All Exams >
Civil Engineering (CE) >
Fluid Mechanics for Civil Engineering >
All Questions
All questions of Hydraulic Machines: Turbines & Pumps for Civil Engineering (CE) Exam
The vertical distance between the centreline of the centrifugal pump and the liquid surface in the pump is called as:- a)dynamic head
- b)manometric head
- c)delivery head
- d)Suction head
Correct answer is option 'D'. Can you explain this answer?
The vertical distance between the centreline of the centrifugal pump and the liquid surface in the pump is called as:
a)
dynamic head
b)
manometric head
c)
delivery head
d)
Suction head
|
Sakshi Basak answered |
Introduction:
In centrifugal pumps, the suction head refers to the vertical distance between the centerline of the pump and the liquid surface inside the pump. It is an important parameter that determines the ability of the pump to draw fluid from a source and transport it to a desired location. The suction head is a crucial factor in pump performance and efficiency.
Explanation:
The suction head plays a significant role in the overall operation of a centrifugal pump. It affects the pump's ability to prime, its net positive suction head (NPSH) requirement, and the pump's performance characteristics. Here is a detailed explanation of the suction head in a centrifugal pump:
1. Definition:
The suction head is defined as the vertical distance between the centerline of the pump and the liquid surface in the pump. It is measured from the pump centerline to the highest liquid level in the suction tank or source.
2. Suction Lift:
The suction head is also referred to as the suction lift when the liquid source is located below the pump centerline. In this case, the pump has to lift the liquid against gravity to draw it into the pump.
3. Suction Head Calculation:
The suction head can be calculated by subtracting the elevation of the liquid source from the elevation of the pump centerline. If the liquid source is at a higher elevation, the suction head will be negative, indicating that the pump is operating under a suction lift condition.
4. Importance:
The suction head is crucial as it determines the ability of the pump to draw fluid from a source. It influences the pump's priming capability, which is the process of removing air or gas from the pump and filling it with the liquid to be pumped. A sufficient suction head is necessary for proper priming.
5. Net Positive Suction Head (NPSH):
The suction head is also related to the concept of NPSH. NPSH is the measure of how much energy the liquid has above its vapor pressure at the suction inlet of the pump. It is essential to prevent cavitation, which can damage the pump and reduce its efficiency. The NPSH required by a pump is influenced by the suction head.
Conclusion:
The vertical distance between the centerline of a centrifugal pump and the liquid surface in the pump is known as the suction head. It is a critical parameter that determines the pump's ability to draw fluid from a source. The suction head affects the pump's priming capability, NPSH requirement, and overall performance. Understanding and considering the suction head is vital for efficient and reliable pump operation.
Which of the following turbine does not require draft tube ?- a)Kaplan turbine
- b)Pelton turbine
- c)Francis turbine
- d)Propeller turbine
Correct answer is option 'B'. Can you explain this answer?
Which of the following turbine does not require draft tube ?
a)
Kaplan turbine
b)
Pelton turbine
c)
Francis turbine
d)
Propeller turbine
|
Gate Funda answered |
Concept:
- In Impulse Turbine, the available hydraulic energy is first converted into kinetic energy by means of an efficient nozzle
- The high-velocity jet issuing from the nozzle then strikes a series of suitably shaped buckets fixed around the rim of a wheel
- The buckets change the direction of the jet without changing its pressure
- The resulting change in momentum sets buckets and wheels into rotary motion and thus mechanical energy is made available at the turbine shaft
- The fluid jet leaves the runner with a reduced energy
- The impulse turbine doesn't use a draft tube. Ex. Pelton wheel
- The draft tube is used only in Reaction turbines. Ex. Francis turbine, Kaplan turbine, Propeller turbine
Draft Tube:
- The draft tube is a conduit that connects the runner exit to the tailrace where the water is being finally discharged from the turbine. It is used with reaction turbines only.
- The draft tube has two purposes as follows if
- It permits a negative or suction head to be established at the runner exit, thus making it possible to install the turbine above the tailrace level without loss head.
- It converts a large proportion of velocity energy rejected from the runner into useful pressure energy.
- A draft tube is made divergent so as to reduce the velocity at the outlet to a minimum. Therefore, a draft tube is basically a diffuser and should be designed properly with the angle between the walls of the tube to be limited to about 8 degrees so as to prevent the flow separation from the wall and to reduce accordingly the loss of energy in the tube.
From the equation of the continuity,
A1V1 = A2V2
V∝1/A
The area at the exit is higher, therefore the velocity of discharged water will be lower.
Which one of the following turbines is the most popularly used one in the medium head range of 60 m - 300 m?- a)Kaplan turbine
- b)Francis turbine
- c)Pelton turbine
- d)Deriaz turbine
Correct answer is option 'B'. Can you explain this answer?
Which one of the following turbines is the most popularly used one in the medium head range of 60 m - 300 m?
a)
Kaplan turbine
b)
Francis turbine
c)
Pelton turbine
d)
Deriaz turbine
|
Sanvi Kapoor answered |
In Francis Turbine the medium head is required generally in the range of (100-500) meters. In Kaplan Turbine very low head is required, generally less than 100-meter
In Francis Turbine medium flow rate is required. In Kaplan Turbine very large flow rate is required
- High-head turbine: In this type of turbine, the net head varies from 150m to 2000m or even more, and these turbines require a small quantity of water. Example: Pelton wheel turbine.
- Medium head turbine: The net head varies from 30m to 150m, and also these turbines require a moderate quantity of water. Example: Francis turbine.
- Low-head turbine: The net head is less than 30m and also these turbines require a large quantity of water. Example: Kaplan turbine.
The volume of fluid confined between two gear teeth of the gear pump is 0.350 cm3. How much fluid volume is pumped per rotation?- a)7.0 cm3
- b)9.8 cm3
- c)9.2 cm2
- d)8.5 cm3
Correct answer is option 'D'. Can you explain this answer?
The volume of fluid confined between two gear teeth of the gear pump is 0.350 cm3. How much fluid volume is pumped per rotation?
a)
7.0 cm3
b)
9.8 cm3
c)
9.2 cm2
d)
8.5 cm3
|
Vertex Academy answered |
Concept:
Pump:
The function of a pump is to convert mechanical energy into hydraulic energy.
It is the heart of any hydraulic system because it generates the force necessary to move the load. Mechanical energy is delivered to the pump using a prime mover such as an electric motor.
The hydraulic pump takes hydraulic fluid (mostly some oil) from the storage tank and delivers it to the rest of the hydraulic circuit. Pumps can be broadly listed under two categories:
Pump:
The function of a pump is to convert mechanical energy into hydraulic energy.
It is the heart of any hydraulic system because it generates the force necessary to move the load. Mechanical energy is delivered to the pump using a prime mover such as an electric motor.
The hydraulic pump takes hydraulic fluid (mostly some oil) from the storage tank and delivers it to the rest of the hydraulic circuit. Pumps can be broadly listed under two categories:
- Non-positive displacement pumps and
- Positive displacement pumps.
Given,
Let, the number of teeth = 12 per gear.
Thus, for each 360o rotation of each gear (n = 1 rotation), 12 × (0.350 cm3) of fluid is pumped.
Since there are two gears, the total volume of fluid pumped per rotation is,
2 × (12) × (0.350 cm3) = 8.40 cm3.
Let, the number of teeth = 12 per gear.
Thus, for each 360o rotation of each gear (n = 1 rotation), 12 × (0.350 cm3) of fluid is pumped.
Since there are two gears, the total volume of fluid pumped per rotation is,
2 × (12) × (0.350 cm3) = 8.40 cm3.
The blades of a fast centrifugal pump impeller will be:- a)propeller type
- b)radially spreading
- c)forward facing
- d)backward facing
Correct answer is option 'D'. Can you explain this answer?
The blades of a fast centrifugal pump impeller will be:
a)
propeller type
b)
radially spreading
c)
forward facing
d)
backward facing
|
|
Vertex Academy answered |
Centrifugal Pump:
Centrifugal pumps are used to transport fluids by the conversion of rotational kinetic energy to the hydrodynamic energy of the fluid flow. The rotational energy typically comes from an engine or electric motor.
Centrifugal pumps are used to transport fluids by the conversion of rotational kinetic energy to the hydrodynamic energy of the fluid flow. The rotational energy typically comes from an engine or electric motor.
- The impeller in the centrifugal pumps is immersed in water and imparts a centrifugal force that moves out the water particles readily.
- The Impellers are known to have backward curved vanes that have less than 90 degrees of blade angle. The backward curved blades are the most preferred types as they have better stabilizing power consumption characteristics than the forward and radial types which are less preferred.
Which is the wrong statement about hydraulic turbine?- a)The relative velocity over the moving blades increases in impulse turbines
- b)A pelton wheel is a tangential flow impulse turbine
- c)A francis turbine is a mix of radial and axial flow reaction turbine
- d)A kaplan turbine is a axial flow reaction turbine
Correct answer is option 'A'. Can you explain this answer?
Which is the wrong statement about hydraulic turbine?
a)
The relative velocity over the moving blades increases in impulse turbines
b)
A pelton wheel is a tangential flow impulse turbine
c)
A francis turbine is a mix of radial and axial flow reaction turbine
d)
A kaplan turbine is a axial flow reaction turbine
|
|
Gate Funda answered |
Hydraulic turbine -
The main classification depends upon the type of action of the water on the turbine. These are :
(i) Impulse Turbine
(ii) Reaction Turbine.
(i) Impulse turbine:-
The main classification depends upon the type of action of the water on the turbine. These are :
(i) Impulse Turbine
(ii) Reaction Turbine.
