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All questions of R-L & R-C Transients for Electrical Engineering (EE) Exam
Three inductors having inductance values 3H, 4H and 5H are connected in series, calculate the equivalent inductance.- a)10H
- b)12H
- c)3H
- d)5H
Correct answer is option 'B'. Can you explain this answer?
Three inductors having inductance values 3H, 4H and 5H are connected in series, calculate the equivalent inductance.
a)
10H
b)
12H
c)
3H
d)
5H
|
Zoya Sharma answered |
When inductances are connected in series, the equivalent inductance is equal to the sum of all the individual inductance values.
Hence Leq= L1+L2+L3= 12H.
Hence Leq= L1+L2+L3= 12H.
Initially, when the switch in a series RL circuit is closed, the inductor acts as?- a)Open circuit
- b)Short circuit
- c)Resistor
- d)Capacitor
Correct answer is option 'A'. Can you explain this answer?
Initially, when the switch in a series RL circuit is closed, the inductor acts as?
a)
Open circuit
b)
Short circuit
c)
Resistor
d)
Capacitor
|
Alok Verma answered |
Initially, when the switch in a series RL circuit is closed, the inductor acts as an open circuit. This is because the current gradually increases as the time increases. At t=0, the current in the inductor is zero, hence it acts as an open circuit.
If the current changes from 5A to 3A in 2 seconds and the inductance is 10H, calculate the emf.- a)5V
- b)10V
- c)15V
- d)20V
Correct answer is option 'B'. Can you explain this answer?
If the current changes from 5A to 3A in 2 seconds and the inductance is 10H, calculate the emf.
a)
5V
b)
10V
c)
15V
d)
20V
|
Shanaya Mehta answered |
We know that:
emf=L(i2-i1)/t
Substituting the values from the question, we get emf=10V.
emf=L(i2-i1)/t
Substituting the values from the question, we get emf=10V.
If the current changes from 5A to 3A in x sec and inductance is 10H. The emf is 10V, calculate the value of x.- a)2s
- b)3s
- c)4s
- d)5s
Correct answer is option 'A'. Can you explain this answer?
If the current changes from 5A to 3A in x sec and inductance is 10H. The emf is 10V, calculate the value of x.
a)
2s
b)
3s
c)
4s
d)
5s
|
Ravi Singh answered |
We know that:
emf=L(i2-i1)/t
Substituting the values from the question, we get x=2s.
emf=L(i2-i1)/t
Substituting the values from the question, we get x=2s.
If there are two bulbs connected in series and one blows out, what happens to the other bulb?- a)The other bulb continues to glow with the same brightness
- b)The other bulb stops glowing
- c)The other bulb glows with increased brightness
- d)The other bulb also burns out
Correct answer is option 'B'. Can you explain this answer?
If there are two bulbs connected in series and one blows out, what happens to the other bulb?
a)
The other bulb continues to glow with the same brightness
b)
The other bulb stops glowing
c)
The other bulb glows with increased brightness
d)
The other bulb also burns out
|
|
Vaishnavi Nair answered |
Since the two bulbs are connected in series, if the first bulb burns out there is a break in the circuit and hence the second bulb does not glow.
What is the total applied voltage in an inductive circuit?- a)V=Ri+Ldi/dt
- b)V=Ri+di/dt
- c)V=i+Ldi/dt
- d)V=R+Ldi/dt
Correct answer is option 'A'. Can you explain this answer?
What is the total applied voltage in an inductive circuit?
a)
V=Ri+Ldi/dt
b)
V=Ri+di/dt
c)
V=i+Ldi/dt
d)
V=R+Ldi/dt
|
Lavanya Menon answered |
The total voltage in an inductive circuit is the sum of the voltage due to the resistor which is Ri and the voltage due to the inductor which is Ldi/dt. Hence V=Ri+Ldi/dt.
What is the expression for current in the given circuit?
- a) i=2(e-2t)A
- b) i=2(1-e-2t)A
- c) i=2(e2t)A
- d)i=2(1+e-2t)A
Correct answer is option 'B'. Can you explain this answer?
