in the line (2x – 3y + 4) + k(x – 2y + 3) = 0, k ∈ R, is a
a)
Straight line parallel to x-axis
b)
Straight line parallel to y-axis
c)
Circle of radius √2
d)
Circle of radius √3
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Keerthana Tiwari answered |
After solving equation (i) & (ii)
2x –3y + 4= 0 .....(i)
2x –4y + 6= 0 .....(ii)
x = 1 and y = 2
Slope of AB × Slope of MN = – 1
(y – 3)(y – 1) = –(x – 2)x
y2 – 4y + 3 = –x2 + 2x
x2 + y2 – 2x – 4y + 3 = 0
Circle of radius = √2
2x –3y + 4= 0 .....(i)
2x –4y + 6= 0 .....(ii)
x = 1 and y = 2
Slope of AB × Slope of MN = – 1
(y – 3)(y – 1) = –(x – 2)x
y2 – 4y + 3 = –x2 + 2x
x2 + y2 – 2x – 4y + 3 = 0
Circle of radius = √2
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Nilesh Saini asked • Jan 22, 2020 |
Two sides of a rhombus are along the lines, x - y + 1 = 0 and 7x - y - 5 = 0. If its diagonals intersect at (-1, -2), then which one of the following is a vertex of this rhombus?- a)(-3, -9)
- b)(-3, -8)
- c)
- d)
Correct answer is option 'C'. Can you explain this answer?
Two sides of a rhombus are along the lines, x - y + 1 = 0 and 7x - y - 5 = 0. If its diagonals intersect at (-1, -2), then which one of the following is a vertex of this rhombus?
a)
(-3, -9)
b)
(-3, -8)
c)
d)
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Peter Parker answered |
Option C is correct...
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Nilesh Saini asked • Jan 19, 2020 |
A mass of 10 kg is suspended vertically by a rope from the roof. When a horizontal force is applied on the rope at some point, the rope deviated at an angle of 45° at the roof point. If the suspended mass is at equilibrium, the magnitude of the force applied is (g = 10 ms –2)- a)200 N
- b)100 N
- c)140 N
- d)70 N
Correct answer is option 'B'. Can you explain this answer?
A mass of 10 kg is suspended vertically by a rope from the roof. When a horizontal force is applied on the rope at some point, the rope deviated at an angle of 45° at the roof point. If the suspended mass is at equilibrium, the magnitude of the force applied is (g = 10 ms –2)
a)
200 N
b)
100 N
c)
140 N
d)
70 N
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Navya Pillai answered |
at equation
F = 100 N
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Nilesh Saini asked • Jan 15, 2020 |
An unknown metal of mass 192 g heated to a temperature of 100ºC was immersed into a brass calorimeter of mass 128 g containing 240 g of water a temperature of 8.4ºC Calculate the specific heat of the unknown metal if water temperature stabilizes at 21.5ºC (Specific heat of brass is 394 J kg–1 K–1)- a)1232 J kg–1 K–1
- b)458 J kg–1 K–1
- c)654 J kg–1 K–1
- d)916 J kg–1 K–1
Correct answer is option 'D'. Can you explain this answer?
An unknown metal of mass 192 g heated to a temperature of 100ºC was immersed into a brass calorimeter of mass 128 g containing 240 g of water a temperature of 8.4ºC Calculate the specific heat of the unknown metal if water temperature stabilizes at 21.5ºC (Specific heat of brass is 394 J kg–1 K–1)
a)
1232 J kg–1 K–1
b)
458 J kg–1 K–1
c)
654 J kg–1 K–1
d)
916 J kg–1 K–1
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Kiran Sengupta answered |
192 × S × (100 – 21.5)
= 128 × 394 × (21.5 – 8.4)
+ 240 × 4200 × (21.5 – 8.4)
⇒ S = 916
= 128 × 394 × (21.5 – 8.4)
+ 240 × 4200 × (21.5 – 8.4)
⇒ S = 916
and 
be a vector such that 
and the angle between 
be 30°. Then 
is equal to
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Nilesh Saini asked • Jan 08, 2020 |
The increasing order of nitration of the following compounds is:
- a)(a) < (b) < (d) < (c)
- b)(a) < (b) < (c) < (d)
- c)(b) < (a) < (c) < (d)
- d)(b) < (a) < (d) < (c)
Correct answer is option 'C'. Can you explain this answer?
The increasing order of nitration of the following compounds is:
a)
(a) < (b) < (d) < (c)
b)
(a) < (b) < (c) < (d)
c)
(b) < (a) < (c) < (d)
d)
(b) < (a) < (d) < (c)
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Geetika Shah answered |
Nitration is electrophilic aromatic substitution reaction. Methoxy and amino groups are strongly activating groups. Methyl group is weakly activating group.
Since among methyl and methoxy group, methoxy group is more reactive than methyl group, (c) is more reactive than (d).
Even-though amino group is strongly activating group, it gets protonated in presence of acid to form anilinium ion which is strongly deactivating. Hence, (a) is less reactive than (c) and (d).
Note:
The activating groups increases the electron density on benzene ring and increases the rate of electrophilic aromatic substitution reaction. The deactivating groups decreases the electron density on benzene ring and decreases the rate of electrophilic aromatic substitution reaction.
Since among methyl and methoxy group, methoxy group is more reactive than methyl group, (c) is more reactive than (d).
Even-though amino group is strongly activating group, it gets protonated in presence of acid to form anilinium ion which is strongly deactivating. Hence, (a) is less reactive than (c) and (d).
Note:
The activating groups increases the electron density on benzene ring and increases the rate of electrophilic aromatic substitution reaction. The deactivating groups decreases the electron density on benzene ring and decreases the rate of electrophilic aromatic substitution reaction.
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Nilesh Saini asked • Jan 05, 2020 |
If an angle A of a ΔABC satisfies 5 cosA + 3 = 0, then the roots of the quadratic equaiton, 9x2 + 27x + 20 = 0 are :- a)sec A, cotA
- b)secA, tanA
- c)tanA, cosA
- d)sinA, secA
Correct answer is option 'B'. Can you explain this answer?
If an angle A of a ΔABC satisfies 5 cosA + 3 = 0, then the roots of the quadratic equaiton, 9x2 + 27x + 20 = 0 are :
a)
sec A, cotA
b)
secA, tanA
c)
tanA, cosA
d)
sinA, secA
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Sushil Kumar answered |
5cosA + 3 = 0 ⇒ cosA = - 3/5 clearly A ∈ (90º, 180º)
Now roots of equation 9x2 + 27x + 20 = 0 are -5/3 and -4/3
⇒ Roots secA and tanA
Now roots of equation 9x2 + 27x + 20 = 0 are -5/3 and -4/3
⇒ Roots secA and tanA
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