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Sum of Raju and Ravi age is 1 less than Ramu. After one year Sum of Raju and Ravi age is equal to Ramu’s age. After another year Sum of Raju and Ravi is 1 more than Ramu’s age. If the sum of Raju, Ravi and Ramu’s age is 23. Then what is the age of Ramu?- a)11
- b)12
- c)13
- d)14
- e)Cannot be determined
Correct answer is option 'B'. Can you explain this answer?
Sum of Raju and Ravi age is 1 less than Ramu. After one year Sum of Raju and Ravi age is equal to Ramu’s age. After another year Sum of Raju and Ravi is 1 more than Ramu’s age. If the sum of Raju, Ravi and Ramu’s age is 23. Then what is the age of Ramu?
a)
11
b)
12
c)
13
d)
14
e)
Cannot be determined
|
Anaya Patel answered |
X+Y+Z = 23
X+Y+1 = Z
Z = 12
X+Y+1 = Z
Z = 12
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Six years ago Manisha age was equal to sum of present ages of her Son and Daughter. Four years hence , the ratio of ages of her Son and Daughter at that time will be 7:6. Manisha is 6 years younger than his Husband. Manisha’s present age is 2.5 times the present age of her Daughter. Then what is the age of Manisha’s Husband?- a)50
- b)54
- c)56
- d)60
- e)Cannot be determined
Correct answer is option 'C'. Can you explain this answer?
Six years ago Manisha age was equal to sum of present ages of her Son and Daughter. Four years hence , the ratio of ages of her Son and Daughter at that time will be 7:6. Manisha is 6 years younger than his Husband. Manisha’s present age is 2.5 times the present age of her Daughter. Then what is the age of Manisha’s Husband?
a)
50
b)
54
c)
56
d)
60
e)
Cannot be determined
|
Preeti Khanna answered |
M-6 = S+D
M =2.5D
s+4/D+4 = 7/6
D = 20
M = 50 H = 56
M =2.5D
s+4/D+4 = 7/6
D = 20
M = 50 H = 56
The ratio of Arun’s and Varun’s ages is 4:5. If the difference between the present age of Varun and the age of Arun 5 years hence is 3 years, then what is the total of present ages of Arun and Varun?- a)73 years
- b)72 years
- c)75 years
- d)69 years
- e)68 years
Correct answer is option 'B'. Can you explain this answer?
The ratio of Arun’s and Varun’s ages is 4:5. If the difference between the present age of Varun and the age of Arun 5 years hence is 3 years, then what is the total of present ages of Arun and Varun?
a)
73 years
b)
72 years
c)
75 years
d)
69 years
e)
68 years
|
|
Preeti Khanna answered |
Arun’s age = x
Varun’s age = y
x/y = 4/5
y – (x + 5) = 3
y – x = 8
y = 8 + x
x/8 + x = 4/5
x = 32 years
y = 40 years.
x + y = 72 years.
Varun’s age = y
x/y = 4/5
y – (x + 5) = 3
y – x = 8
y = 8 + x
x/8 + x = 4/5
x = 32 years
y = 40 years.
x + y = 72 years.
Eight years ago, Pavi’s age was equal to the sum of the present ages of her one son and one daughter. Five years hence, the respective ratio between the ages of her daughter and her son that time will be 7:6. If Pavi’s husband is 7 years elder to her and his present age is three times the present age of their son, what is the present age of the daughter?- a)15 years
- b)23 years
- c)19 years
- d)27 years
- e)13 years
Correct answer is option 'B'. Can you explain this answer?
Eight years ago, Pavi’s age was equal to the sum of the present ages of her one son and one daughter. Five years hence, the respective ratio between the ages of her daughter and her son that time will be 7:6. If Pavi’s husband is 7 years elder to her and his present age is three times the present age of their son, what is the present age of the daughter?
a)
15 years
b)
23 years
c)
19 years
d)
27 years
e)
13 years
|
Yash Patel answered |
P – 8 = S + D —(1)
6D + 30 = 7S + 35 —(2)
H = 7 + P
H = 3S
3S = 7 + P —(3)
Solving eqn (1),(2) and (3) D = 23
6D + 30 = 7S + 35 —(2)
H = 7 + P
H = 3S
3S = 7 + P —(3)
Solving eqn (1),(2) and (3) D = 23
In a college, the average age of students of a class is 15.8 years. The average age of boys in the class is 16.4 years and that of the girls is 15.4 years. The ratio of number of boys to the number of girls in the class is- a)3:5
- b)2:3
- c)2:1
- d)2:7
- e)3:2
Correct answer is option 'B'. Can you explain this answer?
In a college, the average age of students of a class is 15.8 years. The average age of boys in the class is 16.4 years and that of the girls is 15.4 years. The ratio of number of boys to the number of girls in the class is
a)
3:5
b)
2:3
c)
2:1
d)
2:7
e)
3:2
|
Mahima Gaurh answered |
Let no. of boys be x and no. of girls be y
so,
16.4x+15.4y=15.8(x+y)
0.6x=0.4y
x/y=2/3
2:3
so,
16.4x+15.4y=15.8(x+y)
0.6x=0.4y
x/y=2/3
2:3
8 years ago, Geeta was half as old as Saina. Saina is now 20 years older than Geeta. How old will Geeta be in 10 years? - a)45
- b)40
- c)35
- d)38
- e)None of the Above
Correct answer is option 'D'. Can you explain this answer?
8 years ago, Geeta was half as old as Saina. Saina is now 20 years older than Geeta. How old will Geeta be in 10 years?
a)
45
b)
40
c)
35
d)
38
e)
None of the Above
|
|
Preeti Khanna answered |
Saina is now 20 years older than Geeta → S=G+20 → Saina 8 years ago was G+20-8=G+12 years old.
(G-8)*2=G+12 → G=28. 28+10=38 years.
(G-8)*2=G+12 → G=28. 28+10=38 years.
