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All questions of Time and Work for RRB NTPC/ASM/CA/TA Exam
Charlie and Alan run a race between points A and B, 5 km apart. Charlie starts at 9 a.m. from A at a speed of 5 km/hr, reaches B, and returns to A at the same speed. Alan starts at 9:45 a.m. from A at a speed of 10 km/hr, reaches B and comes back to A at the same speed. At what time do Charlie and Alan first meet each other?
- a)10 a.m.
- b)10:20 a.m.
- c)10:10 a.m
- d)10:30 a.m.
Correct answer is option 'C'. Can you explain this answer?
Charlie and Alan run a race between points A and B, 5 km apart. Charlie starts at 9 a.m. from A at a speed of 5 km/hr, reaches B, and returns to A at the same speed. Alan starts at 9:45 a.m. from A at a speed of 10 km/hr, reaches B and comes back to A at the same speed. At what time do Charlie and Alan first meet each other?
a)
10 a.m.
b)
10:20 a.m.
c)
10:10 a.m
d)
10:30 a.m.
|
|
Madhujya Chutia answered |
A can type 100 letters in 5 minutes. B and C typing together can type 50 letters in 2 minutes. If all of them working together then can type 90 letters in how many minutes?
- a)2 minutes
- b)4 minutes
- c)5 minutes
- d)10 minutes
- e)None
Correct answer is option 'A'. Can you explain this answer?
A can type 100 letters in 5 minutes. B and C typing together can type 50 letters in 2 minutes. If all of them working together then can type 90 letters in how many minutes?
a)
2 minutes
b)
4 minutes
c)
5 minutes
d)
10 minutes
e)
None
|
Aisha Gupta answered |
(1/5+1/4)
20/9*90/100 = 2
20/9*90/100 = 2
P can do a work in the same time in which Q and R together can do it. If P and Q work together, the work can be completed in 10 days. R alone needs 50 days to complete the same work. then Q alone can do it in
- a)30 days
- b)25 days
- c)20 days
- d)15 days
Correct answer is option 'B'. Can you explain this answer?
a)
30 days
b)
25 days
c)
20 days
d)
15 days
|
Future Foundation Institute answered |
Let distance between the two places = d km
Let total time taken by faster horse = t hr
⇒ Total time taken by slower horse = (t + 5) hr,
Let total time taken by faster horse = t hr
⇒ Total time taken by slower horse = (t + 5) hr,
Therefore,
speed of the faster horse = d/t km/hr
speed of the slower horse = d/(t + 5) km/hr
The two horses meet each other in 3 hour 20 min i.e. in 3(1/3) hr = 10/3 hr
In this time, total distance travelled by both the horses together is d.
speed of the faster horse = d/t km/hr
speed of the slower horse = d/(t + 5) km/hr
The two horses meet each other in 3 hour 20 min i.e. in 3(1/3) hr = 10/3 hr
In this time, total distance travelled by both the horses together is d.
∴ d/(t+5) * 10/3 + d/t * 10/3 = d
⇒ 10/(3(t+5)) + 10/3t = 1
⇒ 10t + 10(t+5) = 3t(t+5)
⇒ 20t + 50 = 3t2 + 15t
⇒ 3t2 − 5t − 50 = 0
⇒ 3t2 + 10t − 15t − 50 = 0
⇒ t(3t + 10) − 5(3t + 10) = 0
⇒ (3t + 10)(t − 5) = 0
⇒ t = 5 (ignoring -ve value)
⇒ 10/(3(t+5)) + 10/3t = 1
⇒ 10t + 10(t+5) = 3t(t+5)
⇒ 20t + 50 = 3t2 + 15t
⇒ 3t2 − 5t − 50 = 0
⇒ 3t2 + 10t − 15t − 50 = 0
⇒ t(3t + 10) − 5(3t + 10) = 0
⇒ (3t + 10)(t − 5) = 0
⇒ t = 5 (ignoring -ve value)
Thus, Total time taken by slower horse = 5 + 5 = 10 hr
So Option B is correct
Sheldon had to cover a distance of 60 km. However, he started 6 minutes later than his scheduled time and raced at a speed 1 km/h higher than his originally planned speed and reached the finish at the time he would reach it if he began to race strictly at the appointed time and raced with the assumed speed. Find the speed at which he travelled during the journey described.
- a)25 km/h
- b)10 km/h
- c)6 km/h
- d)15 km/h
Correct answer is option 'A'. Can you explain this answer?
Sheldon had to cover a distance of 60 km. However, he started 6 minutes later than his scheduled time and raced at a speed 1 km/h higher than his originally planned speed and reached the finish at the time he would reach it if he began to race strictly at the appointed time and raced with the assumed speed. Find the speed at which he travelled during the journey described.
a)
25 km/h
b)
10 km/h
c)
6 km/h
d)
15 km/h
|
Asf Institute answered |
Solve this question through options.
⇒ For instance, if he travelled at 25 km/h, his original speed would have been 24 km/h.
⇒ The time difference can be seen to be 6 minutes in this case = 60 / 24 – 60 / 25 = 0.1 hrs = 6 mins
⇒ For instance, if he travelled at 25 km/h, his original speed would have been 24 km/h.
⇒ The time difference can be seen to be 6 minutes in this case = 60 / 24 – 60 / 25 = 0.1 hrs = 6 mins
Thus, 25 km/h is the correct answer.
So Option A is correct
7 Indian and 4 American finish a job in 6 days. 7 African and 3 American finish the same job in 8 days. The efficiency of each person of a particular nationality is same but different from others. One Indian One American and One African will complete the work in:- a)10 days
- b)12 days
- c)24 days
- d)36 days
- e)None of these
Correct answer is option 'C'. Can you explain this answer?
7 Indian and 4 American finish a job in 6 days. 7 African and 3 American finish the same job in 8 days. The efficiency of each person of a particular nationality is same but different from others. One Indian One American and One African will complete the work in:
a)
10 days
b)
12 days
c)
24 days
d)
36 days
e)
None of these
|
|
Anaya Patel answered |
7I + 4Am = 1/6
7Af + 4Am = 1/8
7I + 7Af + 7Am = 7/24
1I + 1Af + 1Am = 1/24
One Indian One American and One African will complete the work in – 24 days.
7Af + 4Am = 1/8
7I + 7Af + 7Am = 7/24
1I + 1Af + 1Am = 1/24
One Indian One American and One African will complete the work in – 24 days.
A can do a piece of work in 21days. B is 50% more efficient than A. C is twice efficient than B. A started the work alone and worked for some days and left the work then B and C joined together and completed the work in 2 days. Then how many days does A worked alone?
- a)7 Days
- b)12 Days
- c)14 Days
- d)21 Days
- e)None
Correct answer is option 'B'. Can you explain this answer?
A can do a piece of work in 21days. B is 50% more efficient than A. C is twice efficient than B. A started the work alone and worked for some days and left the work then B and C joined together and completed the work in 2 days. Then how many days does A worked alone?
a)
7 Days
b)
12 Days
c)
14 Days
d)
21 Days
e)
None
|
Machine Experts answered |
A = 21 B = 14 C =7
x/21+2*(1/14+1/7) = 1
x = 12.
x/21+2*(1/14+1/7) = 1
x = 12.
P is able to do a piece of work in 15 days and Q can do the same work in 20 days. If they can work together for 4 days, what is the fraction of work left?- a)8/15
- b)7/15
- c)11/15
- d)2/11
Correct answer is option 'A'. Can you explain this answer?
a)
8/15
b)
7/15
c)
11/15
d)
2/11
|
Academic Studio answered |
Since P to R is double the distance of P to Q,
Therefore, it is evident that the time taken from P to R and back would be double the time taken from P to Q and back (i.e. double of 6.5 hours = 13 hours).
Therefore, it is evident that the time taken from P to R and back would be double the time taken from P to Q and back (i.e. double of 6.5 hours = 13 hours).
Since going from P to R takes 9 hours, coming back from R to P would take 4 hours i.e. 13- 9 = 4
So Option A is correct
Machine P can print one lakh books in 8 hours. Machine Q can print the same number of books in 10 hours while machine R can print the same in 12 hours. All the machines started printing at 9 A.M. Machine P is stopped at 11 A.M. and the remaining two machines complete work. Approximately at what time will the printing of one lakh books be completed?
- a)3 pm
- b)2 pm
- c)1:00 pm
- d)11 am
Correct answer is option 'C'. Can you explain this answer?
a)
3 pm
b)
2 pm
c)
1:00 pm
d)
11 am
|
Kiran Mehta answered |
Arun can do a piece of work in 40 days, but Bala can do the same work in 5 days less, than Arun, when working alone. Arun and Bala both started the work together but Bala left after some days and Arun finished the remaining work in 30 days with half of his efficiency but he did the work with Bala with his complete efficiency. For how many days they had worked together?- a)25/3 days
- b)31/3 days
- c)35/3 days
- d)38/3 days
- e)None of these
Correct answer is option 'C'. Can you explain this answer?