(i) Impulse turbine:-
- In the case of an impulse turbine, all the potential energy is converted to kinetic energy in the nozzles. The impulse provided by the jets is used to turn the turbine wheel.
- This type is found suitable when the available potential energy is high and the flow available is comparatively low.
- The relative velocity over the moving blades either remains constant or slightly decreases so the correct answer is option 1
(ii) Reaction Turbine:-
- In reaction turbines, the available potential energy is progressively converted in the turbine's rotors and the reaction of the accelerating water causes the turning of the wheel.
- The relative velocity over the moving blades increases.
- These are again divided into (a) radial flow, (b) mixed flow, and (c) axial flow machines
In the selection of turbine by specific speed or head, which one of the following statements is not correct?
- a)For specific speed 10-35, Kaplan turbines
- b)For specific speed 60-300, Francis turbines
- c)For head 50-150 m, Francis turbines
- d)For head above 300 m, Pelton wheel
Correct answer is option 'A'. Can you explain this answer?
In the selection of turbine by specific speed or head, which one of the following statements is not correct?
a)
For specific speed 10-35, Kaplan turbines
b)
For specific speed 60-300, Francis turbines
c)
For head 50-150 m, Francis turbines
d)
For head above 300 m, Pelton wheel
|
Abhay Kapoor answered |
- For specific speed 10-35, Kaplan turbines
This statement is incorrect because Kaplan turbines are designed for much higher specific speeds. The correct range for Kaplan turbines is generally from 300 to 1000 (in metric units), making this option inaccurate.
Assuming 80% efficiency, 100 m3/sec of design discharge, and 100 m of design head, what will be the approximate electrical power producted?- a)800 megawatts
- b)8000 kilowatts
- c)80000000 watts
- d)None of the above
Correct answer is option 'C'. Can you explain this answer?
Assuming 80% efficiency, 100 m3/sec of design discharge, and 100 m of design head, what will be the approximate electrical power producted?
a)
800 megawatts
b)
8000 kilowatts
c)
80000000 watts
d)
None of the above
|
|
Sanvi Kapoor answered |
Concept:
Power developed in a reaction turbine is given by:
Where,
ρ = density of the water (kg/m3)
Q = Discharge through the turbine (m3/s)
H = Head (m)
ηo = the overall efficiency of the turbine
Calculation:
ρ = 1000 kg/m3
Q = 100 m3/sec
H = 100 m, Efficiency = 80%
Power developed in a reaction turbine is given by:
P = 1000 × 100 × 10 × 100 × 0.80 / 1000
P = 80000 kW = 80000000 W
Power developed in a reaction turbine is given by:
Where,
ρ = density of the water (kg/m3)
Q = Discharge through the turbine (m3/s)
H = Head (m)
ηo = the overall efficiency of the turbine
Calculation:
ρ = 1000 kg/m3
Q = 100 m3/sec
H = 100 m, Efficiency = 80%
Power developed in a reaction turbine is given by:
P = 1000 × 100 × 10 × 100 × 0.80 / 1000
P = 80000 kW = 80000000 W
Approximate head gain due to installation of a tapered draft tube after a turbine, if the discharge is 9.42 m3/s, draft tube inlet and outlet diameter respectively is 2 m and 4 m with the efficiency of 90 %.- a)0.86 m
- b)0.38 m
- c)0.42 m
- d)0.95 m
Correct answer is option 'B'. Can you explain this answer?
Approximate head gain due to installation of a tapered draft tube after a turbine, if the discharge is 9.42 m3/s, draft tube inlet and outlet diameter respectively is 2 m and 4 m with the efficiency of 90 %.
a)
0.86 m
b)
0.38 m
c)
0.42 m
d)
0.95 m
|
|
Sanvi Kapoor answered |
Concept:
Draft Tube:
Draft Tube:
- The draft tube is a divergent tube that connects the runner exit to the tailrace.
- At the exit of the turbine runner, the fluid has appreciable kinetic energy, and to recover some of this kinetic energy that would otherwise be wasted, the flow enters the expanding area diffuser called a Draft tube.
- It is used with reaction turbines only.
Purposes of Draft tube:
- It permits a negative or suction head to be established at the runner exit, thus making it possible to install the turbine above the tailrace level without loss of head.
- It is used to convert kinetic energy at the exit of the turbine to pressure energy.
The efficiency of the draft tube is given by:
Head gained by draft tube is given by:
Continuity equation, Q = A × V
Calculation:
Given:
Q = 9.42 m3/s, D1 = 2 m, D2 = 4 m, Draft tube efficiency, ηd = 90 %
Head gained by draft tube is given by
=
= 0.38 m
With the increase in cavitation, the drag coefficient of the impeller ______- a)Increases
- b)Decreases
- c)Same
- d)Independent
Correct answer is option 'A'. Can you explain this answer?
With the increase in cavitation, the drag coefficient of the impeller ______
a)
Increases
b)
Decreases
c)
Same
d)
Independent
|
|
Sanya Agarwal answered |
With the increase in cavitation, the drag coefficient of the impeller increases. When the flow output is higher, impellers are connected in parallel. The impeller is mounted on one shaft or different shaft.
An impulse turbine- a)always operates submerged
- b)makes use of a draft tube
- c)operates by initial complete conversion to kinetic energy
- d)converts pressure head into velocity throughout the vanes
Correct answer is option 'C'. Can you explain this answer?
An impulse turbine
a)
always operates submerged
b)
makes use of a draft tube
c)
operates by initial complete conversion to kinetic energy
d)
converts pressure head into velocity throughout the vanes
|
|
Moumita Rane answered |
Impulse Turbine
A impulse turbine is a type of water turbine that operates by initially converting the potential energy of water into kinetic energy. It is commonly used in hydroelectric power plants and is known for its high efficiency and reliability.
Operating Submerged
Contrary to option (a), an impulse turbine does not always operate submerged. In fact, impulse turbines are designed to operate above the water level, with the water jet directed onto the turbine blades.
Draft Tube
Option (b) is incorrect as well. An impulse turbine does not make use of a draft tube. A draft tube is a component used in reaction turbines to recover the kinetic energy of water leaving the turbine and convert it back into pressure energy. Impulse turbines, on the other hand, do not require a draft tube as they operate based on the principle of converting the potential energy of water into kinetic energy.
Conversion to Kinetic Energy
The correct answer, option (c), states that an impulse turbine operates by initially converting the potential energy of water into kinetic energy. This is the fundamental principle behind the operation of an impulse turbine. The water enters the turbine through a nozzle, which accelerates the flow and increases its velocity. This high-velocity jet of water then strikes the turbine blades, causing them to rotate. The kinetic energy of the water is transferred to the turbine blades, resulting in mechanical work.
Pressure Head to Velocity Conversion
Option (d) is incorrect. While impulse turbines do convert pressure energy into kinetic energy, this conversion occurs in the nozzle, not throughout the vanes. The vanes of an impulse turbine are designed to efficiently capture the kinetic energy of the water jet and convert it into mechanical work, rather than further converting pressure energy into velocity.
In summary, an impulse turbine operates by initially converting the potential energy of water into kinetic energy. It does not always operate submerged, does not require a draft tube, and the conversion of pressure energy into velocity occurs in the nozzle, not throughout the vanes.
A impulse turbine is a type of water turbine that operates by initially converting the potential energy of water into kinetic energy. It is commonly used in hydroelectric power plants and is known for its high efficiency and reliability.
Operating Submerged
Contrary to option (a), an impulse turbine does not always operate submerged. In fact, impulse turbines are designed to operate above the water level, with the water jet directed onto the turbine blades.
Draft Tube
Option (b) is incorrect as well. An impulse turbine does not make use of a draft tube. A draft tube is a component used in reaction turbines to recover the kinetic energy of water leaving the turbine and convert it back into pressure energy. Impulse turbines, on the other hand, do not require a draft tube as they operate based on the principle of converting the potential energy of water into kinetic energy.
Conversion to Kinetic Energy
The correct answer, option (c), states that an impulse turbine operates by initially converting the potential energy of water into kinetic energy. This is the fundamental principle behind the operation of an impulse turbine. The water enters the turbine through a nozzle, which accelerates the flow and increases its velocity. This high-velocity jet of water then strikes the turbine blades, causing them to rotate. The kinetic energy of the water is transferred to the turbine blades, resulting in mechanical work.
Pressure Head to Velocity Conversion
Option (d) is incorrect. While impulse turbines do convert pressure energy into kinetic energy, this conversion occurs in the nozzle, not throughout the vanes. The vanes of an impulse turbine are designed to efficiently capture the kinetic energy of the water jet and convert it into mechanical work, rather than further converting pressure energy into velocity.
In summary, an impulse turbine operates by initially converting the potential energy of water into kinetic energy. It does not always operate submerged, does not require a draft tube, and the conversion of pressure energy into velocity occurs in the nozzle, not throughout the vanes.
When the NPSH is low, it leads to ________- a)Breaking
- b)Wear
- c)Corrosion
- d)Cavitation
Correct answer is option 'D'. Can you explain this answer?
When the NPSH is low, it leads to ________
a)
Breaking
b)
Wear
c)
Corrosion
d)
Cavitation
|
|
Sanya Agarwal answered |
When the NPSH is low, it leads to cavitation. Cavitation is one of the major drawbacks that are seen in a centrifugal pump. There are various other problems as well. But, cavitation is due to low NPSH.
In the expression for overall efficiency of turbine, which is p/(k*g*q*h), where “k” is known as ___________- a)Density of liquid
- b)Specific density of liquid
- c)Volume of liquid
- d)Specific gravity of liquid
Correct answer is option 'A'. Can you explain this answer?
