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All questions of October Week 2 for NEET Exam

Ca(HCO3)2 is strongly heated and after equilibrium is attained, temperature changed to 25° C.

Kp = 36 (pressure taken in atm)
Thus, pressure set up due to CO2 is
  • a)
    36 atm
  • b)
    18 atm
  • c)
    12 atm
  • d)
    6 atm
Correct answer is 'D'. Can you explain this answer?

Mira Joshi answered
The reaction is as follow:-
Ca(HCO3)2(s)⇌CaO(s) + 2CO2 (g) + H2O(g)
At 25° C H2O goes in liquid state
Kp = (PCaO)1×(PCO2)2
(PCa(HCO3)2)
Since, Ca(HCO3)2, CaO and H2O are not in gaseous state, so their partial pressure is taken 1.
Putting all values, we have
36 = (PCO2)2 
Or PCO2 = 6 atm
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Water is flowing through a pipe under constant pressure. At some place the pipe becomes narrow. The pressure of water at this place:
  • a)
    remains the same
  • b)
    depends on several factors
  • c)
    decreases
  • d)
    increases
Correct answer is option 'C'. Can you explain this answer?

Suresh Iyer answered
We know that the continuity theorem says that if the cross sectional area of the water flow decreases, the speed must increase to maintain the volume of water flown. And according to Bernoulli's principle if the speed of water flow increases , then the pressure must decrease.

Assume following equilibria when total pressure set up in each are equal to 1 atm, and equilibrium constant (Kp) as K1; K2 and K3


Thus,
  • a)
     K1 = K2 = K3
  • b)
    K1 < K2 < K3
  • c)
    K3 < K2 < K1
  • d)
    None of these
Correct answer is option 'C'. Can you explain this answer?

Pioneer Academy answered
The correct answer is option C
CaCO3 ​→ CaO + CO2​
Kp​ = k1 ​= Pco2​​
total pressure of container P
k1​ = p
NH4​HS → NH3 ​+ H2​S
PNH3​​ = PH2​S ​= P0​
P0​ + P0​ = p (total pressure)
P0 ​= p/2
k2​ = kp ​= [PNH3​​][PH2​s​] p24​
NH2​CoNH2 ​→ 2NH3 ​+ CO2​
PNH3​​ = 2P0​        PCO2​ ​= P0​
2P0​ + P0 ​= P

Water is flowing through a horizontal pipe in streamline flow at the narrowest part of the pipe:
  • a)
    Both pressure and the velocity remains constant
  • b)
    velocity is maximum and pressure is minimum
  • c)
    both the pressure and velocity are maximum
  • d)
    both the pressure and velocity are minimum
Correct answer is option 'B'. Can you explain this answer?

Geetika Shah answered
In streamline flow, the product of cross section area and velocity remains constant (equation of continuity). So in the narrowest part of the pipe velocity is maximum. 
And from Bernoulli's theorem, we know that the sum of potential energy, kinetic energy and pressure energy remains constant. Since pipe is horizontal potential energy is equal at all the points. So the narrowest part  of pipe pressure (pressure energy) will be minimum because velocity (kinetic energy) is maximum in the narrowest part.

Kc forthe decomposition of NH4HS(s) is 1.8x 10-4 at 25°C.

If the system already contains [NH3] = 0.020 M, then when equilibrium is reached, molar concentration are
  • a)
    a
  • b)
    b
  • c)
    c
  • d)
    d
Correct answer is option 'B'. Can you explain this answer?

Sushil Kumar answered
 NH4HS (s)  ⇋ NH3 (g) + H2S (g)
Initial    1                   -               -
At eqm     1-x                 x+0.02     x
Kc = [NH3][H2S]   (Since NH4HS is solid, we ignore it.)
1.8×10-4    = (x+0.02)(x)
x2+0.02x-1.8×10-4 = 0
Applying quadratic formula; x = -0.02+√{(0.02)2-4×1.8×10-4}
= 0.033-0.020/2 = 0.0065
Therefore, concn of NH3 at equilibrium = x+0.020 = 0.0265
concn of H2S at equilibrium = x = 0.0065
So, option b is correct

Bernoulli’s theorem is important in the field of:
  • a)
    Photoelectric effect
  • b)
    flow of liquids
  • c)
    Magnetism
  • d)
    Electrical cells
Correct answer is option 'B'. Can you explain this answer?