The average age of a family of five members is 24. If the present age of the youngest member is 8 year, what was the average age of the family at the time of birth of youngest member?- a)16 years
- b)20 years
- c)18 years
- d)14 years
Correct answer is option 'B'. Can you explain this answer?
The average age of a family of five members is 24. If the present age of the youngest member is 8 year, what was the average age of the family at the time of birth of youngest member?
a)
16 years
b)
20 years
c)
18 years
d)
14 years
|
|
Anaya Patel answered |
Total age of five members = 120
Before 8 years, Total age of the family at the time of birth of youngest member = 120 – 40 (5*8) = 80
Average age of the family at the time of birth of youngest member = 80/4 = 20
Before 8 years, Total age of the family at the time of birth of youngest member = 120 – 40 (5*8) = 80
Average age of the family at the time of birth of youngest member = 80/4 = 20
Ajay got married 6 years ago. His present age is 5/4 times his age at the time of his marriage. Ajay’s brother was 5 years younger to him at the time of his marriage. What is the present age of Ajay’s brother?- a)22 years
- b)11 years
- c)25 years
- d)19 years
- e)15 years
Correct answer is option 'C'. Can you explain this answer?
Ajay got married 6 years ago. His present age is 5/4 times his age at the time of his marriage. Ajay’s brother was 5 years younger to him at the time of his marriage. What is the present age of Ajay’s brother?
a)
22 years
b)
11 years
c)
25 years
d)
19 years
e)
15 years
|
Rajeev Kumar answered |
Present age of Ajay = x ; Present age of Ajay’s sister = y
x = (x-6)(5/4)
x = 30
present age of Ajay’s brother = 30 – 5 = 25
x = (x-6)(5/4)
x = 30
present age of Ajay’s brother = 30 – 5 = 25
The respective ratio between the present age of Monika and Deepak is 5:x. Monika is 9 years younger than Prem. Prem’s age after 9 years will be 33 years. The difference between Deepak’s and Monika’s age is same as the present age of Prem. What is the value of x?- a)18
- b)10
- c)16
- d)11
- e)13
Correct answer is option 'E'. Can you explain this answer?
The respective ratio between the present age of Monika and Deepak is 5:x. Monika is 9 years younger than Prem. Prem’s age after 9 years will be 33 years. The difference between Deepak’s and Monika’s age is same as the present age of Prem. What is the value of x?
a)
18
b)
10
c)
16
d)
11
e)
13
|
|
Aisha Gupta answered |
Prem’s age after 9 years = 33 years
Prem’s present age = 33 – 9 = 24 years
Monika’s present age = 24 – 9 = 15 years
Deepak’s present age = 15 + 24 = 39 years
Ratio between Monika and Deepak = 15 : 39 = 5 : 13
X = 13
Prem’s present age = 33 – 9 = 24 years
Monika’s present age = 24 – 9 = 15 years
Deepak’s present age = 15 + 24 = 39 years
Ratio between Monika and Deepak = 15 : 39 = 5 : 13
X = 13
Ajay’s present age is 1.5 times of Himanshu’s present age. If after 4 years, Ajay’s age will be twice of Himanshu’s age 4 years ago. What is the difference between the present ages of Ajay and Himanshu?- a)12 years
- b)23 years
- c)19 years
- d)27 years
- e)13 years
Correct answer is option 'A'. Can you explain this answer?
Ajay’s present age is 1.5 times of Himanshu’s present age. If after 4 years, Ajay’s age will be twice of Himanshu’s age 4 years ago. What is the difference between the present ages of Ajay and Himanshu?
a)
12 years
b)
23 years
c)
19 years
d)
27 years
e)
13 years
|
|
Kishan Singh answered |
If 6 is subtracted from the present age of neha and the remainder is divided by 6, then the present age of mia is obtained. If Mia is 4 years younger to raj whose age is 12 years, then find the age of neha- a)50
- b)52
- c)54
- d)58
- e)None of these
Correct answer is option 'C'. Can you explain this answer?
If 6 is subtracted from the present age of neha and the remainder is divided by 6, then the present age of mia is obtained. If Mia is 4 years younger to raj whose age is 12 years, then find the age of neha
a)
50
b)
52
c)
54
d)
58
e)
None of these
|
Kavya Saxena answered |
(N – 6)/6 = M = 12 – 4 = 8. We will get N = 54
Ravi is now 4 years older than Emma and half of that amount older than Ishu. If in 2 years, Ravi will be twice as old as Emma, then in 2 years what would be Ravi’s age multiplied by Ishu’s age?- a)68
- b)28
- c)48
- d)50
- e)52
Correct answer is option 'C'. Can you explain this answer?
Ravi is now 4 years older than Emma and half of that amount older than Ishu. If in 2 years, Ravi will be twice as old as Emma, then in 2 years what would be Ravi’s age multiplied by Ishu’s age?
a)
68
b)
28
c)
48
d)
50
e)
52
|
|
Anaya Patel answered |
Ravi – x + 4
Emma – x
Ishu – x + 2
(Ravi 4 years older than Emma & 2 years older than Ishu)
Ages after 2 yrs
Ravi – x + 6
Emma – x + 2
Ishu – x + 4
x+6 = 2(x + 2)
x = 2
Ravi * Ishu = 8 * 6 = 48
Emma – x
Ishu – x + 2
(Ravi 4 years older than Emma & 2 years older than Ishu)
Ages after 2 yrs
Ravi – x + 6
Emma – x + 2
Ishu – x + 4
x+6 = 2(x + 2)
x = 2
Ravi * Ishu = 8 * 6 = 48
Five years ago, the age of Abinav was 4 times the age of Sarita after 10 years, Abinav will be twice as old as Sarita. Find the Present ages of Abinav and sarita?- a)30 years, 10.5 years
- b)32 years, 11.5 years
- c)34 years, 14.5 years
- d)35 years, 12.5 years
Correct answer is option 'D'. Can you explain this answer?
