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All questions of Age for Bank Exams Exam
Sum of Raju and Ravi age is 1 less than Ramu. After one year Sum of Raju and Ravi age is equal to Ramu’s age. After another year Sum of Raju and Ravi is 1 more than Ramu’s age. If the sum of Raju, Ravi and Ramu’s age is 23. Then what is the age of Ramu?- a)11
- b)12
- c)13
- d)14
- e)Cannot be determined
Correct answer is option 'B'. Can you explain this answer?
Sum of Raju and Ravi age is 1 less than Ramu. After one year Sum of Raju and Ravi age is equal to Ramu’s age. After another year Sum of Raju and Ravi is 1 more than Ramu’s age. If the sum of Raju, Ravi and Ramu’s age is 23. Then what is the age of Ramu?
a)
11
b)
12
c)
13
d)
14
e)
Cannot be determined
|
Anaya Patel answered |
X+Y+Z = 23
X+Y+1 = Z
Z = 12
X+Y+1 = Z
Z = 12
Six years ago Manisha age was equal to sum of present ages of her Son and Daughter. Four years hence , the ratio of ages of her Son and Daughter at that time will be 7:6. Manisha is 6 years younger than his Husband. Manisha’s present age is 2.5 times the present age of her Daughter. Then what is the age of Manisha’s Husband?- a)50
- b)54
- c)56
- d)60
- e)Cannot be determined
Correct answer is option 'C'. Can you explain this answer?
Six years ago Manisha age was equal to sum of present ages of her Son and Daughter. Four years hence , the ratio of ages of her Son and Daughter at that time will be 7:6. Manisha is 6 years younger than his Husband. Manisha’s present age is 2.5 times the present age of her Daughter. Then what is the age of Manisha’s Husband?
a)
50
b)
54
c)
56
d)
60
e)
Cannot be determined
|
Preeti Khanna answered |
M-6 = S+D
M =2.5D
s+4/D+4 = 7/6
D = 20
M = 50 H = 56
M =2.5D
s+4/D+4 = 7/6
D = 20
M = 50 H = 56
The ratio of Arun’s and Varun’s ages is 4:5. If the difference between the present age of Varun and the age of Arun 5 years hence is 3 years, then what is the total of present ages of Arun and Varun?- a)73 years
- b)72 years
- c)75 years
- d)69 years
- e)68 years
Correct answer is option 'B'. Can you explain this answer?
The ratio of Arun’s and Varun’s ages is 4:5. If the difference between the present age of Varun and the age of Arun 5 years hence is 3 years, then what is the total of present ages of Arun and Varun?
a)
73 years
b)
72 years
c)
75 years
d)
69 years
e)
68 years
|
|
Preeti Khanna answered |
Arun’s age = x
Varun’s age = y
x/y = 4/5
y – (x + 5) = 3
y – x = 8
y = 8 + x
x/8 + x = 4/5
x = 32 years
y = 40 years.
x + y = 72 years.
Varun’s age = y
x/y = 4/5
y – (x + 5) = 3
y – x = 8
y = 8 + x
x/8 + x = 4/5
x = 32 years
y = 40 years.
x + y = 72 years.
Eight years ago, Pavi’s age was equal to the sum of the present ages of her one son and one daughter. Five years hence, the respective ratio between the ages of her daughter and her son that time will be 7:6. If Pavi’s husband is 7 years elder to her and his present age is three times the present age of their son, what is the present age of the daughter?- a)15 years
- b)23 years
- c)19 years
- d)27 years
- e)13 years
Correct answer is option 'B'. Can you explain this answer?
Eight years ago, Pavi’s age was equal to the sum of the present ages of her one son and one daughter. Five years hence, the respective ratio between the ages of her daughter and her son that time will be 7:6. If Pavi’s husband is 7 years elder to her and his present age is three times the present age of their son, what is the present age of the daughter?
a)
15 years
b)
23 years
c)
19 years
d)
27 years
e)
13 years
|
Naroj Boda answered |
P – 8 = S + D —(1)
6D + 30 = 7S + 35 —(2)
H = 7 + P
H = 3S
3S = 7 + P —(3)
Solving eqn (1),(2) and (3) D = 23
6D + 30 = 7S + 35 —(2)
H = 7 + P
H = 3S
3S = 7 + P —(3)
Solving eqn (1),(2) and (3) D = 23
8 years ago, Geeta was half as old as Saina. Saina is now 20 years older than Geeta. How old will Geeta be in 10 years? - a)45
- b)40
- c)35
- d)38
- e)None of the Above
Correct answer is option 'D'. Can you explain this answer?
8 years ago, Geeta was half as old as Saina. Saina is now 20 years older than Geeta. How old will Geeta be in 10 years?
a)
45
b)
40
c)
35
d)
38
e)
None of the Above
|
|
Preeti Khanna answered |
Saina is now 20 years older than Geeta → S=G+20 → Saina 8 years ago was G+20-8=G+12 years old.
(G-8)*2=G+12 → G=28. 28+10=38 years.
(G-8)*2=G+12 → G=28. 28+10=38 years.
