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All questions of Number System for DSSSB TGT/PGT/PRT Exam

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Sum of three consecutive odd numbers & three consecutive even numbers together is 231. Difference between the smallest odd number and the smallest even number is 11. What is the sum of the largest even number and largest odd number?
  • a)
    71
  • b)
    91
  • c)
    101
  • d)
    81
  • e)
    Can not be determined
Correct answer is option 'D'. Can you explain this answer?

Kendrika answered
Let the three odd numbers be x, (x + 2), (x + 4) and
The three even numbers be (x + 11), (x + 13) and (x + 15)
Then,
⇔ x + (x + 2) + (x + 4) + (x + 11) + (x + 13) + (x + 15) = 231
⇔ 6x + 45 = 231
⇔ 6x = 186
⇔ x = 31
∴ Required sum :
= (x + 4) + (x + 15)
= 2x + 19
= 2 × 31 + 19
= 62 + 19
= 81

The sum of two even numbers is six more than twice of the smaller number. If the difference between these two numbers is 6, If the larger number lies between 15 to 25 Which is the smaller number?
  • a)
    16
  • b)
    6
  • c)
    24
  • d)
    12
  • e)
    Can not be determined
Correct answer is option 'D'. Can you explain this answer?

Kavya Saxena answered
If 12 is smaller number then larger number is 18
Sum = (12+18) = 30
Twice of the smaller number = 24.
The sum of two even numbers is six more than twice of the smaller number.
Therefore Number 12 satisfy both the conditions.

If three numbers are added in pairs, the sums equal to 11,16 and 23.Find the three numbers
  • a)
    8,6,16
  • b)
    9,2,14
  • c)
    9,5,14
  • d)
    7,2,8
Correct answer is option 'B'. Can you explain this answer?

Preeti Khanna answered
X+y = 11 - (1)
Y+z = 16 - (2)
Z+x = 23 -(3)
Add (1), (2), and (3)
2(x + y + z) = 50
X+y+z = 25
X = 25 – 16 = 9
y = 25 – 23 = 2
z = 25 – 11 = 14

Sum of eight consecutive odd numbers is 656. Average of four consecutive even numbers is 87. What is the sum of the largest even number and largest odd number?
  • a)
    171
  • b)
    191
  • c)
    101
  • d)
    181
  • e)
    179
Correct answer is option 'E'. Can you explain this answer?

Preeti Khanna answered
odd numbers — x-8, x-6, x-4, x-2, x, x+2, x+4, x+6
x-8 + x-6 + x-4 + x-2 + x + x+2 + x+4 + x+6 = 656
8x – 8 =656
x = 83
Even numbers — y-2, y, y+2, y+4
4y + 4 = 87 * 4
y = 86
sum of the largest even number and odd number = 89 + 90 = 179

A number is divided by 2, 3, 4, 5 or 6, reminder in each case is one. But the number is exactly divisible by 7. The number lies between 250 and 350, the sum of digits of the number will be
  • a)
    4
  • b)
    7
  • c)
    6
  • d)
    10
  • e)
    Can not be determined
Correct answer is option 'A'. Can you explain this answer?

Preeti Khanna answered
To solve this problem, we need to find a number that satisfies the following conditions:
  1. When divided by 2, 3, 4, 5, or 6, the remainder is 1.
  2. The number is divisible by 7.
  3. The number lies between 250 and 350.
Let's start by finding the least common multiple (LCM) of 2, 3, 4, 5, and 6, which is the smallest number divisible by all of these numbers.
LCM(2, 3, 4, 5, 6) = 60
We need to find a number of the form 7k, where k is an integer, that leaves a remainder of 1 when divided by 60. The numbers in this sequence can be expressed as 60n + 1, where n is an integer.
Now, let's find the first few numbers of the form 60n + 1 that are divisible by 7 and lie between 250 and 350:
  • For n = 4: 60(4) + 1 = 241 (not divisible by 7)
  • For n = 5: 60(5) + 1 = 301 (divisible by 7)
So, the number we're looking for is 301.
Now, let's find the sum of its digits: 3 + 0 + 1 = 4
Therefore, the sum of the digits of the number is 4.