Five years ago, the age of Abinav was 4 times the age of Sarita after 10 years, Abinav will be twice as old as Sarita. Find the Present ages of Abinav and sarita?
a)
30 years, 10.5 years
b)
32 years, 11.5 years
c)
34 years, 14.5 years
d)
35 years, 12.5 years
|
|
Kavya Saxena answered |
Five years ago,
x – 5/y – 5 = 4/1
x – 4y = – 15 —-(i)
After 10 years,
x + 10/y + 10 = 2/1
x – 2y = 10 —–(ii)
From eqn (i) and (ii) ⇒ x = 35, y = 12.5
x – 5/y – 5 = 4/1
x – 4y = – 15 —-(i)
After 10 years,
x + 10/y + 10 = 2/1
x – 2y = 10 —–(ii)
From eqn (i) and (ii) ⇒ x = 35, y = 12.5
Sum of the twice the age of Surya and his Father age is 79. Sum of the twice the age of Father and Surya’s age is 104. The average of Surya, his Father and his Mother is 32. Then what is the age of his Mother?- a)32
- b)33
- c)34
- d)35
- e)36
Correct answer is option 'D'. Can you explain this answer?
Sum of the twice the age of Surya and his Father age is 79. Sum of the twice the age of Father and Surya’s age is 104. The average of Surya, his Father and his Mother is 32. Then what is the age of his Mother?
a)
32
b)
33
c)
34
d)
35
e)
36
|
|
Aarav Sharma answered |
2S+F = 79
2F+S = 104
S =18 F = 43
18+43+M/3 = 32
M =35
Jack is now twice as old as Femina, who is two years older than Suresh. Four years ago, Jack was four times as old as Suresh. How old is Jack now?- a)18
- b)12
- c)16
- d)20
- e)24
Correct answer is option 'D'. Can you explain this answer?
Jack is now twice as old as Femina, who is two years older than Suresh. Four years ago, Jack was four times as old as Suresh. How old is Jack now?
a)
18
b)
12
c)
16
d)
20
e)
24
|
|
Kishan Singh answered |
Let the age of SURESH = X
age of FEMINA = X + 2
age of JACK = 2 ( X + 2 ) = 2X +4
four years ago,
JACK age =( 2X +4 )- 4 = 2X
SURESH age = X - 4
A/Q -
2X = 4 ( X - 4 )
=> X = 8
JACK present age = 2 (X +2)= 20 year . option( D)
age of FEMINA = X + 2
age of JACK = 2 ( X + 2 ) = 2X +4
four years ago,
JACK age =( 2X +4 )- 4 = 2X
SURESH age = X - 4
A/Q -
2X = 4 ( X - 4 )
=> X = 8
JACK present age = 2 (X +2)= 20 year . option( D)
Sum of the Ages of Aruna, Bhaskar, Chaitu and Dinesh is 78. Aruna is 5 years older than Bhaskar. Chaitu is 3 years older than Dinesh. Aruna age is 9 times the age of Dinesh. Then what is the age of Chaitu?- a)4
- b)5
- c)6
- d)7
- e)Cannot be determined
Correct answer is option 'E'. Can you explain this answer?
Sum of the Ages of Aruna, Bhaskar, Chaitu and Dinesh is 78. Aruna is 5 years older than Bhaskar. Chaitu is 3 years older than Dinesh. Aruna age is 9 times the age of Dinesh. Then what is the age of Chaitu?
a)
4
b)
5
c)
6
d)
7
e)
Cannot be determined
|
|
Aarav Sharma answered |
A+B+C+D = 78
B = A-5, C= D+3 , A=9
A = 36
V = 7
Sridhar has three sons Satish, Ritesh and Nitesh. Satish is oldest while Nitesh is the Youngest. The present ages of all the three son’s are square numbers. Sum of their ages after 3 years will be 39. Then what is the present age of Ritesh?- a)1
- b)4
- c)9
- d)16
- e)25
Correct answer is option 'B'. Can you explain this answer?
Sridhar has three sons Satish, Ritesh and Nitesh. Satish is oldest while Nitesh is the Youngest. The present ages of all the three son’s are square numbers. Sum of their ages after 3 years will be 39. Then what is the present age of Ritesh?
a)
1
b)
4
c)
9
d)
16
e)
25
|
Lavanya Menon answered |
Ans.
Method to Solve ;
Let ages of three sons = x,y,z
X+Y+Z = 30
Possible ages ( 1,4,9,16,25)
from above ages = (1,4,25)
Possible ages ( 1,4,9,16,25)
from above ages = (1,4,25)
James’ father was 30 years old when he was born. His mother’s age was 24 when his sister who is 5 years younger to him, was born. What is the difference between the age of James’ father and mother?- a)8
- b)10
- c)6
- d)11
- e)9
Correct answer is option 'D'. Can you explain this answer?
James’ father was 30 years old when he was born. His mother’s age was 24 when his sister who is 5 years younger to him, was born. What is the difference between the age of James’ father and mother?
a)
8
b)
10
c)
6
d)
11
e)
9
|
Nikita Singh answered |
James’age = F – 30
sister’s age = F – 35
M = 24 + Sister’s age
M = 24 + F – 35
F – M = 11
sister’s age = F – 35
M = 24 + Sister’s age
M = 24 + F – 35
F – M = 11
15 years ago the average age of a family of four members was 40 years. Two children were born in this span of 15 years. The present average of the family remains unchanged. Among the two children who were born during the 15 years, if the older child at present is 8 years older than the younger one, what is the ratio of the present age of the older child to the present age of the younger Child?- a)9:4
- b)7:3
- c)7:6
- d)7:4
- e)9:5
Correct answer is option 'B'. Can you explain this answer?