In the expression for overall efficiency of turbine, which is p/(k*g*q*h), where “k” is known as ___________
a)
Density of liquid
b)
Specific density of liquid
c)
Volume of liquid
d)
Specific gravity of liquid
|
|
Sanya Agarwal answered |
Overall efficiency is defined as ratio of power available at shaft of turbine to power supplied at the inlet of turbine which is also product of mechanical and hydraulic efficiency. Its expression is given by p/(k x g x q x h) where k is density of liquid.
In Pelton wheel, if outlet velocity angle of jet is “obtuseangled” then outlet whirl velocity of jet is _____________- a)x- component of V (r2) – blade velocity
- b)x- component of V (r2) + blade velocity
- c)Blade velocity – x- component of V (r2)
- d)Zero
Correct answer is option 'C'. Can you explain this answer?
In Pelton wheel, if outlet velocity angle of jet is “obtuseangled” then outlet whirl velocity of jet is _____________
a)
x- component of V (r2) – blade velocity
b)
x- component of V (r2) + blade velocity
c)
Blade velocity – x- component of V (r2)
d)
Zero
|
|
Ashwin Desai answered |
Greater than 90 degrees, the jet will be deflected backwards and will not hit the buckets of the wheel properly. This will result in reduced efficiency and power output of the Pelton wheel.
The change in head across a small turbine is 10 m, the flow rate of water is 1 m3/s and the efficiency are 80%. The power developed by the turbine is approximately:- a)100 kW
- b)78 kW
- c)1 MW
- d)50 kW
Correct answer is option 'B'. Can you explain this answer?
The change in head across a small turbine is 10 m, the flow rate of water is 1 m3/s and the efficiency are 80%. The power developed by the turbine is approximately:
a)
100 kW
b)
78 kW
c)
1 MW
d)
50 kW
|
|
Shilpa Pillai answered |
Calculating the Power Developed by the Turbine
Given:
Change in head (Δh) = 10 m
Flow rate of water (Q) = 1 m^3/s
Efficiency (η) = 80% = 0.8
We can calculate the power developed by the turbine using the equation:
Power (P) = ρ * g * Q * Δh * η
Where:
ρ = density of water (assumed to be 1000 kg/m^3)
g = acceleration due to gravity (assumed to be 9.81 m/s^2)
Let's calculate the power:
1. Calculate the power developed by the turbine using the given values:
P = 1000 * 9.81 * 1 * 10 * 0.8
2. Simplify the equation:
P = 1000 * 9.81 * 8
3. Calculate the power:
P = 78,480 W
4. Convert the power to kilowatts (kW):
P = 78,480 / 1000
P = 78.48 kW
Therefore, the power developed by the turbine is approximately 78 kW.
Explanation:
The power developed by a turbine is given by the equation P = ρ * g * Q * Δh * η, where ρ is the density of water, g is the acceleration due to gravity, Q is the flow rate of water, Δh is the change in head, and η is the efficiency of the turbine.
In this case, the given values are the change in head (Δh) = 10 m, the flow rate of water (Q) = 1 m^3/s, and the efficiency (η) = 80%.
By substituting these values into the equation, we can calculate the power developed by the turbine.
After simplifying the equation, we find that the power developed is 78.48 kW.
Therefore, the correct answer is option B) 78 kW.
Given:
Change in head (Δh) = 10 m
Flow rate of water (Q) = 1 m^3/s
Efficiency (η) = 80% = 0.8
We can calculate the power developed by the turbine using the equation:
Power (P) = ρ * g * Q * Δh * η
Where:
ρ = density of water (assumed to be 1000 kg/m^3)
g = acceleration due to gravity (assumed to be 9.81 m/s^2)
Let's calculate the power:
1. Calculate the power developed by the turbine using the given values:
P = 1000 * 9.81 * 1 * 10 * 0.8
2. Simplify the equation:
P = 1000 * 9.81 * 8
3. Calculate the power:
P = 78,480 W
4. Convert the power to kilowatts (kW):
P = 78,480 / 1000
P = 78.48 kW
Therefore, the power developed by the turbine is approximately 78 kW.
Explanation:
The power developed by a turbine is given by the equation P = ρ * g * Q * Δh * η, where ρ is the density of water, g is the acceleration due to gravity, Q is the flow rate of water, Δh is the change in head, and η is the efficiency of the turbine.
In this case, the given values are the change in head (Δh) = 10 m, the flow rate of water (Q) = 1 m^3/s, and the efficiency (η) = 80%.
By substituting these values into the equation, we can calculate the power developed by the turbine.
After simplifying the equation, we find that the power developed is 78.48 kW.
Therefore, the correct answer is option B) 78 kW.
Two geometrically similar pumps £re running at the same speed of 100 rpm'arid lifting water against the heads of 25 m and 16 m respectively. First pump is having an impeller diameter of 300 mm. The impeller diameter of second pump shall be- a)192 mm
- b)240 mm
- c)300 mm
- d)469 mm
Correct answer is option 'B'. Can you explain this answer?
Two geometrically similar pumps £re running at the same speed of 100 rpm'arid lifting water against the heads of 25 m and 16 m respectively. First pump is having an impeller diameter of 300 mm. The impeller diameter of second pump shall be
a)
192 mm
b)
240 mm
c)
300 mm
d)
469 mm
|
|
Arjun Menon answered |
Equating head coefficients, we get,
To obtain maximum hydraulic efficiency of pelton turbine, blade velocity should be ___________ Times the inlet velocity of jet.- a)Half
- b)One quarter
- c)Twice
- d)Thrice
Correct answer is option 'A'. Can you explain this answer?
To obtain maximum hydraulic efficiency of pelton turbine, blade velocity should be ___________ Times the inlet velocity of jet.
a)
Half
b)
One quarter
c)
Twice
d)
Thrice
|
|
Sanya Agarwal answered |
Hydraulic efficiency is defined as ratio between power given by water to runner of turbine and to the power supplied by water at inlet of the turbine. This efficiency will be maximum when differentiating it with “u” and it is obtained as u = v/2.
A centrifugal pump running at 500 rpm and at its maximum efficiency is delivering a head of 30 m at a flow rate of 60 liters per minute. If the rpm is changed to 1000, then the head H in metres and flow rate Q in litres per minute at maximum efficiency are estimated to be- a)H = 60, Q = 120
- b)H = 120, Q = 120
- c)H = 60, Q = 480
- d)H= 120, Q = 30
Correct answer is option 'B'. Can you explain this answer?
A centrifugal pump running at 500 rpm and at its maximum efficiency is delivering a head of 30 m at a flow rate of 60 liters per minute. If the rpm is changed to 1000, then the head H in metres and flow rate Q in litres per minute at maximum efficiency are estimated to be
a)
H = 60, Q = 120
b)
H = 120, Q = 120
c)
H = 60, Q = 480
d)
H= 120, Q = 30
|
|
Jyoti Choudhury answered |
We also know that specific speed will be constant.
To generate 10,000 HP under a head of 81 m while working at a speed of 500 rpm, the turbine of choice would be- a)Peiton
- b)Kaplan
- c)Bulb
- d)Francis
Correct answer is option 'D'. Can you explain this answer?
To generate 10,000 HP under a head of 81 m while working at a speed of 500 rpm, the turbine of choice would be
a)
Peiton
b)
Kaplan
c)
Bulb
d)
Francis
|
Ananya Sharma answered |
Power developed in kW
= 10,000 x 0.756 = 7560 kW
= 10,000 x 0.756 = 7560 kW
The product of mechanical efficiency and hydraulic efficiency is known as?- a)Mechanical efficiency
- b)Volumetric efficiency
- c)Hydraulic efficiency
- d)Overall efficiency
Correct answer is option 'D'. Can you explain this answer?
The product of mechanical efficiency and hydraulic efficiency is known as?
a)
Mechanical efficiency
b)
Volumetric efficiency
c)
Hydraulic efficiency
d)
Overall efficiency
|
|
Sanvi Kapoor answered |
Overall efficiency is defined as ratio of power available at shaft of turbine to power supplied at the inlet of turbine which is also product of mechanical and hydraulic efficiency.
The flow in volute casing outside the rotating impeller of a centrifugal pump is:- a)axial flow
- b)free vortex flow
- c)forced vortex flow
- d)radial flow
Correct answer is option 'B'. Can you explain this answer?
The flow in volute casing outside the rotating impeller of a centrifugal pump is:
a)
axial flow
b)
free vortex flow
c)
forced vortex flow
d)
radial flow
|
Mrinalini Chavan answered |
Flow in Volute Casing Outside the Rotating Impeller of a Centrifugal Pump
Explanation:
The flow in the volute casing outside the rotating impeller of a centrifugal pump is free vortex flow. This means that the flow in the volute casing follows a rotational pattern, with the fluid moving in a circular path around the center of the pump.
Understanding Volute Casing:
The volute casing is a spiral-shaped chamber that surrounds the impeller of a centrifugal pump. Its main function is to convert the kinetic energy of the fluid exiting the impeller into pressure energy. The volute casing gradually increases in area as it extends from the impeller outlet to the pump discharge.
Flow Pattern:
The flow pattern in the volute casing outside the rotating impeller is a free vortex flow. This means that the fluid particles move in circular paths around the center of the pump without any external forces acting on them. The fluid particles in the volute casing rotate around the axis of the pump in a smooth and continuous manner.
Characteristics of Free Vortex Flow:
- Rotation: In a free vortex flow, the fluid particles rotate around the center of the flow in a circular path.
- Constant Angular Velocity: The angular velocity of the fluid particles remains constant along the flow path.
- No External Forces: The fluid particles in a free vortex flow are not influenced by any external forces, such as pressure gradients or impeller blades.
