All questions of Basic Electronics for Electrical Engineering (EE) Exam

Which of the following is a unipolar diode?
  • a)
    Zener diode
  • b)
    Step recovery diode
  • c)
    Schottky diode
  • d)
    All of these
Correct answer is option 'C'. Can you explain this answer?

Avinash Mehta answered
Diodes are bipolar consisting of p and n junction where electrons and holes both are responsible for conduction in diode.​

Given figure is of npn bjt (formed by sandwiching of two pn junctions) where electrons and holes both responsible for conduction!
That's why they are called bipolar!
But some diodes are unipolar like Schottky diode.

Which of the following is not possible BJT configuration?
  • a)
    Common base configuration
  • b)
    Common emitter configuration
  • c)
    Common current configuration
  • d)
    Common collector configuration
Correct answer is option 'C'. Can you explain this answer?

Yash Patel answered
The 3 configurations in BJT are


The term “Common” refers to the Common terminal through which input is given and from which output is withdrawn i.e. common terminal between input and output.
The term common current is logically incorrect and is not a BJT Configuration.

The depletion region of PN junction is consist of:
  • a)
    Atoms
  • b)
    Passive component
  • c)
    Mobile charges
  • d)
    Immobile charge
Correct answer is option 'D'. Can you explain this answer?

Rhea Reddy answered
The holes from p-region cross the p-n Junction and recombine with electrons on the n-region. Similarly the electrons form n-region cross the junction & recombine with holes in p-region. Leaving immobile ions behind.
Thus the region near the junction is devoid of any mobile charge carriers, due to their recombination. Hence Depletion region of p-n Junction consists of immobile charges. 

ICBO in a transistor can be reduced by reducing:
  • a)
    IB
  • b)
    VCC
  • c)
    IE
  • d)
    Temperature
Correct answer is option 'D'. Can you explain this answer?

Sanvi Kapoor answered
ICBO is the reverse leakage current between collector and base while emitter is open it is given by ICBO=(1−α)IC−αIB. It is the reverse current in base collector junction, which is dependent on temperature at the junction and is reduced with decreasing current.

The phenomenon of thermal run away is associated with
  • a)
    Vacuum tubes
  • b)
    Transistors
  • c)
    Gas diode
  • d)
    All of these
Correct answer is option 'B'. Can you explain this answer?

Rishika Sen answered
Thermal runaway is a situation in which increase in temperature changes the conditions in a way that further causes temperature to increase.
In BJTs the collector current dissipates lot of heat, this increase in temperature causes increased flow of minority carriers from collector to base, further increasing the collector current. This increase in collector current further raise temperature, thus thermal runaway occurs ending in burnout of BJT.

A transistor connected in common base configuration has:
  • a)
    A high input resistance and low output resistance
  • b)
    A high input resistance and high output resistance
  • c)
    A low input resistance and high output  resistance
  • d)
    A low input resistance and low output resistance
Correct answer is option 'C'. Can you explain this answer?

Gargi Basak answered
Input Terminal Emitter – Base (EB)
Output Terminal Collector – Base (CB)
Since for Amplification Application in BJT
EB Junction → Forward Biased (Low Impedance)
CB Junction → Reversed Biased (High Impedance)
Input Impedance is low
Output Impedance is high

The h-parameter equivalent circuit of a BJT is valid for:
  • a)
    Large signal operation at high frequencies
  • b)
    Small signal operation at low frequencies 
  • c)
    Large signal operation at low frequencies
  • d)
    Small signal operation at high frequencies
Correct answer is option 'B'. Can you explain this answer?

Dhruv Datta answered
The h-parameter equivalent circuit of a Bipolar Junction Transistor (BJT) is a simplified model that represents the transistor's behavior in terms of its hybrid parameters, also known as h-parameters. These parameters are used to describe the relationship between the voltage and current at the BJT terminals.

The h-parameter equivalent circuit consists of three elements: the current source hfe (also known as the forward current transfer ratio or beta), the input impedance hie, and the output impedance hoe. It assumes that the BJT is operating in the active region, where the transistor acts as an amplifier.