In a college, the average age of students of a class is 15.8 years. The average age of boys in the class is 16.4 years and that of the girls is 15.4 years. The ratio of number of boys to the number of girls in the class is- a)3:5
- b)2:3
- c)2:1
- d)2:7
- e)3:2
Correct answer is option 'B'. Can you explain this answer?
In a college, the average age of students of a class is 15.8 years. The average age of boys in the class is 16.4 years and that of the girls is 15.4 years. The ratio of number of boys to the number of girls in the class is
a)
3:5
b)
2:3
c)
2:1
d)
2:7
e)
3:2
|
Bank Exams India answered |
Number of boys = x
Number of boys = y
(x*16.4 + y*15.4)/x + y = 15.8
16.4x + 15.4y = 15.8x + 15.8y
0.6x = 0.4y
x:y = 2:3
Number of boys = y
(x*16.4 + y*15.4)/x + y = 15.8
16.4x + 15.4y = 15.8x + 15.8y
0.6x = 0.4y
x:y = 2:3
Three years from now, Deepa will be three times as old as Emma and Emma will be six years younger than Femina. If Deepa’s age is three years less than twice Femina’s age, how old is Femina?- a)9
- b)15
- c)21
- d)27
- e)33
Correct answer is option 'A'. Can you explain this answer?
Three years from now, Deepa will be three times as old as Emma and Emma will be six years younger than Femina. If Deepa’s age is three years less than twice Femina’s age, how old is Femina?
a)
9
b)
15
c)
21
d)
27
e)
33
|
Ravi Singh answered |
D+3=3(E+3)
E+3=(F+3)-6
D=2F-3.
E+3=F-3 or E=F-6.
D+3=3(F-6+3)
D+3=3F-9
D=3F-12.
now, we have D=2F-3.
2F-3=3F-12
9=F
E+3=(F+3)-6
D=2F-3.
E+3=F-3 or E=F-6.
D+3=3(F-6+3)
D+3=3F-9
D=3F-12.
now, we have D=2F-3.
2F-3=3F-12
9=F
Sridhar has three sons Satish, Ritesh and Nitesh. Satish is oldest while Nitesh is the Youngest. The present ages of all the three son’s are square numbers. Sum of their ages after 3 years will be 39. Then what is the present age of Ritesh?- a)1
- b)4
- c)9
- d)16
- e)25
Correct answer is option 'B'. Can you explain this answer?
Sridhar has three sons Satish, Ritesh and Nitesh. Satish is oldest while Nitesh is the Youngest. The present ages of all the three son’s are square numbers. Sum of their ages after 3 years will be 39. Then what is the present age of Ritesh?
a)
1
b)
4
c)
9
d)
16
e)
25
|
Machine Experts answered |
X+Y+Z = 30
Possible ages (1,4,9,16,25)
from above ages = (1,4,25)
Possible ages (1,4,9,16,25)
from above ages = (1,4,25)
Sum of the Ages of Aruna, Bhaskar, Chaitu and Dinesh is 78. Aruna is 5 years older than Bhaskar. Chaitu is 3 years older than Dinesh. Aruna age is 9 times the age of Dinesh. Then what is the age of Chaitu?- a)4
- b)5
- c)6
- d)7
- e)Cannot be determined
Correct answer is option 'E'. Can you explain this answer?
Sum of the Ages of Aruna, Bhaskar, Chaitu and Dinesh is 78. Aruna is 5 years older than Bhaskar. Chaitu is 3 years older than Dinesh. Aruna age is 9 times the age of Dinesh. Then what is the age of Chaitu?
a)
4
b)
5
c)
6
d)
7
e)
Cannot be determined
|
Cstoppers Instructors answered |
A+B+C+D = 78
B = A-5, C= D+3 , A=9
A = 36
V = 7
B = A-5, C= D+3 , A=9
A = 36
V = 7
Silvia was married 8 year ago. Today her age is 9/7 times to that time of marriage. At present his son’s age is 1/6th of her age. What was her son’s age 3 year ago?- a)4 yr
- b)2 yr
- c)3 yr
- d)5 yr
- e)None of the Above
Correct answer is option 'C'. Can you explain this answer?
Silvia was married 8 year ago. Today her age is 9/7 times to that time of marriage. At present his son’s age is 1/6th of her age. What was her son’s age 3 year ago?
a)
4 yr
b)
2 yr
c)
3 yr
d)
5 yr
e)
None of the Above
|
Yash Patel answered |
Silvia’s age 8 year ago = x
Present age = x + 8
x + 8 = 9/7 x
7(x + 8)= 9x
x = 28; 28 + 8 = 36
Son’s age = 1/6 * 36 = 6
Son’s age 3 year ago = 6-3 =3
Present age = x + 8
x + 8 = 9/7 x
7(x + 8)= 9x
x = 28; 28 + 8 = 36
Son’s age = 1/6 * 36 = 6
Son’s age 3 year ago = 6-3 =3
The ratio of Present age of Madhu and Divya is 6:7. Madhu is 7 years younger than Laxmi. Laxmi’s age after 8 years will be 51 years. Then what is the difference between the present ages of Madhu and Divya?- a)3 Years
- b)4 Years
- c)5 Years
- d)6 Years
- e)Cannot be determined
Correct answer is option 'D'. Can you explain this answer?