Rohan Singh answered
Bernoulli's theorem, in fluid dynamics, relation among the pressure, velocity, and elevation in a moving fluid (liquid or gas), the compressibility and viscosity (internal friction) of which are negligible and the flow of which is steady, or laminar.

Passage I
Solid ammonium chloride is in equilibrium with ammonia and hydrogen chloride gases

0.980 g of solid NH4CI is taken in a closed vessel of 1 L capacity and heated to 275° C.
Q. Percentage decomposition of the original sample is
  • a)
    24.81%
  • b)
    6.24%
  • c)
    3.12%
  • d)
    12.13%
Correct answer is option 'D'. Can you explain this answer?

Knowledge Hub answered
The state of HCl is given wrong. It will be in gaseous state.
So, the reaction be like;-
NH4Cl(s)  ⇌  NH3(g) + HCl(g)        kp = 1.00×10-2 at 275° C
Kp = kc(RT)2
1.00×10-2 = kc(0.0821×548)2
Or kc = 4.94×10-6
                          NH4Cl(s)  ⇌  NH3(g) + HCl(g)
Initial  1                     -             -
At eqm 1-x                  x            x 
Kc = x2
x = √(4.94×10-6)
=  2.22×10-3
Therefore, NH4Cl dissociated at eqm = 2.22×10-3 × 53.5 = 0.118
%age decomposition = 0.118/0.980×100 = 12.13%

For the equilibrium,

at 1000 K. If at equilibrium pCO = 10 then total pressure at equilibrium is 
  • a)
    6.30 atm
  • b)
    0.63 atm
  • c)
    6.93 atm
  • d)
    69.3 atm
Correct answer is option 'C'. Can you explain this answer?

Lavanya Menon answered
C(s) + CO2(g) <=========> 2CO(g)
Kp = pCO2/pCO2
GIven Kp = 63 and pCO = 10pCO2
Putting the value of pCO in above equation,
63 = 100(pCO2)2/pCO2
Or pCO2 = 0.63
pCO = 6.3
Therefore, total pressure = 6.3+0.63 = 6.93 atm

In the houses far away from the municipal water tanks often people find it difficult to get water on the top floor. This happens because
  • a)
    water wets the pipe
  • b)
    the pipes are not of uniform diameter
  • c)
    the viscosity of the water is high
  • d)
    of loss of pressure during the flow of water
Correct answer is option 'D'. Can you explain this answer?

Om Desai answered
Every foot of elevation change causes a 0.433 PSI change in water pressure. If your pipe is going downhill add 0.433 PSI of pressure per vertical foot the pipe goes down. If the pipe is going uphill subtract 0.433 PSI for every vertical foot the pipe goes up.

 Bernoulli’s principle is based on the conservation of:
  • a)
    • Momentum
  • b)
    Energy and momentum both
  • c)
    Mass
  • d)
    Energy
Correct answer is option 'D'. Can you explain this answer?

Rahul Bansal answered
Bernoulli's principle can be derived from the principle of conservation of energy. This states that, in a steady flow, the sum of all forms of energy in a fluid along a streamline is the same at all points on that streamline.

Once the equilibrium is reached under given condition:
  • a)
    Cone, remains the same in spite of the change in temperature
  • b)
    Cone, of all the substances presents do not change
  • c)
    Cone, of reactants remairfs same
  • d)
    Cone, of products remains same
Correct answer is option 'B'. Can you explain this answer?

Raghav Bansal answered
In a chemical reaction, chemical equilibrium is the state in which the forward reaction rate and the reverse reaction rate are equal. The result of this equilibrium is that the concentrations of the reactants and the products do not change. However, just because concentrations aren’t changing does not mean that all chemical reaction has ceased. Just the opposite is true; chemical equilibrium is a dynamic state in which reactants are being converted into products at all times, but at the exact rate that products are being converted back into reactants. The result of such a situation is analogous to a bridge between two cities, where the rate of cars going over the bridge in each direction is exactly equal. The result is that the net number of cars on either side of the bridge does not change.

At 90° C , the following equilibrium is established :

If 0.20 mole of hydrogen and 1.0 mole of sulphur are heated to 90°C in a 1.0 dm3 flask, what will be the partial pressure of H2S gas at equilibrium?
  • a)
    0.36 atm
  • b)
    0.38 atm
  • c)
    0.28 atm
  • d)
    0.26 atm
Correct answer is option 'B'. Can you explain this answer?

