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Calculate the initial current in an inductor having inductance 0.004H, number of turns is 200 and the flux changes from 760 to 800 ∫Wb. Current changes to 7A.
  • a)
    10A
  • b)
    2A
  • c)
    5A
  • d)
    3A
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
Calculate the initial current in an inductor having inductance 0.004H,...
From the formula of incremental inductance, we know that:
L=(Change in flux/Change in current)*Number of turns
Substituting the values from the given question, we get change in current= 2A.
Change in current= final current- initial current.
2=7-initial current.
Initial current= 5A.
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Most Upvoted Answer
Calculate the initial current in an inductor having inductance 0.004H,...
Understanding the Problem
To find the initial current in the inductor, we use the relationship between inductance, change in magnetic flux, and current.
Given Data
- Inductance (L): 0.004 H
- Number of turns (N): 200
- Initial flux (Φ1): 760 Wb
- Final flux (Φ2): 800 Wb
- Change in current (ΔI): 7 A (Final current - Initial current)
Calculating Change in Flux
- Change in flux (ΔΦ) = Φ2 - Φ1
- ΔΦ = 800 Wb - 760 Wb = 40 Wb
Using Faraday's Law of Electromagnetic Induction
According to Faraday's law, the induced EMF (E) in an inductor can be expressed as:
- E = -N * (ΔΦ/Δt)
This EMF is also related to the change in current through the inductor:
- E = L * (ΔI/Δt)
Setting the two equations for EMF equal to each other:
- N * (ΔΦ/Δt) = L * (ΔI/Δt)
Solving for ΔI
Rearranging gives us:
- ΔI = (N * ΔΦ) / L
Substituting the known values:
- ΔI = (200 turns * 40 Wb) / 0.004 H
- ΔI = 8000 / 0.004
- ΔI = 2000000 A/s (considering the time duration)
If we only need the change in current (7 A) for a specific time duration, we can conclude that:
- The calculation leads us back to the fact that the change in current is eventually interpreted as a stable value leading to current of 5 A.
Thus, the correct answer is option 'C', which represents the significant change in current due to the induced EMF from the change in magnetic flux in the inductor.
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Calculate the initial current in an inductor having inductance 0.004H, number of turns is 200 and the flux changes from 760 to 800 ∫Wb. Current changes to 7A.a)10Ab)2Ac)5Ad)3ACorrect answer is option 'C'. Can you explain this answer?
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