The ratio of Present age of Madhu and Divya is 6:7. Madhu is 7 years younger than Laxmi. Laxmi’s age after 8 years will be 51 years. Then what is the difference between the present ages of Madhu and Divya?
a)
3 Years
b)
4 Years
c)
5 Years
d)
6 Years
e)
Cannot be determined
|
Kavya Saxena answered |
M/D = 6/7
L- M =7
L+8 = 51 L = 43
M = 36
D = 42
D-M = 42-36 = 6
L- M =7
L+8 = 51 L = 43
M = 36
D = 42
D-M = 42-36 = 6
Jack is now twice as old as Femina, who is two years older than Suresh. Four years ago, Jack was four times as old as Suresh. How old is Jack now?- a)18
- b)12
- c)16
- d)20
- e)24
Correct answer is option 'D'. Can you explain this answer?
Jack is now twice as old as Femina, who is two years older than Suresh. Four years ago, Jack was four times as old as Suresh. How old is Jack now?
a)
18
b)
12
c)
16
d)
20
e)
24
|
|
Kishan Singh answered |
Let the age of SURESH = X
age of FEMINA = X + 2
age of JACK = 2 ( X + 2 ) = 2X +4
four years ago,
JACK age =( 2X +4 )- 4 = 2X
SURESH age = X - 4
A/Q -
2X = 4 ( X - 4 )
=> X = 8
JACK present age = 2 (X +2)= 20 year . option( D)
age of FEMINA = X + 2
age of JACK = 2 ( X + 2 ) = 2X +4
four years ago,
JACK age =( 2X +4 )- 4 = 2X
SURESH age = X - 4
A/Q -
2X = 4 ( X - 4 )
=> X = 8
JACK present age = 2 (X +2)= 20 year . option( D)
Ravi is now 4 years older than Emma and half of that amount older than Ishu. If in 2 years, Ravi will be twice as old as Emma, then in 2 years what would be Ravi’s age multiplied by Ishu’s age?- a)68
- b)28
- c)48
- d)50
- e)52
Correct answer is option 'C'. Can you explain this answer?
Ravi is now 4 years older than Emma and half of that amount older than Ishu. If in 2 years, Ravi will be twice as old as Emma, then in 2 years what would be Ravi’s age multiplied by Ishu’s age?
a)
68
b)
28
c)
48
d)
50
e)
52
|
|
Anaya Patel answered |
Ravi – x + 4
Emma – x
Ishu – x + 2
(Ravi 4 years older than Emma & 2 years older than Ishu)
Ages after 2 yrs
Ravi – x + 6
Emma – x + 2
Ishu – x + 4
x+6 = 2(x + 2)
x = 2
Ravi * Ishu = 8 * 6 = 48
Emma – x
Ishu – x + 2
(Ravi 4 years older than Emma & 2 years older than Ishu)
Ages after 2 yrs
Ravi – x + 6
Emma – x + 2
Ishu – x + 4
x+6 = 2(x + 2)
x = 2
Ravi * Ishu = 8 * 6 = 48
Sum of the twice the age of Surya and his Father age is 79. Sum of the twice the age of Father and Surya’s age is 104. The average of Surya, his Father and his Mother is 32. Then what is the age of his Mother?- a)32
- b)33
- c)34
- d)35
- e)36
Correct answer is option 'D'. Can you explain this answer?
Sum of the twice the age of Surya and his Father age is 79. Sum of the twice the age of Father and Surya’s age is 104. The average of Surya, his Father and his Mother is 32. Then what is the age of his Mother?
a)
32
b)
33
c)
34
d)
35
e)
36
|
|
Aarav Sharma answered |
2S+F = 79
2F+S = 104
S =18 F = 43
18+43+M/3 = 32
M =35
Present age of Husband and Wife is 28 and 24 Years respectively. At that age twin babies were born to them. After how many years the average of the family will be same as before babies were born?- a)10 Years
- b)11 Years
- c)12 Years
- d)13 Years
- e)Cannot be determined
Correct answer is option 'D'. Can you explain this answer?
Present age of Husband and Wife is 28 and 24 Years respectively. At that age twin babies were born to them. After how many years the average of the family will be same as before babies were born?
a)
10 Years
b)
11 Years
c)
12 Years
d)
13 Years
e)
Cannot be determined
|
Nikita Singh answered |
28+24/2 =26 = (28+x+24+x+2x)/4
104 = (52+4x)
x= 13
104 = (52+4x)
x= 13
Lilly is 5 years older than Martin, and Catherine is twice as old as Lilly. If the sum of their ages is 95, how old is Lilly?- a)26
- b)27
- c)28
- d)25
- e)None of these
Correct answer is option 'D'. Can you explain this answer?
Lilly is 5 years older than Martin, and Catherine is twice as old as Lilly. If the sum of their ages is 95, how old is Lilly?
a)
26
b)
27
c)
28
d)
25
e)
None of these
|
|
Aarav Sharma answered |
To solve this problem, we can use algebraic equations. Let's assign variables to the ages of Lilly, Martin, and Catherine.
Let:
L = Lilly's age
M = Martin's age
C = Catherine's age
Given information:
Lilly is 5 years older than Martin: L = M + 5
Catherine is twice as old as Lilly: C = 2L
The sum of their ages is 95: L + M + C = 95
Now we can substitute the values of L and C from the first two equations into the third equation to solve for M.