The validity of the h-parameter equivalent circuit depends on the operating conditions of the BJT. Let's consider the given options to determine the correct answer:

a) Large signal operation at high frequencies:
The h-parameter equivalent circuit is not valid for large signal operation because it assumes small signal conditions. Large signal operation refers to situations where the signal amplitudes are significant enough to cause non-linear effects in the transistor's behavior. At high frequencies, the BJT's parasitic capacitances also become significant, which are not considered in the h-parameter model.

c) Large signal operation at low frequencies:
Similar to option a, the h-parameter circuit is not suitable for large signal operation, regardless of the frequency. The h-parameter model assumes small signal conditions, where the signal amplitudes are small enough to avoid non-linear effects.

d) Small signal operation at high frequencies:
While the h-parameter circuit assumes small signal conditions, it does not accurately represent the BJT's behavior at high frequencies. At high frequencies, the transistor's parasitic capacitances and other high-frequency effects become significant, which are not considered in the h-parameter model.

b) Small signal operation at low frequencies:
The h-parameter equivalent circuit is most valid for small signal operation at low frequencies. In this operating region, the signal amplitudes are small enough to avoid non-linear effects, and the parasitic capacitances and other high-frequency effects are negligible. Therefore, the h-parameter model provides a reasonably accurate representation of the BJT's behavior in this operating region.

In conclusion, the h-parameter equivalent circuit of a BJT is valid for small signal operation at low frequencies. It provides a simplified yet effective model for analyzing the transistor's behavior in this operating region.

The ripple factor of a power supply is a measure of
  • a)
    Its filter efficiency
  • b)
    Its voltage regulation
  • c)
    Its purity of output
  • d)
    Diode rating
Correct answer is option 'C'. Can you explain this answer?

Dishani Bose answered
Thus if the ripple factor is less, the power supply has less AC components and power supply output is more pure (i.e more DC without much fluctuations)
Thus ripple factor is indication of purity of output of power supply

Of the three BJT configurations CB, CE and CC:
  • a)
    CB does not have miller effect hence higher bandwidth
  • b)
    CC has smallest bandwidth
  • c)
    CB exhibits reduction in bandwidth due to Miller effect
  • d)
    CE exhibits increase in bandwidth due to Miller effect
Correct answer is option 'A'. Can you explain this answer?

Swati Shah answered
Av = gain of Amplifier
Miller Capacitance
CM = CC (1 + AV)
The increase in input capacitance decreases the upper cut off frequency
In case of CB configuration there is no miller capacitance between input and output & hence upper cut off frequency (fH) is high & higher Bandwidth

A Schottky diode is a
  • a)
    Both majority and minority carrier diode
  • b)
    Majority carrier device
  • c)
    Minority carrier device
  • d)
    Fast recovery diode
Correct answer is option 'B'. Can you explain this answer?

Mihir Khanna answered
It is a majority carrier device. It is a semiconductor diode with a very fast switching action, but a low forward voltage drop. When a current flows through the diode there is a small voltage drop across the diode terminals. In a normal diode, the voltage drop is between 0.6 to 1.7 volts, while in a Schottky diode the voltage drop normally ranges between 0.15 and 0.45volts. This lower voltage drop provides higher switching speed and better system efficiency.
In Schottky diode, a semiconductor-metal junction is formed between a semiconductor and a metal, thus creating a Schottky barrier. The N-type semiconductor acts as a cathode and the metal side acts as the anode of the diode. The Schottky barrier diode is a unidirectional device conducting current flows only in one direction.

Fermi level is the measure of
  • a)
    Doping of electrons
  • b)
    Probability of occupancy of electrons or holes
  • c)
    Probability of occupancy of photons
  • d)
    Probability of occupancy of wavelength
Correct answer is option 'B'. Can you explain this answer?

Fermi level is the measure of:

The Fermi level is a concept in solid-state physics that is used to describe the probability of occupancy of electrons or holes in a material. It represents the energy level at which the probability of finding an electron is 50%.

Explanation:

In order to understand the Fermi level, we need to understand the concept of energy bands in solids. Solids are made up of atoms that are closely packed together. When these atoms come together to form a solid, their energy levels combine to form energy bands.

- Energy Bands: Energy bands are ranges of energy levels that electrons can occupy in a solid. The two most important energy bands are the valence band and the conduction band. The valence band is the band that contains the electrons that are bound to the atoms and are not free to move. The conduction band is the band that contains the electrons that are free to move and participate in electrical conduction.

- Fermi-Dirac Distribution: The distribution of electrons in these energy bands is determined by the Fermi-Dirac distribution function. This function describes the probability of occupancy of energy levels by electrons or holes at a given temperature. It is characterized by a parameter called the Fermi-Dirac distribution function, denoted by f(E), which represents the probability of finding an electron at a particular energy level E.

