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Calculate the number of turns in an inductor with a ferromagnetic core when the inductance is 0.004H, the current changes from 5A to 7A and the flux changes from 760 to 800 ∫Wb.
- a)100
- b)200
- c)300
- d)400
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
Calculate the number of turns in an inductor with a ferromagnetic core...
From the formula of incremental inductance, we know that:
L=(Change in flux/Change in current)*Number of turns
Substituting the values from the given question, we get N=200.
L=(Change in flux/Change in current)*Number of turns
Substituting the values from the given question, we get N=200.
Most Upvoted Answer
Calculate the number of turns in an inductor with a ferromagnetic core...
To calculate the number of turns in an inductor with a ferromagnetic core, we can use the formula:
L = (N^2 * μ * A) / l
Where:
L is the inductance (0.004H)
N is the number of turns (unknown)
μ is the permeability of the core material (unknown)
A is the cross-sectional area of the core (unknown)
l is the length of the core (unknown)
We can rearrange the formula to solve for N:
N^2 = (L * l) / (μ * A)
Now, let's calculate the change in flux:
ΔΦ = (ΔI * L) / Δt
Where:
ΔΦ is the change in flux (800 - 760 = 40)
ΔI is the change in current (7 - 5 = 2)
Δt is the change in time (unknown)
We can rearrange the formula to solve for Δt:
Δt = (ΔI * L) / ΔΦ
Now, let's substitute the values into the formulas:
N^2 = (0.004 * l) / (μ * A)
Δt = (2 * 0.004) / 40 = 0.0002 seconds
Since we don't have the values for l, μ, and A, we cannot calculate the exact number of turns.
L = (N^2 * μ * A) / l
Where:
L is the inductance (0.004H)
N is the number of turns (unknown)
μ is the permeability of the core material (unknown)
A is the cross-sectional area of the core (unknown)
l is the length of the core (unknown)
We can rearrange the formula to solve for N:
N^2 = (L * l) / (μ * A)
Now, let's calculate the change in flux:
ΔΦ = (ΔI * L) / Δt
Where:
ΔΦ is the change in flux (800 - 760 = 40)
ΔI is the change in current (7 - 5 = 2)
Δt is the change in time (unknown)
We can rearrange the formula to solve for Δt:
Δt = (ΔI * L) / ΔΦ
Now, let's substitute the values into the formulas:
N^2 = (0.004 * l) / (μ * A)
Δt = (2 * 0.004) / 40 = 0.0002 seconds
Since we don't have the values for l, μ, and A, we cannot calculate the exact number of turns.
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Calculate the number of turns in an inductor with a ferromagnetic core...
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Calculate the number of turns in an inductor with a ferromagnetic core when the inductance is 0.004H, the current changes from 5A to 7A and the flux changes from 760 to 800 ∫Wb.a)100b)200c)300d)400Correct answer is option 'B'. Can you explain this answer?
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Calculate the number of turns in an inductor with a ferromagnetic core when the inductance is 0.004H, the current changes from 5A to 7A and the flux changes from 760 to 800 ∫Wb.a)100b)200c)300d)400Correct answer is option 'B'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about Calculate the number of turns in an inductor with a ferromagnetic core when the inductance is 0.004H, the current changes from 5A to 7A and the flux changes from 760 to 800 ∫Wb.a)100b)200c)300d)400Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Calculate the number of turns in an inductor with a ferromagnetic core when the inductance is 0.004H, the current changes from 5A to 7A and the flux changes from 760 to 800 ∫Wb.a)100b)200c)300d)400Correct answer is option 'B'. Can you explain this answer?.
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