(M + 5) + M + 2(M + 5) = 95
M + 5 + M + 2M + 10 = 95
4M + 15 = 95
4M = 80
M = 20
Now that we know Martin's age is 20, we can substitute this value back into the first equation to find Lilly's age.
L = M + 5
L = 20 + 5
L = 25
Therefore, Lilly is 25 years old. So the correct answer is option D.
Let:
L = Lilly's age
M = Martin's age
C = Catherine's age
Given information:
Lilly is 5 years older than Martin: L = M + 5
Catherine is twice as old as Lilly: C = 2L
The sum of their ages is 95: L + M + C = 95
Now we can substitute the values of L and C from the first two equations into the third equation to solve for M.
(M + 5) + M + 2(M + 5) = 95
M + 5 + M + 2M + 10 = 95
4M + 15 = 95
4M = 80
M = 20
Now that we know Martin's age is 20, we can substitute this value back into the first equation to find Lilly's age.
L = M + 5
L = 20 + 5
L = 25
Therefore, Lilly is 25 years old. So the correct answer is option D.
Suresh got married 8 years ago. His present age is 6/5 times his age at the time of his marriage Suresh’s sister was 10years younger to him at the time of his marriage. The present age of Suresh’s sister is - a)36
- b)37
- c)38
- d)35
- e)None of these
Correct answer is option 'C'. Can you explain this answer?
Suresh got married 8 years ago. His present age is 6/5 times his age at the time of his marriage Suresh’s sister was 10years younger to him at the time of his marriage. The present age of Suresh’s sister is
a)
36
b)
37
c)
38
d)
35
e)
None of these
|
|
Aarav Sharma answered |
Let's say Suresh's age at the time of his marriage is x years.
According to the given information, 6/5 times x is Suresh's present age.
So, 6/5 * x = Suresh's present age.
Since Suresh got married 8 years ago, his present age is x + 8.
Therefore, we can write the equation as follows:
6/5 * x = x + 8.
To solve this equation, we can multiply both sides by 5 to get rid of the fraction:
5 * 6/5 * x = 5 * (x + 8).
6x = 5x + 40.
Now, we can simplify the equation:
6x - 5x = 40.
x = 40.
Therefore, Suresh's age at the time of his marriage was x = 40 years.
And his present age is 6/5 times his age at the time of his marriage, which is:
6/5 * 40 = 48 years.
So, Suresh's present age is 48 years.
According to the given information, 6/5 times x is Suresh's present age.
So, 6/5 * x = Suresh's present age.
Since Suresh got married 8 years ago, his present age is x + 8.
Therefore, we can write the equation as follows:
6/5 * x = x + 8.
To solve this equation, we can multiply both sides by 5 to get rid of the fraction:
5 * 6/5 * x = 5 * (x + 8).
6x = 5x + 40.
Now, we can simplify the equation:
6x - 5x = 40.
x = 40.
Therefore, Suresh's age at the time of his marriage was x = 40 years.
And his present age is 6/5 times his age at the time of his marriage, which is:
6/5 * 40 = 48 years.
So, Suresh's present age is 48 years.
The respective ratio between the present age of Mary and Deepa is x : 42. Mary is 8 years younger than Prema. Prema’s age after 8 years will be 33 years. The difference between Deepa’s and Mary’s age is same as the present age of Prema. What is the value of x?- a)18
- b)10
- c)16
- d)11
- e)17
Correct answer is option 'E'. Can you explain this answer?
The respective ratio between the present age of Mary and Deepa is x : 42. Mary is 8 years younger than Prema. Prema’s age after 8 years will be 33 years. The difference between Deepa’s and Mary’s age is same as the present age of Prema. What is the value of x?
a)
18
b)
10
c)
16
d)
11
e)
17
|
|
Anaya Patel answered |
Prema’s age after 8 years = 33 years
Prema’s present age = 33 – 8= 25 years
Mary’s present age = 25 – 8 = 17 years
Deepa’s present age = 17 + 25 = 42 years
Ratio between Mary and Deepa = 17 : 42
X = 17
Prema’s present age = 33 – 8= 25 years
Mary’s present age = 25 – 8 = 17 years
Deepa’s present age = 17 + 25 = 42 years
Ratio between Mary and Deepa = 17 : 42
X = 17
The ages of Ashwini, Kavitha and Chitra together are 57 years. Kavitha is thrice as old as Ashwini and Chitra is 12 years older than Ashwini. Then, what is the ratio of respective age of Ashwini, Kavitha and Chitra is?- a)3 : 9 : 7
- b)3 : 9 : 2
- c)3 : 9 : 4
- d)3 : 9 : 5
- e)3 : 9 : 8
Correct answer is option 'A'. Can you explain this answer?