- Fermi Level: The Fermi level is a special energy level within the energy band structure of a solid. It represents the energy at which the probability of finding an electron is 50%. At absolute zero temperature, the Fermi level corresponds to the highest filled energy level in the valence band. As temperature increases, the Fermi level moves towards the conduction band, allowing more electrons to occupy higher energy levels.

- Probability of Occupancy: The Fermi level is directly related to the probability of occupancy of electrons or holes in a material. At the Fermi level, the probability of occupancy is highest, and it decreases as we move away from the Fermi level in either direction.

Therefore, the correct answer is option B: Probability of occupancy of electrons or holes. The Fermi level represents the energy level at which the probability of finding an electron is 50%. It is a fundamental concept in solid-state physics that helps us understand the behavior of electrons in materials and their ability to conduct electricity.

What is the required connection for an enhancement type N-MOSFET to function as a resistor?
  • a)
    Gate connected to source
  • b)
    Gate connected to drain
  • c)
    Drain connected to source
  • d)
    Drain voltage should be less than the overdrive voltage 
Correct answer is option 'B'. Can you explain this answer?

Athul Banerjee answered
The overdrive voltage is defined as the voltage between transistor gate and source (VGS) in excess of the threshold voltage (VT) ie Vgs - Vt
For N-Mos to function as a resistor, it should be operated in linear region. I.e. VDS < Vgs – Vt
For using N-Mos as an amplifier, it should be operated in saturation region. I.e. VDS ≥ Vgs – Vt

A transistor is said to be in a quiescent stage when
  • a)
    Emitter junction bias is just equal to collector junction bias
  • b)
    No current are flowing
  • c)
    No signal are applying to the input
  • d)
    It is unbiased
Correct answer is option 'C'. Can you explain this answer?

Palak Verma answered
The Q-point in the Transistor is established for faithful Amplification in middle of DC-load line. The Q-point is established using DC voltage & resistance without any application of AC signal.

Which diode has negative resistance region in its characteristics?
  • a)
    Photodiode
  • b)
    Tunnel diode
  • c)
    Varactor diode
  • d)
    Zener diode
Correct answer is option 'B'. Can you explain this answer?

Manoj Mehra answered
Tunnel diode characteristics
In Region between Peak Point & valley Point the current in Tunnel diode decrease with increase in forward Bias voltage. Thus Tunnel diode shows -ve resistance between peak point & valley point

A Bipolar Junction Transistor saturation point may be defined as
  • a)
    The point where the collector current exceeds maximum value
  • b)
    Large base current is present 
  • c)
    Point above which the increase in base current does not increase the collector current significantly 
  • d)
    None of the other options
Correct answer is option 'C'. Can you explain this answer?

Raj Desai answered
For a BJT operating in active mode, the base current (Ib) and collector current (IC) are related as Ic = β Ib where β is the current gain.
At saturation the voltage across collector – emitter junction (VCE) is constant (∼ 0.2V) and collector current is independent of base current.

A centre tapped full wave rectifier output contains only-
  • a)
    Even harmonics
  • b)
    Odd harmonics
  • c)
    Even and Odd harmonics
  • d)
    No harmonics
Correct answer is option 'A'. Can you explain this answer?

Upasana Joshi answered
Since the output of full wave rectifier is an even function. Hence from Fourier series Analysis we know that even function have even harmonics thus output of FWR contains only even harmonics.

What is the main source of distortion in a push-pull amplifier?
  • a)
    Fundamental component
  • b)
    Second harmonic
  • c)
    Third harmonic
  • d)
    All even harmonics
Correct answer is option 'C'. Can you explain this answer?

Maulik Das answered
In push-pull amplifiers each transistor operates only for one half cycle of AC voltage, in it even harmonics are minimised, so distortion is mainly due to odd harmonics.
Hence of the given options third harmonics needs to be eliminated

UJT are used in
  • a)
    Only timing circuits
  • b)
    Only oscillator circuits
  • c)
    Only bi-stable circuits
  • d)
    In all the circuits
Correct answer is option 'D'. Can you explain this answer?

Isha Singh answered
Uni Junction Transistor is a three terminal semiconductor device formed by single P-N junction. It functions as an ON-OFF switch and has unidirectional conductivity and negative resistance characteristics.
It is used to trigger SCR devices and used in relaxation oscillator.

In the silicon crystal structure, the recombination rate is proportional to the number of;
  • a)
    Free electrons and holes
  • b)
    Covalent bonds
  • c)
    Free electrons
  • d)
    Free holes
Correct answer is option 'A'. Can you explain this answer?