The difference between the digits of a two digit number is 5. Also the original number is 18 more than two times the number obtained by reversing its digits. Find the original number.
  • a)
    94
  • b)
    61
  • c)
    72
  • d)
    49
  • e)
    27
Correct answer is option 'C'. Can you explain this answer?

Ravi Singh answered
Let number is 10x+y
Then x-y = 5 or y-x = 5
Now given that, 10x+y = 2(10y+x) + 18 Solve, 8x – 19y = 18
Now solve: 8x – 19y = 18 and x-y = 5. In this y = 2, x = 7
And also solve; 8x – 19y = 18 and y-x = 5. In this y come to be negative which is not possible so discard this
So number is 10*7 + 2

If the divisor is five times the quotient and six times the remainder, if the remainder is 5 then the dividend is
  • a)
    225
  • b)
    300
  • c)
    185
  • d)
    412
  • e)
    None of these
Correct answer is option 'C'. Can you explain this answer?

Aarav Sharma answered
Let's use the formula for division: dividend = divisor × quotient + remainder
Given: divisor = 5 × quotient and divisor = 6 × remainder
Substituting the first equation into the second equation, we get:
5 × quotient = 6 × remainder
quotient = (6/5) × remainder
Substituting this value of quotient into the formula for division, we get:
dividend = 5 × (6/5) × remainder + remainder
dividend = 6 × remainder + remainder
dividend = 7 × remainder
Since the remainder is 5, we can substitute that value into the formula to get:
dividend = 7 × 5 = 35
Therefore, the correct answer is option C) 185, as it is the only option that has a remainder of 5 when divided by a divisor that is five times the quotient and six times the remainder.

If 4 is added to the numerator of a fraction it becomes 1/3 and if 3 is added to the denominator it becomes 1/6 then find the numerator and denominator is
  • a)
    5/26
  • b)
    25/4
  • c)
    6/17
  • d)
    5/27
  • e)
    None of these
Correct answer is option 'D'. Can you explain this answer?

Preeti Khanna answered
Let the numerator be x and denominator be y 
Fraction will be x/y 
According to the question 
(x + 4)/y = 1/3 
⇒ 3x + 12 = y    ......(1)
Now, 
x/(y + 3) = 1/6 
⇒ 6x = y + 3    ......(2)
Solving both the equations we get 
x = 5 and y = 27 
So , fraction x/y =  5/27

(a-b) = 1, (b-c) = 2 and (c-a) = 3 then the value of (a3 +b3 +c3 -3abc)/(a+b+c) is
  • a)
    5
  • b)
    6
  • c)
    7
  • d)
    8
Correct answer is option 'C'. Can you explain this answer?

Rhea Reddy answered
a3 + b3 + c3 - 3 a b c = ( a + b + c ) ( a2 + b2 + c2 - bc - ab - ac ) .
(a3 +b3 +c3 -3abc)/(a+b+c)
= 1/2[(a-b) 2+(b-c)2 +(c-a)2]
= ½(1+4+9)
= 14/2 = 7

a+b = c and abc = 30, then what is the value of a3 + b3 – c3 ?
  • a)
    60
  • b)
    90
  • c)
    -90
  • d)
    -60
Correct answer is option 'C'. Can you explain this answer?

Amal P answered
Given a+b =c 
also abc =  30, Now substitute c as a+b in ABC = 30

ab(a+b) = 30                                                                                                                         factorize 30, 30 can be (30 *1 ) or (15*2) or (6*5)

Iam taking 30 = 6 * 5  = ( 3 *2 ) (3 +2)  Compare with 
ab(a+b) = 30 


we can conclude a =3, b=2 and c= a+b = 2+3 =5

There fore 
 a^3 + b^3 – c^3 = 3^3 + 2^3 -5^3
                                                    
                                                               = 27 + 8 - 125 
      
                                                               = 35 - 125   = -90

When a number is multiplied by 13 and 13 is added to the product, the resultant is divisible by 5. Find the smallest product possible?
  • a)
    85
  • b)
    130
  • c)
    65
  • d)
    90
  • e)
    105
Correct answer is option 'C'. Can you explain this answer?