15 years ago the average age of a family of four members was 40 years. Two children were born in this span of 15 years. The present average of the family remains unchanged. Among the two children who were born during the 15 years, if the older child at present is 8 years older than the younger one, what is the ratio of the present age of the older child to the present age of the younger Child?
a)
9:4
b)
7:3
c)
7:6
d)
7:4
e)
9:5
|
|
Anaya Patel answered |
15 years ago Total age of a family of four members = 160
Sum of the Present age of a family of four members = 160 + (15*4) = 220
Sum of the Present age of a family of six members = 40*6 = 240
x+x+8 = 20
x=6
present age of the older child to the present age of the younger Child = 14:6 = 7:3
Sum of the Present age of a family of four members = 160 + (15*4) = 220
Sum of the Present age of a family of six members = 40*6 = 240
x+x+8 = 20
x=6
present age of the older child to the present age of the younger Child = 14:6 = 7:3
Three years from now, Deepa will be three times as old as Emma and Emma will be six years younger than Femina. If Deepa’s age is three years less than twice Femina’s age, how old is Femina?- a)9
- b)15
- c)21
- d)27
- e)33
Correct answer is option 'A'. Can you explain this answer?
Three years from now, Deepa will be three times as old as Emma and Emma will be six years younger than Femina. If Deepa’s age is three years less than twice Femina’s age, how old is Femina?
a)
9
b)
15
c)
21
d)
27
e)
33
|
|
Ravi Singh answered |
D+3=3(E+3)
E+3=(F+3)-6
D=2F-3.
E+3=F-3 or E=F-6.
D+3=3(F-6+3)
D+3=3F-9
D=3F-12.
now, we have D=2F-3.
2F-3=3F-12
9=F
E+3=(F+3)-6
D=2F-3.
E+3=F-3 or E=F-6.
D+3=3(F-6+3)
D+3=3F-9
D=3F-12.
now, we have D=2F-3.
2F-3=3F-12
9=F
The ratio of Present age of Madhu and Divya is 6:7. Madhu is 7 years younger than Laxmi. Laxmi’s age after 8 years will be 51 years. Then what is the difference between the present ages of Madhu and Divya?- a)3 Years
- b)4 Years
- c)5 Years
- d)6 Years
- e)Cannot be determined
Correct answer is option 'D'. Can you explain this answer?
The ratio of Present age of Madhu and Divya is 6:7. Madhu is 7 years younger than Laxmi. Laxmi’s age after 8 years will be 51 years. Then what is the difference between the present ages of Madhu and Divya?
a)
3 Years
b)
4 Years
c)
5 Years
d)
6 Years
e)
Cannot be determined
|
|
Kavya Saxena answered |
M/D = 6/7
L- M =7
L+8 = 51 L = 43
M = 36
D = 42
D-M = 42-36 = 6
L- M =7
L+8 = 51 L = 43
M = 36
D = 42
D-M = 42-36 = 6
Ritu married 6 years ago. Today her age is 5/4 times her age at the time of her marriage. Her daughter age is 1/5 of her age. What is the ratio of ritu age to her daughter age after 6 years?- a)2:1
- b)3:1
- c)4:3
- d)5:2
- e)None of these
Correct answer is option 'B'. Can you explain this answer?
Ritu married 6 years ago. Today her age is 5/4 times her age at the time of her marriage. Her daughter age is 1/5 of her age. What is the ratio of ritu age to her daughter age after 6 years?
a)
2:1
b)
3:1
c)
4:3
d)
5:2
e)
None of these
|
|
Ravi Singh answered |
R = (5/4)*(R – 6)
R = 30 years and daughter age = 30/5 = 6 years.
After 6 years ratio will be = 36/12 = 3:1
R = 30 years and daughter age = 30/5 = 6 years.
After 6 years ratio will be = 36/12 = 3:1
One year back, Ria was six times as old as her daughter. Six years hence, Ria’s age will exceed her daughter’s age by 15 years. The ratio of the present ages of Ria and her daughter is?- a)15 : 4
- b)19 : 4
- c)15 : 2
- d)17 : 2
- e)None of the Above
Correct answer is option 'B'. Can you explain this answer?
One year back, Ria was six times as old as her daughter. Six years hence, Ria’s age will exceed her daughter’s age by 15 years. The ratio of the present ages of Ria and her daughter is?
a)
15 : 4
b)
19 : 4
c)
15 : 2
d)
17 : 2
e)
None of the Above
|
|
Pillu Singh answered |
James is now 12 years younger than Mahesh. If 9 years from now Mahesh will be twice as old as James, how old will James be in 4 years?- a)3
- b)7
- c)5
- d)9
- e)8
Correct answer is option 'B'. Can you explain this answer?
James is now 12 years younger than Mahesh. If 9 years from now Mahesh will be twice as old as James, how old will James be in 4 years?
a)
3
b)
7
c)
5
d)
9
e)
8
|
|
Aisha Gupta answered |
James = x years, Mahesh = x+12 years
9 from now,
2(x+9)=x+21
2x+18=x+21
x=3
x+4 =7 years
9 from now,
2(x+9)=x+21
2x+18=x+21
x=3
x+4 =7 years
James’ present age is 2/7th of his father’s present age. James’ brother is three year older to James. The respective ratio between present ages of James’ father and James’ brother is 14:5. What is the present age of James?- a)12 years
- b)23 years
- c)19 years
- d)27 years
- e)13 years
Correct answer is option 'A'. Can you explain this answer?
James’ present age is 2/7th of his father’s present age. James’ brother is three year older to James. The respective ratio between present ages of James’ father and James’ brother is 14:5. What is the present age of James?
a)
12 years
b)
23 years
c)
19 years
d)
27 years
e)
13 years
|
|
Anaya Patel answered |
James’ father present age = x
James’ age = 2/7 x
James’ brother age = 2/7 x + 3
x/(2/7x + 3) = 14/5
x = 42
James’ age = 2/7 x = 2/7 * 42 = 12
James’ age = 2/7 x
James’ brother age = 2/7 x + 3
x/(2/7x + 3) = 14/5
x = 42
James’ age = 2/7 x = 2/7 * 42 = 12
Amit’s present age is 1.5 times of Hari’s present age. If after 4 years, Amit’s age will be twice of Hari’s age 4 years ago. What is the sum of the present ages of Amit and Hari?- a)52 years
- b)53 years
- c)60 years
- d)67 years
- e)63 years
Correct answer is option 'C'. Can you explain this answer?