What is the expression for current in the given circuit?
a)
i=2(e-2t)A
b)
i=2(1-e-2t)A
c)
i=2(e2t)A
d)
i=2(1+e-2t)A
|
Preethi Banerjee answered |
At t = 0+ the current in the circuit is zero. Therefore at t = 0+, i = 0, 0 = c + 2, c = -2. Substituting the value of c in the current equation, we have i = 2(1-e-2t)A.
What happens to the inductance when the current in the coil becomes double its original value?- a)Becomes half
- b)Becomes four times
- c)Becomes infinity
- d)Becomes double
Correct answer is option 'D'. Can you explain this answer?
What happens to the inductance when the current in the coil becomes double its original value?
a)
Becomes half
b)
Becomes four times
c)
Becomes infinity
d)
Becomes double
|
|
Lavanya Menon answered |
The formula for magnetic field strength in a coil is:
H=iN/l
The inductance is: directly proportional to magnetic field strength, hence as the current value doubles, the inductance also doubles.
H=iN/l
The inductance is: directly proportional to magnetic field strength, hence as the current value doubles, the inductance also doubles.
An induced emf is said to be ________- a)Inductive
- b)Capacitive
- c)Resistive
- d)Cannot be determined
Correct answer is option 'A'. Can you explain this answer?
An induced emf is said to be ________
a)
Inductive
b)
Capacitive
c)
Resistive
d)
Cannot be determined
|
Nayanika Kaur answered |
Any circuit in which a change of current is accompanied by a change of flux, and therefore by an induced emf, is said to be inductive.
Calculate the number of turns in an inductor with a ferromagnetic core when the inductance is 0.004H, the current changes from 5A to 7A and the flux changes from 760 to 800 ∫Wb.- a)100
- b)200
- c)300
- d)400
Correct answer is option 'B'. Can you explain this answer?
Calculate the number of turns in an inductor with a ferromagnetic core when the inductance is 0.004H, the current changes from 5A to 7A and the flux changes from 760 to 800 ∫Wb.
a)
100
b)
200
c)
300
d)
400
|
Bijoy Nair answered |
From the formula of incremental inductance, we know that:
L=(Change in flux/Change in current)*Number of turns
Substituting the values from the given question, we get N=200.
L=(Change in flux/Change in current)*Number of turns
Substituting the values from the given question, we get N=200.
Calculate the value of emf in an inductor if the value of inductance is 15H and an average current of 5A flows through it in 10s.- a)15V
- b)7.5V
- c)10V
- d)5.5V
Correct answer is option 'B'. Can you explain this answer?
Calculate the value of emf in an inductor if the value of inductance is 15H and an average current of 5A flows through it in 10s.
a)
15V
b)
7.5V
c)
10V
d)
5.5V
|
|
Arya Mukherjee answered |
The expression for emf in an inductive circuit is:
emf= LI/2t, where I/2 is the average current.
Substituting the values from the given question, we get emf= 2.5V.
emf= LI/2t, where I/2 is the average current.
Substituting the values from the given question, we get emf= 2.5V.
In a series circuit, which of the parameters remain constant across all circuit elements such as resistor, capacitor, inductor etcetera?- a)Voltage
- b)Current
- c)Both voltage and current
- d)Neither voltage nor current
Correct answer is option 'B'. Can you explain this answer?
In a series circuit, which of the parameters remain constant across all circuit elements such as resistor, capacitor, inductor etcetera?
a)
Voltage
b)
Current
c)
Both voltage and current
d)
Neither voltage nor current
|
|
Zoya Sharma answered |
In a series circuit, the current across all elements remain the same and the total voltage of the circuit is the sum of the voltages across all the elements.
For a coil having a magnetic circuit of constant reluctance, the flux is ___________ to the current.- a)Directly proportional
- b)Inversely proportional
- c)Not related
- d)Very large compared to
Correct answer is option 'A'. Can you explain this answer?
For a coil having a magnetic circuit of constant reluctance, the flux is ___________ to the current.
a)
Directly proportional
b)
Inversely proportional
c)
Not related
d)
Very large compared to
|
|
Tanishq Chauhan answered |
For a coil having a magnetic circuit of constant reluctance, the flux is directly proportional to the current.