- Conservation of Angular Momentum: The fluid particles in the volute casing conserve their angular momentum as they move along the flow path.
Advantages of Free Vortex Flow:
- Energy Conversion: The free vortex flow in the volute casing allows for efficient conversion of kinetic energy into pressure energy, increasing the pump's overall efficiency.
- Reduced Friction Losses: The absence of external forces in the free vortex flow minimizes friction losses, resulting in a smoother flow and reduced energy losses.
- Uniform Flow Distribution: The rotational nature of the flow ensures uniform distribution of the fluid across the pump discharge, preventing any localized pressure variations.
In conclusion, the flow in the volute casing outside the rotating impeller of a centrifugal pump is a free vortex flow. This flow pattern allows for efficient energy conversion and uniform flow distribution, making it an ideal choice for centrifugal pump design.
Explanation:
The flow in the volute casing outside the rotating impeller of a centrifugal pump is free vortex flow. This means that the flow in the volute casing follows a rotational pattern, with the fluid moving in a circular path around the center of the pump.
Understanding Volute Casing:
The volute casing is a spiral-shaped chamber that surrounds the impeller of a centrifugal pump. Its main function is to convert the kinetic energy of the fluid exiting the impeller into pressure energy. The volute casing gradually increases in area as it extends from the impeller outlet to the pump discharge.
Flow Pattern:
The flow pattern in the volute casing outside the rotating impeller is a free vortex flow. This means that the fluid particles move in circular paths around the center of the pump without any external forces acting on them. The fluid particles in the volute casing rotate around the axis of the pump in a smooth and continuous manner.
Characteristics of Free Vortex Flow:
- Rotation: In a free vortex flow, the fluid particles rotate around the center of the flow in a circular path.
- Constant Angular Velocity: The angular velocity of the fluid particles remains constant along the flow path.
- No External Forces: The fluid particles in a free vortex flow are not influenced by any external forces, such as pressure gradients or impeller blades.
- Conservation of Angular Momentum: The fluid particles in the volute casing conserve their angular momentum as they move along the flow path.
Advantages of Free Vortex Flow:
- Energy Conversion: The free vortex flow in the volute casing allows for efficient conversion of kinetic energy into pressure energy, increasing the pump's overall efficiency.
- Reduced Friction Losses: The absence of external forces in the free vortex flow minimizes friction losses, resulting in a smoother flow and reduced energy losses.
- Uniform Flow Distribution: The rotational nature of the flow ensures uniform distribution of the fluid across the pump discharge, preventing any localized pressure variations.
In conclusion, the flow in the volute casing outside the rotating impeller of a centrifugal pump is a free vortex flow. This flow pattern allows for efficient energy conversion and uniform flow distribution, making it an ideal choice for centrifugal pump design.
The simple elbow draft tube is placed close to the_______- a)Head race
- b)Tail race
- c)Tank
- d)Nozzle
Correct answer is option 'B'. Can you explain this answer?
The simple elbow draft tube is placed close to the_______
a)
Head race
b)
Tail race
c)
Tank
d)
Nozzle
|
Pankaj Rane answered |
Elbow Draft Tube Placement
The correct answer to the question is option 'B', which states that the simple elbow draft tube is placed close to the tail race. In order to understand why the draft tube is placed in this location, let's explore the concept of the draft tube and its purpose.
Draft Tube
A draft tube is a component used in hydraulic turbines, which are widely used in hydroelectric power plants. The primary function of the draft tube is to recover the kinetic energy of the water leaving the turbine and convert it into pressure energy. This helps in improving the overall efficiency of the turbine.
Purpose of the Draft Tube
The draft tube serves the following purposes:
1. Energy Recovery: As water flows through the turbine, its kinetic energy increases due to the pressure difference between the head race (where the water enters the turbine) and the tail race (where the water exits the turbine). The draft tube helps in converting this kinetic energy into pressure energy by gradually increasing the cross-sectional area of the flow path.
2. Pressure Stabilization: The draft tube also helps in stabilizing the pressure at the exit of the turbine. This is important because the pressure at the exit should be as close to atmospheric pressure as possible to minimize losses and prevent cavitation.
Placement of the Draft Tube
Now, let's discuss why the simple elbow draft tube is placed close to the tail race:
1. Flow Conditions: The tail race is the location where the water exits the turbine and enters the river or a reservoir. At this point, the water has already passed through the turbine and its velocity is relatively low. Placing the draft tube close to the tail race allows for a smooth transition of flow from the turbine to the draft tube.
2. Pressure Recovery: By placing the draft tube close to the tail race, the water can gradually expand and decelerate, allowing for the recovery of kinetic energy and conversion into pressure energy. This helps in maximizing the efficiency of the turbine.
3. Space Considerations: The tail race area usually has more available space compared to the head race area. This makes it easier to accommodate the draft tube and its associated components, such as the elbow.
Therefore, the simple elbow draft tube is placed close to the tail race in order to effectively recover the kinetic energy of the water exiting the turbine and convert it into pressure energy, while also considering flow conditions and space availability.
The correct answer to the question is option 'B', which states that the simple elbow draft tube is placed close to the tail race. In order to understand why the draft tube is placed in this location, let's explore the concept of the draft tube and its purpose.
Draft Tube
A draft tube is a component used in hydraulic turbines, which are widely used in hydroelectric power plants. The primary function of the draft tube is to recover the kinetic energy of the water leaving the turbine and convert it into pressure energy. This helps in improving the overall efficiency of the turbine.
Purpose of the Draft Tube
The draft tube serves the following purposes:
1. Energy Recovery: As water flows through the turbine, its kinetic energy increases due to the pressure difference between the head race (where the water enters the turbine) and the tail race (where the water exits the turbine). The draft tube helps in converting this kinetic energy into pressure energy by gradually increasing the cross-sectional area of the flow path.
2. Pressure Stabilization: The draft tube also helps in stabilizing the pressure at the exit of the turbine. This is important because the pressure at the exit should be as close to atmospheric pressure as possible to minimize losses and prevent cavitation.
Placement of the Draft Tube
Now, let's discuss why the simple elbow draft tube is placed close to the tail race:
1. Flow Conditions: The tail race is the location where the water exits the turbine and enters the river or a reservoir. At this point, the water has already passed through the turbine and its velocity is relatively low. Placing the draft tube close to the tail race allows for a smooth transition of flow from the turbine to the draft tube.
2. Pressure Recovery: By placing the draft tube close to the tail race, the water can gradually expand and decelerate, allowing for the recovery of kinetic energy and conversion into pressure energy. This helps in maximizing the efficiency of the turbine.
3. Space Considerations: The tail race area usually has more available space compared to the head race area. This makes it easier to accommodate the draft tube and its associated components, such as the elbow.
Therefore, the simple elbow draft tube is placed close to the tail race in order to effectively recover the kinetic energy of the water exiting the turbine and convert it into pressure energy, while also considering flow conditions and space availability.
A francis turbine is:- a)inward flow reaction turbine
- b)inward flow impulse turbine
- c)outward flow reaction turbine
- d)outward flow impulse turbine
Correct answer is option 'A'. Can you explain this answer?
A francis turbine is:
a)
inward flow reaction turbine
b)
inward flow impulse turbine
c)
outward flow reaction turbine
d)
outward flow impulse turbine
|
|
Gate Funda answered |
Impulse Turbine: If at the inlet of the turbine, the energy available is only kinetic energy, the turbine is known as impulse turbine. e.g. a Pelton wheel turbine.
Reaction Turbine: If at the inlet of the turbine, the water possesses kinetic energy as well as pressure energy, the turbine is known as a reaction turbine. e.g. e Francis and Kaplan turbine.
Tangential flow turbines: In this type of turbine, the water strikes the runner in the direction of the tangent to the wheel. Example: Pelton wheel turbine
Radial flow turbines: In this type of turbine, the water strikes in the radial direction. accordingly, it is further classified as
Reaction Turbine: If at the inlet of the turbine, the water possesses kinetic energy as well as pressure energy, the turbine is known as a reaction turbine. e.g. e Francis and Kaplan turbine.
Tangential flow turbines: In this type of turbine, the water strikes the runner in the direction of the tangent to the wheel. Example: Pelton wheel turbine
Radial flow turbines: In this type of turbine, the water strikes in the radial direction. accordingly, it is further classified as
- Inward flow turbine: The flow is inward from periphery to the centre (centripetal type); Example: old Francis turbine
- Outward flow turbine: The flow is outward from the centre to periphery (centrifugal type); Example: Fourneyron turbine
Axial flow turbine: The flow of water is in the direction parallel to the axis of the shaft. Example: Kaplan turbine and propeller turbine
∴ Francis turbine is a radial inward flowing reaction turbine.
∴ Francis turbine is a radial inward flowing reaction turbine.
Tests were conducted on a francis turbine of 0.8 m diameter under a head of 9m. The turbine running at 240 rpm develops 84.5 kW and the water consumption was 1.2 m3/s. If the some turbine operated under a head of 16 m, the new discharge will be- a)1.4 m3/s
- b)1.6 m3/s
- c)1.8 m 3/s
- d)2 m3/s
Correct answer is option 'B'. Can you explain this answer?
Tests were conducted on a francis turbine of 0.8 m diameter under a head of 9m. The turbine running at 240 rpm develops 84.5 kW and the water consumption was 1.2 m3/s. If the some turbine operated under a head of 16 m, the new discharge will be
a)
1.4 m3/s
b)
1.6 m3/s
c)
1.8 m 3/s
d)
2 m3/s
|
|
Baishali Chopra answered |
A Francis turbine working at 400 rpm has a unit speed of 50 rpm and develops 500 kW of power. What is the effective head under which this turbine operates?- a)62.5 m
- b)64.0 m
- c)40.0 m
- d)100 m
Correct answer is option 'B'. Can you explain this answer?
