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All questions of 2012 for NEET Exam

In a flowering plant, the pollen tube first arrives in
  • a)
    egg
  • b)
    an antipodal cell
  • c)
    a synergid
  • d)
    central cell
Correct answer is option 'C'. Can you explain this answer?

Jyoti Kapoor answered
The correct option is C.
In flowering plants, the pollen tube first arrives in synergids. The pollen tube coming from the micropyle is first interacts with synergids and then to the egg cell in between the two synergids.

Which one of the following compounds is most acidic?



  • a)
    a
  • b)
    b
  • c)
    c
  • d)
    d
Correct answer is 'B'. Can you explain this answer?

Rekha Yadav answered
B is the right answere because there is -No2 group attached on the benzene ring which is an electron withdrawing group and so -I effect increase thus acidity increases.

A marble block of mass 2 kg lying on ice when given a velocity of 6 m/s is stopped by friction in 10 s. Then the coefficient offriction is
  • a)
    0.01
  • b)
    0.02
  • c)
    0.03
  • d)
    none of the above
Correct answer is 'B'. Can you explain this answer?

Rohan Singh answered
The answer is d.Mass of block, M = 2 kgInitial velocity, u = 6m/sFinal velocity , v =0time ,t = 10 sa=v−ut=0−610=−0.6m/s2Coefficient of friction = a/gμ=−0.69.8=−0.061-ve means direction of frictional force is opposite to motion of marble.

The ratio of radius of two bubbles is 2: 1. What is the ratio excess pressure inside them?
  • a)
    1 : 2
  • b)
    1 : 4
  • c)
    2 : 1
  • d)
    4 : 1
Correct answer is option 'A'. Can you explain this answer?

Rajeev Saxena answered
Given :
Let R1 and R2 be the radii of two soap bubbles
R1/R2=2/1
let σ be the surface tension of soap bubble.
Excess pressure inside bubble with radius R1=P1=4σ/R1
Excess pressure inside bubble with radius R2=P2=4σ/R2
P1/P2=[4σ/R1 ]xR2/4σ
=R2/R1
p1 / p2=1/2
hence the ratio is 1:2

Clamp connection is found In
  • a)
    Basidiomycetes
  • b)
    Ascomycetes
  • c)
    Saccharomycetes
  • d)
    Haplomycetes
Correct answer is option 'B'. Can you explain this answer?

Jeeshan Ahmed answered
Correct answer is basidiomycetes.In members of basidiomycetes cell division accompained by clamp connection.These are bridge hooke like connection .They function as bypass hyphae through which nuclei migrate to make all of mycelium diakaryotic.......

1 mole of gas occupies a volume of 200 mL at 100 mm pressure. What is the volume occupied by two moles of gas at 400 mm pressure and at same temperature?
  • a)
    50 ml.
  • b)
    100 mL
  • c)
    200 mL
  • d)
    400 mL
Correct answer is option 'B'. Can you explain this answer?

Kirti Kulkarni answered
equation 1:
PV= n RT
value of RT = PV/n
RT= 100×200/1 = 20000 .........(1)

equation 2:
PV = nRT
value of RT= PV/n
RT = 400×V/2 = 200V .........(2)


as both R And T are constant
we can equate both the equations

we get,
200V=20000
V= 100 ml

The reduction potential at pH = 14 for the Cue2+/Cu couples is [Given, E°Cu2+/Cu = 0.34V; Ksp Cu(OH)2 = 1 x 10-19
  • a)
    0.34 V
  • b)
    – 0.34 V
  • c)
    0.22 V
  • d)
    – 0.22 V
Correct answer is 'D'. Can you explain this answer?

Anjali Chauhan answered
°(Cu2+/Cu) = +0.34 V]

The reduction potential of Cue2/Cu at pH = 14 can be calculated using the Nernst equation:

E = E° - (0.0592/n) x log([Cu]/[Cue2])

Since the reduction potential of Cu2+/Cu is given, we can assume that Cue2/Cu2+ is in equilibrium with Cu/Cue2-. Therefore, we can use the following equations:

[Cue2-]/[Cu2+] = exp[(E° - E)/ (0.0592/n)]

[Cu]/[Cue2-] = [Cu2+]/[Cue2-] x [Cue2-]/[Cu] = [Cu2+]/[Cu] x [Cue2-]/[Cue2+]

At pH = 14, the concentration of Cu2+ and Cue2- can be assumed to be equal to 10^-14 M, since the dissociation constant of water (Kw) is 10^-14 M^2.