At steady state, the current in the inductor is?- a)Maximum
- b)Minimum
- c)Zero
- d)Infinity
Correct answer is option 'A'. Can you explain this answer?
At steady state, the current in the inductor is?
a)
Maximum
b)
Minimum
c)
Zero
d)
Infinity
|
Yash Patel answered |
At steady state maximum current flows in the inductor because it acts as an open circuit.
In case of Inductive circuit, Frequency is ______________ to the current.- a)Directly proportional
- b)Inversely proportional
- c)Unrelated
- d)Much greater than
Correct answer is option 'B'. Can you explain this answer?
In case of Inductive circuit, Frequency is ______________ to the current.
a)
Directly proportional
b)
Inversely proportional
c)
Unrelated
d)
Much greater than
|
|
Mansi Choudhury answered |
Inductance is inversely proportional to current since, as the inductance increases, current decreases.
Among the following, which is the right formula for inductance?- a)L=emf*t/I
- b)L=emf/t*I
- c)L=emf*I/t
- d)L=emf*t*I
Correct answer is option 'A'. Can you explain this answer?
Among the following, which is the right formula for inductance?
a)
L=emf*t/I
b)
L=emf/t*I
c)
L=emf*I/t
d)
L=emf*t*I
|
Sanya Agarwal answered |
The average emf induced is proportional to the current per unit time, the constant of proportionality being L. Hence emf=LI/t. Making L the subject of the formula, we get: L=emf*t/I.
At steady state, inductor acts as ____________- a)Open circuit
- b)Short circuit
- c)Resistor
- d)Capacitor
Correct answer is option 'B'. Can you explain this answer?
At steady state, inductor acts as ____________
a)
Open circuit
b)
Short circuit
c)
Resistor
d)
Capacitor
|
|
Yash Patel answered |
At steady state, inductor acts as a short circuit because at steady state maximum current flows across the inductor. Hence it acts as a zero resistance source or an open circuit.
Which, among the following, is the correct formula to fing coupling coefficient?- a)k=M/sqrt(L1L2)
- b)k=M/sqrt(L12)
- c)k=M/sqrt(L22)
- d)k=M/(L1L2)
Correct answer is option 'A'. Can you explain this answer?
Which, among the following, is the correct formula to fing coupling coefficient?
a)
k=M/sqrt(L1L2)
b)
k=M/sqrt(L12)
c)
k=M/sqrt(L22)
d)
k=M/(L1L2)
|
|
Nilesh Joshi answered |
The correct formula for coupling coefficient is k=M/sqrt(L1L2). Where, L1 and L2 are the inductance values of the first and second coil respectively and M is the mutual inductance.
When inductors are connected in series, the voltage across each inductor is _________- a)Equal
- b)Different
- c)Zero
- d)Infinity
Correct answer is option 'B'. Can you explain this answer?
When inductors are connected in series, the voltage across each inductor is _________
a)
Equal
b)
Different
c)
Zero
d)
Infinity
|
Ameya Gupta answered |
In a series circuit, the current across all elements remain the same and the total voltage of the circuit is the sum of the voltages across all the elements.
Calculate the emf induced in an inductor if the inductance is 10H and the current is 2A in 4s.- a)2.5V
- b)1.5V
- c)3.5V
- d)5V
Correct answer is option 'A'. Can you explain this answer?
Calculate the emf induced in an inductor if the inductance is 10H and the current is 2A in 4s.
a)
2.5V
b)
1.5V
c)
3.5V
d)
5V
|
Malavika Nair answered |
The expression for emf in an inductive circuit is:
emf= LI/2t
Substituting the values from the given question, we get emf= 2.5V.
emf= LI/2t
Substituting the values from the given question, we get emf= 2.5V.
Calculate the current in an inductor if the energy stored is 160J and the inductance is 20H.- a)1A
- b)2A
- c)3A
- d)4A
Correct answer is option 'D'. Can you explain this answer?
Calculate the current in an inductor if the energy stored is 160J and the inductance is 20H.
a)
1A
b)
2A
c)
3A
d)
4A
|
|
Ishan Chawla answered |
The expression for energy in an inductor is:
W= LI2/2t
Substituting the values from the given question, we get I=4A.
W= LI2/2t
Substituting the values from the given question, we get I=4A.
