What kV potential is to be applied on X-ray tube so that minimum wavel...
Lambda(minimum)=12375/V
V= 12375/1=12375V
12.375 kV is nearly equals to 12.42 kV
What kV potential is to be applied on X-ray tube so that minimum wavel...
To calculate the kV potential required to produce X-rays with a minimum wavelength of 1 A, we can use the equation for the energy of a photon: E = hc/λ, where E is the energy of the photon, h is the Planck's constant (6.6 x 10^-34 J-s), c is the speed of light (3 x 10^8 m/s), and λ is the wavelength of the photon.
We know that the energy of a photon is related to the potential difference applied to the X-ray tube by the equation: E = qV, where E is the energy of the photon, q is the charge of the electron (1.6 x 10^-19 C), and V is the potential difference applied to the X-ray tube.
By equating these two equations, we can solve for V:
hc/λ = qV
V = hc/(qλ)
Substituting the given values, we get:
V = (6.6 x 10^-34 J-s * 3 x 10^8 m/s) / (1.6 x 10^-19 C * 1 A)
V = 12.375 kV
Therefore, the kV potential required to produce X-rays with a minimum wavelength of 1 A is approximately 12.375 kV.
However, since the question asks for the minimum wavelength to be 1 A, the answer should be rounded up to the nearest whole number. Hence, the correct answer is option 'A': 12.42 kV.