A Francis turbine working at 400 rpm has a unit speed of 50 rpm and develops 500 kW of power. What is the effective head under which this turbine operates?
a)
62.5 m
b)
64.0 m
c)
40.0 m
d)
100 m
|
|
Madhurima Banerjee answered |
Unit speed of the turbine is given by,
The velocity of the flow at the inlet of Kaplan turbine is V. In an experimental setup, what could be the possible value of the velocity of the flow at the outlet of Kaplan turbine?- a)V
- b)0.8V
- c)1.2V
- d)2V
Correct answer is option 'B'. Can you explain this answer?
The velocity of the flow at the inlet of Kaplan turbine is V. In an experimental setup, what could be the possible value of the velocity of the flow at the outlet of Kaplan turbine?
a)
V
b)
0.8V
c)
1.2V
d)
2V
|
|
Sanya Agarwal answered |
The flow velocity of turbine at the outlet of the Kaplan turbine will be lesser than that of the inlet due to effects of friction in the blade. Hence, practically a lower value would be obtained. 0.8V is the only option lower than V.
Most common application of the draft tube is ______- a)Rotor
- b)Motor
- c)Pump
- d)Filter
Correct answer is option 'C'. Can you explain this answer?
Most common application of the draft tube is ______
a)
Rotor
b)
Motor
c)
Pump
d)
Filter
|
Partho Jain answered |
Application of Draft Tube
Draft tubes are commonly used in pumps for various applications.
- Increased Efficiency: The primary application of a draft tube is to increase the overall efficiency of a pump. By using a draft tube, the velocity of the fluid leaving the pump impeller is reduced, which results in increased pressure and efficiency.
- Energy Savings: Draft tubes help in reducing the energy consumption of pumps by converting the kinetic energy of the fluid into pressure energy. This leads to energy savings in the long run.
- Preventing Recirculation: Draft tubes help in preventing recirculation of fluid back into the pump impeller, which can cause cavitation and reduce the performance of the pump.
- Improved Flow: The use of a draft tube ensures a more uniform and stable flow of fluid, which is essential for many industrial and agricultural applications.
- Applications in Hydropower: Draft tubes are also commonly used in hydropower plants to increase the efficiency of turbines and generate more power from the same amount of water flow.
Overall, the draft tube plays a crucial role in enhancing the performance and efficiency of pumps, especially in applications where high pressure and flow rates are required.
The value of coefficient of velocity is _____________- a)0.98
- b)0.65
- c)0.85
- d)0.33
Correct answer is option 'A'. Can you explain this answer?
The value of coefficient of velocity is _____________
a)
0.98
b)
0.65
c)
0.85
d)
0.33
|
|
Sanya Agarwal answered |
Coefficient of velocity is defined as ratio of actual velocity of jet at vena contraction to theoretical velocity. Its value is approximate to 0.98.
NPSH is relevant ________- a)Outside the pumps
- b)Inside the pumps
- c)Away from the pumps
- d)Series and parallel with the pumps
Correct answer is option 'A'. Can you explain this answer?
NPSH is relevant ________
a)
Outside the pumps
b)
Inside the pumps
c)
Away from the pumps
d)
Series and parallel with the pumps
|
|
Rounak Saini answered |
Outside the pumps
NPSH (Net Positive Suction Head) is a critical parameter in pump operation and is relevant outside the pumps for various reasons.
Preventing cavitation
One of the main reasons NPSH is relevant outside the pumps is to prevent cavitation. Cavitation occurs when the NPSH available (NPSHa) is insufficient to prevent the formation of vapor bubbles in the pump. These vapor bubbles can collapse violently, causing damage to the pump components and reducing its efficiency. Therefore, it is crucial to ensure that the NPSHa exceeds the NPSH required (NPSHr) to prevent cavitation.
Determining pump performance
NPSH is also relevant outside the pumps as it is used to determine the pump's performance under different operating conditions. By calculating the NPSHa and comparing it to the NPSHr, engineers can assess the pump's ability to operate efficiently without cavitation. This information is crucial in selecting the right pump for a particular application and ensuring its optimal performance.
Designing piping systems
In addition, NPSH is relevant outside the pumps when designing piping systems. Engineers need to consider the NPSHa at various points along the suction piping to ensure that the pump receives an adequate supply of liquid without causing cavitation. By analyzing the NPSH requirements at different locations, designers can optimize the piping layout to minimize pressure losses and maintain sufficient NPSHa.
In conclusion, NPSH is a critical parameter in pump operation, and its relevance extends beyond the pumps themselves. By considering NPSH requirements outside the pumps, engineers can prevent cavitation, optimize pump performance, and design efficient piping systems.
NPSH (Net Positive Suction Head) is a critical parameter in pump operation and is relevant outside the pumps for various reasons.
Preventing cavitation
One of the main reasons NPSH is relevant outside the pumps is to prevent cavitation. Cavitation occurs when the NPSH available (NPSHa) is insufficient to prevent the formation of vapor bubbles in the pump. These vapor bubbles can collapse violently, causing damage to the pump components and reducing its efficiency. Therefore, it is crucial to ensure that the NPSHa exceeds the NPSH required (NPSHr) to prevent cavitation.
Determining pump performance
NPSH is also relevant outside the pumps as it is used to determine the pump's performance under different operating conditions. By calculating the NPSHa and comparing it to the NPSHr, engineers can assess the pump's ability to operate efficiently without cavitation. This information is crucial in selecting the right pump for a particular application and ensuring its optimal performance.
Designing piping systems
In addition, NPSH is relevant outside the pumps when designing piping systems. Engineers need to consider the NPSHa at various points along the suction piping to ensure that the pump receives an adequate supply of liquid without causing cavitation. By analyzing the NPSH requirements at different locations, designers can optimize the piping layout to minimize pressure losses and maintain sufficient NPSHa.
In conclusion, NPSH is a critical parameter in pump operation, and its relevance extends beyond the pumps themselves. By considering NPSH requirements outside the pumps, engineers can prevent cavitation, optimize pump performance, and design efficient piping systems.
If we use two lower capacity pumps in parallel, cavitation ________- a)Increases
- b)Decreases
- c)Same
- d)Independent
Correct answer is option 'B'. Can you explain this answer?
If we use two lower capacity pumps in parallel, cavitation ________
a)
Increases
b)
Decreases
c)
Same
d)
Independent
|
|
Sanvi Kapoor answered |
If we use two lower capacity pumps in parallel, cavitation decreases. It happens when the NPSh value is bought in its safety limit.
Which among the following velocities cannot be found using the velocity triangle?- a)Tangential
- b)Whirl
- c)Relative
- d)Parabolic
Correct answer is option 'D'. Can you explain this answer?
Which among the following velocities cannot be found using the velocity triangle?
a)
Tangential
b)
Whirl
c)
Relative
d)
Parabolic
|
|
Anjana Mukherjee answered |
Understanding the Velocity Triangle
The velocity triangle is a fundamental concept in fluid mechanics, particularly in the analysis of turbomachines. It helps visualize different components of velocity in relation to a rotating system.
Components of the Velocity Triangle
The velocity triangle consists of three main velocities:
- Tangential Velocity (Vt): The velocity of the fluid in the tangential direction at the rotor or impeller.
- Whirl Velocity (Vw): This represents the velocity component that contributes to the swirling motion of the fluid around the rotor.
- Relative Velocity (Vr): The velocity of the fluid relative to the moving rotor.
Why Parabolic Velocity Cannot Be Found Using the Velocity Triangle
The parabolic velocity refers to a trajectory of fluid flow that follows a parabolic path, typically seen in free-fall scenarios or projectile motion. This type of motion does not relate to rotational systems and thus cannot be represented within the framework of the velocity triangle.
- Non-Rotational Context: Parabolic motion is not associated with rotating machinery or flow around an impeller, making it irrelevant to the velocity triangle.
- Different Dynamics: The dynamics of parabolic motion involve gravitational acceleration and initial velocity factors, which are outside the scope of the velocity triangle's application.
Conclusion
In summary, among the given options, parabolic velocity (Option D) cannot be derived from the velocity triangle due to its distinct nature and application in fluid dynamics compared to tangential, whirl, and relative velocities, which are all applicable to rotating systems.
The velocity triangle is a fundamental concept in fluid mechanics, particularly in the analysis of turbomachines. It helps visualize different components of velocity in relation to a rotating system.
Components of the Velocity Triangle
The velocity triangle consists of three main velocities:
- Tangential Velocity (Vt): The velocity of the fluid in the tangential direction at the rotor or impeller.
- Whirl Velocity (Vw): This represents the velocity component that contributes to the swirling motion of the fluid around the rotor.
- Relative Velocity (Vr): The velocity of the fluid relative to the moving rotor.
Why Parabolic Velocity Cannot Be Found Using the Velocity Triangle
The parabolic velocity refers to a trajectory of fluid flow that follows a parabolic path, typically seen in free-fall scenarios or projectile motion. This type of motion does not relate to rotational systems and thus cannot be represented within the framework of the velocity triangle.
- Non-Rotational Context: Parabolic motion is not associated with rotating machinery or flow around an impeller, making it irrelevant to the velocity triangle.
- Different Dynamics: The dynamics of parabolic motion involve gravitational acceleration and initial velocity factors, which are outside the scope of the velocity triangle's application.