Substituting the given values into the equations, we get:

[Cue2-]/[Cu2+] = exp[(0.34 - E)/ (0.0592/2)] = exp[(0.34 - E)/ 0.0296]

[Cu]/[Cue2-] = [Cu2+]/[Cu] x [Cue2-]/[Cue2+] = 1 x [Cue2-]/[Cu2+] = [Cue2-]^2/[Cu2+] = 10^-28/[Cu2+]

Substituting the values into the Nernst equation, we get:

E = 0.34 - (0.0592/2) x log(exp[(0.34 - E)/ 0.0296]/10^-14)

Simplifying the equation, we get:

E = 0.34 - (0.0296/2) x log(exp[(0.34 - E)/ 0.0296])

E = 0.34 - 0.0148 x log(exp[(0.34 - E)/ 0.0296])

E = 0.34 - 0.0148 x [(0.34 - E)/ 0.0296]

E = 0.34 - 0.503 x (0.34 - E)

E = 0.34 - 0.17 + 0.503E

0.497E = 0.17

E = 0.34 - 0.34

E = 0 V

Therefore, the reduction potential of Cue2/Cu at pH = 14 is 0 V. This indicates that the Cue2/Cu couple is not stable at pH = 14 and Cu2+/Cu couple is more stable.

Excess carbohydrates and proteins are stored in the body as
  • a)
    amino acids
  • b)
    fats
  • c)
    starch
  • d)
    monosaccharides
Correct answer is option 'B'. Can you explain this answer?

Jaga Priyan answered
Muscle glycogen content varies from person to person, but it's approximately 500 grams . In circumstances in which you have all of the glucose your body needs and your glycogen stores are full, your body can convert excess carbohydrates into triglyceride molecules and store them as fat.

First National park developed in India is
  • a)
    Gir
  • b)
    Kaziranga
  • c)
    Jim Corbett
  • d)
    None of these
Correct answer is option 'C'. Can you explain this answer?

The first National Park in India was established as Hailey National Park in 1936. Now, it is known as Jim Corbett National Park. It is the oldest national park in India. It was named Hailey National Park after its founder Sir Malcolm Hailey. In 1956, in honour of Jim Corbett, who took the initiative for wildlife preservation in India, the Indian Government renamed it as Corbett National Park. It is located in the Nainital district of Uttarakhand. Therefore, the correct answer is option 'C'.

If the total amount of adenine and thymine in a double•stranded DNA is 60%, the amount of guanine in this DNA will be
  • a)
    15%
  • b)
    20%
  • c)
    30%
  • d)
    40%
Correct answer is option 'B'. Can you explain this answer?

Yes correct because of in DNA base pair arrange in complementary sequence for example A=T and G=_C then mentioned in question 60% AT 40% GC and when we are solve it then answer will be 20%

 If the total amount of adenine and thyrnine in a double-stranded DNA is 45%, the amount of guznine in this DNA will be
  • a)
    22.5%
  • b)
    27 5%
  • c)
    45%
  • d)
    55%
Correct answer is 'B'. Can you explain this answer?

Keerthana Saha answered
Explanation:

The four nitrogenous bases found in DNA are Adenine (A), Thymine (T), Guanine (G), and Cytosine (C).

In a double-stranded DNA, the amount of A always equals the amount of T and the amount of G always equals the amount of C.

If the total amount of A and T is 45%, then the total amount of G and C must also be 45% since they are always equal.

Therefore, the amount of G in this DNA would be 45% - 22.5% (since G and C are equal) = 22.5%

Hence, the correct answer is option B, 27.5%.

Equal volumes of three acid solutions of pH 3, 4 and 5 are mixed in a vessel. What will be the H+ ion concentration in the mixture?​
  • a)
    1.11 x 10-4 M
  • b)
    3.7 x 10-4 M
  • c)
    1.11 x 10-3 M
  • d)
    None of the above
Correct answer is option 'B'. Can you explain this answer?

