When 1 is added to the numerator of a fraction it becomes 1/4 and 1 is...
Let fraction = x/y
Then (x+1)/y = 1/4
And x/(y-1) = 1/5
Solve both equations, x = 3, y = 16
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When 1 is added to the numerator of a fraction it becomes 1/4 and 1 is...
Given Information:
- When 1 is added to the numerator of a fraction, it becomes 1/4.
- When 1 is subtracted from the denominator of that fraction, it becomes 1/5.
To Find: The fraction.
Solution:
Let's assume that the fraction is x/y.
According to the given information,
- (x+1)/y = 1/4 ...(1)
- x/(y-1) = 1/5 ...(2)
We need to find the value of x/y from these equations.
Let's solve equation (1) for x:
x+1 = y/4
x = y/4 - 1 ...(3)
Substitute equation (3) into equation (2) and solve for y:
(y/4 - 1)/(y-1) = 1/5
5(y/4 - 1) = y-1
5y/4 - 5 = y-1
4y - 20 = 5(y-1)
4y - 20 = 5y-5
y = 15 ...(4)
Now, substitute the value of y from equation (4) into equation (3) and solve for x:
x = 15/4 - 1
x = 11/4
Therefore, the fraction is 11/15.
Answer: The fraction is not given in the options. Hence, the correct answer is option 'E' - None of these.
When 1 is added to the numerator of a fraction it becomes 1/4 and 1 is...
When 1 is added in numerator of number 3/16 it becomes 4/16 it means 1/4 and when we subtract to denominator in 3/16 it becomes 3/15 it means 1/5 . So you solve these types of questions from gives answers because it takes less time and when you will going to create equation it will take too much time to solve