Conclusion
In summary, among the given options, parabolic velocity (Option D) cannot be derived from the velocity triangle due to its distinct nature and application in fluid dynamics compared to tangential, whirl, and relative velocities, which are all applicable to rotating systems.
The velocity of flow through a Kaplan turbine is 10 m/s. The outer diameter of the runner is 4 m and the hub diameter is 2 m. Find the volume flow rate of the turbine in m3/s?- a)95
- b)75
- c)85
- d)105
Correct answer is option 'A'. Can you explain this answer?
The velocity of flow through a Kaplan turbine is 10 m/s. The outer diameter of the runner is 4 m and the hub diameter is 2 m. Find the volume flow rate of the turbine in m3/s?
a)
95
b)
75
c)
85
d)
105
|
Sharmila Gupta answered |
To find the volume flow rate of the turbine, we need to calculate the cross-sectional area of flow and multiply it by the velocity of flow.
Given data:
Velocity of flow (v) = 10 m/s
Outer diameter of the runner (D) = 4 m
Hub diameter (d) = 2 m
To calculate the cross-sectional area of flow, we need to subtract the area of the hub from the area of the runner.
1. Calculate the area of the runner (A_r):
The area of a circle is given by the formula A = πr^2, where r is the radius.
The radius of the runner (R_r) is half the diameter, so R_r = D/2 = 4/2 = 2 m.
Therefore, the area of the runner is A_r = π(2)^2 = 4π m^2.
2. Calculate the area of the hub (A_h):
The radius of the hub (R_h) is half the hub diameter, so R_h = d/2 = 2/2 = 1 m.
Therefore, the area of the hub is A_h = π(1)^2 = π m^2.
3. Calculate the cross-sectional area of flow (A_flow):
A_flow = A_r - A_h
A_flow = 4π - π
A_flow = 3π m^2.
4. Calculate the volume flow rate (Q):
Q = A_flow * v
Q = 3π * 10
Q ≈ 30π m^3/s
Approximating the value of π as 3.14:
Q ≈ 30 * 3.14
Q ≈ 94.2 m^3/s
Rounding off to the nearest whole number, the volume flow rate of the turbine is approximately 94 m^3/s.
Therefore, the correct answer is option A: 95.
Given data:
Velocity of flow (v) = 10 m/s
Outer diameter of the runner (D) = 4 m
Hub diameter (d) = 2 m
To calculate the cross-sectional area of flow, we need to subtract the area of the hub from the area of the runner.
1. Calculate the area of the runner (A_r):
The area of a circle is given by the formula A = πr^2, where r is the radius.
The radius of the runner (R_r) is half the diameter, so R_r = D/2 = 4/2 = 2 m.
Therefore, the area of the runner is A_r = π(2)^2 = 4π m^2.
2. Calculate the area of the hub (A_h):
The radius of the hub (R_h) is half the hub diameter, so R_h = d/2 = 2/2 = 1 m.
Therefore, the area of the hub is A_h = π(1)^2 = π m^2.
3. Calculate the cross-sectional area of flow (A_flow):
A_flow = A_r - A_h
A_flow = 4π - π
A_flow = 3π m^2.
4. Calculate the volume flow rate (Q):
Q = A_flow * v
Q = 3π * 10
Q ≈ 30π m^3/s
Approximating the value of π as 3.14:
Q ≈ 30 * 3.14
Q ≈ 94.2 m^3/s
Rounding off to the nearest whole number, the volume flow rate of the turbine is approximately 94 m^3/s.
Therefore, the correct answer is option A: 95.
For a hydro-electric project with reaction turbine, the draft tube at the exit from the turbine is- a)always immersed in water
- b)always above the water
- c)may either be above or below the water
- d)above or below the water depending on the unit speed of the turbine
Correct answer is option 'A'. Can you explain this answer?
For a hydro-electric project with reaction turbine, the draft tube at the exit from the turbine is
a)
always immersed in water
b)
always above the water
c)
may either be above or below the water
d)
above or below the water depending on the unit speed of the turbine
|
|
Rajdeep Gupta answered |
Draft tube must be air-tight and under all-conditions of its operation its lower end must be submerged below the level of water in the tail race. It has two purposes:
(i) Permits a negative or suction head to be established at the runner exit.
(ii) Converts a large portion of velocity energy rejected from the runner into useful pressure energy.
(i) Permits a negative or suction head to be established at the runner exit.
(ii) Converts a large portion of velocity energy rejected from the runner into useful pressure energy.
In this type of low head turbine, the guide vanes are fixed to the hub of the turbine and are not adjustable. What is this type of turbine called?
- a)Propeller Turbine
- b)Kaplan Turbine
- c)Francis turbine
- d)Pelton turbine
Correct answer is option 'A'. Can you explain this answer?
In this type of low head turbine, the guide vanes are fixed to the hub of the turbine and are not adjustable. What is this type of turbine called?
a)
Propeller Turbine
b)
Kaplan Turbine
c)
Francis turbine
d)
Pelton turbine
|
Jaya Yadav answered |
Francis turbine
The correct answer is option 'A' - Francis turbine.
The Francis turbine is a type of water turbine that is widely used in hydroelectric power plants for generating electricity. It is a reaction turbine, which means that the turbine blades are fully submerged in the water flow and the energy conversion occurs through both pressure and velocity changes.
Design and Components
The Francis turbine consists of several key components, including the runner, guide vanes, and the turbine shaft.
1. Runner: The runner is the main rotating component of the turbine. It is composed of a series of curved blades that are attached to a central hub. The runner is responsible for extracting energy from the water flow and converting it into rotational motion.
2. Guide Vanes: The guide vanes are fixed to the hub of the turbine and are not adjustable. They are designed to direct the water flow onto the runner blades at a specific angle. The angle of the guide vanes determines the efficiency and power output of the turbine. In a Francis turbine, the guide vanes are typically arranged in a spiral or helical pattern, allowing for better control over the water flow.
3. Turbine Shaft: The turbine shaft is connected to the runner and transfers the rotational motion to the generator, which converts it into electrical energy. It is designed to withstand the high rotational speeds and torque generated by the turbine.
Working Principle
The working principle of a Francis turbine involves the following steps:
1. Water enters the turbine through a spiral casing, which directs the flow onto the guide vanes.
2. The guide vanes control the flow direction and angle, redirecting the water onto the runner blades.
3. As the water strikes the runner blades, it exerts a force on them, causing the runner to rotate.
4. The rotational motion of the runner is transferred to the turbine shaft, which is connected to a generator.
5. The generator converts the mechanical energy into electrical energy, which can be used to power homes, businesses, and industries.
Advantages of Francis Turbine
- High efficiency: The Francis turbine is known for its high efficiency, especially in medium to high head applications.
- Wide operating range: It can operate efficiently over a wide range of water flow rates and heads.
- Compact design: The turbine has a compact design, making it suitable for installations with limited space.
- Low maintenance: The fixed guide vanes require minimal maintenance compared to adjustable guide vanes.
In conclusion, the Francis turbine is a type of low head turbine where the guide vanes are fixed to the hub of the turbine and are not adjustable. It is a widely used turbine in hydroelectric power plants due to its high efficiency, wide operating range, and compact design.
The correct answer is option 'A' - Francis turbine.
The Francis turbine is a type of water turbine that is widely used in hydroelectric power plants for generating electricity. It is a reaction turbine, which means that the turbine blades are fully submerged in the water flow and the energy conversion occurs through both pressure and velocity changes.
Design and Components
The Francis turbine consists of several key components, including the runner, guide vanes, and the turbine shaft.
1. Runner: The runner is the main rotating component of the turbine. It is composed of a series of curved blades that are attached to a central hub. The runner is responsible for extracting energy from the water flow and converting it into rotational motion.
2. Guide Vanes: The guide vanes are fixed to the hub of the turbine and are not adjustable. They are designed to direct the water flow onto the runner blades at a specific angle. The angle of the guide vanes determines the efficiency and power output of the turbine. In a Francis turbine, the guide vanes are typically arranged in a spiral or helical pattern, allowing for better control over the water flow.
3. Turbine Shaft: The turbine shaft is connected to the runner and transfers the rotational motion to the generator, which converts it into electrical energy. It is designed to withstand the high rotational speeds and torque generated by the turbine.
Working Principle
The working principle of a Francis turbine involves the following steps:
1. Water enters the turbine through a spiral casing, which directs the flow onto the guide vanes.
2. The guide vanes control the flow direction and angle, redirecting the water onto the runner blades.
3. As the water strikes the runner blades, it exerts a force on them, causing the runner to rotate.
4. The rotational motion of the runner is transferred to the turbine shaft, which is connected to a generator.
5. The generator converts the mechanical energy into electrical energy, which can be used to power homes, businesses, and industries.
Advantages of Francis Turbine
- High efficiency: The Francis turbine is known for its high efficiency, especially in medium to high head applications.
- Wide operating range: It can operate efficiently over a wide range of water flow rates and heads.
- Compact design: The turbine has a compact design, making it suitable for installations with limited space.
- Low maintenance: The fixed guide vanes require minimal maintenance compared to adjustable guide vanes.
In conclusion, the Francis turbine is a type of low head turbine where the guide vanes are fixed to the hub of the turbine and are not adjustable. It is a widely used turbine in hydroelectric power plants due to its high efficiency, wide operating range, and compact design.
Specific speed of a Francis turbine is _______- a)8.5 to 30
- b)30 to 51
- c)51 to 225
- d)230 to 500
Correct answer is option 'C'. Can you explain this answer?
Specific speed of a Francis turbine is _______
a)
8.5 to 30
b)
30 to 51
c)
51 to 225
d)
230 to 500
|
|
Sanya Agarwal answered |
Specific speed of a Francis turbine is equal to 51 to 225. Specific speed is denoted by Ns. It is used to characterize speeds in turbo machinery. Some of the main examples of turbomachinery are turbines. Specific speed plays an important role in the turbine.