The charging time constant of a circuit consisting of an inductor is the time taken for the voltage in the inductor to become __________% of the initial voltage.- a)33
- b)63
- c)37
- d)36
Correct answer is option 'B'. Can you explain this answer?
The charging time constant of a circuit consisting of an inductor is the time taken for the voltage in the inductor to become __________% of the initial voltage.
a)
33
b)
63
c)
37
d)
36
|
Kunal Sharma answered |
We know that: V=V0(1-e-t /time constant).
When time constant=t, we have: V=V0(1-e-1)= 0.63*V0.
Hence the time constant is the time taken for the charge in an inductive circuit to become 0.63 times its initial charge.
When time constant=t, we have: V=V0(1-e-1)= 0.63*V0.
Hence the time constant is the time taken for the charge in an inductive circuit to become 0.63 times its initial charge.
The discharging time constant of a circuit consisting of an inductor is the time taken for the voltage in the inductor to become __________% of the initial voltage.- a)33
- b)63
- c)37
- d)36
Correct answer is option 'D'. Can you explain this answer?
The discharging time constant of a circuit consisting of an inductor is the time taken for the voltage in the inductor to become __________% of the initial voltage.
a)
33
b)
63
c)
37
d)
36
|
|
Pranab Basu answered |
We know that: V=V0(e-t/time constant).
When time constant=t, we have: V=V0(e-1)= 0.36*V0.
Hence the time constant is the time taken for the charge in an inductive circuit to become 0.36 times its initial charge.
When time constant=t, we have: V=V0(e-1)= 0.36*V0.
Hence the time constant is the time taken for the charge in an inductive circuit to become 0.36 times its initial charge.
If either the inductance or the rate of change of current is doubled, the induced e.m.f?- a)Remains constant
- b)Becomes zero
- c)Doubles
- d)Becomes half
Correct answer is option 'C'. Can you explain this answer?
If either the inductance or the rate of change of current is doubled, the induced e.m.f?
a)
Remains constant
b)
Becomes zero
c)
Doubles
d)
Becomes half
|
|
Parth Ghoshal answered |
If either the inductance or the rate of change of current is doubled, the induced e.m.f. becomes double because, emf=LI/t.
At DC, inductor acts as _____________- a)Open circuit
- b)Short circuit
- c)Resistor
- d)Inductor
Correct answer is option 'B'. Can you explain this answer?
At DC, inductor acts as _____________
a)
Open circuit
b)
Short circuit
c)
Resistor
d)
Inductor
|
|
Shivam Das answered |
At DC, the inductor acts as short circuit because the inductive resistance is zero. The frequency of a DC circuit is 0. The inductive resistance=(2*pi*f*L). Therefore, if the frequency is 0, the inductive resistance is zero and it acts as an short circuit.
Can the coupling coefficient practically ever be equal to 1?- a)Yes
- b)No
- c)Depends on current in coil 1
- d)Depends on current in coil 2
Correct answer is option 'B'. Can you explain this answer?
Can the coupling coefficient practically ever be equal to 1?
a)
Yes
b)
No
c)
Depends on current in coil 1
d)
Depends on current in coil 2
|
|
Dipika Basak answered |
Coupling coefficient can never be equal to 1 because all the flux of coil 1 can never link with coil 2. There are bound to be losses.
What is the unit for inductive reactance?- a)Henry
- b)Ohm
- c)Farad
- d)Volts
Correct answer is option 'B'. Can you explain this answer?
What is the unit for inductive reactance?
a)
Henry
b)
Ohm
c)
Farad
d)
Volts
|
|
Sanya Agarwal answered |
Inductive reactance is nothing but the impedance. Impedance is the AC equivalent of resistance, hence the unit for inductive reactance is ohm.
If the power factor is 10 and the value of inductive reactance is 20 ohm, calculate the resistance in the circuit.- a)1 ohm
- b)2 ohm
- c)3 ohm
- d)4 ohm
Correct answer is option 'B'. Can you explain this answer?