Amit’s present age is 1.5 times of Hari’s present age. If after 4 years, Amit’s age will be twice of Hari’s age 4 years ago. What is the sum of the present ages of Amit and Hari?
a)
52 years
b)
53 years
c)
60 years
d)
67 years
e)
63 years
|
|
Aarav Sharma answered |
I am sorry, but I need more information to understand your request. Can you please provide me with more details?
The ratio between the A and B age is 7: 9. If the difference between the present ages of Q and P’s age after 4 years is 2 then what is the total of the present ages of P and Q?- a)42
- b)44
- c)46
- d)48
- e)None of these
Correct answer is option 'D'. Can you explain this answer?
The ratio between the A and B age is 7: 9. If the difference between the present ages of Q and P’s age after 4 years is 2 then what is the total of the present ages of P and Q?
a)
42
b)
44
c)
46
d)
48
e)
None of these
|
|
Aarav Sharma answered |
Is 10 years and P is 5 years younger than A, what is the present age of B?
Let's start by using the information given in the problem to set up some equations:
- The ratio between A and B age is 7:9, so we can write: A/B = 7/9
- P is 5 years younger than A, so we can write: P = A - 5
- The difference between the present ages of Q and P is 10 years, so we can write: Q - P = 10
Now we can use these equations to solve for the present age of B:
1. Start by substituting the second equation into the first equation to get: A/B = 7/9 becomes (A-5)/B = 7/9
2. Cross-multiply to get: 9(A-5) = 7B
3. Simplify to get: 9A - 45 = 7B
4. Rearrange to get: B = (9A - 45)/7
5. Substitute this expression for B into the third equation to get: Q - P = 10 becomes Q - (A-5) = 10
6. Simplify to get: Q - A + 5 = 10
7. Rearrange to get: Q = A + 5
8. Substitute this expression for Q into the previous equation to get: (9A - 45)/7 = A + 5
9. Simplify to get: 9A - 45 = 7A + 35
10. Solve for A to get: A = 20
11. Substitute this value of A into the expression for B to get: B = (9A - 45)/7 = (9(20) - 45)/7 = 15
Therefore, the present age of B is 15.
Let's start by using the information given in the problem to set up some equations:
- The ratio between A and B age is 7:9, so we can write: A/B = 7/9
- P is 5 years younger than A, so we can write: P = A - 5
- The difference between the present ages of Q and P is 10 years, so we can write: Q - P = 10
Now we can use these equations to solve for the present age of B:
1. Start by substituting the second equation into the first equation to get: A/B = 7/9 becomes (A-5)/B = 7/9
2. Cross-multiply to get: 9(A-5) = 7B
3. Simplify to get: 9A - 45 = 7B
4. Rearrange to get: B = (9A - 45)/7
5. Substitute this expression for B into the third equation to get: Q - P = 10 becomes Q - (A-5) = 10
6. Simplify to get: Q - A + 5 = 10
7. Rearrange to get: Q = A + 5
8. Substitute this expression for Q into the previous equation to get: (9A - 45)/7 = A + 5
9. Simplify to get: 9A - 45 = 7A + 35
10. Solve for A to get: A = 20
11. Substitute this value of A into the expression for B to get: B = (9A - 45)/7 = (9(20) - 45)/7 = 15
Therefore, the present age of B is 15.
The ratio of the ages of two persons are in the ratio of 5:7 and the difference between their ages is 18 years. Find the sum of the ages of the person after 5 years,- a)112 years
- b)115 years
- c)117 years
- d)119 years
- e)None of these
Correct answer is option 'E'. Can you explain this answer?
The ratio of the ages of two persons are in the ratio of 5:7 and the difference between their ages is 18 years. Find the sum of the ages of the person after 5 years,
a)
112 years
b)
115 years
c)
117 years
d)
119 years
e)
None of these
|
|
Athar Mir answered |
7x-5× =18
2x=9
(7+5)×9 = 108
after 5 yrs
108+10 = 118yrs
2x=9
(7+5)×9 = 108
after 5 yrs
108+10 = 118yrs
Ravi has three children: two daughters and one son. All were born on the same date in different years. The sum of the ages of the two daughters today is smaller than the age of the son today, but a year from now the sum of the ages of the daughters will equal the age of the son. Three years from today, the difference between the age of the son and the combined ages of the daughters will be- a)1
- b)2
- c)3
- d)–2
- e)–1
Correct answer is option 'D'. Can you explain this answer?
Ravi has three children: two daughters and one son. All were born on the same date in different years. The sum of the ages of the two daughters today is smaller than the age of the son today, but a year from now the sum of the ages of the daughters will equal the age of the son. Three years from today, the difference between the age of the son and the combined ages of the daughters will be
a)
1
b)
2
c)
3
d)
–2
e)
–1
|
Faizan Khan answered |
one year from now, D+d=s
two years after that, D+2+d+2=s+2
D+d-s=2-4=-2
two years after that, D+2+d+2=s+2
D+d-s=2-4=-2
Out of the three annual examinations, each with a total of 500 marks, a student secured average marks of 45% and 55% in the first and second annual examinations. To have an overall average of 60%, how many marks does the student need to secure in the third annual examination ?- a)450
- b)400
- c)350
- d)300
- e)None of the Above
Correct answer is option 'B'. Can you explain this answer?