Which one of the following statements is not correct in respect of hydraulic turbines?- a)(Speed) is proportional to (Diameter)1/2
- b)(Power) is proportional to (Speed)3
- c)(Power) is proportional to (Head)3/2
- d)(Speed) is proportional to (Head)1/2
Correct answer is option 'A'. Can you explain this answer?
Which one of the following statements is not correct in respect of hydraulic turbines?
a)
(Speed) is proportional to (Diameter)1/2
b)
(Power) is proportional to (Speed)3
c)
(Power) is proportional to (Head)3/2
d)
(Speed) is proportional to (Head)1/2
|
|
Gitanjali Menon answered |
In a Francis turbine, maximum efficiency is obtained when:- a)Relative velocity is radial at the outlet
- b)Absolute velocity is radial at the outlet
- c)Velocity of flow is constant
- d)Guide vane angle is 90 degree
Correct answer is option 'B'. Can you explain this answer?
In a Francis turbine, maximum efficiency is obtained when:
a)
Relative velocity is radial at the outlet
b)
Absolute velocity is radial at the outlet
c)
Velocity of flow is constant
d)
Guide vane angle is 90 degree
|
|
Tanishq Nair answered |
Explanation:
Francis turbine is a type of reaction turbine that is designed to work with high pressure and low flow rate. It is widely used in hydroelectric power plants. The efficiency of the Francis turbine can be increased by optimizing the angle of the guide vanes and the shape of the runner blades.
Radial Outlet:
When the relative velocity is radial at the outlet, the water flows in a direction perpendicular to the axis of the turbine. This results in a decrease in the tangential component of the velocity, which reduces the overall efficiency of the turbine.
Absolute Velocity:
When the absolute velocity is radial at the outlet, the water flows in the same direction as the axis of the turbine. This results in a decrease in the axial component of the velocity, which increases the overall efficiency of the turbine.
Constant Velocity:
If the velocity of flow is constant, it means that the turbine is not extracting the maximum energy from the water. In this case, the efficiency of the turbine will be less than the maximum.
Guide Vane Angle:
The guide vane angle is the angle between the direction of the incoming water and the direction of the guide vanes. The angle of the guide vanes can be optimized to increase the efficiency of the turbine. However, the maximum efficiency is not obtained when the guide vane angle is 90 degrees.
Therefore, the correct answer is option 'B', which states that the maximum efficiency is obtained when the absolute velocity is radial at the outlet.
Francis turbine is a type of reaction turbine that is designed to work with high pressure and low flow rate. It is widely used in hydroelectric power plants. The efficiency of the Francis turbine can be increased by optimizing the angle of the guide vanes and the shape of the runner blades.
Radial Outlet:
When the relative velocity is radial at the outlet, the water flows in a direction perpendicular to the axis of the turbine. This results in a decrease in the tangential component of the velocity, which reduces the overall efficiency of the turbine.
Absolute Velocity:
When the absolute velocity is radial at the outlet, the water flows in the same direction as the axis of the turbine. This results in a decrease in the axial component of the velocity, which increases the overall efficiency of the turbine.
Constant Velocity:
If the velocity of flow is constant, it means that the turbine is not extracting the maximum energy from the water. In this case, the efficiency of the turbine will be less than the maximum.
Guide Vane Angle:
The guide vane angle is the angle between the direction of the incoming water and the direction of the guide vanes. The angle of the guide vanes can be optimized to increase the efficiency of the turbine. However, the maximum efficiency is not obtained when the guide vane angle is 90 degrees.
Therefore, the correct answer is option 'B', which states that the maximum efficiency is obtained when the absolute velocity is radial at the outlet.
Which one of the following statements is correct?- a)Reciprocating pumps are less efficient than centrifugal pumps.
- b)Delivery from a reciprocating pump is pulsating.
- c)Reciprocating pumps are suitable for large discharges and smaller heads.
- d)For a negative slip to occur, a reciprocating pump must have a coefficient of discharge less than unity.
Correct answer is option 'B'. Can you explain this answer?
Which one of the following statements is correct?
a)
Reciprocating pumps are less efficient than centrifugal pumps.
b)
Delivery from a reciprocating pump is pulsating.
c)
Reciprocating pumps are suitable for large discharges and smaller heads.
d)
For a negative slip to occur, a reciprocating pump must have a coefficient of discharge less than unity.
|
|
Abhay Kapoor answered |
If coefficient of discharge is more than one, negative slip would occur.
In Pelton wheel if angle of deflection is not mentioned then we assume it as______________- a)150 degrees
- b)200 degrees
- c)165 degrees
- d)185 degrees
Correct answer is option 'C'. Can you explain this answer?
In Pelton wheel if angle of deflection is not mentioned then we assume it as______________
a)
150 degrees
b)
200 degrees
c)
165 degrees
d)
185 degrees
|
|
Sanya Agarwal answered |
It is standard value for deflection of jet, which is found by performing several experimental operations.
Degree of reactions are most commonly used in________- a)Turbomachinery
- b)Pressure drag
- c)Aerodynamics
- d)Automobiles
Correct answer is option 'A'. Can you explain this answer?
Degree of reactions are most commonly used in________
a)
Turbomachinery
b)
Pressure drag
c)
Aerodynamics
d)
Automobiles
|
Nishanth Banerjee answered |
Degree of reactions refers to the ratio of the change in fluid momentum to the change in rotor momentum in a turbomachinery system. It is a measure of the energy transfer that occurs in the rotor of a turbomachine, such as a turbine or a compressor. The degree of reaction is most commonly used in turbomachinery applications.
Turbomachinery (Option A):
- In turbomachinery, such as turbines and compressors, the degree of reaction is an important parameter that characterizes the performance of the machine.
- It is used to determine the energy transfer and efficiency of the machine.
- The degree of reaction is calculated by comparing the change in fluid momentum across the rotor with the change in rotor momentum.
- It provides valuable information about the aerodynamic behavior of the machine and helps in the design and analysis of turbomachinery systems.
Pressure Drag (Option B):
- Pressure drag is a type of drag force that acts on an object moving through a fluid.
- It is caused by the pressure difference between the front and rear surfaces of the object.
- The degree of reaction is not directly related to pressure drag. Pressure drag is primarily influenced by the shape and size of the object, rather than the energy transfer in the fluid.
Aerodynamics (Option C):
- Aerodynamics is the study of the motion of air and other gases, particularly as they interact with solid objects.
- The degree of reaction is commonly used in aerodynamics, especially in the design and analysis of turbomachinery, which is utilized in various aerodynamic applications such as aircraft engines.
- It helps in understanding the energy transfer and efficiency of the turbomachinery in aerodynamic systems.
Automobiles (Option D):
- While the degree of reaction may have some applications in the automotive industry, it is not commonly used in this context.
- Automobiles typically use different propulsion systems, such as internal combustion engines or electric motors, which do not rely on turbomachinery.
- The degree of reaction is more relevant to the design and analysis of turbomachinery systems, which are not commonly found in automobiles.
In conclusion, the degree of reaction is most commonly used in turbomachinery applications, such as turbines and compressors, where it helps in understanding the energy transfer and efficiency of the system. It is not directly related to pressure drag, aerodynamics, or automobiles.
Turbomachinery (Option A):
- In turbomachinery, such as turbines and compressors, the degree of reaction is an important parameter that characterizes the performance of the machine.
- It is used to determine the energy transfer and efficiency of the machine.
- The degree of reaction is calculated by comparing the change in fluid momentum across the rotor with the change in rotor momentum.
- It provides valuable information about the aerodynamic behavior of the machine and helps in the design and analysis of turbomachinery systems.
Pressure Drag (Option B):
- Pressure drag is a type of drag force that acts on an object moving through a fluid.
- It is caused by the pressure difference between the front and rear surfaces of the object.
- The degree of reaction is not directly related to pressure drag. Pressure drag is primarily influenced by the shape and size of the object, rather than the energy transfer in the fluid.
Aerodynamics (Option C):
- Aerodynamics is the study of the motion of air and other gases, particularly as they interact with solid objects.
- The degree of reaction is commonly used in aerodynamics, especially in the design and analysis of turbomachinery, which is utilized in various aerodynamic applications such as aircraft engines.
- It helps in understanding the energy transfer and efficiency of the turbomachinery in aerodynamic systems.
Automobiles (Option D):
- While the degree of reaction may have some applications in the automotive industry, it is not commonly used in this context.
- Automobiles typically use different propulsion systems, such as internal combustion engines or electric motors, which do not rely on turbomachinery.
- The degree of reaction is more relevant to the design and analysis of turbomachinery systems, which are not commonly found in automobiles.
In conclusion, the degree of reaction is most commonly used in turbomachinery applications, such as turbines and compressors, where it helps in understanding the energy transfer and efficiency of the system. It is not directly related to pressure drag, aerodynamics, or automobiles.
When a container containing a liquid is rotated, then due to centrifugal action, then which of these energies are changed?- a)Kinetic energy
- b)Pressure energy
- c)Potential energy
- d)Energy due to viscous force
Correct answer is option 'B'. Can you explain this answer?
When a container containing a liquid is rotated, then due to centrifugal action, then which of these energies are changed?
a)
Kinetic energy
b)
Pressure energy
c)
Potential energy
d)
Energy due to viscous force
|
|
Sanvi Kapoor answered |
When a container containing a liquid is rotated, then due to centrifugal action there is a change in pressure energy.
