The sum of three consecutive multiple of 4 is 72 .What is the largest ...
4x+(4x+4)+(4x+8) = 72
12x+12 = 72
X=(72-12)/12
X=5
Largest number = 4(5)+8 = 20+8 = 28
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The sum of three consecutive multiple of 4 is 72 .What is the largest ...
4x+(4x+4)+(4x+8) = 72
12x+12 = 72
X=(72-12)/12
X=5
Largest number = 4(5)+8 = 20+8 = 28
The sum of three consecutive multiple of 4 is 72 .What is the largest ...
To find the largest number among three consecutive multiples of 4, we need to understand the concept of consecutive multiples and how to solve equations involving them.
Consecutive multiples refer to a series of numbers that are divisible by the same number and follow each other in sequence. In this case, we are looking for three consecutive multiples of 4.
Let's assume the first number in the series is x. Since we are dealing with multiples of 4, the next two numbers will be x + 4 and x + 8.
The sum of these three consecutive multiples is given as 72. So, we can write the equation as:
x + (x + 4) + (x + 8) = 72
Now, let's solve this equation step by step.
Step 1: Simplify the equation by combining like terms:
3x + 12 = 72
Step 2: Move the constant term to the right side of the equation by subtracting 12 from both sides:
3x = 60
Step 3: Divide both sides of the equation by 3 to isolate x:
x = 20
Therefore, the first number in the series is 20. The next two numbers are 20 + 4 = 24 and 20 + 8 = 28.
Conclusion: Among the three consecutive multiples of 4 (20, 24, and 28), the largest number is 28, which corresponds to option C.