Arun can do a piece of work in 40 days, but Bala can do the same work in 5 days less, than Arun, when working alone. Arun and Bala both started the work together but Bala left after some days and Arun finished the remaining work in 30 days with half of his efficiency but he did the work with Bala with his complete efficiency. For how many days they had worked together?
a)
25/3 days
b)
31/3 days
c)
35/3 days
d)
38/3 days
e)
None of these
|
|
Anaya Patel answered |
1 day work of Arun and Bala = 1/40 + 1/35 = 15/280
Arun finished the remaining work in 30 days = 30 * 1/40 * 2 = 3/8
Remaining work done by Arun and Bala = 5/8
Worked together = (5/8)/(15/280) = 35/3 days.
Arun finished the remaining work in 30 days = 30 * 1/40 * 2 = 3/8
Remaining work done by Arun and Bala = 5/8
Worked together = (5/8)/(15/280) = 35/3 days.
6 men and 8 women can complete a work in 10 days. 26 men and 48 women can finish the same work in 2 days. 15 men and 20 women can do the same work in - days.
- a)4 days
- b)6 days
- c)2 days
- d)8 days
Correct answer is option 'A'. Can you explain this answer?
a)
4 days
b)
6 days
c)
2 days
d)
8 days
|
Vikas Choudhury answered |
Let work done by 1 man in 1 day = m and work done by 1 woman in 1 day = b
Work done by 6 men and 8 women in 1 day = 1/10
=> 6m + 8b = 1/10
=> 60m + 80b = 1 (1)
Work done by 26 men and 48 women in 1 day = 1/2
=> 26m + 48b =1/2
=> 52m + 96b = 1 (2)
Solving equation 1 and equation 2. We get m = 1/100 and b = 1/200
Work done by 15 men and 20 women in 1 day
= 15/100 + 20/200 =1/4
=> Time taken by 15 men and 20 women in doing the work = 4 days
The ratio of efficiency of Arun is to Chitra is 5:3. The ratio of number of days taken by Bala is to Chitra is 2:3. Arun takes 6 days less than Chitra, when Arun and Chitra complete the work individually. Bala and Chitra started the work and left after 2 days. The number of days taken by Arun to finish the remaining work is?- a)4 days
- b)5 days
- c)6 days
- d)9 days
- e)None of these
Correct answer is option 'C'. Can you explain this answer?
The ratio of efficiency of Arun is to Chitra is 5:3. The ratio of number of days taken by Bala is to Chitra is 2:3. Arun takes 6 days less than Chitra, when Arun and Chitra complete the work individually. Bala and Chitra started the work and left after 2 days. The number of days taken by Arun to finish the remaining work is?
a)
4 days
b)
5 days
c)
6 days
d)
9 days
e)
None of these
|
|
Anaya Patel answered |
Ratio of number of days = 9:10:15
Work done By B and C in first two days = 2*1/6 = 1/3
Rest of the work = 2/3
Number of days = (2/3)/(1/9) = 6 days
Work done By B and C in first two days = 2*1/6 = 1/3
Rest of the work = 2/3
Number of days = (2/3)/(1/9) = 6 days
A Contractor employed a certain number of workers to finish constructing a building in a certain scheduled time. Some time later, when a part of work had been completed, he realized that the work would get delayed by half of the scheduled time, so he at once doubled the no of workers and thus he managed to finish the building on the scheduled time. How much work he had been completed, before increasing the number of workers?- a)200/3%
- b)100/3%
- c)300/3%
- d)Can’t be determined
- e)None of these
Correct answer is option 'B'. Can you explain this answer?
A Contractor employed a certain number of workers to finish constructing a building in a certain scheduled time. Some time later, when a part of work had been completed, he realized that the work would get delayed by half of the scheduled time, so he at once doubled the no of workers and thus he managed to finish the building on the scheduled time. How much work he had been completed, before increasing the number of workers?
a)
200/3%
b)
100/3%
c)
300/3%
d)
Can’t be determined
e)
None of these
|
KS Coaching Center answered |
D * x +(100- D) * 2x= 150x
⇒ D = 50 days
work done in 50 days = 50x
Total work = 150x
50x/150x * 100 = 100/3
⇒ D = 50 days
work done in 50 days = 50x
Total work = 150x
50x/150x * 100 = 100/3
P can finish a work in 18 days. Q can finish the same work in 15 days. Q worked for 10 days and left the job. how many days does P alone need to finish the remaining work?
- a)8
- b)5
- c)4
- d)6
Correct answer is option 'D'. Can you explain this answer?
a)
8
b)
5
c)
4
d)
6
|
Spectrum Coaching Institute answered |
Initial distance = 25 dog leaps
Per-minute dog makes 5 dog leaps and cat makes 6 cat leaps = 3 dog leaps
⇒ Relative speed = 2 dog leaps / minutes
⇒ An initial distance of 25 dog leaps would get covered in 12.5 minutes.
Per-minute dog makes 5 dog leaps and cat makes 6 cat leaps = 3 dog leaps
⇒ Relative speed = 2 dog leaps / minutes
⇒ An initial distance of 25 dog leaps would get covered in 12.5 minutes.
So Option D is correct
Sekar, Pradeep and Sandeep can do a piece of work in 15 days. After all the three worked for 2 days, sekar left. Pradeep and Sandeep worked for 10 more days and Pradeep left. Sandeep worked for another 40 days and completed the work. In how many days can sekar alone complete the work if sandeep can complete it in 75 days?- a)25 days
- b)20 days
- c)30 days
- d)35 days
- e)15 days
Correct answer is option 'C'. Can you explain this answer?
Sekar, Pradeep and Sandeep can do a piece of work in 15 days. After all the three worked for 2 days, sekar left. Pradeep and Sandeep worked for 10 more days and Pradeep left. Sandeep worked for another 40 days and completed the work. In how many days can sekar alone complete the work if sandeep can complete it in 75 days?
a)
25 days
b)
20 days
c)
30 days
d)
35 days
e)
15 days
|
Bank Exams India answered |
Assume the total work to be 600 units. (LCM of all the numbers) Then Sandeep’s 1 day work = 8 units.
All three’s 1 day work = 40 units.All work together in the first 2 days
Work done in the first 2 days = 40 × 2 = 80 units
Sandeep alone works during the last 40 days
Work done in the last 40 days = 40 × 8 = 320 units
Remaining work = 600 – (320 + 80) = 200 units
This work is done by pradeep and sandeep in 10 days.
Pradeep and Sandeep together’s 1 day work = 20 units
Sekar’s 1 day work = All three 1 day work – Pradeep and Sandeep together’s 1 day
work = 40 units – 20 units = 20 units
Sekar can do the work of 600 units in 30 days.
All three’s 1 day work = 40 units.All work together in the first 2 days
Work done in the first 2 days = 40 × 2 = 80 units
Sandeep alone works during the last 40 days
Work done in the last 40 days = 40 × 8 = 320 units
Remaining work = 600 – (320 + 80) = 200 units
This work is done by pradeep and sandeep in 10 days.
Pradeep and Sandeep together’s 1 day work = 20 units
Sekar’s 1 day work = All three 1 day work – Pradeep and Sandeep together’s 1 day
work = 40 units – 20 units = 20 units
Sekar can do the work of 600 units in 30 days.
Arun can do a certain work in the same time in which Bipasha and Rahul together can do it. If Arun and Bipasha together could do it in 10 days and Rahul alone in 50 days, then Bipasha alone could do it in:- a)15 days
- b)20 days
- c)25 days
- d)30 days
- e)35 days
Correct answer is option 'C'. Can you explain this answer?
Arun can do a certain work in the same time in which Bipasha and Rahul together can do it. If Arun and Bipasha together could do it in 10 days and Rahul alone in 50 days, then Bipasha alone could do it in:
a)
15 days
b)
20 days
c)
25 days
d)
30 days
e)
35 days
|
|
Kavya Saxena answered |
Arun, Bipasha and rahul’s 1 day work = 1/10 + 1/50 = 6/50 = 3/25
Arun’s 1 day work = Bipasha + Rahul ‘s 1 day work
2*(Arun’s 1 day work) = 3/25
Arun’s 1 day work = 3/50
Bipasha’s 1 day work = 1/10 – 3/50 = 2/50 = 1/25
Arun’s 1 day work = Bipasha + Rahul ‘s 1 day work
2*(Arun’s 1 day work) = 3/25
Arun’s 1 day work = 3/50
Bipasha’s 1 day work = 1/10 – 3/50 = 2/50 = 1/25
Efficiency of A is 25% more then B and B takes 25 days to complete a piece of work. A started a work alone and then B joined her 5 days before actual completion of the work. For how many days A worked alone?- a)9
- b)11
- c)10
- d)25
- e)12
Correct answer is option 'B'. Can you explain this answer?