Out of the three annual examinations, each with a total of 500 marks, a student secured average marks of 45% and 55% in the first and second annual examinations. To have an overall average of 60%, how many marks does the student need to secure in the third annual examination ?
a)
450
b)
400
c)
350
d)
300
e)
None of the Above
|
|
Rhea Reddy answered |
Total marks for three examinations = 3x 500 = 1500
Total required marks in three examinations = 60% of 1500
= (3 x 500 x 60) / 100
= 900
Marks secured in first examination = 45 % of 500
= (500 x 45) / 100
= 225
Marks secured in third examination = 55 % of 500
= (500 x 55) / 100
= 275
Thus, the required marks in third examination
= 900 – (225 + 275)
= 900 – 500
= 400
Total required marks in three examinations = 60% of 1500
= (3 x 500 x 60) / 100
= 900
Marks secured in first examination = 45 % of 500
= (500 x 45) / 100
= 225
Marks secured in third examination = 55 % of 500
= (500 x 55) / 100
= 275
Thus, the required marks in third examination
= 900 – (225 + 275)
= 900 – 500
= 400
The ratio of the present age of Palash to that of Arnav is 3 : 11. Arnav is 12 years younger than Rahim. Rahim’s age after 7 years will be 85 years. What is the present age of Palash’s father, who is 25 years older than Palash?- a)43 years
- b)67 years
- c)45 years
- d)69 years
Correct answer is option 'A'. Can you explain this answer?
The ratio of the present age of Palash to that of Arnav is 3 : 11. Arnav is 12 years younger than Rahim. Rahim’s age after 7 years will be 85 years. What is the present age of Palash’s father, who is 25 years older than Palash?
a)
43 years
b)
67 years
c)
45 years
d)
69 years
|
Saurabh Bhatt answered |
Palash/ Arnav= 3/11
Rahim present age = 85 - 7 = 78 yrs
Thats why Arnav present age =78-12= 66yrs
Now, Palash age = 3/11 × 66
=18 yrs
Palash father's age = 18 + 25 = 43 yrs
Rahim present age = 85 - 7 = 78 yrs
Thats why Arnav present age =78-12= 66yrs
Now, Palash age = 3/11 × 66
=18 yrs
Palash father's age = 18 + 25 = 43 yrs
The sum of ages of Sonu and Monu is 60 at present. Also Sonu’s age was five time that of Monu 6 years ago. What will be the age of Monu 5 years after? - a)14
- b)20
- c)18
- d)19
- e)22
Correct answer is option 'D'. Can you explain this answer?
The sum of ages of Sonu and Monu is 60 at present. Also Sonu’s age was five time that of Monu 6 years ago. What will be the age of Monu 5 years after?
a)
14
b)
20
c)
18
d)
19
e)
22
|
|
Aarav Sharma answered |
Is twice as old as Monu was when Sonu was as old as Monu is now. Find their present ages.
Let the present age of Monu be x.
Then the present age of Sonu will be 60 - x.
Let the time when Sonu was as old as Monu is now be t years ago.
Then the age of Sonu at that time was 60 - x - t.
And the age of Monu at that time was x - t.
Since Sonu was twice as old as Monu was at that time, we have:
60 - x - t = 2(x - t)
Simplifying this equation, we get:
60 - x - t = 2x - 2t
3x = 60 + t
x = (60 + t)/3
Since x is an integer, t must be a multiple of 3.
Also, we know that x + (60 - x) = 60, so x must be less than or equal to 30.
Trying different values of t, we find that t = 6 satisfies both conditions.
Thus, x = (60 + 6)/3 = 22, and Sonu's age is 60 - x = 38.
Therefore, the present ages of Sonu and Monu are 38 and 22, respectively.
Let the present age of Monu be x.
Then the present age of Sonu will be 60 - x.
Let the time when Sonu was as old as Monu is now be t years ago.
Then the age of Sonu at that time was 60 - x - t.
And the age of Monu at that time was x - t.
Since Sonu was twice as old as Monu was at that time, we have:
60 - x - t = 2(x - t)
Simplifying this equation, we get:
60 - x - t = 2x - 2t
3x = 60 + t
x = (60 + t)/3
Since x is an integer, t must be a multiple of 3.
Also, we know that x + (60 - x) = 60, so x must be less than or equal to 30.
Trying different values of t, we find that t = 6 satisfies both conditions.
Thus, x = (60 + 6)/3 = 22, and Sonu's age is 60 - x = 38.
Therefore, the present ages of Sonu and Monu are 38 and 22, respectively.
The ratio of the ages of priya and riya is 2:5. After 8 years, their ages will be in the ratio of 2:3. Then the sum of their present ages- a)12 years
- b)14 years
- c)16 years
- d)18 years
- e)None of these
Correct answer is option 'B'. Can you explain this answer?
The ratio of the ages of priya and riya is 2:5. After 8 years, their ages will be in the ratio of 2:3. Then the sum of their present ages
a)
12 years
b)
14 years
c)
16 years
d)
18 years
e)
None of these
|
|
Nikita Singh answered |
Let priya age = 2x and riya age = 5x.
So, (2x + 8)/(5x + 8) = 2/3, we get x = 2. So sum of priya and riya = 14
So, (2x + 8)/(5x + 8) = 2/3, we get x = 2. So sum of priya and riya = 14
Mr. Suresh has three daughters namely Ramya, Anita and Kiran. Ramya is the eldest daughter of Mr. Suresh while Kiran is the youngest one. The present ages of all three of them are square numbers. The sum of their ages after 5 years is 44. What is the age of Ramya after two years?- a)15 years
- b)13 years
- c)18 years
- d)17 years
- e)16 years
Correct answer is option 'C'. Can you explain this answer?
Mr. Suresh has three daughters namely Ramya, Anita and Kiran. Ramya is the eldest daughter of Mr. Suresh while Kiran is the youngest one. The present ages of all three of them are square numbers. The sum of their ages after 5 years is 44. What is the age of Ramya after two years?
a)
15 years
b)
13 years
c)
18 years
d)
17 years
e)
16 years
|
|
Anaya Patel answered |
Square numbers – a, b, c
(a + 5) + (b + 5)+ (c + 5) = 44
a + b + c = 44 – 15 = 29
Possible values of a, b, c = 4, 9, 16 [Out of 1, 4, 9, 16, 25] Ramya’s present age = 16; after two years = 18
(a + 5) + (b + 5)+ (c + 5) = 44
a + b + c = 44 – 15 = 29
Possible values of a, b, c = 4, 9, 16 [Out of 1, 4, 9, 16, 25] Ramya’s present age = 16; after two years = 18
One year before, Reshma was six times as old as her daughter. Six years hence, Reshma’s age will exceed her daughter’s age by 20 years. The ratio of the present ages of Reshma and her daughter is?- a)5 : 4
- b)9 : 4
- c)5 : 1
- d)7 : 2
- e)None of the Above
Correct answer is option 'C'. Can you explain this answer?
