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All questions of June Week 3 for Class 10 Exam
The 5th term of an A.P. is 18, the common difference is 2. What is the first term ?
- a)8
- b)9
- c)10
- d)7
Correct answer is option 'C'. Can you explain this answer?
The 5th term of an A.P. is 18, the common difference is 2. What is the first term ?
a)
8
b)
9
c)
10
d)
7
|
Indu Gupta answered |
5th term of AP is 18 and common difference is 2
We have, l = a + (n - 1)d
Where l = 18,a = ?,n = 5,d = 2
Substituting the values,
18 = a+8
a = 10
We have, l = a + (n - 1)d
Where l = 18,a = ?,n = 5,d = 2
Substituting the values,
18 = a+8
a = 10
Give that an A.P. has term as 5 and common differences as 2. What is the A.p.?- a)5,7,9,11,13…
- b)5,7,9,10,11,12…
- c)5,6,8,10,12…
- d)5,6,7,8,9,10…
Correct answer is option 'A'. Can you explain this answer?
Give that an A.P. has term as 5 and common differences as 2. What is the A.p.?
a)
5,7,9,11,13…
b)
5,7,9,10,11,12…
c)
5,6,8,10,12…
d)
5,6,7,8,9,10…
|
Krishna Iyer answered |
A¹=5 d=2
a²=a¹+d =5+2=7
a³=a²+d =7+2 =9
a⁴=a³+d=9+2=11
A5 =a⁴+d=11+2=13
Therefore 5,7,9,11,13 is an AP.
a²=a¹+d =5+2=7
a³=a²+d =7+2 =9
a⁴=a³+d=9+2=11
A5 =a⁴+d=11+2=13
Therefore 5,7,9,11,13 is an AP.
Is the sequence, whose general term is 5n2 + 2n + 3 an AP?
- a)No
- b)Insufficent information
- c)Yes
- d)Depends on n
Correct answer is option 'A'. Can you explain this answer?
Is the sequence, whose general term is 5n2 + 2n + 3 an AP?
a)
No
b)
Insufficent information
c)
Yes
d)
Depends on n
|
Ananya Das answered |
We have the sequence 5n2+2n+3
It will be in AP if it satisfies an-an-1=d where d is a constant.
Here, an=5n2+2n+3
And, an-1=5(n-1)2+2(n-1)+3=5(n2+1-2n)+2n-2+3
=5n2+5-10n+2n+1=5n2-8n+6
an-an-1=5n2+2n+3-(5n2-8n+6)
=5n2+2n+3-5n2+8n-6
=10n-3, which depends on a variable , so its not constant.
It will be in AP if it satisfies an-an-1=d where d is a constant.
Here, an=5n2+2n+3
And, an-1=5(n-1)2+2(n-1)+3=5(n2+1-2n)+2n-2+3
=5n2+5-10n+2n+1=5n2-8n+6
an-an-1=5n2+2n+3-(5n2-8n+6)
=5n2+2n+3-5n2+8n-6
=10n-3, which depends on a variable , so its not constant.
… is:
For an A.P. the third and the fifth terms are given as 10 and 16 .What is the fourth term and the common difference?
- a)22,4
- b)4,6
- c)13,3
- d)22,6
Correct answer is option 'C'. Can you explain this answer?
For an A.P. the third and the fifth terms are given as 10 and 16 .What is the fourth term and the common difference?
a)
22,4
b)
4,6
c)
13,3
d)
22,6
|
Aisha Negi answered |
Abe yrr we are given third term means a+ 2d and fifth term means a+ 4d now make two equation separately i.e, a+ 2d = 10 ------ eq1 and a+ 4d = 16 ---------eq2 now eliminate both the equation and Iam sure ans will be 13, 3
The IUPAC name of CH3CHO is
- a)Ethanal
- b)Ethanol
- c)Methanol
- d)Acetone
Correct answer is option 'A'. Can you explain this answer?
The IUPAC name of CH3CHO is
a)
Ethanal
b)
Ethanol
c)
Methanol
d)
Acetone
|
Pooja Shah answered |
The IUPAC name of CH3CHO is Ethanal.
The IUPAC name for CH3CHO is Ethanal, also known as Acetaldehyde. It has 2 carbons, so the term “Eth” is used as prefix and it belongs to the aldehyde group, so the term “al” is used as suffix.
The IUPAC name for CH3CHO is Ethanal, also known as Acetaldehyde. It has 2 carbons, so the term “Eth” is used as prefix and it belongs to the aldehyde group, so the term “al” is used as suffix.
Ramesh’s salary in February 2008 is Rs. 10,000. If he’s promised an increase of Rs. 1000 every year, what would be his salary in Feb 2011?- a)Rs. 13,000
- b)Rs.14,000
- c)Rs. 12,000
- d)Rs. 15,000
Correct answer is option 'A'. Can you explain this answer?