The ages of Ashwini, Kavitha and Chitra together are 57 years. Kavitha is thrice as old as Ashwini and Chitra is 12 years older than Ashwini. Then, what is the ratio of respective age of Ashwini, Kavitha and Chitra is?
a)
3 : 9 : 7
b)
3 : 9 : 2
c)
3 : 9 : 4
d)
3 : 9 : 5
e)
3 : 9 : 8
|
|
Kishan Singh answered |
Sum of Sita and Gita age is 1 less than Rita. After one year Sum of Sita and Gita age is equal to Rita’s age. After another year Sum of Sita and Gita is 1 more than Rita’s age. If the sum of Sita, Gita and Rita’s age is 19. Then what is the age of Sita?- a)4
- b)5
- c)6
- d)7
- e)Cannot be determined
Correct answer is option 'E'. Can you explain this answer?
Sum of Sita and Gita age is 1 less than Rita. After one year Sum of Sita and Gita age is equal to Rita’s age. After another year Sum of Sita and Gita is 1 more than Rita’s age. If the sum of Sita, Gita and Rita’s age is 19. Then what is the age of Sita?
a)
4
b)
5
c)
6
d)
7
e)
Cannot be determined
|
|
Preeti Khanna answered |
X+Y+Z = 19
X+Y+1 = Z
Z =10
X+Y+2 = Z+1
X+Y+4 = Z+2+1. Based on above solution cannot be determined
X+Y+1 = Z
Z =10
X+Y+2 = Z+1
X+Y+4 = Z+2+1. Based on above solution cannot be determined
Arun will be half as old as Lilly in 3 years. Arun will also be one-third as old as James in 5 years. If James is 15 years older than Lilly, how old is Arun?- a)6
- b)8
- c)9
- d)5
- e)4
Correct answer is option 'B'. Can you explain this answer?
Arun will be half as old as Lilly in 3 years. Arun will also be one-third as old as James in 5 years. If James is 15 years older than Lilly, how old is Arun?
a)
6
b)
8
c)
9
d)
5
e)
4
|
|
Aisha Gupta answered |
let age of Arun =x, Lilly =y James = z
(x+3) =1/2 *(y+3) so we have 2x-y =-3 -(1)
(x+5) =1/3 * (z+5) ; ⇒ 3x-z=-10 -(2)
From (1)&(2) we get, x+y-z =-7 -(3)
we have z =15+y – (4)
from equation 3 and 4 we get x=8
(x+3) =1/2 *(y+3) so we have 2x-y =-3 -(1)
(x+5) =1/3 * (z+5) ; ⇒ 3x-z=-10 -(2)
From (1)&(2) we get, x+y-z =-7 -(3)
we have z =15+y – (4)
from equation 3 and 4 we get x=8
Ravi has three children: two daughters and one son. All were born on the same date in different years. The sum of the ages of the two daughters today is smaller than the age of the son today, but a year from now the sum of the ages of the daughters will equal the age of the son. Three years from today, the difference between the age of the son and the combined ages of the daughters will be- a)1
- b)2
- c)3
- d)–2
- e)–1
Correct answer is option 'D'. Can you explain this answer?
Ravi has three children: two daughters and one son. All were born on the same date in different years. The sum of the ages of the two daughters today is smaller than the age of the son today, but a year from now the sum of the ages of the daughters will equal the age of the son. Three years from today, the difference between the age of the son and the combined ages of the daughters will be
a)
1
b)
2
c)
3
d)
–2
e)
–1
|
Faizan Khan answered |
one year from now, D+d=s
two years after that, D+2+d+2=s+2
D+d-s=2-4=-2
two years after that, D+2+d+2=s+2
D+d-s=2-4=-2
One year before, Reshma was six times as old as her daughter. Six years hence, Reshma’s age will exceed her daughter’s age by 20 years. The ratio of the present ages of Reshma and her daughter is?- a)5 : 4
- b)9 : 4
- c)5 : 1
- d)7 : 2
- e)None of the Above
Correct answer is option 'C'. Can you explain this answer?
One year before, Reshma was six times as old as her daughter. Six years hence, Reshma’s age will exceed her daughter’s age by 20 years. The ratio of the present ages of Reshma and her daughter is?
a)
5 : 4
b)
9 : 4
c)
5 : 1
d)
7 : 2
e)
None of the Above
|
|
Rhea Reddy answered |
Ages of Reshma and her daughter = 6x, x
[6x + 1 + 6] – [x + 1 + 6] = 20
5x = 20; x = 4
Ratio = 6x + 1 : x + 1 = 25 : 5 = 5:1
[6x + 1 + 6] – [x + 1 + 6] = 20
5x = 20; x = 4
Ratio = 6x + 1 : x + 1 = 25 : 5 = 5:1
The ratio of present ages of Ramya and Karan’s age is 4:5 and the ratio of present ages of Karan and Priya is 2:5 respectively. If Ramya is two-fifth of Priya’s age, What is Ramya’s age?- a)12 years
- b)10 years
- c)20 years
- d)Cannot be determined
- e)None of the Above
Correct answer is option 'D'. Can you explain this answer?
The ratio of present ages of Ramya and Karan’s age is 4:5 and the ratio of present ages of Karan and Priya is 2:5 respectively. If Ramya is two-fifth of Priya’s age, What is Ramya’s age?
a)
12 years
b)
10 years
c)
20 years
d)
Cannot be determined
e)
None of the Above
|
Akash Pandey answered |
Data Insufficient – Can not be determined.