One year before, Reshma was six times as old as her daughter. Six years hence, Reshma’s age will exceed her daughter’s age by 20 years. The ratio of the present ages of Reshma and her daughter is?
a)
5 : 4
b)
9 : 4
c)
5 : 1
d)
7 : 2
e)
None of the Above
|
|
Rhea Reddy answered |
Ages of Reshma and her daughter = 6x, x
[6x + 1 + 6] – [x + 1 + 6] = 20
5x = 20; x = 4
Ratio = 6x + 1 : x + 1 = 25 : 5 = 5:1
[6x + 1 + 6] – [x + 1 + 6] = 20
5x = 20; x = 4
Ratio = 6x + 1 : x + 1 = 25 : 5 = 5:1
The present age of Ravi’s father is four times Ravi’s present age. Five years back, Ravi’s father seven times as old as Ravi was at that time. What is the present age of Ravi’s father?- a)43 years
- b)67 years
- c)40 years
- d)69 years
Correct answer is option 'C'. Can you explain this answer?
The present age of Ravi’s father is four times Ravi’s present age. Five years back, Ravi’s father seven times as old as Ravi was at that time. What is the present age of Ravi’s father?
a)
43 years
b)
67 years
c)
40 years
d)
69 years
|
|
Nikita Singh answered |
Present age of Ravi – x
Present age of Ravi’s father = 4x
Five years ago,
Ravi’s father age = 7 * Ravi’s age
4x – 5 = 7(x – 5)
x = 10
Present age of Ravi’s father = 4x = 40 years.
Present age of Ravi’s father = 4x
Five years ago,
Ravi’s father age = 7 * Ravi’s age
4x – 5 = 7(x – 5)
x = 10
Present age of Ravi’s father = 4x = 40 years.
Three years ago, Poorvi was thrice as old as his sister Reena. After three years Poorvi will be twice as old as Reena. What is the present age of Reena?- a)10 years
- b)6 years
- c)9 years
- d)15 years
- e)12 years
Correct answer is option 'C'. Can you explain this answer?
Three years ago, Poorvi was thrice as old as his sister Reena. After three years Poorvi will be twice as old as Reena. What is the present age of Reena?
a)
10 years
b)
6 years
c)
9 years
d)
15 years
e)
12 years
|
|
Anaya Patel answered |
P – 3 = 3 *(R – 3) —(1)
P + 3 = 2 *(R + 3) —(2)
Solving eqn (1) and (2) R = 9
P + 3 = 2 *(R + 3) —(2)
Solving eqn (1) and (2) R = 9
Present age of Husband and Wife is 28 and 24 Years respectively. At that age twin babies were born to them. After how many years the average of the family will be same as before babies were born?- a)10 Years
- b)11 Years
- c)12 Years
- d)13 Years
- e)Cannot be determined
Correct answer is option 'D'. Can you explain this answer?
Present age of Husband and Wife is 28 and 24 Years respectively. At that age twin babies were born to them. After how many years the average of the family will be same as before babies were born?
a)
10 Years
b)
11 Years
c)
12 Years
d)
13 Years
e)
Cannot be determined
|
|
Nikita Singh answered |
28+24/2 =26 = (28+x+24+x+2x)/4
104 = (52+4x)
x= 13
104 = (52+4x)
x= 13
Arun will be half as old as Lilly in 3 years. Arun will also be one-third as old as James in 5 years. If James is 15 years older than Lilly, how old is Arun?- a)6
- b)8
- c)9
- d)5
- e)4
Correct answer is option 'B'. Can you explain this answer?
Arun will be half as old as Lilly in 3 years. Arun will also be one-third as old as James in 5 years. If James is 15 years older than Lilly, how old is Arun?
a)
6
b)
8
c)
9
d)
5
e)
4
|
|
Aisha Gupta answered |
let age of Arun =x, Lilly =y James = z
(x+3) =1/2 *(y+3) so we have 2x-y =-3 -(1)
(x+5) =1/3 * (z+5) ; ⇒ 3x-z=-10 -(2)
From (1)&(2) we get, x+y-z =-7 -(3)
we have z =15+y – (4)
from equation 3 and 4 we get x=8
(x+3) =1/2 *(y+3) so we have 2x-y =-3 -(1)
(x+5) =1/3 * (z+5) ; ⇒ 3x-z=-10 -(2)
From (1)&(2) we get, x+y-z =-7 -(3)
we have z =15+y – (4)
from equation 3 and 4 we get x=8
The ratio of present ages of Ramya and Karan’s age is 4:5 and the ratio of present ages of Karan and Priya is 2:5 respectively. If Ramya is two-fifth of Priya’s age, What is Ramya’s age?- a)12 years
- b)10 years
- c)20 years
- d)Cannot be determined
- e)None of the Above
Correct answer is option 'D'. Can you explain this answer?
The ratio of present ages of Ramya and Karan’s age is 4:5 and the ratio of present ages of Karan and Priya is 2:5 respectively. If Ramya is two-fifth of Priya’s age, What is Ramya’s age?
a)
12 years
b)
10 years
c)
20 years
d)
Cannot be determined
e)
None of the Above
|
Akash Pandey answered |
Data Insufficient – Can not be determined.
The present age of Kiran five times the age of Suji. After 10 years Kiran will be three times as old as Suji. Find out the present ages of Kiran and Suji?- a)25 years, 5 years
- b)30 years, 6 years
- c)35 years, 7 years
- d)50 years, 10 years
Correct answer is option 'D'. Can you explain this answer?