Efficiency of A is 25% more then B and B takes 25 days to complete a piece of work. A started a work alone and then B joined her 5 days before actual completion of the work. For how many days A worked alone?
a)
9
b)
11
c)
10
d)
25
e)
12
|
|
KS Coaching Center answered |
Efficiency (A : B) = 5 : 4
Number of days(A : B) = 4x : 5x = 4x : 25
∴ Number of days required by A to finish the work alone = 4x
= 4 x 5 = 20.
A and B work together for last 5 days = 5 x 9 = 45%
Efficiency of A = 5% and B’s efficiency = 4%
∴ No. of days taken by A to complete 55% work = 55/5 = 11days
Number of days(A : B) = 4x : 5x = 4x : 25
∴ Number of days required by A to finish the work alone = 4x
= 4 x 5 = 20.
A and B work together for last 5 days = 5 x 9 = 45%
Efficiency of A = 5% and B’s efficiency = 4%
∴ No. of days taken by A to complete 55% work = 55/5 = 11days
Chetan is thrice as efficient as Mamta and together they can finish a piece of work in 60 days. Mamta will take how many days to finish this work alone?- a)80
- b)160
- c)240
- d)320
Correct answer is option 'C'. Can you explain this answer?
Chetan is thrice as efficient as Mamta and together they can finish a piece of work in 60 days. Mamta will take how many days to finish this work alone?
a)
80
b)
160
c)
240
d)
320
|
Ritika Choudhury answered |
- Chetan is thrice as efficient as Mamta.
- Let, Mamta takes 3x days and Chetan takes x days to complete the work.
- ∴ 1/x + 1/3x = 1/60 ⇒ x = 80.
- ∴ Mamta will take 80 × 3 = 240 days to complete the work.
To complete a work, A takes 50% more time than B. If together they take 18 days to complete the work, how much time shall B take to do it?- a)30 days
- b)35 days
- c)40 days
- d)45 days
Correct answer is option 'A'. Can you explain this answer?
To complete a work, A takes 50% more time than B. If together they take 18 days to complete the work, how much time shall B take to do it?
a)
30 days
b)
35 days
c)
40 days
d)
45 days
|
Rajesh Khatri answered |
We have,
B = 3/2*A
→
A = 2/3*B
One day's work, (A+B) = 1/18
(2/3*B+B) = 1/18
5/3*B = 1/18
One day's work of B = 3/90
B alone can complete the work in,
= 90/3
= 30 days.
Sruthi, Swetha and Swati together can cut 216 Apples of the same size in 3 hours. Number of Apples cut by Sruthi in 9 hours is same as the number of Apples cut by Swati in 7 hours. In one hour, Swati can cut as many Apples more than Swetha as Swetha can cut more than Sruthi.Then the number of Apples cut by Swetha in one hour?
- a)21
- b)24
- c)27
- d)29
- e)None
Correct answer is option 'B'. Can you explain this answer?
Sruthi, Swetha and Swati together can cut 216 Apples of the same size in 3 hours. Number of Apples cut by Sruthi in 9 hours is same as the number of Apples cut by Swati in 7 hours. In one hour, Swati can cut as many Apples more than Swetha as Swetha can cut more than Sruthi.Then the number of Apples cut by Swetha in one hour?
a)
21
b)
24
c)
27
d)
29
e)
None
|
|
Aruna Singh answered |
Let's denote:
- Sruthi's efficiency as 'S' apples/hour
- Swetha's efficiency as 'W' apples/hour
- Swati's efficiency as 'T' apples/hour
Given information:
- S * 9 = T * 7 => S = (7/9)T
- T - W = W - S => T = 2W - S
Total work done in 3 hours:
- (S + W + T) * 3 = 216
- S + W + T = 72
Substituting S and T in terms of W:
- (7/9)T + W + 2W - (7/9)T = 72
- 3W = 72
- W = 24
Therefore, Swetha can cut 24 apples in one hour.
So, the correct answer is option B: 24.
Ramu, Hari and Sanjay are three typists, who working simultaneously, can type 228 pages in four hours. In one hour, Sanjay can type as many pages more than Hari as Hari can type more than Ramu. During a period of five hours, Sanjay can type as many passages as Ramu can, during seven hours. How many pages does each of them type per hour?- a)16, 18, 22
- b)14, 17, 20
- c)15, 17, 22
- d)15, 18, 21
- e)16, 19, 22
Correct answer is option 'E'. Can you explain this answer?
Ramu, Hari and Sanjay are three typists, who working simultaneously, can type 228 pages in four hours. In one hour, Sanjay can type as many pages more than Hari as Hari can type more than Ramu. During a period of five hours, Sanjay can type as many passages as Ramu can, during seven hours. How many pages does each of them type per hour?
a)
16, 18, 22
b)
14, 17, 20
c)
15, 17, 22
d)
15, 18, 21
e)
16, 19, 22
|
|
Future Foundation Institute answered |
Let Rohit, Harsh and Sanjeev can type x, y and z pages respectively in 1 h. Therefore, they together can type 4(x + y + z) pages in 4 h
∴ 4(x + y + z) = 228
⇒ x + y + z = 57 …..(i)
Also, z – y = y – x
i.e., 2y = x + z ……(ii)
5z = 7x ……(iii)
From Eqs. (i) and (ii), we get
3y = 57
⇒ y = 19
From Eq. (ii), x + z = 38
x = 16 and z = 22
∴ 4(x + y + z) = 228
⇒ x + y + z = 57 …..(i)
Also, z – y = y – x
i.e., 2y = x + z ……(ii)
5z = 7x ……(iii)
From Eqs. (i) and (ii), we get
3y = 57
⇒ y = 19
From Eq. (ii), x + z = 38
x = 16 and z = 22
Nakul and Ram are working on aproduction company. Nakul takes 6 hours to make 32 products, while Ram takes 5 hours to make 40 products. How much time will they take, working together to make 110 products?- a)8 hours
- b)8 hours 15 minutes
- c)9 hours
- d)8 hours 25 minutes
- e)9 hours 15 minutes
Correct answer is option 'B'. Can you explain this answer?
Nakul and Ram are working on aproduction company. Nakul takes 6 hours to make 32 products, while Ram takes 5 hours to make 40 products. How much time will they take, working together to make 110 products?
a)
8 hours
b)
8 hours 15 minutes
c)
9 hours
d)
8 hours 25 minutes
e)
9 hours 15 minutes
|
Pratibha Ekka answered |
B
Working together Bala and Chitra take 50% more number of days than Angel, Bala and Chitra together take and Angel and Bala working together, take 8/3 more number of days than Angel, Bala and Chitra take together. If Angel, Bala and Chitra all have worked together till the completion of the work and Bala has received Rs.120 out of total earnings of Rs. 480 then in how many days did Angel, Bala and Chitra together complete the whole work?- a)2 days
- b)4 days
- c)6 days
- d)8 days
- e)5 days
Correct answer is option 'E'. Can you explain this answer?
Working together Bala and Chitra take 50% more number of days than Angel, Bala and Chitra together take and Angel and Bala working together, take 8/3 more number of days than Angel, Bala and Chitra take together. If Angel, Bala and Chitra all have worked together till the completion of the work and Bala has received Rs.120 out of total earnings of Rs. 480 then in how many days did Angel, Bala and Chitra together complete the whole work?
a)
2 days
b)
4 days
c)
6 days
d)
8 days
e)
5 days
|
|
Future Foundation Institute answered |
The days ratio of (Angel + Bala + Chitra) : (Bala + Chitra) = X:3X/2 = 2X:3x;
Efficiency ratio = 3X:2X
Efficiency of Angel = x.
(480/3X) = Rs.160
Amount received by Bala = Rs.120 & Chitra = 200
160:120:200 =4:3:5
1/4:1/3:1/5= 15:20:12;
(1/15+1/12+1/20)*Y = 1
Y = 5 days
Efficiency ratio = 3X:2X
Efficiency of Angel = x.
(480/3X) = Rs.160
Amount received by Bala = Rs.120 & Chitra = 200
160:120:200 =4:3:5
1/4:1/3:1/5= 15:20:12;
(1/15+1/12+1/20)*Y = 1
Y = 5 days
A piece of work is to be completed in 100days, 11 Men are employed to do the work it is found that after 50 days only 1/3 rd work is completed. Now additionally how many more Men are to be employed to work to finish the work in time?- a)5
- b)6
- c)7
- d)11
- e)None
Correct answer is option 'D'. Can you explain this answer?