Draft tube is also called_______- a)Straight divergent tube
- b)Simple elbow tube
- c)Thermal tube
- d)Elbow tube with varying cross section
Correct answer is option 'A'. Can you explain this answer?
Draft tube is also called_______
a)
Straight divergent tube
b)
Simple elbow tube
c)
Thermal tube
d)
Elbow tube with varying cross section
|
|
Prasad Desai answered |
Draft Tube - Explanation
Draft tube is a crucial component in hydraulic turbines to improve their efficiency. Let's discuss the different aspects of draft tube below:
Straight Divergent Tube
- The correct answer, a draft tube is also known as a straight divergent tube.
- It is a component in hydraulic turbines that helps in converting the kinetic energy of water into useful mechanical energy.
Function of Draft Tube
- The main function of a draft tube is to recover the kinetic energy of water leaving the turbine runner.
- It helps in reducing the loss of energy and increases the overall efficiency of the turbine.
Design of Draft Tube
- Draft tubes are designed with a gradually increasing cross-sectional area in the flow direction.
- This design helps in reducing the flow velocity of water leaving the turbine, which in turn reduces the energy losses.
Types of Draft Tubes
- There are different types of draft tubes such as simple elbow tube, thermal tube, and elbow tube with varying cross-section.
- Each type is designed based on the specific requirements of the hydraulic turbine and the operating conditions.
Importance of Draft Tube
- A well-designed draft tube is essential for the optimal performance of hydraulic turbines.
- It plays a crucial role in increasing the efficiency of the turbine and maximizing the power output.
In conclusion, a draft tube, also known as a straight divergent tube, is a critical component in hydraulic turbines that helps in recovering the kinetic energy of water leaving the turbine runner. Its design and function are essential for improving the overall efficiency of the turbine.
Owing to a sudden closure of turbines in a powerhouse:- a)A positive surge will occur in head race channel with surge front moving downstream
- b)A positive surge will occur in head race channel with surge front moving upstream
- c)A negative surge will occur in head race channel with surge front moving up stream
- d)A negative surge will occur In head race channel with surge front moving downstream
Correct answer is option 'B'. Can you explain this answer?
Owing to a sudden closure of turbines in a powerhouse:
a)
A positive surge will occur in head race channel with surge front moving downstream
b)
A positive surge will occur in head race channel with surge front moving upstream
c)
A negative surge will occur in head race channel with surge front moving up stream
d)
A negative surge will occur In head race channel with surge front moving downstream
|
|
Navya Kaur answered |
If the sluice gate of the head race channel is suddenly closed (for closing turbine) positive surge will move upstream. If the sluice gate is suddenly opened (to start turbine) positive surge will move downstream.
The speed factor of a Peiton turbine for maximum efficiency condition is about- a)0.46
- b)0.50
- c)0.86
- d)0.95
Correct answer is option 'A'. Can you explain this answer?
The speed factor of a Peiton turbine for maximum efficiency condition is about
a)
0.46
b)
0.50
c)
0.86
d)
0.95
|
Diya Ahuja answered |
**Explanation:**
The Peiton turbine is a type of hydraulic turbine that operates based on the principle of impulse. Its efficiency depends on various factors, including the speed factor.
The speed factor, denoted by λ (lambda), is a dimensionless parameter that represents the ratio of the actual speed of the turbine runner to the ideal speed at which it should operate for maximum efficiency. It is defined as:
λ = (n * D) / (g * H)^0.5
Where:
- λ = Speed factor
- n = Runner speed in rpm
- D = Runner diameter in meters
- g = Acceleration due to gravity (9.81 m/s^2)
- H = Water head (the difference in water level between the inlet and outlet of the turbine) in meters
For maximum efficiency, the speed factor should be around 0.46.
**Reasoning:**
The speed factor determines the relative velocity of the water at the inlet of the turbine runner. At maximum efficiency, the water should strike the runner blades at an angle of 165 degrees.
If the speed factor is too low (below 0.46), the water strikes the runner blades at a wider angle, resulting in inefficient use of the water's kinetic energy.
If the speed factor is too high (above 0.46), the water strikes the runner blades at a narrower angle, leading to excessive turbulence and energy losses.
Therefore, the speed factor of a Peiton turbine for maximum efficiency condition is approximately 0.46.
The Peiton turbine is a type of hydraulic turbine that operates based on the principle of impulse. Its efficiency depends on various factors, including the speed factor.
The speed factor, denoted by λ (lambda), is a dimensionless parameter that represents the ratio of the actual speed of the turbine runner to the ideal speed at which it should operate for maximum efficiency. It is defined as:
λ = (n * D) / (g * H)^0.5
Where:
- λ = Speed factor
- n = Runner speed in rpm
- D = Runner diameter in meters
- g = Acceleration due to gravity (9.81 m/s^2)
- H = Water head (the difference in water level between the inlet and outlet of the turbine) in meters
For maximum efficiency, the speed factor should be around 0.46.
**Reasoning:**
The speed factor determines the relative velocity of the water at the inlet of the turbine runner. At maximum efficiency, the water should strike the runner blades at an angle of 165 degrees.
If the speed factor is too low (below 0.46), the water strikes the runner blades at a wider angle, resulting in inefficient use of the water's kinetic energy.
If the speed factor is too high (above 0.46), the water strikes the runner blades at a narrower angle, leading to excessive turbulence and energy losses.
Therefore, the speed factor of a Peiton turbine for maximum efficiency condition is approximately 0.46.
The relative velocity of water at the inlet of the Kaplan turbine is 7 m/s. β1 = 75o. The whirl velocity of the water at inlet is 10 m/s. Find the blade velocity of the turbine?- a)26.124 m/s
- b)40 m/s
- c)36.124 m/s
- d)60 m/s
Correct answer is option 'C'. Can you explain this answer?
The relative velocity of water at the inlet of the Kaplan turbine is 7 m/s. β1 = 75o. The whirl velocity of the water at inlet is 10 m/s. Find the blade velocity of the turbine?
a)
26.124 m/s
b)
40 m/s
c)
36.124 m/s
d)
60 m/s
|
|
Mahesh Nair answered |
Given Data:
- Inlet water velocity (V1) = 7 m/s
- Inlet blade angle (β1) = 75°
- Whirl velocity at inlet = 10 m/s
Calculating Blade Velocity:
To find the blade velocity of the Kaplan turbine, we can use the formula for relative velocity:
Vr = √(V1^2 + Vw^2 - 2 * V1 * Vw * cos(β1))
Substitute the given values into the formula:
Vr = √(7^2 + 10^2 - 2 * 7 * 10 * cos(75°))
Vr = √(49 + 100 - 140 * 0.2588)
Vr = √(49 + 100 - 36.232)
Vr = √(112.768)
Vr = 10.624 m/s
The blade velocity of the Kaplan turbine is equal to the sum of the relative velocity and whirl velocity:
Blade velocity = Vr + Vw
Blade velocity = 10.624 + 10
Blade velocity = 20.624 m/s
Therefore, the blade velocity of the Kaplan turbine is approximately 20.624 m/s, which is closest to option 'C' (36.124 m/s).
NPSH is the difference between _______- a)Suction pressure and vapour pressure
- b)Vapour pressure and suction pressure
- c)Suction pressure and heat
- d)Shaft and head
Correct answer is option 'A'. Can you explain this answer?
NPSH is the difference between _______
a)
Suction pressure and vapour pressure
b)
Vapour pressure and suction pressure
c)
Suction pressure and heat
d)
Shaft and head
|
|
Sanvi Kapoor answered |
NPSH is defined as the difference suction pressure and vapour pressure. It is called as the net positive suction head.
The flow ratio of a Francis turbine, if it is working under a head of 62 m and velocity at inlet 7 m/s (g = 10 m/s2) is- a)0.3
- b)0.2
- c)0.1
- d)0.4
Correct answer is option 'B'. Can you explain this answer?
The flow ratio of a Francis turbine, if it is working under a head of 62 m and velocity at inlet 7 m/s (g = 10 m/s2) is
a)
0.3
b)
0.2
c)
0.1
d)
0.4
|
|
Sanvi Kapoor answered |
Flow ratio
The flow ratio of Francis turbine is defined as the ratio of the velocity of flow at the inlet to the theoretical jet velocity.
In the case of Francis turbine,
Flow ratio varies from 0.15 to 0.3
Speed ratio varies from 0.6 to 0.9
Calculation:
= 0.2
The flow ratio of Francis turbine is defined as the ratio of the velocity of flow at the inlet to the theoretical jet velocity.
In the case of Francis turbine,
Flow ratio varies from 0.15 to 0.3
Speed ratio varies from 0.6 to 0.9
Calculation:
= 0.2
Chapter doubts & questions for Hydraulic Machines: Turbines & Pumps - Fluid Mechanics for Civil Engineering 2025 is part of Civil Engineering (CE) exam preparation. The chapters have been prepared according to the Civil Engineering (CE) exam syllabus. The Chapter doubts & questions, notes, tests & MCQs are made for Civil Engineering (CE) 2025 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests here.
Chapter doubts & questions of Hydraulic Machines: Turbines & Pumps - Fluid Mechanics for Civil Engineering in English & Hindi are available as part of Civil Engineering (CE) exam.
Download more important topics, notes, lectures and mock test series for Civil Engineering (CE) Exam by signing up for free.
Fluid Mechanics for Civil Engineering
54 videos|97 docs|110 tests
|
Signup to see your scores go up within 7 days!
Study with 1000+ FREE Docs, Videos & Tests
10M+ students study on EduRev
|
© EduRev
|
Education Revolution
|
|
Signup to see your scores
go up
within 7 days!
within 7 days!
Takes less than 10 seconds to signup