Recombination Rate in Silicon Crystal Structure

Introduction:
Silicon is a semiconductor material that is widely used in electronics. In its crystal structure, the recombination rate is an important parameter that affects the performance of electronic devices. Recombination refers to the process by which free electrons and holes combine, leading to the release of energy in the form of photons or heat. The rate of recombination is proportional to the number of free electrons and holes in the crystal.

Proportional to the Number of Electrons and Holes:
The recombination rate in a silicon crystal is proportional to the number of free electrons and holes. This is because recombination occurs when free electrons and holes come into contact with each other. The more free electrons and holes there are in the crystal, the more likely they are to come into contact and recombine.

Covalent Bonds:
Covalent bonds are the chemical bonds that hold the silicon atoms together in the crystal. They are formed by the sharing of electrons between adjacent atoms. Covalent bonds do not directly affect the recombination rate in the crystal.

Free Electrons:
Free electrons are electrons that are not bound to any atom in the crystal. They are created when silicon is doped with impurities such as phosphorus. Free electrons contribute to the conductivity of the crystal and are also involved in the recombination process.

Free Holes:
Free holes are vacant spaces in the crystal lattice where an electron is missing. They are created when silicon is doped with impurities such as boron. Free holes also contribute to the conductivity of the crystal and are involved in the recombination process.

Conclusion:
In conclusion, the recombination rate in a silicon crystal is proportional to the number of free electrons and holes. The covalent bonds that hold the crystal together do not directly affect the recombination rate. Understanding the recombination rate is important for the design and optimization of electronic devices based on silicon.

The bonding forces in compound semiconductors, such as GaAs, arise form
  • a)
    Ionic bonding
  • b)
    Metallic bonding
  • c)
    Covalent bonding
  • d)
    Combination of ironic and covalent bonding
Correct answer is option 'C'. Can you explain this answer?

Mihir Chawla answered
In semiconductors like GaAs the elements Ga and As are in covalent bond. Arsenic has five valence electrons while gallium has three valence electrons. Therefore, in GaAs crystal Arsenic contribute one electron to Gallium and it is shared between both atoms in a covalent bond

Transistors leakage current mainly depends on:
  • a)
    Doping of base
  • b)
    Size of emitter
  • c)
    Rating of transistor
  • d)
    Temperature
Correct answer is option 'D'. Can you explain this answer?

Bijoy Mehta answered
Transistor leakage current refers to the small amount of current that flows through a transistor even when it is in the off state. This leakage current can have a significant impact on the overall performance and efficiency of a transistor.

The leakage current mainly depends on the temperature of the transistor. However, other factors like the doping of the base, size of the emitter, and rating of the transistor can also have some influence on the leakage current.

1. Temperature:
The temperature of the transistor is a critical factor that affects the leakage current. As the temperature increases, the energy level of the electrons in the base region also increases. This results in a higher probability of electrons crossing the base-emitter junction and causing a leakage current. Therefore, higher temperatures lead to higher leakage currents.

2. Doping of the base:
The doping of the base region also affects the leakage current. The base region is typically lightly doped compared to the emitter and collector regions. If the base doping concentration is too high, it can lead to an increase in the leakage current. This is because a higher doping concentration increases the probability of electrons crossing the base-emitter junction, even in the off state.

3. Size of the emitter:
The size of the emitter can indirectly affect the leakage current. A larger emitter area provides more space for electrons to cross the base-emitter junction, leading to a higher leakage current. However, the size of the emitter is usually chosen based on other performance requirements, and optimizing it solely for reducing leakage current may not be practical.

4. Rating of the transistor:
The rating of the transistor, such as its breakdown voltage and maximum operating temperature, can also influence the leakage current. Transistors with higher breakdown voltages and higher temperature ratings tend to have lower leakage currents. This is because these transistors are designed to operate under more stringent conditions, which also helps reduce leakage current.

In summary, while the temperature of the transistor is the primary factor affecting leakage current, other factors like the doping of the base, size of the emitter, and rating of the transistor can also have some influence. It is important to consider these factors during the design and selection of transistors to minimize leakage current and optimize overall performance.

What are the ON/OFF terminals of a transistor when it is operated as a switch?
  • a)
    Collector to base
  • b)
    Collector to emitter
  • c)
    Base to collector
  • d)
    Emitter to base
Correct answer is option 'B'. Can you explain this answer?

Transistor switches can be used to switch low DC voltages ON or OFF by operating it in saturation or cut-off mode
The CE terminals act as ON/OFF terminals as shown in figure above.