A piece of work is to be completed in 100days, 11 Men are employed to do the work it is found that after 50 days only 1/3 rd work is completed. Now additionally how many more Men are to be employed to work to finish the work in time?
a)
5
b)
6
c)
7
d)
11
e)
None
|
|
Bank Exams India answered |
11*50/1/3 = (11+x)*50/2/3
X = 11
X = 11
(x-2) person can do a work in x days and (x+7) person can do 75% of the same work in (x-10)days. Then in how many days can (x+10) person finish the work?- a)27 days
- b)12 days
- c)25 days
- d)18 days
- e)None of these
Correct answer is option 'B'. Can you explain this answer?
(x-2) person can do a work in x days and (x+7) person can do 75% of the same work in (x-10)days. Then in how many days can (x+10) person finish the work?
a)
27 days
b)
12 days
c)
25 days
d)
18 days
e)
None of these
|
|
Aisha Gupta answered |
3/4 * (x-2)x = (x+7)(x-10)
x – 6x – 280 = 0
x = 20; x = -14
(x-2)x = 18 * 20 = 360
360 = 30 * y
y = 12 days
x – 6x – 280 = 0
x = 20; x = -14
(x-2)x = 18 * 20 = 360
360 = 30 * y
y = 12 days
When Ashok and Karthik are working alone, they can complete a piece of work in 25 days and 30 days respectively. On day 1, Karthik started the work and Ashok joined B from day 3 on-wards. Find approximately after how many days will the work be completed?- a)20 days
- b)10 days
- c)15 days
- d)25 days
- e)30 days
Correct answer is option 'C'. Can you explain this answer?
When Ashok and Karthik are working alone, they can complete a piece of work in 25 days and 30 days respectively. On day 1, Karthik started the work and Ashok joined B from day 3 on-wards. Find approximately after how many days will the work be completed?
a)
20 days
b)
10 days
c)
15 days
d)
25 days
e)
30 days
|
|
Aisha Gupta answered |
Fraction of work completed by Karthik on day 1 and day 2 = 2* 1/30 = 1/15
Fraction of work left after 2 days = 14/15
Fraction of work completed by Both = 1/25 + 1/30 = 11/150
Number of days after day 2 to complete work = 14*150/15*11 = 13 days
So after 2+13 = 15 days works will be completed
Fraction of work left after 2 days = 14/15
Fraction of work completed by Both = 1/25 + 1/30 = 11/150
Number of days after day 2 to complete work = 14*150/15*11 = 13 days
So after 2+13 = 15 days works will be completed
Angel can do a piece of work in 10 days, Balu in 15 days. They work together for 5 days, the rest of the work is finished by Chitra in two more days. If they get Rs. 6000 as wages for the whole work, what are the daily wages of Angel, Bala and Chitra respectively?- a)200, 250, 300
- b)300, 200, 250
- c)600, 400, 200
- d)600, 400, 500
- e)None of these
Correct answer is option 'D'. Can you explain this answer?
Angel can do a piece of work in 10 days, Balu in 15 days. They work together for 5 days, the rest of the work is finished by Chitra in two more days. If they get Rs. 6000 as wages for the whole work, what are the daily wages of Angel, Bala and Chitra respectively?
a)
200, 250, 300
b)
300, 200, 250
c)
600, 400, 200
d)
600, 400, 500
e)
None of these
|
|
Bank Exams India answered |
Angel’s 5 days work = 50%
Balu’s 5 days work = 33.33%
Chitra’s 2 days work = 16.66%
[100- (50+33.33)]
Ratio of work of Angel, Balu and Chitra = 3: 2: 1
Angel’s total share = Rs. 3000
Balu’s total share = Rs. 2000
Chitra’s total share = Rs. 1000
Angel’s one day’s wage = Rs.600
Balu’s one day’s wage = Rs.400
Chitra’s one day’s wage = Rs.500
Balu’s 5 days work = 33.33%
Chitra’s 2 days work = 16.66%
[100- (50+33.33)]
Ratio of work of Angel, Balu and Chitra = 3: 2: 1
Angel’s total share = Rs. 3000
Balu’s total share = Rs. 2000
Chitra’s total share = Rs. 1000
Angel’s one day’s wage = Rs.600
Balu’s one day’s wage = Rs.400
Chitra’s one day’s wage = Rs.500
A can do a piece of work in 60days working 14 hours. B has the same efficiency as of A. A and B started working together. A works 5,6,7 and 8 hours respectively on first four days and repeats the cycle again. Then B has to work how many hours daily if they together completed the work in 80 days?
- a)1 Hour
- b)2 Hours
- c)3 Hours
- d)4 Hours
- e)None of these
Correct answer is option 'D'. Can you explain this answer?
A can do a piece of work in 60days working 14 hours. B has the same efficiency as of A. A and B started working together. A works 5,6,7 and 8 hours respectively on first four days and repeats the cycle again. Then B has to work how many hours daily if they together completed the work in 80 days?
a)
1 Hour
b)
2 Hours
c)
3 Hours
d)
4 Hours
e)
None of these
|
Arya Roy answered |
Ravi can do a piece of work in 16 days. Rakesh can do the same work in 64/5 days, while Geeta can do it in 32 days. All of them started to work together but Ravi leaves after 4 days. Rakesh leaves the job 3 days before the completion of the work. How long would the work last?- a)6 days
- b)9 days
- c)18 days
- d)5 days
- e)None of these
Correct answer is option 'B'. Can you explain this answer?
Ravi can do a piece of work in 16 days. Rakesh can do the same work in 64/5 days, while Geeta can do it in 32 days. All of them started to work together but Ravi leaves after 4 days. Rakesh leaves the job 3 days before the completion of the work. How long would the work last?
a)
6 days
b)
9 days
c)
18 days
d)
5 days
e)
None of these
|
|
Kavya Saxena answered |
Let the work lasted for x days,
Ravi’s 4 day’s work + Rakesh (x – 3) day’s work + Geeta’s x day’s work = 1
⇒ (4/16) + (x – 3) / (64/5) + x/32 = 1
⇒ 5(x – 3)/64 + x/32 = 1 – 1/4
⇒ [5(x – 3) + 2x] / 64 = 3/4
⇒ 7x – 15 = 48
∴ x = (48 + 15)/7 = 63/7 = 9 days
Ravi’s 4 day’s work + Rakesh (x – 3) day’s work + Geeta’s x day’s work = 1
⇒ (4/16) + (x – 3) / (64/5) + x/32 = 1
⇒ 5(x – 3)/64 + x/32 = 1 – 1/4
⇒ [5(x – 3) + 2x] / 64 = 3/4
⇒ 7x – 15 = 48
∴ x = (48 + 15)/7 = 63/7 = 9 days
Madhavan can finish a work in 5 hours. He invites Manohar and Manjima who can work 3/4th as fast as he can to join him. He also invites Mani and Mohan who can work only 1/5th as fast as he can to join him. If the five person team works the same job and they start together, how long will it take for them to finish the job?- a)50/97 days
- b)87 days
- c)50/29 days
- d)78 days
- e)62 days
Correct answer is option 'C'. Can you explain this answer?
Madhavan can finish a work in 5 hours. He invites Manohar and Manjima who can work 3/4th as fast as he can to join him. He also invites Mani and Mohan who can work only 1/5th as fast as he can to join him. If the five person team works the same job and they start together, how long will it take for them to finish the job?
a)
50/97 days
b)
87 days
c)
50/29 days
d)
78 days
e)
62 days
|
|
Anaya Patel answered |
Let the work be 100 units.
Madhavan’s 1 hour work = 100/5 = 20 units
Manohar and Manjima’s 1 day work = 3/4 × 20 = 15 units.
Mohan and Mani’s 1 day work = 1/5 × 20 = 4 units.
In one day all five of them can do = 20 + 15 + 15 + 4 + 4 = 58 units of work. Hence they can complete the work in 100/58 days.
Madhavan’s 1 hour work = 100/5 = 20 units
Manohar and Manjima’s 1 day work = 3/4 × 20 = 15 units.
Mohan and Mani’s 1 day work = 1/5 × 20 = 4 units.
In one day all five of them can do = 20 + 15 + 15 + 4 + 4 = 58 units of work. Hence they can complete the work in 100/58 days.
X can do a piece of work in 20 days. He worked at it for 5 days and then Y finished it in 15 days. In how many days can X and Y together finish the work?- a)12 days
- b)15 days
- c)10 days
- d)5 days
Correct answer is option 'C'. Can you explain this answer?