If the power factor is 10 and the value of inductive reactance is 20 ohm, calculate the resistance in the circuit.
a)
1 ohm
b)
2 ohm
c)
3 ohm
d)
4 ohm
|
|
Poulomi Ahuja answered |
We know that:
cos(phi)=R/XL
From the given question, we find that the resistance in the circuit is 2 ohm.
cos(phi)=R/XL
From the given question, we find that the resistance in the circuit is 2 ohm.
Calculate the power in an inductive circuit if the inductance is 10H, the current flowing in the inductor is 2A in 4s.- a)50W
- b)4W
- c)5W
- d)10W
Correct answer is option 'C'. Can you explain this answer?
Calculate the power in an inductive circuit if the inductance is 10H, the current flowing in the inductor is 2A in 4s.
a)
50W
b)
4W
c)
5W
d)
10W
|
Prerna Tiwari answered |
The expression for power in an inductive circuit is:
P= LI2/2
Substituting the values from the given question, we get P=5W.
P= LI2/2
Substituting the values from the given question, we get P=5W.
Among the following, which is the right formula for inductance?- a)L=emf*t/I
- b)L=emf/t*I
- c)L=emf*I/t
- d)L=emf*t*I
Correct answer is option 'A'. Can you explain this answer?
Among the following, which is the right formula for inductance?
a)
L=emf*t/I
b)
L=emf/t*I
c)
L=emf*I/t
d)
L=emf*t*I
|
|
Avik Iyer answered |
The average emf induced is proportional to the current per unit time, the constant of proportionality being L. Hence emf=LI/t. Making L the subject of the formula, we get: L=emf*t/I.
Calculate the initial current in an inductor having inductance 0.004H, number of turns is 200 and the flux changes from 760 to 800 ∫Wb. Current changes to 7A.- a)10A
- b)2A
- c)5A
- d)3A
Correct answer is option 'C'. Can you explain this answer?
Calculate the initial current in an inductor having inductance 0.004H, number of turns is 200 and the flux changes from 760 to 800 ∫Wb. Current changes to 7A.
a)
10A
b)
2A
c)
5A
d)
3A
|
|
Abhishek Chauhan answered |
From the formula of incremental inductance, we know that:
L=(Change in flux/Change in current)*Number of turns
Substituting the values from the given question, we get change in current= 2A.
Change in current= final current- initial current.
2=7-initial current.
Initial current= 5A.
L=(Change in flux/Change in current)*Number of turns
Substituting the values from the given question, we get change in current= 2A.
Change in current= final current- initial current.
2=7-initial current.
Initial current= 5A.
The discharging time constant of a circuit consisting of an inductor is the time taken for the voltage in the inductor to become __________% of the initial voltage.- a)33
- b)63
- c)37
- d)36
Correct answer is option 'D'. Can you explain this answer?
The discharging time constant of a circuit consisting of an inductor is the time taken for the voltage in the inductor to become __________% of the initial voltage.
a)
33
b)
63
c)
37
d)
36
|
|
Vaishnavi Singh answered |
We know that: V=V0(e-t/time constant).
When time constant=t, we have: V=V0(e-1)= 0.36*V0.
Hence the time constant is the time taken for the charge in an inductive circuit to become 0.36 times its initial charge.
When time constant=t, we have: V=V0(e-1)= 0.36*V0.
Hence the time constant is the time taken for the charge in an inductive circuit to become 0.36 times its initial charge.
What is the time constant of an inductive circuit?- a)LR
- b)R/L
- c)1/LR
- d)L/R
Correct answer is option 'D'. Can you explain this answer?
What is the time constant of an inductive circuit?
a)
LR
b)
R/L
c)
1/LR
d)
L/R
|
|
Nikhil Iyer answered |
The time constant in an inductive circuit is the time taken for the voltage across the inductor to become 63 percent of its initial value. It is given by: Time constant= L/R.
The flux linkage in coil 1 is x Wb-t and it has 500 turns and the current in coil 2 is 2A, calculate the value of x if the mutual inductance is 750H.- a)1Wb-t
- b)2Wb-t
- c)3Wb-t
- d)4Wb-t
Correct answer is option 'C'. Can you explain this answer?