Hridoy Mehta answered
The problem is valid only if strong acids are mixed. After mixing equal volumes of three acids, total volume = 3V.
∴ [H^+] after mixing
= 10^−3 x V/3V + 10^−4 x V/3V + 10^−5 x V/3V = 1.11 x 10^−3/3
= 3.7 x10^−4

The half-life of radioactive element is 600 yr. The fraction of sample that would remain after 3000 yr is
  • a)
    1/2
  • b)
    1/16
  • c)
    1/8
  • d)
    1/32
Correct answer is option 'D'. Can you explain this answer?

Devika Singh answered
Given: Half-life of radioactive element = 600 yr

To find: Fraction of sample that would remain after 3000 yr

Solution:

We know that the half-life of a radioactive substance is the time taken for the substance to decay to half of its initial value.

Let the initial amount of the substance be 1 unit.

After 1 half-life, the amount of substance remaining = 1/2 unit
After 2 half-lives, the amount of substance remaining = (1/2) * (1/2) = 1/4 unit
After 3 half-lives, the amount of substance remaining = (1/2) * (1/2) * (1/2) = 1/8 unit
After 4 half-lives, the amount of substance remaining = (1/2) * (1/2) * (1/2) * (1/2) = 1/16 unit

Therefore, after 5 half-lives (i.e. 3000 years in this case), the amount of substance remaining = (1/2)^5 = 1/32 unit.

Hence, the correct answer is option D, i.e. 1/32.

HIV is a member of a group of viruses called
  • a)
    bacteriophages
  • b)
    geminiviruses
  • c)
    lysogenic viruses
  • d)
    retroviruses
Correct answer is option 'D'. Can you explain this answer?

It's bcoz in all organism even all viruses are store their genetic material in form of DNA but in case of HIV virus it has genetic material as RNA so it belongs to retrovirus.

The headquarters of UNESCO is at
  • a)
    Rome
  • b)
    Geneva
  • c)
    Paris
  • d)
    New York
Correct answer is option 'C'. Can you explain this answer?

Vijay Bansal answered
UNESCO Headquarters or Maison de l'UNESCO is a building inaugurated on 3 November 1958 at number 7 Place de Fontenoy in Paris, France to serve as the headquarters for the United Nations Educational, Scientific and Cultural Organization. 

Tides are comhlied and they vary from place to place because of
  • a)
    the movemeni of moon in relation to earth
  • b)
    unevem distribution of water over the globe
  • c)
    irregularities in the configuration of oceans
  • d)
    All of the above
Correct answer is option 'D'. Can you explain this answer?

Raza Great answered
Tides are complied and they vary from place to place because of The movement of Moon in relation to Earth, Uneven distribution of water over the globe and Irregularities in the configuration of oceans.

A solid sphere rolls without slipping on the roof. The ratio of its rotational kinetic energy and its total kinetic energy is
  • a)
    2/S
  • b)
    4/5
  • c)
    2/7
  • d)
    3/7
Correct answer is option 'C'. Can you explain this answer?

Gopal Mehra answered
Solution:

When a solid sphere rolls without slipping on a surface, its total kinetic energy is given by the sum of its translational kinetic energy and rotational kinetic energy.

Let the mass of the sphere be m, radius be R and velocity be v.

Translational kinetic energy = (1/2)mv^2

Rotational kinetic energy = (1/2)Iω^2, where I is the moment of inertia of the sphere and ω is the angular velocity of the sphere.

For a solid sphere, moment of inertia I = (2/5)mr^2, where r is the radius of the sphere.

Since the sphere is rolling without slipping, its translational velocity v is related to its angular velocity ω as v = ωR.