X can do a piece of work in 20 days. He worked at it for 5 days and then Y finished it in 15 days. In how many days can X and Y together finish the work?
a)
12 days
b)
15 days
c)
10 days
d)
5 days
|
|
Rahul Mehta answered |
- X’s five day work = 5/20 = 1/4. Remaining work = 1 – 1/4 = 3/4.
- This work was done by Y in 15 days. Y does 3/4th of the work in 15 days, he will finish the work in 15 × 4/3 = 20 days.
- X & Y together would take 1/20 + 1/20 = 2/20 = 1/10 i.e. 10 days to complete the work.
A building contractor undertook to finish a certain work in 162 days and employed 150 men. After 72 days, he found that he had already done 2/3 of the work. How many men can be discharged now, so that the work finish in time?- a)80
- b)75
- c)90
- d)70
- e)65
Correct answer is option 'C'. Can you explain this answer?
A building contractor undertook to finish a certain work in 162 days and employed 150 men. After 72 days, he found that he had already done 2/3 of the work. How many men can be discharged now, so that the work finish in time?
a)
80
b)
75
c)
90
d)
70
e)
65
|
|
Rajeev Kumar answered |
M1 = 150, M2 = 150 – n, D1 = 72, D2 = 90
W1= 2/3 and W2 = 1/3
According to the formula,
(M1D1) / W1 = (M2D2) / W2
⇒ [150 x 72] / 2 = [(150 – n) x 90] / 1
⇒ (150 x 72) / (2 x 60) = (150 – n)
⇒ (150 – n) = 60
∴ n = 150 – 60 = 90
W1= 2/3 and W2 = 1/3
According to the formula,
(M1D1) / W1 = (M2D2) / W2
⇒ [150 x 72] / 2 = [(150 – n) x 90] / 1
⇒ (150 x 72) / (2 x 60) = (150 – n)
⇒ (150 – n) = 60
∴ n = 150 – 60 = 90
Gopal does a work in 90 days, Vikash in 40 days and Santhosh in 12 days. They work one after another for a day each, starting with Gopal followed by Vikash and then by Santhosh. If the total wages received are Rs 360 and Gopal, Vikash, Santhosh share them in the ratio of the work done, find their respective individual wages.- a)Rs 44, Rs 80 and Rs 264
- b)Rs 40, Rs 87 and Rs 276
- c)Rs 36, Rs 81 and Rs 243
- d)Rs 42, Rs 86 and Rs 232
- e)Rs 37, Rs 89 and Rs 284
Correct answer is option 'C'. Can you explain this answer?
Gopal does a work in 90 days, Vikash in 40 days and Santhosh in 12 days. They work one after another for a day each, starting with Gopal followed by Vikash and then by Santhosh. If the total wages received are Rs 360 and Gopal, Vikash, Santhosh share them in the ratio of the work done, find their respective individual wages.
a)
Rs 44, Rs 80 and Rs 264
b)
Rs 40, Rs 87 and Rs 276
c)
Rs 36, Rs 81 and Rs 243
d)
Rs 42, Rs 86 and Rs 232
e)
Rs 37, Rs 89 and Rs 284
|
|
Rajeev Kumar answered |
Assume there are 360 units of work (LCM of 90, 40 and 12).
Hence, they can do 4,9 and 30 units per day or together 43 units every 3 days.
So In 24 days, 43×8=344 units of work is completed.
In the next 2 days, 13 unitsare completed and on 27th day,Santhosh takes 1/10 thof a day to finish the rest.
So, gopal and vikash worked for 9 days each and have hence put in 36 and 81 units respectively, and the rest of the 243 units is put in by santhosh.
The wages shall also be distributed in the same ratio as: Rs 36, Rs 81 and Rs 243.
Hence, they can do 4,9 and 30 units per day or together 43 units every 3 days.
So In 24 days, 43×8=344 units of work is completed.
In the next 2 days, 13 unitsare completed and on 27th day,Santhosh takes 1/10 thof a day to finish the rest.
So, gopal and vikash worked for 9 days each and have hence put in 36 and 81 units respectively, and the rest of the 243 units is put in by santhosh.
The wages shall also be distributed in the same ratio as: Rs 36, Rs 81 and Rs 243.
A, B and C together can complete a work in 8 days. If A is 50% more efficient than B and B is 50% less efficient than C, then B alone will complete the same work in:- a)16 days
- b)24 days
- c)48 days
- d)36 days
- e)None of these
Correct answer is option 'D'. Can you explain this answer?
A, B and C together can complete a work in 8 days. If A is 50% more efficient than B and B is 50% less efficient than C, then B alone will complete the same work in:
a)
16 days
b)
24 days
c)
48 days
d)
36 days
e)
None of these
|
Mihir Chawla answered |
Solution:
Let's assume that C can complete the work in x days.
Efficiency of B compared to C:
B is 50% less efficient than C. This means B can complete only half the work that C can complete in the same time. So, B can complete the work in 2x days.
Efficiency of A compared to B:
A is 50% more efficient than B. This means A can complete 1.5 times the work that B can complete in the same time. So, A can complete the work in (2x/1.5) days.
Efficiency of A, B, and C together:
Given that A, B, and C together can complete the work in 8 days. So, their combined efficiency is 1/8 of the work per day.
Let's calculate their combined efficiency:
1/A + 1/B + 1/C = 1/8
Substituting the values of A, B, and C:
1/(2x/1.5) + 1/2x + 1/x = 1/8
Taking the LCM and simplifying the equation:
[(1.5 + 3 + 4)/2x] = 1/8
8/2x = 1/8
2x = 64
x = 32
So, C alone can complete the work in 32 days.
Now, let's find out how many days B alone will take to complete the work:
B can complete the work in 2x days.
Substituting the value of x:
B can complete the work in 2(32) = 64 days.
Therefore, the correct answer is option D) 36 days.
Let's assume that C can complete the work in x days.
Efficiency of B compared to C:
B is 50% less efficient than C. This means B can complete only half the work that C can complete in the same time. So, B can complete the work in 2x days.
Efficiency of A compared to B:
A is 50% more efficient than B. This means A can complete 1.5 times the work that B can complete in the same time. So, A can complete the work in (2x/1.5) days.
Efficiency of A, B, and C together:
Given that A, B, and C together can complete the work in 8 days. So, their combined efficiency is 1/8 of the work per day.
Let's calculate their combined efficiency:
1/A + 1/B + 1/C = 1/8
Substituting the values of A, B, and C:
1/(2x/1.5) + 1/2x + 1/x = 1/8
Taking the LCM and simplifying the equation:
[(1.5 + 3 + 4)/2x] = 1/8
8/2x = 1/8
2x = 64
x = 32
So, C alone can complete the work in 32 days.
Now, let's find out how many days B alone will take to complete the work:
B can complete the work in 2x days.
Substituting the value of x:
B can complete the work in 2(32) = 64 days.
Therefore, the correct answer is option D) 36 days.
Ramu completes 30% of work in 7.5 days. Raju is 50% as efficient as Ramu, Venu is 50% as efficient as Raju. Now Raju and Venu joined with Ramu for the rest of the work then in how many days will take to complete the work?- a)9 Days
- b)10 Days
- c)12 Days
- d)15 Days
- e)None of these
Correct answer is option 'B'. Can you explain this answer?
Ramu completes 30% of work in 7.5 days. Raju is 50% as efficient as Ramu, Venu is 50% as efficient as Raju. Now Raju and Venu joined with Ramu for the rest of the work then in how many days will take to complete the work?
a)
9 Days
b)
10 Days
c)
12 Days
d)
15 Days
e)
None of these
|
|
Arya Roy answered |
Ramu takes 25 days to complete work.
Raju = 50 days Venu = 100 days
Now 70% work is left
They can complete whole work in = 1/ 1/25+1/50+1/100
100/7 days then 70% in 10 days
Arun can do a piece of work in 10 days, Bala in 15 days. They work together for 5 days, the rest of the work is finished by Chitra in two more days. If they get Rs.3000 as wages for the whole work, what are the daily wages of Arun, Bala and Chitra respectively (in Rs)?
- a)300, 200, 250
- b)200, 300, 400
- c)500, 300, 400
- d)600, 500, 300
- e)400, 300, 200
Correct answer is option 'A'. Can you explain this answer?
Arun can do a piece of work in 10 days, Bala in 15 days. They work together for 5 days, the rest of the work is finished by Chitra in two more days. If they get Rs.3000 as wages for the whole work, what are the daily wages of Arun, Bala and Chitra respectively (in Rs)?
a)
300, 200, 250
b)
200, 300, 400
c)
500, 300, 400
d)
600, 500, 300
e)
400, 300, 200
|
Arshiya Mehta answered |
Correct Answer is A.