Ramesh’s salary in February 2008 is Rs. 10,000. If he’s promised an increase of Rs. 1000 every year, what would be his salary in Feb 2011?
a)
Rs. 13,000
b)
Rs.14,000
c)
Rs. 12,000
d)
Rs. 15,000
|
|
Anita Menon answered |
So this is an AP with a=10,000 , d= 1000
So after 4 years
l=a+(n-1)d=10000+(4 -1)1000=10000+3000=13000
So after 4 years
l=a+(n-1)d=10000+(4 -1)1000=10000+3000=13000
Find the next two terms of the A.P.:- -10, -6,-2…- a)4,8
- b)-4,-8
- c)2,6
- d)6,10
Correct answer is option 'C'. Can you explain this answer?
Find the next two terms of the A.P.:- -10, -6,-2…
a)
4,8
b)
-4,-8
c)
2,6
d)
6,10
|
|
Amit Sharma answered |
We have A.P.: -10, -6,-2…
So a= -10, d=-6+10=-2+6=4
l=a+(n-1)d
For fourth term,
= -10+(3)*4=-10+12=2
For 5th term
= -10+4*4=6
So a= -10, d=-6+10=-2+6=4
l=a+(n-1)d
For fourth term,
= -10+(3)*4=-10+12=2
For 5th term
= -10+4*4=6
The angles of a triangle in A.P. the smallest being half of the greatest. So what are the angles ?- a)45°, 55°, 90°
- b)50°, 25°, 75°
- c)60°, 40°, 80°
- d)40°, 60°, 30°
Correct answer is 'C'. Can you explain this answer?
The angles of a triangle in A.P. the smallest being half of the greatest. So what are the angles ?
a)
45°, 55°, 90°
b)
50°, 25°, 75°
c)
60°, 40°, 80°
d)
40°, 60°, 30°
|
Rajiv Gupta answered |
Let a-d, a, a+d be the three angles of the triangle that form AP.Now, 2(a-d)=a+d2a-2d=a+da=3d (eq. 1)Now by angle sum property,(a-d)+a+(a+d)=1803a=180a=60 (eq.2)from (1) and (2),3d=60d=20Now, the angles are,a-d=60-20=40a=60a+d=60+20=80
If p – 1, p + 3, 3p – 1 are in A.P., then p is equal to:- a)-4
- b)4
- c)2
- d)-2
Correct answer is option 'B'. Can you explain this answer?
If p – 1, p + 3, 3p – 1 are in A.P., then p is equal to:
a)
-4
b)
4
c)
2
d)
-2
|
|
Kiran Mehta answered |
We have given that
p-1,p+3 , 3p-1 are in A.P
p-1,p+3 , 3p-1 are in A.P
we have to find p= ?
solution :-
we know that :
if a,b,c are in AP
then 2b = a + c
we know that :
if a,b,c are in AP
then 2b = a + c
here
=> 2(p+3) = { (p-1) + ( 3p -1) }
=> 2(p+3) = { (p-1) + ( 3p -1) }
=> 2p +6 = 4p -2
=> 2p = 8
=> p = 4
For what values of k can the following numbers form an A.P:2k-1,k+2,2k- a)3/ 2
- b)5/ 2
- c)2/ 3
- d)2/ 5
Correct answer is option 'B'. Can you explain this answer?
For what values of k can the following numbers form an A.P:2k-1,k+2,2k
a)
3/ 2
b)
5/ 2
c)
2/ 3
d)
2/ 5
|
|
Krishna Iyer answered |
If 2k-1,k+2,2k are in AP, the difference of two consecutive terms will be same.
Therefore,
Therefore,
The weights of 11 students selected for a team are noted in ascending order and are in A. P. The lowest value is 45 Kg, and the middle value is 55 Kg. What is the difference between the two values placed consecutively ?
- a)4
- b)2
- c)6
- d)3
Correct answer is option 'B'. Can you explain this answer?
The weights of 11 students selected for a team are noted in ascending order and are in A. P. The lowest value is 45 Kg, and the middle value is 55 Kg. What is the difference between the two values placed consecutively ?
a)
4
b)
2
c)
6
d)
3
|
Nk Classes answered |
as there are 11 students so 6 th student would be middle one
a=45
a+(6-1)d=55
a+5d=55
45+5d=55
5d=10
d=2
a=45
a+(6-1)d=55
a+5d=55
45+5d=55
5d=10
d=2
Amit starts his exercise regime with 25 push ups on Monday. He plans to increase 5 push ups every following Monday. How many push ups will he be doing on the 3rd Monday since he started?- a)60
- b)70
- c)35
- d)45
Correct answer is option 'C'. Can you explain this answer?
Amit starts his exercise regime with 25 push ups on Monday. He plans to increase 5 push ups every following Monday. How many push ups will he be doing on the 3rd Monday since he started?
a)
60
b)
70
c)
35
d)
45
|
|
Pooja Shah answered |
On 1st Monday he did 25
on 2nd next he did 25+5=30
on 3rd Monday he did 30+5=35
on 2nd next he did 25+5=30
on 3rd Monday he did 30+5=35
If p, q, r, s, t are the terms of an A.P. with common difference -1 the relation between p and t is:- a)t = p – 5
- b)t = p – 4
- c)t = p – 6
- d)t = p + 4
Correct answer is option 'B'. Can you explain this answer?
