8 years ago, Geeta was half as old as Saina. Saina is now 20 years older than Geeta. How old will Geeta be in 10 years?a)45b)40c)35d)38e)None of the AboveCorrect answer is option 'D'. Can you explain this answer?

Question

Answer

Saina is now 20 years older than Geeta → S=G+20 → Saina 8 years ago was G+20-8=G+12 years old.
(G-8)*2=G+12 → G=28. 28+10=38 years.

Answer

Saina is now 20 years older than Geeta → S=G+20 → Saina 8 years ago was G+20-8=G+12 years old.
(G-8)*2=G+12 → G=28. 28+10=38 years.

Answer

Saina is now 20 years older than Geeta → S=G+20 → Saina 8 years ago was G+20-8=G+12 years old.
(G-8)*2=G+12 → G=28. 28+10=38 years.

Answer

Saina is now 20 years older than Geeta → S=G+20 → Saina 8 years ago was G+20-8=G+12 years old.
(G-8)*2=G+12 → G=28. 28+10=38 years.

Answer

Problem:
8 years ago, Geeta was half as old as Saina. Saina is now 20 years older than Geeta. How old will Geeta be in 10 years?

Solution:
Let's break down the problem step by step.

Step 1:
Let's assume Geeta's current age as G and Saina's current age as S.

Step 2:
8 years ago, Geeta was half as old as Saina, so we can form an equation: G - 8 = (S - 8)/2.

Step 3:
Saina is now 20 years older than Geeta, so we can form another equation: S = G + 20.

Step 4:
Now we have two equations:
G - 8 = (S - 8)/2 ...(Equation 1)
S = G + 20 ...(Equation 2)

Step 5:
Let's substitute Equation 2 into Equation 1:
G - 8 = (G + 20 - 8)/2
G - 8 = (G + 12)/2
2G - 16 = G + 12
2G - G = 12 + 16
G = 28

Step 6:
Now we know that Geeta's current age is 28.

Step 7:
To find out how old Geeta will be in 10 years, we add 10 to her current age:
Geeta's age in 10 years = 28 + 10 = 38

Answer:
Geeta will be 38 years old in 10 years. Therefore, the correct answer is option D.

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