Transistor biasing is done to keep _______ in the circuit.
  • a)
    Proper direct current
  • b)
    Proper alternating current
  • c)
    The base current small
  • d)
    Collector current small
Correct answer is option 'A'. Can you explain this answer?

Palak Verma answered
Transistor biasing is a technique used in electronic circuits to establish and maintain the desired operating conditions of a transistor. The goal of transistor biasing is to keep the transistor in its active region, where it can amplify signals accurately and efficiently. The correct answer to the given question is option 'A': Proper direct current.

Proper Direct Current:

Transistors are current-operated devices, which means they require a direct current (DC) to operate. The biasing of a transistor involves applying a suitable DC voltage or current to its terminals, namely the base, emitter, and collector, to ensure that it operates within its desired operating region.

The base-emitter junction of a transistor is forward-biased, which means a small forward current should flow through this junction. This current is known as the base current (IB). The collector current (IC) is controlled by the base current, and it is typically much larger than the base current.

Importance of Transistor Biasing:

Transistor biasing is crucial for several reasons:

1. Stability: Proper biasing ensures the stability of the transistor's operating point, preventing it from drifting or varying due to changes in temperature, component characteristics, or supply voltage.

2. Linearity: Biasing maintains the transistor's linearity, which is essential for accurate amplification of signals. It ensures that the input-output relationship of the transistor remains linear within its active region.

3. Efficiency: Biasing at the correct operating point allows the transistor to operate efficiently, maximizing its power output and minimizing distortion.

4. Thermal Stability: Biasing also helps in maintaining the thermal stability of the transistor by preventing excessive heat generation. This is important to prevent thermal runaway, where the transistor's temperature rises uncontrollably.

Types of Biasing:

There are different methods of biasing a transistor, depending on the application requirements. Some common biasing techniques include:

1. Fixed Bias: In this method, a fixed voltage or current is applied to the base-emitter junction of the transistor using resistors. It is simple but lacks stability.

2. Collector Feedback Bias: This technique uses a feedback resistor from the collector to the base of the transistor. It provides better stability and temperature compensation.

3. Voltage Divider Bias: A voltage divider network is used to bias the transistor. This method provides stability and is widely used in amplifier circuits.

4. Emitter Bias: This biasing method uses a resistor connected between the emitter and ground to establish the desired operating conditions. It offers good stability but lowers the voltage gain of the transistor.

Conclusion:

Transistor biasing is essential to maintain the operating conditions of a transistor for accurate and efficient signal amplification. By providing the proper direct current, transistor biasing ensures stability, linearity, and thermal stability, which are crucial for the reliable operation of electronic circuits.

Generally, mobility of electrons in semiconductor is _________ times the mobility of holes:
  • a)
    Two
  • b)
    Three
  • c)
    Four
  • d)
    Five
Correct answer is option 'B'. Can you explain this answer?

Raj Desai answered
Mobility of electrons and holes depends on their effective masses. Effective mass of electrons is less than that of holes hence electrons have higher mobility than holes.
For both Ge & Si μe > 2μh
Hence option (b) is correct.

The LED emits light of a particular colour because
  • a)
    It is fabricated from a fluorescent material
  • b)
    Transition between energy levels of the carriers takes place while crossing the p-n junction
  • c)
    Heat generated in the diode is converted into light
  • d)
    The band gap of the semiconductor material used in the fabrication of the diode is equal to the energy hν of the light photon
Correct answer is option 'D'. Can you explain this answer?

Lekshmi Rane answered
LEDs are fabricated using direct bandgap semiconductors.In which, when electron transfers from conductor band to valence band and recombines with the holes the energy difference between the both bandsget converted in to light with frequency ‘ν’, it is related with energy as,
E = hν, where h is Planck’s constant.

Which of the following is a bipolar device?
  • a)
    Tunnel diode
  • b)
    Gunn diode
  • c)
    FET
  • d)
    UJT
Correct answer is option 'A'. Can you explain this answer?

Srestha Gupta answered
Gunn diode, FET and UJT are unipolar devices in which current is due to only one type of carrier. While tunnel diode is bipolar device in which both electrons and holes contribute to current.

Consider the following circuit configurations:
1. Common emitter
2. Common base
3. Emitter follower
The correct sequence in increasing input impedance is 
  • a)
    2, 1, 3
  • b)
    1, 2, 3
  • c)
    1, 3, 2
  • d)
    3, 2, 1
Correct answer is option 'A'. Can you explain this answer?