A can do a piece of work in 40 days B can do the same piece of work in 60 days. A and B started the work together in the first 15 days A worked with 50% of his efficiency, in the next 15days B worked with 50% of his efficiency. Now in how many days does the remaining work will be completed if both of them work with their full efficiencies?- a)1 Day
- b)1.5 Days
- c)2 Days
- d)2.5 Days
- e)None
Correct answer is option 'B'. Can you explain this answer?
A can do a piece of work in 40 days B can do the same piece of work in 60 days. A and B started the work together in the first 15 days A worked with 50% of his efficiency, in the next 15days B worked with 50% of his efficiency. Now in how many days does the remaining work will be completed if both of them work with their full efficiencies?
a)
1 Day
b)
1.5 Days
c)
2 Days
d)
2.5 Days
e)
None
|
|
Aarav Sharma answered |
Given:
A can do the work in 40 days
B can do the work in 60 days
In the first 15 days, A worked with 50% of his efficiency
In the next 15 days, B worked with 50% of his efficiency
To find:
In how many days will the remaining work be completed if both of them work with their full efficiencies?
Solution:
Let the total work be 120 units (LCM of 40 and 60)
A's 1-day work = 3 units (120/40)
B's 1-day work = 2 units (120/60)
In the first 15 days,
A's work = (15 days) × (1/2) × (3 units/day) = 22.5 units
Remaining work = 120 units - 22.5 units = 97.5 units
In the next 15 days,
B's work = (15 days) × (1/2) × (2 units/day) = 15 units
Total work done in 30 days = 22.5 units + 15 units = 37.5 units
Remaining work = 120 units - 37.5 units = 82.5 units
Let the number of days required to complete the remaining work be x.
A and B work together for x days to complete the remaining work.
∴ A's work in x days + B's work in x days = 82.5 units
⇒ x × (3 units/day) × (100/100) + x × (2 units/day) × (100/100) = 82.5 units
⇒ 5x = 82.5
⇒ x = 16.5 days
Therefore, the remaining work will be completed in 16.5 days.
But we need to find the total number of days taken to complete the entire work.
Total number of days = 15 days + 15 days + 16.5 days = 46.5 days
Hence, the correct option is (b) 1.5 Days.
A can do the work in 40 days
B can do the work in 60 days
In the first 15 days, A worked with 50% of his efficiency
In the next 15 days, B worked with 50% of his efficiency
To find:
In how many days will the remaining work be completed if both of them work with their full efficiencies?
Solution:
Let the total work be 120 units (LCM of 40 and 60)
A's 1-day work = 3 units (120/40)
B's 1-day work = 2 units (120/60)
In the first 15 days,
A's work = (15 days) × (1/2) × (3 units/day) = 22.5 units
Remaining work = 120 units - 22.5 units = 97.5 units
In the next 15 days,
B's work = (15 days) × (1/2) × (2 units/day) = 15 units
Total work done in 30 days = 22.5 units + 15 units = 37.5 units
Remaining work = 120 units - 37.5 units = 82.5 units
Let the number of days required to complete the remaining work be x.
A and B work together for x days to complete the remaining work.
∴ A's work in x days + B's work in x days = 82.5 units
⇒ x × (3 units/day) × (100/100) + x × (2 units/day) × (100/100) = 82.5 units
⇒ 5x = 82.5
⇒ x = 16.5 days
Therefore, the remaining work will be completed in 16.5 days.
But we need to find the total number of days taken to complete the entire work.
Total number of days = 15 days + 15 days + 16.5 days = 46.5 days
Hence, the correct option is (b) 1.5 Days.
Arun is twice efficient as Bala and together they do the same work in as much time as Chitra and David together. If Chitra and David can complete the work in 20 and 30 days respectively, working alone, then in how many days A can complete the work individually?- a)12 days
- b)18 days
- c)24 days
- d)30 days
- e)None of these
Correct answer is option 'B'. Can you explain this answer?
Arun is twice efficient as Bala and together they do the same work in as much time as Chitra and David together. If Chitra and David can complete the work in 20 and 30 days respectively, working alone, then in how many days A can complete the work individually?
a)
12 days
b)
18 days
c)
24 days
d)
30 days
e)
None of these
|
|
Kavya Saxena answered |
1/x + 1/2x = 1/20 + 1/30
3/2x = 1/12
Number of days taken by Arun = 18 days
3/2x = 1/12
Number of days taken by Arun = 18 days
Kiran can do a work in 20 days, while Karan can do the same work in 25 days. They started the work jointly. Few days later Suman also joined them and thus all of them completed the whole work in 10 days. All of them were paid total Rs.1000. What is the share of Suman?- a)200
- b)400
- c)100
- d)300
- e)500
Correct answer is option 'C'. Can you explain this answer?
Kiran can do a work in 20 days, while Karan can do the same work in 25 days. They started the work jointly. Few days later Suman also joined them and thus all of them completed the whole work in 10 days. All of them were paid total Rs.1000. What is the share of Suman?
a)
200
b)
400
c)
100
d)
300
e)
500
|
|
Aarav Sharma answered |
Efficiency of Kiran = 5%
Efficiency of Karan = 4%
They will complete only 90% of the work = [(5+4)*10] = 90
Remaining work done by Suman = 10%.
Share of Suman = 10/100 * 1000 = 100
Efficiency of Karan = 4%
They will complete only 90% of the work = [(5+4)*10] = 90
Remaining work done by Suman = 10%.
Share of Suman = 10/100 * 1000 = 100
Hari and Vijay can together finish a work in 30 days. They worked together for 20 days and then Vijay left. After another 20 days, hari finished the remaining work. In how many days hari alone can finish the work?- a)45
- b)60
- c)35
- d)50
- e)65
Correct answer is option 'B'. Can you explain this answer?
Hari and Vijay can together finish a work in 30 days. They worked together for 20 days and then Vijay left. After another 20 days, hari finished the remaining work. In how many days hari alone can finish the work?
a)
45
b)
60
c)
35
d)
50
e)
65
|
Yash Patel answered |
Hari + vijay 20 days work = 1/30 *20 = 2/3
Remaining work = 1/3
1/3 work in 20 days so whole work in 60 days.
Remaining work = 1/3
1/3 work in 20 days so whole work in 60 days.
In a cucumber factory, there are equal number of women and children. Women work for 8 h a day and children for 6 h a day. During festival time, the work load goes up by 50%. The government rule does not allow children to work for more than 8 h a day. If they are equally efficient and the extra work is done by women, then extra hours of work put in by women every day are?- a)5
- b)3
- c)4
- d)9
- e)None of these
Correct answer is option 'A'. Can you explain this answer?
In a cucumber factory, there are equal number of women and children. Women work for 8 h a day and children for 6 h a day. During festival time, the work load goes up by 50%. The government rule does not allow children to work for more than 8 h a day. If they are equally efficient and the extra work is done by women, then extra hours of work put in by women every day are?
a)
5
b)
3
c)
4
d)
9
e)
None of these
|
|
Rajeev Kumar answered |
Let extra hours a day are x.
According to the formula,
(M1D1T1) / W1 = (M2D2T2) / W2
⇒ [1 x 1 x (8 + 6)] / 1 = [1 x 1 x (8 + 8 + x)] / 3/2
⇒ (3/2) x 14 = 16 + x
⇒ 21= 16 + x
∴ x = 21 – 16 = 5
According to the formula,
(M1D1T1) / W1 = (M2D2T2) / W2
⇒ [1 x 1 x (8 + 6)] / 1 = [1 x 1 x (8 + 8 + x)] / 3/2
⇒ (3/2) x 14 = 16 + x
⇒ 21= 16 + x
∴ x = 21 – 16 = 5
Kiran can do a work in 25 days, while Ravi can do the same work in 50 days. They started the work jointly. Few days later Sumit also joined them and thus all of them completed the whole work in 10 days. All of them were paid total Rs.600. What is the Share of Sumit?- a)Rs.360
- b)Rs.385
- c)Rs.240
- d)can’t be determined
- e)None of these
Correct answer is option 'C'. Can you explain this answer?
Kiran can do a work in 25 days, while Ravi can do the same work in 50 days. They started the work jointly. Few days later Sumit also joined them and thus all of them completed the whole work in 10 days. All of them were paid total Rs.600. What is the Share of Sumit?
a)
Rs.360
b)
Rs.385
c)
Rs.240
d)
can’t be determined
e)
None of these
|
|
Aarav Sharma answered |
Not be determined
Kiran's one day work=1/25
Ravi's one day work=1/50
Let Sumit's one day work=x
Together their one day work=(1/25)+(1/50)+x=3/50+x
In 10 days, their total work=10*(3/50+x)=3/5+10x
As they completed the whole work, we can equate it to 1.