Therefore, the total kinetic energy of the rolling sphere is given by:

K = (1/2)mv^2 + (1/2)Iω^2
= (1/2)mv^2 + (1/2)(2/5)mr^2(ω/R)^2
= (1/2)mv^2 + (1/5)mv^2
= (7/10)mv^2

The ratio of rotational kinetic energy to total kinetic energy is given by:

(rotational kinetic energy) / (total kinetic energy)
= [(1/2)Iω^2] / [(1/2)mv^2 + (1/2)Iω^2]
= [(1/2)(2/5)mr^2(ω/R)^2] / [(1/2)mv^2 + (1/2)(2/5)mr^2(ω/R)^2]
= (2/5)(ω/R)^2 / [v^2 + (2/5)(ω/R)^2]
= (2/5)(ω/Rv)^2 / [1 + (2/5)(ω/Rv)^2]

Substituting ω = v/R, we get:

(rotational kinetic energy) / (total kinetic energy)
= (2/5)(v/Rv)^2 / [1 + (2/5)(v/Rv)^2]
= (2/5)(1/1)^2 / [1 + (2/5)(1/1)^2]
= 2/7

Therefore, the correct option is (C) 2/7.

The principle that distinguishes Jainism from Buddhism is the
  • a)
    practice of the eight-fold path
  • b)
    rejection of the infallibility of the Vedas
  • c)
    attribution of a i.oul to all beings and things
  • d)
    belief in rebirth
Correct answer is option 'C'. Can you explain this answer?

Kirti Khanna answered
The Principle that Distinguishes Jainism from Buddhism: Attribution of a Soul to all Beings and Things

Jainism and Buddhism are two ancient religions that originated in India around the 6th century BCE. While they share some similarities, such as their emphasis on non-violence and the rejection of the caste system, there is a key principle that sets Jainism apart from Buddhism. This principle is the attribution of a soul, known as a jiva, to all beings and things.

Jainism and the Concept of Jiva

In Jainism, the concept of jiva is central to understanding the nature of existence. According to Jain philosophy, all living beings possess a soul or jiva, which is eternal and unchanging. This soul is believed to be distinct from the body and mind and is responsible for the individual's consciousness and experiences.

Belief in the Eternal Nature of the Soul

Jainism teaches that the soul is eternal and goes through a cycle of birth and death known as samsara. This belief in the transmigration of the soul is similar to the concept of rebirth in Buddhism. However, what sets Jainism apart is its assertion that not only humans and animals but also plants, rocks, and even inanimate objects possess a soul.

The Doctrine of Ahimsa

The concept of jiva is closely tied to the Jain principle of ahimsa, which means non-violence or non-harming. Jains believe that every living being, regardless of its form, possesses a soul and therefore deserves respect and compassion. This belief in the sanctity of all life forms has led Jains to adopt strict dietary and lifestyle practices, such as vegetarianism and avoiding harm to even the smallest organisms.

Buddhism and the Absence of a Permanent Soul

In contrast, Buddhism does not subscribe to the belief in a permanent, unchanging soul. According to Buddhist teachings, the self is an illusion or a construct of the mind, and there is no enduring entity that can be identified as a soul. Buddhism emphasizes the impermanence and interdependence of all phenomena, including sentient beings.

The Eightfold Path and the Rejection of the Vedas

Options a) and b) mentioned in the question, the practice of the eightfold path and the rejection of the infallibility of the Vedas, are not distinguishing principles of Jainism from Buddhism. The eightfold path is a fundamental practice in Buddhism that leads to the cessation of suffering, while the Vedas are ancient Hindu scriptures that both Jainism and Buddhism reject as authoritative texts.

In Conclusion

The key principle that distinguishes Jainism from Buddhism is the attribution of a soul to all beings and things. Jainism asserts that every living being, as well as non-living entities, possess an eternal and unchanging soul, known as jiva. This belief in the existence of a soul is central to Jain philosophy and shapes their understanding of the nature of existence and the practice of non-violence towards all forms of life. In contrast, Buddhism does not posit the existence of a permanent soul and instead focuses on the impermanence and interdependence of all phenomena.

Can you explain the answer of this question below:

Photon and electron are given same energy (10-20 J) Wavelength associated with photon statement will he and electron are λp and λe the correct

  • A:

    λp > λe

  • B:

    λp < λe

  • C:

    λp = λe

  • D:

    λe / λp = c

The answer is a.

Since Both are provided with same energy and it's the large amount of energy (as per the question given 10-20J) given to the microscopic particles, here kinetic energy dominates. Hence the debroglie wavelength inversely proportional to mass and photons are mass less, so photon has longer wavelength as electron is massive than photon. Hope you get it!