Partho Saha answered
Understanding Input Impedance in BJT Configurations
Input impedance is a crucial parameter in transistor amplifiers, influencing how they interact with preceding circuit stages. The three common configurations of bipolar junction transistors (BJTs) are common emitter, common base, and emitter follower. Each has distinct characteristics regarding input impedance.
1. Common Emitter Configuration
- The common emitter configuration has a moderate input impedance, typically in the range of 1kΩ to 100kΩ.
- It is often used for voltage amplification and has a relatively high gain but lower input impedance compared to the other configurations.
2. Common Base Configuration
- The common base configuration offers the lowest input impedance, usually around 50Ω to 500Ω.
- This configuration is less commonly used for voltage amplification as it has low gain and input impedance, making it suitable for specific applications like RF amplifiers.
3. Emitter Follower Configuration
- The emitter follower, also known as common collector, has the highest input impedance, typically ranging from tens of kΩ to several MΩ.
- This configuration is designed for impedance matching, providing a buffered output while maintaining high input impedance.
Sequence of Input Impedance
- When comparing the input impedances:
- Common Base: Lowest (2)
- Common Emitter: Moderate (1)
- Emitter Follower: Highest (3)
Thus, the correct sequence in increasing input impedance is:
2, 1, 3
Therefore, option 'A' is indeed correct, reflecting the expected trend of input impedance across these configurations. Understanding these differences helps in selecting the appropriate configuration for specific circuit requirements.

The gain of a CE amplifier is highest at
  • a)
    Low frequencies
  • b)
    Mid frequencies
  • c)
    High frequencies
  • d)
    All frequencies
Correct answer is option 'B'. Can you explain this answer?

Rounak Rane answered
A common emitter amplifier acts as a bandpass amplifier due to reduced gain at low and high frequencies. This is due to source, emitter and parasitic capacitances.

Two p-n junction diodes are connected back to back to make a transistor. Which one of the following is correct?
  • a)
    The current gain of such a transistor will be high
  • b)
    The current gain of such a transistor will be moderate
  • c)
    It cannot be used as a transistor due to large base width
  • d)
    It can be used only for p-n-p transistor
Correct answer is option 'C'. Can you explain this answer?

A transistor operation needs very small base width to allow the minority carriers, drifted from emitter to diffuse into collector.
By connecting two PN diodes back to back the transistor will have wide base causing the minority carriers from emitter to recombine in base region before they diffuse into collector. This reduces collector current or cut off entirely.

Which of the following diode is used for voltage stabilization?
  • a)
    P – N junction
  • b)
    Zener
  • c)
    Tunnel
  • d)
    PIN
Correct answer is option 'B'. Can you explain this answer?

Bhavana Reddy answered
The I - V characteristic of Zener diode is shown
When Zener diode is reversed Biased the voltage across it is constant (V2).
Hence Zener Diode on reverse Biasing acts as voltage Stabilizer

A tuned amplifier is used:
  • a)
    In audio amplification
  • b)
    For noise removal in radio signals
  • c)
    In radio receivers
  • d)
    None of the above
Correct answer is option 'C'. Can you explain this answer?

Tuned amplifiers are employed for the purpose of selecting a particular frequency among set of available frequencies. Hence they are employed in radio receives.

In a rectifier, commutation of diodes refers to transferring energy from –
  • a)
    Rectifier diode to load
  • b)
    Freewheeling diode to load
  • c)
    Freewheeling diode to rectifier diode
  • d)
    Rectifier diode to freewheeling diode
Correct answer is option 'D'. Can you explain this answer?

Bijoy Mehta answered
Commutation in a rectifier is the process of transfer of current from one device (diode or thyristor) to the other in a rectifier. The device from which the current is transferred is called the outgoing device and the device to which the current is transferred is called the incoming device. The incoming device turns on at the beginning of commutation while the outgoing device turns off at the end of commutation.
Here, commutation of diodes refers to transferring energy from rectifier diode to freewheeling diode. Freewheeling diode is used to reduce the harmonics and also suppress the voltage spikes occur in inductive load.

The intersection of the D.C. load line with the given base current curve is the
  • a)
    A.C load line
  • b)
    Operating point
  • c)
    Stabilizing point
  • d)
    None of the above
Correct answer is option 'B'. Can you explain this answer?

Ameya Roy answered
The intersection of DC load line with the parameter graph of a semiconductor device (for example base current vs VCE in transistor) gives operating point of the said device

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