3/5+10x=1
10x=2/5
x=1/25
So, Sumit's one day work=1/25
Therefore, his share= (1/25)*(10 days)*(Rs.600 total payment)=Rs.240
Hence, the answer is (c) Rs.240.
Kiran's one day work=1/25
Ravi's one day work=1/50
Let Sumit's one day work=x
Together their one day work=(1/25)+(1/50)+x=3/50+x
In 10 days, their total work=10*(3/50+x)=3/5+10x
As they completed the whole work, we can equate it to 1.
3/5+10x=1
10x=2/5
x=1/25
So, Sumit's one day work=1/25
Therefore, his share= (1/25)*(10 days)*(Rs.600 total payment)=Rs.240
Hence, the answer is (c) Rs.240.
Two pipes, when working one at a time, can fill a cistern in 3 hours and 4 hours, respectively while a third pipe can drain the cistern empty in 8 hours. All the three pipes were opened together when the cistern was 1/12 full. How long did it take for the cistern to be completely full?- a)2 hours
- b)1 hour 45 minutes
- c)2 hour 11 minutes
- d)2 hour 10 minutes
Correct answer is option 'A'. Can you explain this answer?
Two pipes, when working one at a time, can fill a cistern in 3 hours and 4 hours, respectively while a third pipe can drain the cistern empty in 8 hours. All the three pipes were opened together when the cistern was 1/12 full. How long did it take for the cistern to be completely full?
a)
2 hours
b)
1 hour 45 minutes
c)
2 hour 11 minutes
d)
2 hour 10 minutes
|
EduRev CLAT answered |
Let the total amount of work in filling a cistern be 24 units. (LCM of 3, 4 and 8)
Work done by pipe 1 in 1 hour = 24/3 = 8 units.
Work done by pipe 2 in 1 hour = 24/4 = 6 units.
Work done by pipe 3 in 1 hour = 24/ (-8) = -3 units
Total work done in 1 hour = 8 + 6 – 3 = 11 units
The time required to complete 11/12th of the work = 11/12 × 24/ 11 = 2 hours
∴ The correct answer is 2 hours.
Chitra is twice efficient as Arun. Bala takes thrice as many days as Chitra. Arun takes 12 days to finish the work alone. If they work in pairs(i.e Arun-Bala, BalaChitra, Chitra-Arun) starting with Arun – Bala on the first day, Bala – Chitra on the second day and Chitra – Arun on the third day and so on, then how many days are required to finish the work?- a)26/9 days
- b)46/9 days
- c)16/9 days
- d)56/9 days
- e)None of these
Correct answer is option 'B'. Can you explain this answer?
Chitra is twice efficient as Arun. Bala takes thrice as many days as Chitra. Arun takes 12 days to finish the work alone. If they work in pairs(i.e Arun-Bala, BalaChitra, Chitra-Arun) starting with Arun – Bala on the first day, Bala – Chitra on the second day and Chitra – Arun on the third day and so on, then how many days are required to finish the work?
a)
26/9 days
b)
46/9 days
c)
16/9 days
d)
56/9 days
e)
None of these
|
Faizan Khan answered |
No of days taken by Arun = 12 days
No of days(Arun:Bala:Chitra) = 2:3:1
1 day work of (Arun+Bala) = 5/36
1 day work of (Bala+Chitra) = 8/36
1 day work of (Chitra+Arun) = 9/36
5 days total work – 35/36
1/36 is done by Arun-Chitra
Number of days taken by Arun-Chitra for the rest of the work = (1/36)/(9/36) = 1/9
Total time taken to complete the work = 5 + 1/9 = 46/9 days
No of days(Arun:Bala:Chitra) = 2:3:1
1 day work of (Arun+Bala) = 5/36
1 day work of (Bala+Chitra) = 8/36
1 day work of (Chitra+Arun) = 9/36
5 days total work – 35/36
1/36 is done by Arun-Chitra
Number of days taken by Arun-Chitra for the rest of the work = (1/36)/(9/36) = 1/9
Total time taken to complete the work = 5 + 1/9 = 46/9 days
Sanjay can do a piece of work in 50 days. He started the work and left after some days, when 25% work was done. After it Ajit joined and completed it working for 25 days. In how many days Sanjay and Ajit can do the complete work, working together?- a)6
- b)8
- c)10
- d)12
- e)20
Correct answer is option 'E'. Can you explain this answer?
Sanjay can do a piece of work in 50 days. He started the work and left after some days, when 25% work was done. After it Ajit joined and completed it working for 25 days. In how many days Sanjay and Ajit can do the complete work, working together?
a)
6
b)
8
c)
10
d)
12
e)
20
|
Nikita Singh answered |
Efficiency of Sanjay = (100/50) = 2%
Rest work = 75%
∴ Efficiency of Ajit = 75/25 = 3%
∴ Combined efficiency of Sanjay and Ajit = 5%
∴ Number of days required by Sonu and Abhijeet, to work together = 100/5 = 20 days.
Rest work = 75%
∴ Efficiency of Ajit = 75/25 = 3%
∴ Combined efficiency of Sanjay and Ajit = 5%
∴ Number of days required by Sonu and Abhijeet, to work together = 100/5 = 20 days.
If A and B together can complete a piece of work in 15 days and B alone in 20 days, in how many days can A alone complete the work?- a)60
- b)45
- c)40
- d)30
Correct answer is option 'A'. Can you explain this answer?
If A and B together can complete a piece of work in 15 days and B alone in 20 days, in how many days can A alone complete the work?
a)
60
b)
45
c)
40
d)
30
|
|
Rahul Mehta answered |
1st method:
A and B complete a work in = 15 days
One day's work of (A + B) = 1/ 15
A and B complete a work in = 15 days
One day's work of (A + B) = 1/ 15
B complete the work in = 20 days;
One day's work of B = 1/20
One day's work of B = 1/20
Then, A's one day's work
=1/15−1/20
=(4−3)/6
=1/60
=(4−3)/6
=1/60
Thus, A can complete the work in = 60 days.
Two sprinters run the same race of100 m One runs at a speed of 10 m/s and the other runs at 8 m/s. By what time will the first sprinter beat the other sprinter?- a)1.5 sec
- b)2 sec
- c)2.5sec
- d)3 sec
Correct answer is option 'C'. Can you explain this answer?
Two sprinters run the same race of100 m One runs at a speed of 10 m/s and the other runs at 8 m/s. By what time will the first sprinter beat the other sprinter?
a)
1.5 sec
b)
2 sec
c)
2.5sec
d)
3 sec
|
Navya Chavan answered |
To determine the time it takes for the first sprinter to beat the second sprinter, we need to compare their speeds and calculate the time it takes for the first sprinter to cover a distance of 100m.
Let's start by calculating the time it takes for each sprinter to cover 100m:
- Sprinter 1 runs at a speed of 10m/s, so the time it takes for Sprinter 1 to cover 100m is:
Time = Distance / Speed = 100m / 10m/s = 10 seconds
- Sprinter 2 runs at a speed of 8m/s, so the time it takes for Sprinter 2 to cover 100m is:
Time = Distance / Speed = 100m / 8m/s = 12.5 seconds
From the above calculations, we can see that Sprinter 1 takes 10 seconds to cover 100m, while Sprinter 2 takes 12.5 seconds to cover the same distance.
Now, let's find out the time difference between the two sprinters:
- Time difference = Time taken by Sprinter 2 - Time taken by Sprinter 1
Time difference = 12.5 seconds - 10 seconds = 2.5 seconds
Therefore, the first sprinter beats the second sprinter by a time difference of 2.5 seconds. Hence, the correct answer is option 'C' - 2.5 seconds.
Let's start by calculating the time it takes for each sprinter to cover 100m:
- Sprinter 1 runs at a speed of 10m/s, so the time it takes for Sprinter 1 to cover 100m is:
Time = Distance / Speed = 100m / 10m/s = 10 seconds
- Sprinter 2 runs at a speed of 8m/s, so the time it takes for Sprinter 2 to cover 100m is:
Time = Distance / Speed = 100m / 8m/s = 12.5 seconds
From the above calculations, we can see that Sprinter 1 takes 10 seconds to cover 100m, while Sprinter 2 takes 12.5 seconds to cover the same distance.
Now, let's find out the time difference between the two sprinters:
- Time difference = Time taken by Sprinter 2 - Time taken by Sprinter 1
Time difference = 12.5 seconds - 10 seconds = 2.5 seconds
Therefore, the first sprinter beats the second sprinter by a time difference of 2.5 seconds. Hence, the correct answer is option 'C' - 2.5 seconds.