James is now 12 years younger than Mahesh. If 9 years from now Mahesh will be twice as old as James, how old will James be in 4 years?- a)3
- b)7
- c)5
- d)9
- e)8
Correct answer is option 'B'. Can you explain this answer?
James is now 12 years younger than Mahesh. If 9 years from now Mahesh will be twice as old as James, how old will James be in 4 years?
a)
3
b)
7
c)
5
d)
9
e)
8
|
|
Aisha Gupta answered |
James = x years, Mahesh = x+12 years
9 from now,
2(x+9)=x+21
2x+18=x+21
x=3
x+4 =7 years
9 from now,
2(x+9)=x+21
2x+18=x+21
x=3
x+4 =7 years
Amit’s present age is 1.5 times of Hari’s present age. If after 4 years, Amit’s age will be twice of Hari’s age 4 years ago. What is the sum of the present ages of Amit and Hari?- a)52 years
- b)53 years
- c)60 years
- d)67 years
- e)63 years
Correct answer is option 'C'. Can you explain this answer?
Amit’s present age is 1.5 times of Hari’s present age. If after 4 years, Amit’s age will be twice of Hari’s age 4 years ago. What is the sum of the present ages of Amit and Hari?
a)
52 years
b)
53 years
c)
60 years
d)
67 years
e)
63 years
|
|
Aarav Sharma answered |
I am sorry, but I need more information to understand your request. Can you please provide me with more details?
Mr. Sharma has three sons namely Ram, Amit and Karan. Ram is the eldest son of Mr. Sharma while Karan is the youngest one. The present ages of all three of them are square numbers. The sum of their ages after 5 years is 44. What is the age of Ram after three years?- a)15 years
- b)13 years
- c)19 years
- d)17 years
- e)16 years
Correct answer is option 'C'. Can you explain this answer?
Mr. Sharma has three sons namely Ram, Amit and Karan. Ram is the eldest son of Mr. Sharma while Karan is the youngest one. The present ages of all three of them are square numbers. The sum of their ages after 5 years is 44. What is the age of Ram after three years?
a)
15 years
b)
13 years
c)
19 years
d)
17 years
e)
16 years
|
|
Aarav Sharma answered |
Problem Analysis:
We are given that Ram is the eldest son of Mr. Sharma and Karan is the youngest. Also, the present ages of all three of them are square numbers. We need to find the age of Ram after three years.
Given:
Ram, Amit and Karan are the three sons of Mr. Sharma.
Ram is the eldest son of Mr. Sharma.
Karan is the youngest son of Mr. Sharma.
The present ages of all three of them are square numbers.
The sum of their ages after 5 years is 44.
To Find:
The age of Ram after three years.
Solution:
Let’s assume that the present age of Ram is x^2, Amit is y^2, and Karan is z^2.
From the given conditions, we know that:
x > y > z
x, y, and z are square numbers.
After 5 years, their ages would be (x^2+5), (y^2+5), and (z^2+5).
According to the problem, the sum of their ages after 5 years is 44.
(x^2+5) + (y^2+5) + (z^2+5) = 44
x^2 + y^2 + z^2 = 24
As x, y, and z are square numbers, we can try to find the squares that add up to 24. We can use trial and error method for this.
We get the following values of x, y, and z:
x = 4, y = 2, z = 2
x^2 = 16, y^2 = 4, z^2 = 4
Therefore, Ram’s present age is 16 years.
The age of Ram after three years would be:
Ram’s age after three years = 16+3 = 19 years.
Therefore, option (c) is the correct answer.
Final Answer:
The age of Ram after three years is 19 years.
We are given that Ram is the eldest son of Mr. Sharma and Karan is the youngest. Also, the present ages of all three of them are square numbers. We need to find the age of Ram after three years.
Given:
Ram, Amit and Karan are the three sons of Mr. Sharma.
Ram is the eldest son of Mr. Sharma.
Karan is the youngest son of Mr. Sharma.
The present ages of all three of them are square numbers.
The sum of their ages after 5 years is 44.
To Find:
The age of Ram after three years.
Solution:
Let’s assume that the present age of Ram is x^2, Amit is y^2, and Karan is z^2.
From the given conditions, we know that:
x > y > z
x, y, and z are square numbers.
After 5 years, their ages would be (x^2+5), (y^2+5), and (z^2+5).
According to the problem, the sum of their ages after 5 years is 44.
(x^2+5) + (y^2+5) + (z^2+5) = 44
x^2 + y^2 + z^2 = 24
As x, y, and z are square numbers, we can try to find the squares that add up to 24. We can use trial and error method for this.
We get the following values of x, y, and z:
x = 4, y = 2, z = 2
x^2 = 16, y^2 = 4, z^2 = 4
Therefore, Ram’s present age is 16 years.
The age of Ram after three years would be:
Ram’s age after three years = 16+3 = 19 years.
Therefore, option (c) is the correct answer.
Final Answer:
The age of Ram after three years is 19 years.
Ravi’s present age is three times his son’s present age and 4/5th of his father’s present age. The average of the present ages of all of them is 62 years. What is the difference between the Ravi’s son’s present age and Ravi’s father’s present age?- a)62 years
- b)64 years
- c)69 years
- d)67 years
- e)66 years
Correct answer is option 'E'. Can you explain this answer?