The flux linkage in coil 1 is x Wb-t and it has 500 turns and the current in coil 2 is 2A, calculate the value of x if the mutual inductance is 750H.
a)
1Wb-t
b)
2Wb-t
c)
3Wb-t
d)
4Wb-t
|
|
Mayank Sengupta answered |
We know that mutual inductance is the product of the number of turns in one coil and the flux linkages of that coil, divided by the current in the other coil.
φ=750*2/500= 3Wb-t.
φ=750*2/500= 3Wb-t.
Calculate the inductance in an inductive circuit whose time constant is 2s and the resistance is 5 ohm.- a)10H
- b)20H
- c)5H
- d)15H
Correct answer is option 'A'. Can you explain this answer?
Calculate the inductance in an inductive circuit whose time constant is 2s and the resistance is 5 ohm.
a)
10H
b)
20H
c)
5H
d)
15H
|
Jaya Datta answered |
We know that: Time constant= L/R
Substituting the values from the given question, we get L=10H.
Substituting the values from the given question, we get L=10H.
Among the following, which is the right formula for inductance?- a)L=NΦ/t
- b)L=NΦt
- c)L=N/Φt
- d)L=NΦ2t
Correct answer is option 'A'. Can you explain this answer?
Among the following, which is the right formula for inductance?
a)
L=NΦ/t
b)
L=NΦt
c)
L=N/Φt
d)
L=NΦ2t
|
|
Aditya Basu answered |
We know that:
emf=L(i2-i1)/t
Inductance = L=NΦ/t.
emf=L(i2-i1)/t
Inductance = L=NΦ/t.
If the switch is closes at t=0, what is the current in the circuit?
- a)0A
- b)10A
- c)20A
- d)30A
Correct answer is option 'A'. Can you explain this answer?
If the switch is closes at t=0, what is the current in the circuit?
a)
0A
b)
10A
c)
20A
d)
30A
|
Engineering Essentials. answered |
Due to the presence of inductor current won't rise immediately when the switch is closed. inductor current= integral V dt. over 0 seconds results in zero
If the current changes from 20A to 10A in 5 seconds and the value of inductance is 1H, calculate the emf induced.- a)8V
- b)6V
- c)4V
- d)2V
Correct answer is option 'D'. Can you explain this answer?
If the current changes from 20A to 10A in 5 seconds and the value of inductance is 1H, calculate the emf induced.
a)
8V
b)
6V
c)
4V
d)
2V
|
|
Jyoti Basak answered |
We know that:
emf=L(i2-i1)/t
Substituting the values from the question we get emf=2V.
emf=L(i2-i1)/t
Substituting the values from the question we get emf=2V.
In an inductive circuit, when the XL value increases, the circuit power factor?- a)Increases
- b)Decreases
- c)Remains the same
- d)Becomes zero
Correct answer is option 'B'. Can you explain this answer?
In an inductive circuit, when the XL value increases, the circuit power factor?
a)
Increases
b)
Decreases
c)
Remains the same
d)
Becomes zero
|
|
Avik Iyer answered |
The power factor, that is, cos(phi) is equal to the resistance divided by the impedance in the circuit, hence as impedance increases, the power factor decreases.
Find the average current in an inductor if the total current in the inductor is 26A.- a)10A
- b)26A
- c)13A
- d)5A
Correct answer is option 'C'. Can you explain this answer?
Find the average current in an inductor if the total current in the inductor is 26A.
a)
10A
b)
26A
c)
13A
d)
5A
|
|
Nandita Bajaj answered |
Average current= I/2.
Substituting the value of I from the equation, average current= 13A.
Substituting the value of I from the equation, average current= 13A.
If the current in one coil becomes steady, the magnetic field is?- a)Zero
- b)Infinity
- c)Doubles
- d)Halves
Correct answer is option 'A'. Can you explain this answer?
If the current in one coil becomes steady, the magnetic field is?
a)
Zero
b)
Infinity
c)
Doubles
d)
Halves
|
|
Jaya Rane answered |
A magnetic field is produced when there is a changing electric field. Hence the magnetic field is zero when the current is steady.
If the current in one coil is steady, what happens to the mutual inductance?- a)Zero
- b)Infinity
- c)Doubles
- d)Halves
Correct answer is option 'A'. Can you explain this answer?