Kiran can do a piece of work in 9 days and Kumar can do the same work in 18 days. They started the work. After 3 days Sanjay joined them, who can complete alone the same whole work in 3 days. What is the total number of days in which they had completed the work?- a)12
- b)8
- c)4
- d)6
- e)None of these
Correct answer is option 'C'. Can you explain this answer?
Kiran can do a piece of work in 9 days and Kumar can do the same work in 18 days. They started the work. After 3 days Sanjay joined them, who can complete alone the same whole work in 3 days. What is the total number of days in which they had completed the work?
a)
12
b)
8
c)
4
d)
6
e)
None of these
|
|
Kavya Saxena answered |
Efficiency of Kiran and Kumar = 11.11 + 5.55 = 16.66%
Work done in 3 days = 3 x 16.66 = 50%
Rest work done by Kiran, Kumar and Sanjay = 50/50 = 1 day
Work can be completed in 4 days.
Work done in 3 days = 3 x 16.66 = 50%
Rest work done by Kiran, Kumar and Sanjay = 50/50 = 1 day
Work can be completed in 4 days.
Dinesh does 80% of a work in 20 days. He then calls in Gokul and theytogether finish the remaining work in 3 days. How long Gokul alone would take to do the whole work?- a)39 days
- b)37 days
- c)37 ½ days
- d)40 days
- e)39 ½ days
Correct answer is option 'C'. Can you explain this answer?
Dinesh does 80% of a work in 20 days. He then calls in Gokul and theytogether finish the remaining work in 3 days. How long Gokul alone would take to do the whole work?
a)
39 days
b)
37 days
c)
37 ½ days
d)
40 days
e)
39 ½ days
|
|
Rajeev Kumar answered |
Dinesh work done = 20*5/4 = 25 days
1/5 workdone by Dinesh and gokul in 3days.
Whole work done = 15 days
Dinesh 1 days work = 1/25
Dinesh and gokul’s 1 day work = 1/15
Gokul’s 1 day work = 1/15 – 1/25 = 2/75
Gokul alone in 75/2 days or 37 ½ days.
1/5 workdone by Dinesh and gokul in 3days.
Whole work done = 15 days
Dinesh 1 days work = 1/25
Dinesh and gokul’s 1 day work = 1/15
Gokul’s 1 day work = 1/15 – 1/25 = 2/75
Gokul alone in 75/2 days or 37 ½ days.
A can do a piece of work in 30 days, B can do in 45 days and C can do same work alone in 60 days. If on the first day A worked alone and on the second day A and B worked together and on the third day A and C worked together. If they repeat the cycle as follows then in how many days total work can be completed?- a)21 Days
- b)21 7/8 Days
- c)21 5/6 Days
- d)21 4/9 Days
- e)None
Correct answer is option 'C'. Can you explain this answer?
A can do a piece of work in 30 days, B can do in 45 days and C can do same work alone in 60 days. If on the first day A worked alone and on the second day A and B worked together and on the third day A and C worked together. If they repeat the cycle as follows then in how many days total work can be completed?
a)
21 Days
b)
21 7/8 Days
c)
21 5/6 Days
d)
21 4/9 Days
e)
None
|
|
Aarav Sharma answered |
Given: A can do a piece of work in 30 days, B can do in 45 days and C can do the same work alone in 60 days.
Let the total work be 180 units (LCM of 30, 45 and 60).
On the first day, A alone does 6 units of work (180/30).
On the second day, A and B together do (6+4) 10 units of work (LCM of 30 and 45 is 90, and A does 3 units of work in 1 day while B does 2 units of work in 1 day. So, in 1 day they will do 5 units of work. So, in 2 days, they will do 10 units of work).
On the third day, A and C together do (6+3) 9 units of work (LCM of 30 and 60 is 60, and A does 1 unit of work in 1 day while C does 1/3 units of work in 1 day. So, in 1 day they will do 4/3 units of work. So, in 3 days, they will do 4 units of work).
So, in 3 days, they have done a total of 25 units of work (6+10+9).
To complete 180 units of work, they need 155 units more (180-25).
Let's calculate the next 3 days cycle:
On the fourth day, A alone does 6 units of work.
On the fifth day, A and B together do 10 units of work.
On the sixth day, A and C together do 9 units of work.
So, in 6 days, they have done a total of 50 units of work (25+6+10+9).
To complete 180 units of work, they need 130 units more (180-50).
Let's calculate the next 3 days cycle:
On the seventh day, A alone does 6 units of work.
On the eighth day, A and B together do 10 units of work.
On the ninth day, A and C together do 9 units of work.
So, in 9 days, they have done a total of 75 units of work (25+6+10+9+6+10+9).
To complete 180 units of work, they need 105 units more (180-75).
Let's calculate the next 3 days cycle:
On the tenth day, A alone does 6 units of work.
On the eleventh day, A and B together do 10 units of work.
On the twelfth day, A and C together do 9 units of work.
So, in 12 days, they have done a total of 100 units of work (25+6+10+9+6+10+9+6+10+9).
To complete 180 units of work, they need 80 units more (180-100).
Let's calculate the next 3 days cycle:
On the thirteenth day, A alone does 6 units of work.
On the fourteenth day, A and B together do 10 units of work.
On the fifteenth day, A and C together do 9 units of work.
So, in 15 days, they have done a total of 125
Let the total work be 180 units (LCM of 30, 45 and 60).
On the first day, A alone does 6 units of work (180/30).
On the second day, A and B together do (6+4) 10 units of work (LCM of 30 and 45 is 90, and A does 3 units of work in 1 day while B does 2 units of work in 1 day. So, in 1 day they will do 5 units of work. So, in 2 days, they will do 10 units of work).
On the third day, A and C together do (6+3) 9 units of work (LCM of 30 and 60 is 60, and A does 1 unit of work in 1 day while C does 1/3 units of work in 1 day. So, in 1 day they will do 4/3 units of work. So, in 3 days, they will do 4 units of work).
So, in 3 days, they have done a total of 25 units of work (6+10+9).
To complete 180 units of work, they need 155 units more (180-25).
Let's calculate the next 3 days cycle:
On the fourth day, A alone does 6 units of work.
On the fifth day, A and B together do 10 units of work.
On the sixth day, A and C together do 9 units of work.
So, in 6 days, they have done a total of 50 units of work (25+6+10+9).
To complete 180 units of work, they need 130 units more (180-50).
Let's calculate the next 3 days cycle:
On the seventh day, A alone does 6 units of work.
On the eighth day, A and B together do 10 units of work.
On the ninth day, A and C together do 9 units of work.
So, in 9 days, they have done a total of 75 units of work (25+6+10+9+6+10+9).
To complete 180 units of work, they need 105 units more (180-75).
Let's calculate the next 3 days cycle:
On the tenth day, A alone does 6 units of work.
On the eleventh day, A and B together do 10 units of work.
On the twelfth day, A and C together do 9 units of work.
So, in 12 days, they have done a total of 100 units of work (25+6+10+9+6+10+9+6+10+9).
To complete 180 units of work, they need 80 units more (180-100).
Let's calculate the next 3 days cycle:
On the thirteenth day, A alone does 6 units of work.
On the fourteenth day, A and B together do 10 units of work.
On the fifteenth day, A and C together do 9 units of work.
So, in 15 days, they have done a total of 125
A work is done by 30 workers not all of them have the same capacity to work. Every day exactly 2 workers, do the work with no pair of workers working together twice. Even after all possible pairs have worked once, all the workers together works for six more days to finish the work. Find the number of days in which all the workers together will finish the work?- a)22 days
- b)20 days
- c)24 days
- d)35 days
- e)32 days
Correct answer is option 'D'. Can you explain this answer?
A work is done by 30 workers not all of them have the same capacity to work. Every day exactly 2 workers, do the work with no pair of workers working together twice. Even after all possible pairs have worked once, all the workers together works for six more days to finish the work. Find the number of days in which all the workers together will finish the work?
a)
22 days
b)
20 days
c)
24 days
d)
35 days
e)
32 days
|
Gowri Chakraborty answered |
Explanation :
30 workers work in pairs, with no same pair of workers working together twice
29[1/w1 + 1/w2 ….. + 1/w30] + 6[1/w1 + 1/w2 ….. + 1/w30] = 1
[1/w1 + 1/w2 ….. + 1/w30] = 1/35
35 days.
Chapter doubts & questions for Time and Work - Mathematics for RRB NTPC / ASM 2025 is part of RRB NTPC/ASM/CA/TA exam preparation. The chapters have been prepared according to the RRB NTPC/ASM/CA/TA exam syllabus. The Chapter doubts & questions, notes, tests & MCQs are made for RRB NTPC/ASM/CA/TA 2025 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests here.
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