The present age of Kiran five times the age of Suji. After 10 years Kiran will be three times as old as Suji. Find out the present ages of Kiran and Suji?
a)
25 years, 5 years
b)
30 years, 6 years
c)
35 years, 7 years
d)
50 years, 10 years
|
|
Ravi Singh answered |
5x + 10/ x + 10 = 3/1
x = 10
Kiran – 50 years, Suji – 10 years.
x = 10
Kiran – 50 years, Suji – 10 years.
Eight years ago, Poorvi’s age was equal to the sum of the present ages of her one son and one daughter. Five years hence, the respective ratio between the ages of her daughter and her son that time will be 7:6. If Poorvi’s husband is 7 years elder to her and his present age is three times the present age of their son, what is the present age of the daughter?- a)15 years
- b)23 years
- c)19 years
- d)27 years
- e)13 years
Correct answer is option 'B'. Can you explain this answer?
Eight years ago, Poorvi’s age was equal to the sum of the present ages of her one son and one daughter. Five years hence, the respective ratio between the ages of her daughter and her son that time will be 7:6. If Poorvi’s husband is 7 years elder to her and his present age is three times the present age of their son, what is the present age of the daughter?
a)
15 years
b)
23 years
c)
19 years
d)
27 years
e)
13 years
|
Dhruv Mehra answered |
Ans: 23 years
Let present age of her son =x
Present age of Poorvi's husband =3x
Present age of Poorvi =3x−7
Eight years ago, Poorvi’s age =3x−15
present age of her daughter =(3x−15)−x=(2x−15)
after 5 years,
age of her daughter =(2x−10)age of her son =(x+5)(2x−10):(x+5)=7:6⇒12x−6=7x+35⇒5x=95⇒x=19
Present age of her daughter =(2x−15)=23
Sum of Sita and Gita age is 1 less than Rita. After one year Sum of Sita and Gita age is equal to Rita’s age. After another year Sum of Sita and Gita is 1 more than Rita’s age. If the sum of Sita, Gita and Rita’s age is 19. Then what is the age of Sita?- a)4
- b)5
- c)6
- d)7
- e)Cannot be determined
Correct answer is option 'E'. Can you explain this answer?
Sum of Sita and Gita age is 1 less than Rita. After one year Sum of Sita and Gita age is equal to Rita’s age. After another year Sum of Sita and Gita is 1 more than Rita’s age. If the sum of Sita, Gita and Rita’s age is 19. Then what is the age of Sita?
a)
4
b)
5
c)
6
d)
7
e)
Cannot be determined
|
|
Preeti Khanna answered |
X+Y+Z = 19
X+Y+1 = Z
Z =10
X+Y+2 = Z+1
X+Y+4 = Z+2+1. Based on above solution cannot be determined
X+Y+1 = Z
Z =10
X+Y+2 = Z+1
X+Y+4 = Z+2+1. Based on above solution cannot be determined
Ravi’s age was one third of his father’s 18 years ago. Now he is half the age of his father. What is the difference in the present ages of father and Ravi? - a)72
- b)36
- c)25
- d)20
- e)30
Correct answer is option 'B'. Can you explain this answer?
Ravi’s age was one third of his father’s 18 years ago. Now he is half the age of his father. What is the difference in the present ages of father and Ravi?
a)
72
b)
36
c)
25
d)
20
e)
30
|
|
Anaya Patel answered |
Ravi’s present = x, father’s = 2x
Then, (2x-18) = 3 (x – 18)
Solve, x = 36
So difference = 2x-x = x = 36
Then, (2x-18) = 3 (x – 18)
Solve, x = 36
So difference = 2x-x = x = 36
B is eight years older than A and 8 years younger than C. 12 years hence, respective ratio of the ages of A and C will be 5:9. what is the sum of present ages of A, B and C?- a)58 years
- b)46 years
- c)48 years
- d)60 years
- e)None of the Above
Correct answer is option 'C'. Can you explain this answer?
B is eight years older than A and 8 years younger than C. 12 years hence, respective ratio of the ages of A and C will be 5:9. what is the sum of present ages of A, B and C?
a)
58 years
b)
46 years
c)
48 years
d)
60 years
e)
None of the Above
|
|
Aarav Sharma answered |
B = A + 8
B = C – 8
C – 8 = A + 8
C – A = 16
4x = 16
x = 4
12 years hence, A = 5x, C = 9x B = A + C ⇒ A= 20, B = 28, C = 36
Sum of present ages of A, B and C = 20 + 28 + 36 – 36 = 48 years.
B = C – 8
C – 8 = A + 8
C – A = 16
4x = 16
x = 4
12 years hence, A = 5x, C = 9x B = A + C ⇒ A= 20, B = 28, C = 36
Sum of present ages of A, B and C = 20 + 28 + 36 – 36 = 48 years.
Silvia was married 8 year ago. Today her age is 9/7 times to that time of marriage. At present his son’s age is 1/6th of her age. What was her son’s age 3 year ago?- a)4 yr
- b)2 yr
- c)3 yr
- d)5 yr
- e)None of the Above
Correct answer is option 'C'. Can you explain this answer?
Silvia was married 8 year ago. Today her age is 9/7 times to that time of marriage. At present his son’s age is 1/6th of her age. What was her son’s age 3 year ago?
a)
4 yr
b)
2 yr
c)
3 yr
d)
5 yr
e)
None of the Above
|
|
Yash Patel answered |
Silvia’s age 8 year ago = x
Present age = x + 8
x + 8 = 9/7 x
7(x + 8)= 9x
x = 28; 28 + 8 = 36
Son’s age = 1/6 * 36 = 6
Son’s age 3 year ago = 6-3 =3
Present age = x + 8
x + 8 = 9/7 x
7(x + 8)= 9x
x = 28; 28 + 8 = 36
Son’s age = 1/6 * 36 = 6
Son’s age 3 year ago = 6-3 =3
Chapter doubts & questions for Problem on Ages - Numerical Ability for Banking Exams 2024 is part of Bank Exams exam preparation. The chapters have been prepared according to the Bank Exams exam syllabus. The Chapter doubts & questions, notes, tests & MCQs are made for Bank Exams 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests here.
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