If the current in one coil is steady, what happens to the mutual inductance?
a)
Zero
b)
Infinity
c)
Doubles
d)
Halves
|
|
Lavanya Menon answered |
A magnetic field is produced when there is a changing electric field. Hence the magnetic field is zero when the current is steady. When the magnetic field is zero there is no current induced in the other coil, thus electric field is zero.
Calculate the time constant of an inductive circuit having resistance 5 ohm and inductance 10H.- a)2s
- b)4s
- c)5s
- d)10s
Correct answer is option 'A'. Can you explain this answer?
Calculate the time constant of an inductive circuit having resistance 5 ohm and inductance 10H.
a)
2s
b)
4s
c)
5s
d)
10s
|
|
Disha Das answered |
We know that: Time constant= L/R
Substituting the values from the given question, we get time constant= 2s.
Substituting the values from the given question, we get time constant= 2s.
An RL network is one which consists of ____________- a)Resistor and capacitor in parallel
- b)Resistor and capacitor in series
- c)Resistor and inductor in parallel
- d)Resistor and inductor in series
Correct answer is option 'D'. Can you explain this answer?
An RL network is one which consists of ____________
a)
Resistor and capacitor in parallel
b)
Resistor and capacitor in series
c)
Resistor and inductor in parallel
d)
Resistor and inductor in series
|
Anuj Rane answered |
An R-L network is a network which consists of a resistor which is connected in series to an inductor.
What happens to the effective inductance when a ferromagnetic core is introduced?- a)Increases
- b)Decreases
- c)Remains the same
- d)Becomes zero
Correct answer is option 'A'. Can you explain this answer?
What happens to the effective inductance when a ferromagnetic core is introduced?
a)
Increases
b)
Decreases
c)
Remains the same
d)
Becomes zero
|
|
Dipanjan Nambiar answered |
The effective inductance increases when a ferromagnetic core is introduced within an inductor because the flux increases. Inductance varies directly with the flux hence it increases.
The flux linkage in coil 1 is 3Wb-t and it has x turns and the current in coil 2 is 2A, calculate the value of x if the mutual inductance is 750H.- a)300
- b)400
- c)500
- d)700
Correct answer is option 'C'. Can you explain this answer?
The flux linkage in coil 1 is 3Wb-t and it has x turns and the current in coil 2 is 2A, calculate the value of x if the mutual inductance is 750H.
a)
300
b)
400
c)
500
d)
700
|
|
Avik Saha answered |
We know that mutual inductance is the product of the number of turns in one coil and the flux linkages of that coil, divided by the current in the other coil.
N=750*2/3= 300 turns.
N=750*2/3= 300 turns.
A coil has a resistance of 4 ohm and an inductance of 2H. It is connected to a 20V dc supply. Calculate the final value of current in the circuit.- a)5A
- b)10A
- c)15A
- d)20A
Correct answer is option 'A'. Can you explain this answer?
A coil has a resistance of 4 ohm and an inductance of 2H. It is connected to a 20V dc supply. Calculate the final value of current in the circuit.
a)
5A
b)
10A
c)
15A
d)
20A
|
|
Prerna Tiwari answered |
The final value of current in the circuit is:
I=V/R= 5A.
I=V/R= 5A.
What is Helmholtz equation?- a) i=I(1-eRt/L)
- b) i=I(1-e-Rt/L)
- c) i=I(1+e-Rt/L)
- d) i=I(e-Rt/L)
Correct answer is option 'B'. Can you explain this answer?
What is Helmholtz equation?
a)
i=I(1-eRt/L)
b)
i=I(1-e-Rt/L)
c)
i=I(1+e-Rt/L)
d)
i=I(e-Rt/L)
|
|
Aaditya Choudhary answered |
Helmholtz equation is an equation which gives the formula for the growth in an inductive circuit. Hence the Helmholtz formula is: i=I(1-e-Rt/L).
Chapter doubts & questions for R-L & R-C Transients - 6 Months Preparation for GATE Electrical 2025 is part of Electrical Engineering (EE) exam preparation. The chapters have been prepared according to the Electrical Engineering (EE) exam syllabus. The Chapter doubts & questions, notes, tests & MCQs are made for Electrical Engineering (EE) 2025 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests here.
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