Geetika Shah answered
Initial moles of H₂ = 0.2
Initial moles of S = 1  
Kp = 6.8 * 10⁻²
Given equation:
H2(g) + S(s) ⇋ H2S(g)
Initial moles:          0.2        1
At equilibrium: (0.2-α)   (1-α)       α
Here, in the above equation we can see that hydrogen is the limiting reagent.  
∴ Kp = α/(0.2 – α)
⇒ 6.8 * 10⁻²  = α/(0.2 – α)
⇒ 1.36*10⁻² – (6.8*10⁻²)α = α
⇒ α + 0.068α = 1.36*10⁻²
⇒ α = 1.36*10⁻² / 1.068 = 1.273 * 10⁻² ← moles of H₂S
So, at equilibrium moles of H₂ = 0.2 – α = 0.2 – 1.273 * 10⁻² = 0.1873
Now, using the Ideal Gas equation,
PV = nRT ….. (i)
Where P = total pressure of the vessel
n = total no. of moles = (0.2-α) + (1-α) + α = 1.2 – α = 1.2 – 1.273*10⁻² = 1.1873
V = volume of vessel = 1 litre
R = Ideal gas constant = 0.082 L atm K⁻¹mol⁻¹
T = total temperature = 90℃ = 90+273 = 363 K
Substituting all the values in eq. (i), we get
P * 1 =  1.1873 * 0.082 * 363  
⇒ P = 35.34 atm
Thus,  
The partial pressure of H₂S at equilibrium
= (mole fraction of H₂S) * (total pressure)
= [1.273*10⁻² /  1.1873] * 35.34
= 0.3789 atm
≈ 0.38 atm

Water is flowing through a horizontal tube. The pressure of the liquid in the portion where velocity is 2 m/s is 2 m of Hg. What will be the pressure in the portion where velocity is 4 m/s?
  • a)
    430 x 10³ Pa
  • b)
    4.3 x 10³ Pa
  • c)
    1.31 x 105 Pa
  • d)
    0.43 x 10³ Pa
Correct answer is option 'C'. Can you explain this answer?

Sparsh Datta answered
We know that Pv remains constant for any fluid and for non compressible fluids like water we get that Pv is always constant.
Also as 76cm of Hg = 105 Pa  
We get 2m Hg = 200/76 x 105 Pa
Thus from conservation of Pv, we get that
2 x  200/76 x 105  = 4 x P
Thus we get P = 100/76 x 105
Thus we get P = 1.31 x 105

Bernoulli’s theorem includes as a special case of:
  • a)
    Torricelli’s law
  • b)
    Hooke’s law
  • c)
    Archimedes’ principle
  • d)
    Pascal’s law
Correct answer is option 'A'. Can you explain this answer?

Rohan Singh answered
Bernoulli’s Theorem
Bernoulli’s theorem, in fluid dynamics, relation among the pressure, velocity, and elevation in a moving fluid (liquid or gas), the compressibility and viscosity (internal friction) of which are negligible and the flow of which is steady, or laminar. First derived (1738) by the Swiss mathematician Daniel Bernoulli, the theorem states, in effect, that the total mechanical energy of the flowing fluid, comprising the energy associated with fluid pressure, the gravitational potential energy of elevation, and the kinetic energy of fluid motion, remains constant. Bernoulli’s theorem is the principle of energy conservation for ideal fluids in steady, or streamline, flow and is the basis for many engineering applications.

Which enzyme catalyzes the conversion of sucrose into glucose and fructose in plants?
  • a)
    Hexokinase
  • b)
    Invertase
  • c)
    Phosphofructokinase
  • d)
    Lactate dehydrogenase
Correct answer is option 'B'. Can you explain this answer?