Ravi’s present age is three times his son’s present age and 4/5th of his father’s present age. The average of the present ages of all of them is 62 years. What is the difference between the Ravi’s son’s present age and Ravi’s father’s present age?
a)
62 years
b)
64 years
c)
69 years
d)
67 years
e)
66 years
|
|
Nikita Singh answered |
Present age of Ravi is = 4/5x
Present age of Ravi’s father is = 4/15x
Ratio = 15: 12 : 4
Difference between the Ravi’s son’s present age and Ravi’s father’s present age = 62/31 * 3(15 – 4).
= 2*3*11 = 66 year.
Present age of Ravi’s father is = 4/15x
Ratio = 15: 12 : 4
Difference between the Ravi’s son’s present age and Ravi’s father’s present age = 62/31 * 3(15 – 4).
= 2*3*11 = 66 year.
When Ramesh was born, his father was 32 years older than his brother and his mother was 25 years older than his sister. If Ramesh’s brother is 6 years older than Ramesh and his mother is 3 years younger than his father, how old was Ramesh’s sister when Ramesh was born? - a)15
- b)10
- c)25
- d)20
- e)None of the Above
Correct answer is option 'B'. Can you explain this answer?
When Ramesh was born, his father was 32 years older than his brother and his mother was 25 years older than his sister. If Ramesh’s brother is 6 years older than Ramesh and his mother is 3 years younger than his father, how old was Ramesh’s sister when Ramesh was born?
a)
15
b)
10
c)
25
d)
20
e)
None of the Above
|
|
Rajeev Kumar answered |
Ramesh’s age = 0
Ramesh’s father age = 38
Ramesh’s mother age = 35
Ramesh’s sister is 25 years younger than his mother; 35 – 25 = 10
Ramesh’s father age = 38
Ramesh’s mother age = 35
Ramesh’s sister is 25 years younger than his mother; 35 – 25 = 10
Leena’s age is 5 years more than twice Gayathri’s age. Vijay’s age is 13 years less than 10 times Gayathri’s age. If Vijay is 3 times as old as Leena, how old is Leena? - a)17
- b)16
- c)12
- d)14
- e)19
Correct answer is option 'E'. Can you explain this answer?
Leena’s age is 5 years more than twice Gayathri’s age. Vijay’s age is 13 years less than 10 times Gayathri’s age. If Vijay is 3 times as old as Leena, how old is Leena?
a)
17
b)
16
c)
12
d)
14
e)
19
|
|
Nikita Singh answered |
given l = 2g+5
v = 10g-13
v = 3l
f rom v = 3l ⇒ 10g-13 = 6g+15
g = 7
l = 2g+5 = 19
v = 10g-13
v = 3l
f rom v = 3l ⇒ 10g-13 = 6g+15
g = 7
l = 2g+5 = 19
Ratio of the ages of Mani and Naveen is 5 : A. Mani is 18 years younger to Ravi. After nine years Ravi will be 47 years old. If the difference between the ages of Mani and Naveen is same as the age of Ravi, what is the value of A?- a)16.5
- b)18.5
- c)19.5
- d)15.5
- e)14.5
Correct answer is option 'E'. Can you explain this answer?
Ratio of the ages of Mani and Naveen is 5 : A. Mani is 18 years younger to Ravi. After nine years Ravi will be 47 years old. If the difference between the ages of Mani and Naveen is same as the age of Ravi, what is the value of A?
a)
16.5
b)
18.5
c)
19.5
d)
15.5
e)
14.5
|
Arya Roy answered |
Present ages of Mani, Naveen and Ravi be x, y and z respectively.
x/y = 5/A —— (1)
x = z – 18 —— (2)
z + 9 = 47 —— (3)
x – y = z —– (4)
From (1) (2) (3) and (4)
4A = 58 => A = 14.5
This year, the sum of ages of the Suresh’s family members is 78. Currently, there are 4 members namely viz Suresh, Rita, Deepa and Tarun. Suresh is 4 years older than Rita. Deepa is two years older than Tarun. If Suresh is 7 times as old as Tarun, how old is Deepa?- a)5
- b)7
- c)8
- d)9
- e)6
Correct answer is option 'B'. Can you explain this answer?
This year, the sum of ages of the Suresh’s family members is 78. Currently, there are 4 members namely viz Suresh, Rita, Deepa and Tarun. Suresh is 4 years older than Rita. Deepa is two years older than Tarun. If Suresh is 7 times as old as Tarun, how old is Deepa?
a)
5
b)
7
c)
8
d)
9
e)
6
|
|
Faizan Khan answered |
S+R+D+T = 78 – (i)
S = R + 4 – (ii)
D = T + 2 – (iii)
S = 7T – (iv)
7T = R+4
R= 7T – 4
h+w+d+s = 78 – (i)
7T+7T-4+T+2+T = 78
16T = 80
T = 5
d = T+2 = 5+2 = 7
S = R + 4 – (ii)
D = T + 2 – (iii)
S = 7T – (iv)
7T = R+4
R= 7T – 4
h+w+d+s = 78 – (i)
7T+7T-4+T+2+T = 78
16T = 80
T = 5
d = T+2 = 5+2 = 7
If two times of the Ria’s age in years is included to her mother’s age, the total is 70 and if two times of the mother’s age is included to the Ria’s age, the total is 95. So what is the age of Ria’s Mother?- a)55
- b)35
- c)45
- d)40
- e)50
Correct answer is option 'D'. Can you explain this answer?