Can you explain the answer of this question below:

A mixture containing DNA fragments, a, b, c and d, with molecular weights of a b c. a > b and d > c, was subjected to agarose gel electrophoresis. The positions of these fragments from cathode to anode sides of the gel would be

  • A:

    b, a, c, d

  • B:

    a, b, c, d

  • C:

    c, b, a, d

  • D:

    b, a. d, c

The answer is a.

Aastha Agarwal answered
Lesser is the weight, far they move ... also as dna is negatively charged it moves towards cathode ... so either b or d is towards cathode first .. as there is no option with d first it's either 1or 4th option ... then similarly c is lighter than d , c comes be4 d .. Hence first option is correct

 In the equation.

Identify the metal M.
  • a)
    Copper
  • b)
    Iron
  • c)
    Gold
  • d)
    Zinc
Correct answer is 'C'. Can you explain this answer?

It is leaching methodgiven in metallurgy chapter of ncert of chemistry⭐💯💯💯⭐💯⭐💯💯⭐⭐⭐💯💯⭐⭐⭐💯💯⭐⭐⭐💯💯⭐⭐⭐💯💯⭐⭐⭐⭐⭐⭐⭐💯💯💯⭐💯💯⭐💯💯💯💯⭐💯💯💯💯⭐💯💯💯💯⭐💯💯⭐💯💯💯⭐⭐⭐⭐⭐⭐⭐💯💯💯⭐💯💯⭐💯💯💯💯⭐💯💯💯💯⭐💯💯💯💯⭐💯💯⭐💯💯💯⭐sure

A simple harmonic oscillator consists of a panicle of mass in and an ideal spring with spring constant k. The particle oscillates with a time period T. The spring is cut into two equal parts. If one part oscillates with the same particle, the time period will be
  • a)
    2T
  • b)
    √2T
  • c)
    T / √2
  • d)
    T/2
Correct answer is option 'C'. Can you explain this answer?

Explanation:

Concept:
- The time period of a simple harmonic oscillator is given by T = 2π√(m/k), where m is the mass of the particle and k is the spring constant.

When the spring is cut into two equal parts:
- When the spring is cut into two equal parts, the spring constant of each part becomes k/2.
- Due to conservation of energy, the time period of oscillation remains the same.

Calculation:
- For the original system with the full spring, T = 2π√(m/k).
- For each part of the spring after cutting, T' = 2π√(m/(k/2)) = 2π√(2m/k).
- Therefore, the new time period T' = T/√2.

Conclusion:
- When one part of the spring oscillates with the same particle, the time period of oscillation becomes T/√2.
- Hence, the correct answer is option 'C' - T/√2.

A transformer of 100% efficiency has 200 turns in the primary coil and 40000 rums in secondary coil. It is connected to a 220 V main supply and secondary feeds to a 100 kfl resistance. The potential difference per turn is
  • a)
    1.1 V
  • b)
    25 V
  • c)
    18 V
  • d)
    11 V
Correct answer is option 'A'. Can you explain this answer?

Anshika Shah answered
Potential difference per turn is given by the formula:

Vp = Vs/Ns

Where:
Vp = potential difference per turn in the primary coil
Vs = potential difference across the secondary coil
Ns = number of turns in the secondary coil

Given data:
Number of turns in the primary coil (Np) = 200
Number of turns in the secondary coil (Ns) = 40000
Potential difference across the secondary coil (Vs) = 220 V
Resistance in the secondary coil (Rs) = 100 kΩ = 100000 Ω

Let's calculate the potential difference per turn:

Step 1: Calculate the current flowing through the secondary coil using Ohm's law.

Is = Vs / Rs
= 220 V / 100000 Ω
= 0.0022 A

Step 2: Calculate the current flowing through the primary coil using the transformer equation.

Is / Ip = Ns / Np
Ip = (Ns / Np) * Is
= (40000 / 200) * 0.0022 A
= 0.44 A

Step 3: Calculate the potential difference per turn in the primary coil.

Vp = Ip * Rp
= 0.44 A * 220 V
= 96.8 V

Since we have 200 turns in the primary coil, the potential difference per turn is:

Vp / Np = 96.8 V / 200
= 0.484 V

Therefore, the potential difference per turn in the primary coil is approximately 0.484 V. None of the given options match this value, so the correct answer is not provided in the options given.