Sonal Reddy answered
Enzyme Overview
The enzyme responsible for the conversion of sucrose into glucose and fructose in plants is called invertase. This process is crucial for various physiological functions in plants, particularly in carbohydrate metabolism.
Function of Invertase
- Invertase, also known as sucrose-α-D-glucosidase, catalyzes the hydrolysis of sucrose.
- It breaks the glycosidic bond between glucose and fructose in sucrose, resulting in free glucose and fructose.
Biological Importance
- Energy Source: The glucose produced serves as a primary energy source for plant cells.
- Sugar Transport: Fructose can also be utilized in energy production and serves as a precursor for other carbohydrates.
- Growth and Development: The availability of these simple sugars is essential for various metabolic processes, including growth and development.
Comparison with Other Enzymes
- Hexokinase: This enzyme phosphorylates glucose but does not convert sucrose.
- Phosphofructokinase: This enzyme is involved in glycolysis, acting on fructose-6-phosphate, not sucrose.
- Lactate Dehydrogenase: This enzyme is related to anaerobic respiration, specifically converting pyruvate to lactate.
Conclusion
In summary, invertase is the key enzyme that hydrolyzes sucrose into glucose and fructose, playing a vital role in plant metabolism and energy production. Understanding this enzyme's function is essential for comprehending how plants utilize carbohydrates effectively.

Direction (Q. Nos. 11-14) This section contains  a paragraph, wach describing theory, experiments, data etc. three Questions related to paragraph have been given.Each question have only one correct answer among the four given options (a),(b),(c),(d)
Passage I
Solid ammonium chloride is in equilibrium with ammonia and hydrogen chloride gases

0.980 g of solid NH4CI is taken in a closed vessel of 1 L capacity and heated to 275° C.
Q. Partial pressure of NH3(g) or HCI (g) at equilibrium is
  • a)
    0.10 atm
  • b)
    1.0 atm
  • c)
    0.01 atm
  • d)
    1 x 10-4 atm
Correct answer is option 'A'. Can you explain this answer?

Neha Joshi answered
The reaction is as follow:-
NH4Cl(s)  ⇋  NH3(g) + HCl(g)
Kp = (pNH3)(pHCl)
1×10-2 = p2   (SInce reactant dissociates into same ratio, so the partial pressure will be same for both)
100×10-4 = p2
Or p = 10×10-2 = 0.10
So,  the partial pressure of NH3 and HCl are 0.10 atm.

What is the total ATP gain during glycolysis from one molecule of glucose?
  • a)
    2 ATP
  • b)
    4 ATP
  • c)
    6 ATP
  • d)
    8 ATP
Correct answer is option 'A'. Can you explain this answer?

Ambition Institute answered
Glycolysis directly synthesizes 4 ATP molecules, but 2 ATP are used in early steps, resulting in a net gain of 2 ATP per glucose molecule.

Passage lI
One of the reactions that takes place in producing steel from iron ore is the reduction of iron (II) oxide by carbon monoxide to give iron metal and carbon dioxide.

Initial partial pressure
CO(g) = 1.40 atm
CO2(g) = 0.80 atm
Q. When equilibrium is attained,
  • a)
    = Pco = 1-74 atm
  • b)
    = Pco = 0.46 atm
  • c)
    = 0-46 atm, pco = 1.74 atm
  • d)
    = 1.74 atm, pco = 0.46 atm
Correct answer is option 'C'. Can you explain this answer?

Ashwini Majumdar answered
For the given reaction,

the reaction will proceed in the backward direction.
Therefore, we can say that the pressure of CO will increase while the pressure of CO
2
 will decrease.
Now, let the increase in pressure of CO = decrease in pressure of CO
2 
be p.
Then, we can write,

Therefore, equilibrium partial of


And, equilibrium partial pressure of


For the following equilibrium,

  • a)
    a
  • b)
    b
  • c)
    c
  • d)
    d
Correct answer is option 'A'. Can you explain this answer?

Raghav Shukla answered
It's a very easy
you can solve it very easily with help of le Chatlier principle
clearly pressure is of co2 only as all other components are solid and there concentrations are taken as 1
clearly putting values with help of ideal gas equation, you will get the answer

Match the following glycolytic enzymes with their functions:​Options:
  • a)
    a-iii, b-ii, c-i, d-iv
  • b)
    a-ii, b-i, c-iv, d-iii
  • c)
    a-iv, b-iii, c-ii, d-i
  • d)
    a-i, b-iv, c-iii, d-ii
Correct answer is option 'A'. Can you explain this answer?

Stepway Academy answered
Hexokinase phosphorylates glucose, invertase breaks sucrose, pyruvic acid decarboxylase aids ethanol formation, and lactate dehydrogenase reduces pyruvate to lactic acid.

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