If two times of the Ria’s age in years is included to her mother’s age, the total is 70 and if two times of the mother’s age is included to the Ria’s age, the total is 95. So what is the age of Ria’s Mother?
a)
55
b)
35
c)
45
d)
40
e)
50
|
|
Kavya Saxena answered |
Ria’s age = x ; Ria’s mother age = y
2x+y = 70 and x+2y = 95
y = 40.
2x+y = 70 and x+2y = 95
y = 40.
When Rajesh was born, his father age was 29 years older than his Brother and his Mother was 25 years older than his Sister. If his Brother is 2 years elder than his Sister. After 6 years the average age of the family is 20. Then what is the age of Mother when Rajesh was born?- a)27
- b)28
- c)29
- d)30
- e)Cannot be determined
Correct answer is option 'B'. Can you explain this answer?
When Rajesh was born, his father age was 29 years older than his Brother and his Mother was 25 years older than his Sister. If his Brother is 2 years elder than his Sister. After 6 years the average age of the family is 20. Then what is the age of Mother when Rajesh was born?
a)
27
b)
28
c)
29
d)
30
e)
Cannot be determined
|
|
Arya Roy answered |
Answer – 2. 28
Explanation :
Sister = x; Brother = x+2; Father = 29+x+2; Mother = 25+x
Present age – 4x+58
After 6 years
4x+58+30 = 4x+88
4x+88 = 100
x = 3
Mothers age = 25+x = 28.
Eight years ago Ravi’s mother was five times older than her daughter. After Eight years Ravi’s mother will be twice older than her daughter. Find the present age of Ravi?- a)18.33 years
- b)12.5 years
- c)16.7 years
- d)13.33 years
- e)14.5 years
Correct answer is option 'D'. Can you explain this answer?
Eight years ago Ravi’s mother was five times older than her daughter. After Eight years Ravi’s mother will be twice older than her daughter. Find the present age of Ravi?
a)
18.33 years
b)
12.5 years
c)
16.7 years
d)
13.33 years
e)
14.5 years
|
|
Anaya Patel answered |
Eight years ago, Ravi’s age = x
Eight years ago, Ravi’s Mother age = 5x
2(x+16) = 5x+16
2x+32 = 5x+16
x=16/3
Present age of Ravi = 16/3 + 8 = 13.33 years
Eight years ago, Ravi’s Mother age = 5x
2(x+16) = 5x+16
2x+32 = 5x+16
x=16/3
Present age of Ravi = 16/3 + 8 = 13.33 years
Ravi is as much younger than Surya as he is older than Suresh. If the sum of the ages of Surya and Suresh is 50 years, what is definitely the difference between Surya and Ravi’s age?- a)12 years
- b)23 years
- c)19 years
- d)27 years
- e)Can not be determined
Correct answer is option 'E'. Can you explain this answer?
Ravi is as much younger than Surya as he is older than Suresh. If the sum of the ages of Surya and Suresh is 50 years, what is definitely the difference between Surya and Ravi’s age?
a)
12 years
b)
23 years
c)
19 years
d)
27 years
e)
Can not be determined
|
|
Faizan Khan answered |
Surya’s age – Ravi’s age = Ravi’s age – Surya’s age
Suresh’s age + Surya’s age = 2 Ravi’s age
Surya’s age + Suresh’s age = 50
Ravi’s age = 25; We can not find the difference between Surya and Ravi’s age
Suresh’s age + Surya’s age = 2 Ravi’s age
Surya’s age + Suresh’s age = 50
Ravi’s age = 25; We can not find the difference between Surya and Ravi’s age
The average runs scored by a cricketer is 42 innings, is 40. The difference between his maximum and minimum scores in an inning is 100. If these two innings are not taken into consideration, then the average score of remaining 40 inning is 37. Calculate the maximum runs scored by him in an innings?- a)125
- b)150
- c)110
- d)100
- e)None of these
Correct answer is option 'B'. Can you explain this answer?
The average runs scored by a cricketer is 42 innings, is 40. The difference between his maximum and minimum scores in an inning is 100. If these two innings are not taken into consideration, then the average score of remaining 40 inning is 37. Calculate the maximum runs scored by him in an innings?
a)
125
b)
150
c)
110
d)
100
e)
None of these
|
|
Faizan Khan answered |
Let the minimum score = x
∴ Maximum score = x + 100
∴ x + (x + 100) = 42 x 40 – 40 x 37
⇒ 2x + 100 = 1680 – 1480 = 200
⇒ 2x = 200 – 100 = 100
⇒ x = 50
Maximum score = x + 100 = 50 + 100 = 150
∴ Maximum score = x + 100
∴ x + (x + 100) = 42 x 40 – 40 x 37
⇒ 2x + 100 = 1680 – 1480 = 200
⇒ 2x = 200 – 100 = 100
⇒ x = 50
Maximum score = x + 100 = 50 + 100 = 150
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