If p, q, r, s, t are the terms of an A.P. with common difference -1 the relation between p and t is:
a)
t = p – 5
b)
t = p – 4
c)
t = p – 6
d)
t = p + 4
|
|
Anita Menon answered |
p, q, r, s, t are the terms of AP. So a=p , d= -1
To find a relation between t and p we use
l=a+(n-1)d, where l=t and n=5
t=p+(5-1)(-1)=p+4(-1)=p-4
This is because the difference is negative so it will be smaller than p.
To find a relation between t and p we use
l=a+(n-1)d, where l=t and n=5
t=p+(5-1)(-1)=p+4(-1)=p-4
This is because the difference is negative so it will be smaller than p.
If a- b, 0 and a + b are consecutive terms of an AP then- a)a can take any real value and b = 0
- b)a = 0 and b can take any real value
- c)a = 1 and b= 0
- d)a = 0 and b = 1
Correct answer is option 'B'. Can you explain this answer?
If a- b, 0 and a + b are consecutive terms of an AP then
a)
a can take any real value and b = 0
b)
a = 0 and b can take any real value
c)
a = 1 and b= 0
d)
a = 0 and b = 1
|
Archana Pandey answered |
We know formula a-b ,a,a+b a=0 and b is unknown so it can be any real no like if b=3 then 0-3,0,0+3=-3,0,3 is an AP if b=4 then 0-4 , 0 ,0+4=-4,0,4 is an AP so b can be any real no.
Given an A.P. few of whose terms are x, y, 2, 4, 6, 8,………. What must be the values of x and y?- a)x = 2, y = -4
- b)x = -2, y = 0
- c)x = 0, y = -2
- d)x = -4, y = 2
Correct answer is option 'A'. Can you explain this answer?
Given an A.P. few of whose terms are x, y, 2, 4, 6, 8,………. What must be the values of x and y?
a)
x = 2, y = -4
b)
x = -2, y = 0
c)
x = 0, y = -2
d)
x = -4, y = 2
|
|
Raghav Bansal answered |
Arithmetic progression is a sequence of numbers such that the difference of any two successive members is a constant,d
AP is x, y, 2, 4, 6, 8,…
So we have 4-2=2,6-4=2 so we have d=2
So y=2-2=0
And x=0-2=-2
AP is x, y, 2, 4, 6, 8,…
So we have 4-2=2,6-4=2 so we have d=2
So y=2-2=0
And x=0-2=-2
From an A.P. 5 consecutive terms are required to be written. The central term out of the five terms is given as 5 and it’s informed that the common difference of the A.P. is 4. Write the 5 terms in the correct sequence.- a)1,3,5,7,9
- b)-10,-5,5,10,15
- c)-3,1,5,9,13
- d)3,4,5,6,7
Correct answer is option 'C'. Can you explain this answer?
From an A.P. 5 consecutive terms are required to be written. The central term out of the five terms is given as 5 and it’s informed that the common difference of the A.P. is 4. Write the 5 terms in the correct sequence.
a)
1,3,5,7,9
b)
-10,-5,5,10,15
c)
-3,1,5,9,13
d)
3,4,5,6,7
|
|
Pooja Shah answered |
AP is: a,a+d,a+2d,a+3d,a+4d
Middle term is a+2d=5
d=4
a+2d=5
a+2*4=5
a=5-8= -3
a+d= -3+4=1
a+3d= -3+3*4=-3+12=9
a+4d= -3+4*4= -3+16=13
So the terms are : -3,1,5,9,13
Middle term is a+2d=5
d=4
a+2d=5
a+2*4=5
a=5-8= -3
a+d= -3+4=1
a+3d= -3+3*4=-3+12=9
a+4d= -3+4*4= -3+16=13
So the terms are : -3,1,5,9,13
Roots of quadratic equation x2 – 3x = 0, will be- a)3
- b)0, –3
- c)0, 3
- d)none of these
Correct answer is option 'C'. Can you explain this answer?
Roots of quadratic equation x2 – 3x = 0, will be
a)
3
b)
0, –3
c)
0, 3
d)
none of these
|
|
Genius answered |
X² & 3x me se x common niklega ?,......................... x common nikla usko x-0 likh skte hai ?...
x(x-3)=0 » (x-0)(x-3)=0.............................
ab tere paas 2 equation hai ?............................... (x-0)=0..... & (x-3)=0........ ab samjhae why option c is correct ?
The IUPAC name of CH3-O-C2H5 is- a)Methyl ethane
- b)Ethoxy ethane
- c)Methoxy ethane
- d)Ethyl ethane
Correct answer is option 'C'. Can you explain this answer?
The IUPAC name of CH3-O-C2H5 is
a)
Methyl ethane
b)
Ethoxy ethane
c)
Methoxy ethane
d)
Ethyl ethane
|
Kds Coaching answered |
The compound CH3-O-C2H5 is an ether.
- The IUPAC name is based on identifying the groups attached to the oxygen atom.
- CH3 is the methoxy group.
- C2H5 is an ethyl group.
Therefore, the IUPAC name of the compound is methoxy ethane.
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