Alok Verma answered
13x + 13 which is divisible by 5, or 13(x+1) should be divisible by 5. The smallest value of x = 4 to be put here to make it divisible by 5. So the number is 13(4+1)

When all the students in a school are made to stand in row of 68, 40 such rows are formed.If the students are made to stand in the row of 20, how many such rows can be formed ?
  • a)
    85
  • b)
    136
  • c)
    129
  • d)
    97
  • e)
    None of these
Correct answer is option 'B'. Can you explain this answer?

Aarav Sharma answered
Given:
Number of students in each row = 68
Number of rows = 40

To find:
Number of rows when the students are made to stand in the row of 20

Solution:
Let the total number of students be N

Number of students in each row = 68
Number of rows = 40

So, N = 68 x 40 = 2720

Number of rows when the students are made to stand in the row of 20

Let the number of rows be n

Number of students in each row = 20

So, N = 20 x n

n = N/20 = 2720/20 = 136

Therefore, the number of rows that can be formed when the students are made to stand in the row of 20 is 136.

Hence, the correct option is (b) 136.

If the number 10*47* is divisible by both 5 and 11, then the missing digits are respectively
  • a)
    1 and 5
  • b)
    6 and 0
  • c)
    5 and 0
  • d)
    2 and 5
  • e)
    None of these
Correct answer is option 'A'. Can you explain this answer?

Cstoppers Instructors answered
Check the options in the number 10x47y
all numbers will be divisible by 5 because in end it is 5 and 0
for number to be divisible by 11, (y+4+0) – (7+x+1) should be divisible by 11
from option A, y = 5, x = 1 gives (y+4+0) – (7+x+1) as 0 which is divisible by 11

When a number is divided by 527 gives the remainder as 21. When the same number is divided by 17, the remainder will be?
  • a)
    2
  • b)
    3
  • c)
    4
  • d)
    7
  • e)
    None of these
Correct answer is option 'C'. Can you explain this answer?

Aarav Sharma answered
Solution:

Let the number be x.

When x is divided by 527, the remainder is 21.

So, x = 527k + 21, where k is a positive integer.

We need to find the remainder when x is divided by 17.

Let's try to express x in terms of 17.

527 can be written as 17 x 31.

So, x = (17 x 31 x k) + 21

We can write (17 x 31 x k) as 527k - 10k.

So, x = 527k - 10k + 21

Now, we can see that x leaves a remainder of 21 when divided by 17 if and only if 10k leaves a remainder of 4 when divided by 17.

Let's try to find such a value of k.

10k leaves a remainder of 4 when divided by 17 means: 10k = 17n + 4, where n is a positive integer.

Solving for k, we get:

k = (17n + 4)/10

We can see that k is an integer only when n leaves a remainder of 8 when divided by 10.

Let n = 10m + 8, where m is a positive integer.

Substituting in the above equation, we get:

k = (17 x (10m + 8) + 4)/10

Simplifying, we get:

k = 17m + 14

So, for any positive integer m, k leaves a remainder of 14 when divided by 17.

Substituting in the equation for x, we get:

x = 527k - 10k + 21

x = (527 - 10)k + 21

x = 517k + 21

x leaves a remainder of 4 when divided by 17.

Therefore, the correct answer is option C (4).

Chapter doubts & questions for Number System - Arithmetic Ability for DSSSB exams 2025 is part of DSSSB TGT/PGT/PRT exam preparation. The chapters have been prepared according to the DSSSB TGT/PGT/PRT exam syllabus. The Chapter doubts & questions, notes, tests & MCQs are made for DSSSB TGT/PGT/PRT 2025 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests here.

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