Note: The given answer in option 'A' is incorrect.

A thin convex lens of refractive index 1.5 has 20 cm focal length in air. If the lens is completely immersed in a liquid of refractive index 1.6, us focal length will be
  • a)
    – 160 cm,
  • b)
    – 100 cm
  • c)
    + 10 cm
  • d)
    + 100 cm
Correct answer is option 'A'. Can you explain this answer?

Using the formula $\frac{1}{f}=(n-1)\left(\frac{1}{R_1}-\frac{1}{R_2}\right)$, where $f$ is the focal length, $n$ is the refractive index, and $R_1$ and $R_2$ are the radii of curvature of the lens surfaces, we can solve for the new focal length $f'$:

In air:
$n_1=1$ (air)
$n_2=1.5$ (lens)
$f=20\text{ cm}$

$\frac{1}{20}=(1.5-1)\left(\frac{1}{R_1}-\frac{1}{R_2}\right)$

Simplifying:

$R_1=R_2=10\text{ cm}$ (since it's a thin lens, the radii of curvature are the same and equal to half the focal length)

When the lens is immersed in a liquid of refractive index 1.6, we have:

$n_1=1.6$ (liquid)
$n_2=1.5$ (lens)
$f'=?$

$\frac{1}{f'}=(1.5-1.6)\left(\frac{1}{10}-\frac{1}{10}\right)$

Simplifying:

$\frac{1}{f'}=0.1\times0$

Since the term on the right-hand side is zero, we can't solve for $f'$ using this formula. However, we know that when a lens is immersed in a medium of higher refractive index, its focal length decreases. Therefore, we can conclude that the focal length of the lens will be less than 20 cm when it is immersed in a liquid of refractive index 1.6.

An artificial satellite moving in a circular orbit around the earth has a total (kinetic + potential) energy E0. Its potential energy is
  • a)
    -E0
  • b)
    1.5 E0
  • c)
    2E0
  • d)
    E0
Correct answer is option 'C'. Can you explain this answer?

Preethi Saha answered
Explanation:

When an artificial satellite moves in a circular orbit around the earth, it experiences a gravitational force towards the center of the earth, which provides the necessary centripetal force to keep the satellite in the circular orbit.

The total energy of the satellite is the sum of its kinetic energy and potential energy.

1. Kinetic Energy of the Satellite:

The kinetic energy of the satellite is given by the formula:

KE = (1/2)mv^2

where m is the mass of the satellite and v is its velocity.

In a circular orbit, the velocity of the satellite is given by:

v = √(GM/r)

where G is the gravitational constant, M is the mass of the earth, and r is the radius of the orbit.

Substituting the value of v in the formula for KE, we get:

KE = (1/2)m(GM/r)

KE = (1/2)(GMm/r)

2. Potential Energy of the Satellite:

The potential energy of the satellite is given by the formula:

PE = -GMm/r

where G is the gravitational constant, M is the mass of the earth, m is the mass of the satellite, and r is the radius of the orbit.

3. Total Energy of the Satellite:

The total energy of the satellite is the sum of its kinetic energy and potential energy:

E0 = KE + PE

E0 = (1/2)(GMm/r) - (GMm/r)

E0 = -(1/2)(GMm/r)

Therefore, the potential energy of the satellite is given by:

PE = -E0/2

PE = -1/2(KE)

PE = -1/2(E0 - PE)

PE = -1/2E0 + 1/2PE

2PE = -E0

PE = -E0/2

Hence, option C is the correct answer: 2E0.

The moment of inertia of a circular loop of radius R. at a distance of R / 2 around a rotating axis parallel to horizontal diameter of loop is
  • a)
    MR2
  • b)
    1/2 MR2
  • c)
    2MR2
  • d)
    3/4 MR2
Correct answer is option 'D'. Can you explain this answer?

Shalini Saha answered
Final Answer: 3MR^2 / 4
Steps :
1) Find I (CM) about the axis of rotation in plane of Loop passing through diameter.
2) Use Parallel axis theorem to find Moment of Inertia at r/2 from it.
For Calculation see Pic.

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